Java DateComparison - java

I use the code below to see if my input date (format mm/dd/yyyy HH:mm:ss) falls within the range of startDate and endDate.
I use compareTo() in this logic. But with the format mm/dd/yyyy, it compares the month alone and prints output in "MYLOGIC methood". But I need the year to be compared to see if the input date is within startDate and endDate range.
public class DateLogicNew {
public static void main(String[] args) {
String startDate[] = new String[1];
String endDate[] = new String[1];
startDate[0] = "01/01/0600 00:00:00";
endDate[0] = "11/27/3337 00:00:00";
String inputArr[] = { "05/01/0500 01:00:00", "11/27/3337 00:00:00",
"05/05/0700 00:00:00", "11/27/2337 00:00:00",
"06/05/4000 00:00:00" };
String protectedArr[] = new String[inputArr.length];
int temp[] = new int[inputArr.length];
System.out.println(inputArr.length);
System.out.println("Length of the inputArr: " + inputArr.length);
// System.out.println("");
for (int i = 0; i < inputArr.length; i++) {
if (inputArr[i]
.matches("^([0-1][0-9])/([0-3][0-9])/([0-9]{4})(?:( [0-2][0-9]):([0-5][0-9]):([0-5][0-9]))?$")) {
System.out.println("Inside if loop");
if (inputArr[i].compareTo(startDate[0]) > 0
&& inputArr[i].compareTo(endDate[0]) < 0) {
System.out.println("inside the compare condition");
temp[i] = 1;
protectedArr[i] = inputArr[i];
System.out
.println("Values of the inputArr in MYLOGIC method : "
+ protectedArr[i]);
}
} else {
temp[i] = 0;
}
}
System.out.println("");
for (int i = 0; i < inputArr.length; i++) {
if (temp[i] == 1) {
inputArr[i] = protectedArr[i];
}
System.out
.println("Final Value to the output port: " + inputArr[i]);
}
}
}

java.time
Parse as date-time objects. Regex is overkill.
The modern approach uses the java.time classes rather than the old legacy date-time classes.
String input = "05/01/0500 01:00:00" ;
DateTimeFormatter f = DateTimeFormatter.ofPattern( "MM/dd/uuuu HH:mm:ss" ) ;
LocalDateTime ldt = LocalDateTime.parse( input , f ) ;
Compare using methods isBefore, isAfter, isEqual.
if( ( ! x.isBefore( start ) ) && x.isBefore( stop ) ) { … }

I myself figured out the solution for my question. Please check the code below to see the logic before comparing the dates.
String startDate = "0600/01/01 00:00:00";
String endDate = "3337/11/27 00:00:00";
try {
for (int i = 0; i < inputArr.length; i++) {
String newDateInput = inputArr[i];
// System.out.println("NewInput:" + newInput);
DateFormat parser = new SimpleDateFormat("MM/dd/yyyy");
DateFormat formatter = new SimpleDateFormat("yyyy/MM/dd");
Date convertedDate = parser.parse(newDateInput);
String newFormattedInput = formatter.format(convertedDate);
// System.out.println("newFormattedInput: " +
// newFormattedInput);
if (newFormattedInput
.matches("^([0-9]{4})/([0-1][0-9])/([0-3][0-9])(?:( [0-2][0-9]):([0-5][0-9]):([0-5][0-9]))?$")) {
if (newFormattedInput.compareTo(startDate) > 0
&& newFormattedInput.compareTo(endDate) < 0) {
temp[i] = 1;
protectedArr[i] = inputArr[i];
System.out
.println("Values of the inputArr in PROTECT method : "
+ protectedArr[i]);
} else {
temp[i] = 0;
}
}
}
} catch (ParseException e) {
e.printStackTrace();
}

Related

How to get Time Slot based on 1hour interval

I want to store time slot in the arraylist. i have start time and end time. based on start time it should create time slot.
For example if start time is 09:00AM and end time is 21:00PM then it should add into arraylist like below
09:00AM
10:00AM
11:00AM
12:00PM
13:00PM
14:00PM
..... so on
21:00PM
so one user books 13:00PM to 15:00PM slots so it should not be available to another user and other slot should be available. how to compare already booking time with new array list.
Code
private void getStartHourArray() {
times = new ArrayList<TimeSlot>();
Calendar calender = Calendar.getInstance();
calender.setTimeZone(TimeZone.getTimeZone("Asia/Calcutta"));
int ti = calender.get(Calendar.HOUR_OF_DAY);
int minutes = calender.get(Calendar.MINUTE);
System.out.println(minutes);
String[] quarterHours = {
"00",
"30",
};
boolean isflag = false;
times = new ArrayList<>();
for (int i = 9; i < 22; i++) {
if (ti > 8) {
for (int j = 0; j < 2; j++) {
if ((i == ti && minutes < Integer.parseInt(quarterHours[j])) || (i != ti) || isflag == true) {
isflag = true;
String time = i + ":" + quarterHours[j];
if (i < 10) {
time = "0" + time;
}
String hourFormat = i + ":" + quarterHours[j];
if (i < 12) {
hourFormat = time + " AM";
} else
hourFormat = time + " PM";
TimeSlot t = new TimeSlot();
t.time = hourFormat;
t.isAvailable = "Available";
times.add(t);
}
}
}
}
if (times != null) {
load.setVisibility(View.GONE);
}
}
Time Slot model class
public class TimeSlot {
public String time;
public String isAvailable;
}
Try something like this :
String firstDate = "26/02/2019";
String firstTime = "00:00 AM";
String secondDate = "26/02/2019";
String secondTime = "12:00 PM";
String format = "dd/MM/yyyy hh:mm a";
SimpleDateFormat sdf = new SimpleDateFormat(format);
Date dateObj1 = sdf.parse(firstDate + " " + firstTime);
Date dateObj2 = sdf.parse(secondDate + " " + secondTime);
System.out.println("Date Start: "+dateObj1);
System.out.println("Date End: "+dateObj2);
long dif = dateObj1.getTime();
while (dif < dateObj2.getTime()) {
Date slot = new Date(dif);
System.out.println("Hour Slot --->" + slot);
dif += 3600000;
}
This will give you a time slot for each hour, add this in ArrayList and when any user select time then remove that from ArrayList and update to the server so when next
user tries to get data it won't get the first selected user time slot.
try this:
import java.time.LocalTime;
import java.util.HashMap;
import java.util.Map;
public class PlayGround {
private Map<LocalTime, Boolean> slots = new HashMap();
public static void main(String[] args) {
PlayGround client = new PlayGround();
client.initializeSlots();
client.allocateSlots("10:00", "13:00");
//this shouldn't be available
client.allocateSlots("11:00", "12:00");
//not sure if u want this to be available. since it is start when the 1st just finished.
client.allocateSlots("13:00", "15:00");
client.allocateSlots("16:00", "18:00");
}
private void initializeSlots() {
LocalTime time = LocalTime.of(9, 0);
slots.put(time, true);
for (int i = 1; i < 24; i++) {
slots.put(time.plusHours(i), true);
}
}
private void allocateSlots(String strTime, String edTime) {
LocalTime startTime = LocalTime.parse(strTime);
LocalTime endTime = LocalTime.parse(edTime);
while (startTime.isBefore(endTime)) {
//check if the time slots between start and end time are available
if (!slots.get(startTime) || !slots.get(endTime)) {
System.out.println("slots not available" + " start time: " + strTime + " end time: " + edTime);
return;
}
startTime = startTime.plusHours(1);
endTime = endTime.minusHours(1);
}
System.out.println("slots are available" + " start time: " + strTime + " end time: " + edTime);
//then here u can mark all slots between to unavailable.
startTime = LocalTime.parse(strTime);
endTime = LocalTime.parse(edTime);
while (startTime.isBefore(endTime)) {
slots.put(startTime, false);
slots.put(endTime, false);
startTime = startTime.plusHours(1);
endTime = endTime.minusHours(1);
}
}
}

How to get first and last date of weeks on basis of month and year in android

how to get first and last date of weeks on basis of month and year in android
ex:we pass month and year (March,2016) then i want all weeks just like
mar5- mar11,(sat to fri)
mar12- mar18,
mar19- mar25,
mar26-april01
please help me
Call this function to get results in a valid week pair list of given month of a year.
ex: getWeekStartEnd("December","2016");
Result: [
December3-December9,
December10-December16,
December17-December23,
December24-December30
]
List<String> getWeekStartEnd (String month , String year) {
List<String> validWeekPairs = new ArrayList<>();
SimpleDateFormat sdf = new SimpleDateFormat("dd-MMMMM-yyyy");
String day = "01";
try {
Date date = sdf.parse(day + "-" + month + "-" + year);
Calendar calendar = Calendar.getInstance();
calendar.clear();
calendar.setTime(date);
calendar.setFirstDayOfWeek(Calendar.SATURDAY);
List<String> startDayOfWeek = new ArrayList<>();
List<String> endDayOfWeek = new ArrayList<>();
int daysInMonth = calendar.getActualMaximum(Calendar.DAY_OF_MONTH);
boolean isStartDaySet = false;
boolean hasLastDayOfWeek = true;
for (int currentDay = 01; currentDay <= daysInMonth; currentDay++) {
Date newDate = sdf.parse(currentDay + "-" + month + "-" + year);
calendar.setTime(newDate);
int dayOfWeek = calendar.get(Calendar.DAY_OF_WEEK);
if (dayOfWeek == Calendar.SATURDAY) {
if (hasLastDayOfWeek) {
startDayOfWeek.add(month + String.valueOf(currentDay));
isStartDaySet = true;
hasLastDayOfWeek = false;
}
} else if (dayOfWeek == Calendar.FRIDAY) {
if (isStartDaySet) {
endDayOfWeek.add(month + String.valueOf(currentDay));
hasLastDayOfWeek = true;
}
}
}
for (int i = 0; i < endDayOfWeek.size(); i++) {
validWeekPairs.add(startDayOfWeek.get(i) + "-" + endDayOfWeek.get(i));
}
return validWeekPairs;
} catch (ParseException e) {
e.printStackTrace();
return validWeekPairs;
}catch (Exception e){
e.printStackTrace();
return validWeekPairs;
}
}
If you are using java.util.Date you can use the method getDay(). It returns Calendar constant, like Calendar.MONDAY.
You can pass the string as 02,2016
List<String> getWeekendsOftheMonth(String monthYearString) {
long monthDate;
List<String> weekEnds = new ArrayList<>();
SimpleDateFormat simpleDateFormat= new SimpleDateFormat("dd,MM,yyyy");
try {
monthYearString="01,".concat(monthYearString);
monthDate = simpleDateFormat.parse(monthYearString).getTime();
Calendar calendar = Calendar.getInstance();
calendar.setTimeInMillis(monthDate);
int maxDate = calendar.getActualMaximum(Calendar.DATE);
int minDate = calendar.getActualMinimum(Calendar.DATE);
for (int i = minDate; i <= maxDate; i++) {
calendar.set(Calendar.DATE, i);
if (calendar.get(Calendar.DAY_OF_WEEK) == Calendar.FRIDAY|| calendar.get(Calendar.DAY_OF_WEEK) == Calendar.SATURDAY) {
weekEnds.add(convertToDate(calendar.getTimeInMillis()));
}
}
}catch (Exception e){
e.printStackTrace();
}
return weekEnds;
}
String convertToDate(Long datetime) {
SimpleDateFormat simpleDateFormat = new SimpleDateFormat("dd MMM. yyyy");
Date date = new Date(datetime);
return simpleDateFormat.format(date);
}
you can do it from this method.

Unable to loop for different data

I am unable to loop through my database for timeList to output different time that I require. They only loop through the first one and display the same data for every output that I require. If I were to close the for loop of of the conversion, I would have problem displaying it in the output statement.
String[] timeMinute = timeList .split("<SPLIT>");
for (int t = 0; t <timeMinute.length; t ++)
{
String strDate = timeList;
SimpleDateFormat sdf = new SimpleDateFormat("yyyyMMddHHmmss");
Date getDate = sdf.parse(strDate);
Calendar calendar = Calendar.getInstance();
calendar.setTime(getDate);
int noOfHours = calendar.get(Calendar.HOUR_OF_DAY);
int noOfMinutes = calendar.get(Calendar.MINUTE);
int totalMinutes = noOfHours * 60 + noOfMinutes;
while ( rs.next() )
{
String RTD= rs.getString("RTD");
if ( !trd1.contains( RTD) )
trd1.add(RTD);
String admissionCOUNT = "";
if ( rs.getString("jae") != null )
admission = rs.getString("jae");
String[] admissionCOUNT = admission.split("<SPLIT>");
for ( int i = 0 ; i <gateNo.length ; i ++ )
{
if ( kpm.containsKey(gateNo[i]) )
kpm.get(admissionCOUNT [i]).put(RTD, + totalMinutes);
}
}
for ( int i = 0 ; i < .size(); i++)
{
stringWriter.append( trd1.get(i) + ",");
for ( String admissionCOUNT : kpm.keySet() )
{
if ( kpm.get(admissionCOUNT ).containsKey(trd1.get(i) ) )
MSO.get(admissionCOUNT ).append(totalMinutes +",");
else
MSO.get(admissionCOUNT ).append("0,");
}
}
The current output example -
data1,0,56,0
data2,56,0,0
data3,56,0,0
data4,0,0,56
Desire output example -
data1,0,87,0
data2,56,0,0
data3,43,0,0
data4,0,0,91
edit:
for ( String egm : .keySet() )
resultString += System.getProperty("line.separator") + gate + "," + MSO.get(egm).toString();

How to itrate the json list?

I have a list,that list i have put inside the json object that list I want to iterate using jquery and I need to append to the table.Could anyone please help me to solve this.
This is my action class.
String startdate = request.getParameter("startdate");
String endate = request.getParameter("endate");
String leavepolicyid = request.getParameter("leavepolicyid");
Session session = HibernateUtil.getSessionFactory().openSession();
LeavePolicyEntity lpe = (LeavePolicyEntity) session.get(LeavePolicyEntity.class, Integer.parseInt(leavepolicyid));
SimpleDateFormat sdf = new SimpleDateFormat("MM/dd/yyyy");
Calendar fromcal = Calendar.getInstance();
fromcal.setTime(sdf.parse(startdate));
Calendar endCal = Calendar.getInstance();
endCal.setTime(sdf.parse(endate));
int actualDays = 0;
boolean excludeWeekends = lpe.isExcludeweekends();
int totalDays = 0;
List daysList = new ArrayList();
StringBuffer sb = new StringBuffer();
SimpleDateFormat dateFormat = new SimpleDateFormat("EEE", Locale.US);
SimpleDateFormat sdf1 = new SimpleDateFormat("dd-MMM-yyyy");
while (!fromcal.after(endCal)) {
sb.setLength(0);
System.out.println("fromcal.get(Calendar.DAY_OF_WEEK)" + fromcal.get(Calendar.DAY_OF_WEEK));
if (excludeWeekends) {
if ((7 != fromcal.get(Calendar.DAY_OF_WEEK)) && (1 != fromcal.get(Calendar.DAY_OF_WEEK))) {
actualDays++;
// String asWeek = dateFormat.format(fromcal.getTime());
sb.append(dateFormat.format(fromcal.getTime()) + "-" + sdf1.format(fromcal.getTime()) + ",true");
} else {
sb.append(dateFormat.format(fromcal.getTime()) + "-" + sdf1.format(fromcal.getTime()) + ",false");
}
} else {
sb.append(dateFormat.format(fromcal.getTime()) + "-" + sdf1.format(fromcal.getTime()) + ",true");
actualDays++;
}
daysList.add(sb.toString());
fromcal.add(Calendar.DATE, 1);
totalDays++;
}
// System.out.println("daysListdaysListdaysList" + daysList);
// JSONObject json = new JSONObject();
// json.accumulate("weekdays", daysList);
response.setContentType("application/json");
String json = new Gson().toJson(daysList);
System.out.println("Json" + json);
response.getWriter().print(json);
Jquery ajax
$("[id^='leavetype']").change(function() {
var startdate = $('#leavetypefromdate').val();
var enddate = $('#leavetypetodate').val();
// alert(startdate)
// alert(enddate)
if (startdate != "" && enddate != "") {
if (new Date(startdate) <= new Date(enddate)) {
$.get("leaverequestvalidation.do?method=validateleavetype", {startdate: startdate, endate: enddate, leavepolicyid: $('#leaveTypeid').val()}, function(responce) {
alert(responce);
$.each(JSON.parse(responce), function(idx, obj) {
alert(1);
});
});
} else {
alert("FromDate Cannot Be Greater Than ToDate")
}
}
});

Conversion from 12 hours time to 24 hours time in java

In my app, I have a requirement to format 12 hours time to 24 hours time. What is the method I have to use?
For example, time like 10:30 AM. How can I convert to 24 hours time in java?
Try this:
import java.text.SimpleDateFormat;
import java.util.Date;
public class Main {
public static void main(String [] args) throws Exception {
SimpleDateFormat displayFormat = new SimpleDateFormat("HH:mm");
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a");
Date date = parseFormat.parse("10:30 PM");
System.out.println(parseFormat.format(date) + " = " + displayFormat.format(date));
}
}
which produces:
10:30 PM = 22:30
See: http://download.oracle.com/javase/1.5.0/docs/api/java/text/SimpleDateFormat.html
java.time
In Java 8 and later it could be done in one line using class java.time.LocalTime.
In the formatting pattern, lowercase hh means 12-hour clock while uppercase HH means 24-hour clock.
Code example:
String result = // Text representing the value of our date-time object.
LocalTime.parse( // Class representing a time-of-day value without a date and without a time zone.
"03:30 PM" , // Your `String` input text.
DateTimeFormatter.ofPattern( // Define a formatting pattern to match your input text.
"hh:mm a" ,
Locale.US // `Locale` determines the human language and cultural norms used in localization. Needed here to translate the `AM` & `PM` value.
) // Returns a `DateTimeFormatter` object.
) // Return a `LocalTime` object.
.format( DateTimeFormatter.ofPattern("HH:mm") ) // Generate text in a specific format. Returns a `String` object.
;
See this code run live at IdeOne.com.
15:30
See Oracle Tutorial.
Assuming that you use SimpleDateFormat implicitly or explicitly, you need to use H instead of h in the format string.
E.g
HH:mm:ss
instead of
hh:mm:ss
12 to 24 hour time conversion and can be reversed if change time formate in output and input SimpleDateFormat class parameter
Test Data Input:
String input = "07:05:45PM";
timeCoversion12to24(input);
output
19:05:45
public static String timeCoversion12to24(String twelveHoursTime) throws ParseException {
//Date/time pattern of input date (12 Hours format - hh used for 12 hours)
DateFormat df = new SimpleDateFormat("hh:mm:ssaa");
//Date/time pattern of desired output date (24 Hours format HH - Used for 24 hours)
DateFormat outputformat = new SimpleDateFormat("HH:mm:ss");
Date date = null;
String output = null;
//Returns Date object
date = df.parse(twelveHoursTime);
//old date format to new date format
output = outputformat.format(date);
System.out.println(output);
return output;
}
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a");
provided by Bart Kiers answer should be replaced with somethig like
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm a",Locale.UK);
Try This
public static String convertTo24Hour(String Time) {
DateFormat f1 = new SimpleDateFormat("hh:mm a"); //11:00 pm
Date d = null;
try {
d = f1.parse(Time);
} catch (ParseException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
DateFormat f2 = new SimpleDateFormat("HH:mm");
String x = f2.format(d); // "23:00"
return x;
}
static String timeConversion(String s)
{
String s1[]=s.split(":");
char c[]=s1[2].toCharArray();
if(s1[2].contains("PM"))
{
int n=Integer.parseInt(s1[0]);
n=n+12;
return n+":"+s1[1]+":"+c[0]+c[1];
}
else``
return s1[0]+":"+s1[1]+":"+c[0]+c[1];
}
It can be done using Java8 LocalTime. Here is the code.
import java.time.LocalTime;
import java.time.format.DateTimeFormatter;
public class TimeConversion {
public String timeConversion(String s) {
LocalTime.parse(s, DateTimeFormatter.ofPattern("hh:mm a"));
}
}
And Here is the test case for the same:
import org.junit.jupiter.api.Assertions;
import org.junit.jupiter.api.Test;
class TimeConversionTest {
#Test
void shouldReturnTimeIn24HrFormat() {
TimeConversion timeConversion = new TimeConversion();
Assertions.assertEquals("22:30", timeConversion.timeConversion("10:30 PM"));
}
}
Using LocalTime in Java 8, LocalTime has many useful methods like getHour() or the getMinute() method,
For example,
LocalTime intime = LocalTime.parse(inputString, DateTimeFormatter.ofPattern("h:m a"));
String outtime = intime.format(DateTimeFormatter.ISO_LOCAL_TIME);
In some cases, First line alone can do the required parsing
This is the extract of code that I have done.
String s="08:10:45";
String[] s1=s.split(":");
int milipmHrs=0;
char[] arr=s1[2].toCharArray();
boolean isFound=s1[2].contains("PM");
if(isFound){
int pmHrs=Integer.parseInt(s1[0]);
milipmHrs=pmHrs+12;
return(milipmHrs+":"+s1[1]+":"+arr[0]+arr[1]);
}
else{
return(s1[0]+":"+s1[1]+":"+arr[0]+arr[1]);
}
import java.text.SimpleDateFormat;
import java.text.DateFormat;
import java.util.Date;
public class Main {
public static void main(String [] args){
try {
DateFormat parseFormat = new SimpleDateFormat("dd-MM-yyyy hh:mm:ss a");
String sDate = "22-01-2019 9:0:0 PM";
Date date = parseFormat.parse(sDate);
SimpleDateFormat displayFormat = new SimpleDateFormat("dd-MM-yyyy HH:mm:ss");
sDate = displayFormat.format(date);
LOGGER.info("The required format : " + sDate);
} catch (Exception e) {}
}
}
Try this to calculate time difference between two times.
first it will convert 12 hours time into 24 hours then it will take diff between two times
String a = "09/06/18 01:55:33 AM";
String b = "07/06/18 05:45:33 PM";
String [] b2 = b.split(" ");
String [] a2 = a.split(" ");
SimpleDateFormat displayFormat = new SimpleDateFormat("HH:mm:ss");
SimpleDateFormat parseFormat = new SimpleDateFormat("hh:mm:ss a");
String time1 = null ;
String time2 = null ;
if ( a.contains("PM") && b.contains("AM")) {
Date date = parseFormat.parse(a2[1]+" PM");
time1 = displayFormat.format(date);
time2 = b2[1];
}else if (b.contains("PM") && a.contains("AM")) {
Date date = parseFormat.parse(a2[1]+" PM");
time1 = a2[1];
time2 = displayFormat.format(date);
}else if (a.contains("PM") && b.contains("PM")){
Date datea = parseFormat.parse(a2[1]+" PM");
Date dateb = parseFormat.parse(b2[1]+" PM");
time1 = displayFormat.format(datea);
time2 = displayFormat.format(dateb);
}
System.out.println(time1);
System.out.println(time2);
SimpleDateFormat format = new SimpleDateFormat("HH:mm:ss");
Date date1 = format.parse(time1);
Date date2 = format.parse(time2);
long difference = date2.getTime() - date1.getTime();
System.out.println(difference);
System.out.println("Duration: "+DurationFormatUtils.formatDuration(difference, "HH:mm"));
For More Details Click Here
I have written a simple utility function.
public static String convert24HourTimeTo12Hour(String timeStr) {
try {
DateFormat inFormat = new SimpleDateFormat( "HH:mm:ss");
DateFormat outFormat = new SimpleDateFormat( "hh:mm a");
Date date = inFormat.parse(timeStr);
return outFormat.format(date);
}catch (Exception e){}
return "";
}
Try this below code,
public static String timeConversion(String s) {
String militaryTime = "";
String hourString = s.substring(0,2);
String timeFormat = s.substring(8,10);
String timeBody = s.substring(2,8);
if (timeFormat.equals("AM")){
if (hourString.equals("12")){
militaryTime = "00" + timeBody;
}else{
militaryTime = hourString + timeBody;
}
}else if (timeFormat.equals("PM")){
if (hourString.equals("12")){
militaryTime = hourString + timeBody;
}else{
int value = Integer.parseInt(hourString) + 12;
militaryTime = String.valueOf(value) + timeBody;
}
}
return militaryTime;
}
Without using library methods
public static String timeConversion(String s) {
String[] timeElements = s.split(":");
if (s.contains("PM")) {
timeElements[0] = getPMHours(timeElements[0]);
} else {
timeElements[0] = getAMHours(timeElements[0]);
}
timeElements[2] = timeElements[2].substring(0,2);
return timeElements[0]+":"+timeElements[1]+":"+timeElements[2];
}
private static String getAMHours(String hour) {
if(Integer.parseInt(hour) == 12) return "00";
return hour;
}
private static String getPMHours(String hour) {
int i = Integer.parseInt(hour);
if(i != 12) return 12+i+"";
return i+"";
}
I was looking for same thing but in number, means from integer xx hour, xx minutes and AM/PM to 24 hour format xx hour and xx minutes, so here what i have done:
private static final int AM = 0;
private static final int PM = 1;
/**
* Based on concept: day start from 00:00AM and ends at 11:59PM,
* afternoon 12 is 12PM, 12:xxAM is basically 00:xxAM
* #param hour12Format
* #param amPm
* #return
*/
private int get24FormatHour(int hour12Format,int amPm){
if(hour12Format==12 && amPm==AM){
hour12Format=0;
}
if(amPm == PM && hour12Format!=12){
hour12Format+=12;
}
return hour12Format;
}`
private int minutesTillMidnight(int hour12Format,int minutes, int amPm){
int hour24Format=get24FormatHour(hour12Format,amPm);
System.out.println("24 Format :"+hour24Format+":"+minutes);
return (hour24Format*60)+minutes;
}
We can solve this by using String Buffer
String s;
static String timeConversion(String s) {
StringBuffer st=new StringBuffer(s);
for(int i=0;i<=st.length();i++){
if(st.charAt(0)=='0' && st.charAt(1)=='1' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '3');
}else if(st.charAt(0)=='0' && st.charAt(1)=='2' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '4');
}else if(st.charAt(0)=='0' && st.charAt(1)=='3' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '5');
}else if(st.charAt(0)=='0' && st.charAt(1)=='4' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '6');
}else if(st.charAt(0)=='0' && st.charAt(1)=='5' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '7');
}else if(st.charAt(0)=='0' && st.charAt(1)=='6' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '8');
}else if(st.charAt(0)=='0' && st.charAt(1)=='7' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '1');
st.setCharAt(1, '9');
}else if(st.charAt(0)=='0' && st.charAt(1)=='8' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '2');
st.setCharAt(1, '0');
}else if(st.charAt(0)=='0' && st.charAt(1)=='9' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '2');
st.setCharAt(1, '1');
}else if(st.charAt(0)=='1' && st.charAt(1)=='0' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '2');
st.setCharAt(1, '2');
}else if(st.charAt(0)=='1' && st.charAt(1)=='1' &&st.charAt(8)=='P' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '2');
st.setCharAt(1, '3');
}else if(st.charAt(0)=='1' && st.charAt(1)=='2' &&st.charAt(8)=='A' ){
// if(st.charAt(2)=='1'){
// st.replace(1,2,"13");
st.setCharAt(0, '0');
st.setCharAt(1, '0');
}else if(st.charAt(0)=='1' && st.charAt(1)=='2' &&st.charAt(8)=='P' ){
st.setCharAt(0, '1');
st.setCharAt(1, '2');
}
if(st.charAt(8)=='P'){
st.setCharAt(8,' ');
}else if(st.charAt(8)== 'A'){
st.setCharAt(8,' ');
}
if(st.charAt(9)=='M'){
st.setCharAt(9,' ');
}
}
String result=st.toString();
return result;
}

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