I am using the following CURL command to save the response in .pdf format:
curl -d "#name_of_xmlFile.xml" -X POST http:url/ -o name_of_response_pdfFile.pdf
how to make the call and save the response generated pdf file in a specific folder using java.
Welcome to stack overflow !
The problem here is that curl is a Linux command. Because Java is intended to be written once and run everywhere (on any machine), then java cannot directly use commands like curl, which do not exist by default on every operating system.
Therefore you need to include additional functionality from elsewhere.
Personally I like to use Unirest which is a nice simple lightweight framework to aid with using Rest in Java.
Good luck !
You can also perform a post in Java without using curl (not sure whether using curl is a MUST have requirement)
taken from this article:
private void doPost() throws Exception {
String url = "http:url/";
URL obj = new URL(url);
HttpsURLConnection con = (HttpsURLConnection) obj.openConnection();
//add reuqest header
con.setRequestMethod("POST");
String urlParameters = "sn=C02G8416DRJM&cn=&locale=&caller=&num=12345";
// Send post request
con.setDoOutput(true);
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
wr.writeBytes(urlParameters);
wr.flush();
wr.close();
int responseCode = con.getResponseCode();
System.out.println("\nSending 'POST' request to URL : " + url);
System.out.println("Post parameters : " + urlParameters);
System.out.println("Response Code : " + responseCode);
BufferedReader in = new BufferedReader(
new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
//print result
System.out.println(response.toString());
// could ewually save to file rather than to stdout.
}
For sending the body, you may try this.
If using curl is a hard requirement, you may use Runtime.getRuntime().exec(command); as shown here, but be aware that this isn't necessarily portable (e.g. if curl is not installed) and could be unsafe if the commands being run aren't in some way validated to prevent bad actors running arbitrary commands etc...
I know this may be a duplicate question but I applied all the patches as suggested in other related questions, but still have no luck resolving the issue.
The issue is When I hit a URL (It's an API provided by SMS provider through which we send SMS to our clients. It worked for more than a year and suddenly we start getting an exception.) from Browser I get the required result but When I do it through code then it gives me 404 Not Found. It freaks me out when 1 out (10/20) hit is successful and I get a response to that specific hit.
URL we hit:
https://rest.nexmo.com/sms/xml
In response, we git XML based text file. e.g if I hit the above URL from a browser I get a file with a name api.txt which has an XML based response.
This is the code I have written.
URL obj = new URL(url);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
con.setRequestMethod("GET");
int responseCode = con.getResponseCode();
System.out.println("\nSending 'GET' request to URL : " + url);
System.out.println("Response Code : " + responseCode);
BufferedReader in = new BufferedReader(new
InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
This is the exception:
java.io.FileNotFoundException: https://rest.nexmo.com/sms/xml?api_key=apiKey&api_secret=password&from=ourprojectname&to=mobilenumber&account-ref=account_registeration_number&text=encoded_message&type=text
As the provider accepts requests as post also.We converted this code for sending post request still getting the same exception.
As this URL is when hitting through a browser we are getting a response so I added a header user-agent in request property still got the same exception.
we have some certificate problem for other URLs before which we fixed. Added the same configuration for this URL still getting the same 404 response.
Need some suggestion on this matter any small help will be appreciated.
I got the authorization code following this document. But when I tried to get access token, I always got errors. Can anyone help me ?
public String AccessToken()
{
String accessToken = "";
StringBuilder strBuild = new StringBuilder();
String authURL = "https://accounts.google.com/o/oauth2/token?";
String code = "4/SVisuz_x*********************";
String client_id = "******************e.apps.googleusercontent.com";
String client_secret = "*******************";
String redirect_uri = "urn:ietf:wg:oauth:2.0:oob";
String grant_type="authorization_code";
strBuild.append("code=").append(code)
.append("&client_id=").append(client_id)
.append("&client_secret=").append(client_secret)
.append("&redirect_uri=").append(redirect_uri)
.append("&grant_type=").append(grant_type);
System.out.println(strBuild.toString());
try{
URL obj = new URL(authURL);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
con.setDoOutput(true);
con.setRequestMethod("POST");
con.setRequestProperty("Content-Type", "application/x-www-form-urlencoded");
con.setRequestProperty("Host", "www.googleapis.com");
//BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(con.getOutputStream()));
//bw.write(strBuild.toString());
//bw.close();
DataOutputStream wr = new DataOutputStream(con.getOutputStream());
wr.writeBytes(strBuild.toString());
wr.flush();
wr.close();
//OutputStreamWriter out = new OutputStreamWriter(con.getOutputStream());
System.out.println(con.getResponseCode());
System.out.println(con.getResponseMessage());
} catch (Exception e)
{
System.out.println("Error.");
}
return "";
}
when I ran this code, the output is:
400
Bad Request
How to get access token using gmail api?
Ans: As per your following tutorial, you are using OAuth 2.0. So there is a basic pattern for accessing a Google API using OAuth 2.0. It follows 4 steps:
Obtain OAuth 2.0 credentials from the Google Developers Console.
Obtain an access token from the Google Authorization Server.
Send the access token to an API.
Refresh the access token, if necessary.
For details, you can follow the tutorial - Using OAuth 2.0 to Access Google APIs
You have to visit the Google Developers Console to obtain OAuth 2.0 credentials such as a client ID and client secret that are known to both Google and your application
Root Cause Analysis:
Issue-1:
After studying your code, some lacking are found. If your code runs smoothly, then the code always give an empty string. Because your AccessToken() method always return return "";
Issue-2:
catch (Exception e)
{
System.out.println("Error.");
}
Your try catch block is going exception block. Because, it seems that you have not completed your code properly. You have missed encoding as well as using JSONObject which prepares the access token. So it is giving output as
Error.
Solution:
I got that your code is similar with this tutorial
As your code needs more changes to solve your issue. So I offer you to use LinkedHashMap or ArrayList. Those will provide easier way to make solution. So I give you 2 sample code to make your life easier. You can choose any of them. You need to change refresh_token, client id, client secret and grant type as yours.
private String getAccessToken()
{
try
{
Map<String,Object> params = new LinkedHashMap<>();
params.put("grant_type","refresh_token");
params.put("client_id",[YOUR CLIENT ID]);
params.put("client_secret",[YOUR CLIENT SECRET]);
params.put("refresh_token",[YOUR REFRESH TOKEN]);
StringBuilder postData = new StringBuilder();
for(Map.Entry<String,Object> param : params.entrySet())
{
if(postData.length() != 0)
{
postData.append('&');
}
postData.append(URLEncoder.encode(param.getKey(),"UTF-8"));
postData.append('=');
postData.append(URLEncoder.encode(String.valueOf(param.getValue()),"UTF-8"));
}
byte[] postDataBytes = postData.toString().getBytes("UTF-8");
URL url = new URL("https://accounts.google.com/o/oauth2/token");
HttpURLConnection con = (HttpURLConnection)url.openConnection();
con.setDoOutput(true);
con.setUseCaches(false);
con.setRequestMethod("POST");
con.getOutputStream().write(postDataBytes);
BufferedReader reader = new BufferedReader(new InputStreamReader(con.getInputStream()));
StringBuffer buffer = new StringBuffer();
for (String line = reader.readLine(); line != null; line = reader.readLine())
{
buffer.append(line);
}
JSONObject json = new JSONObject(buffer.toString());
String accessToken = json.getString("access_token");
return accessToken;
}
catch (Exception ex)
{
ex.printStackTrace();
}
return null;
}
For accessing google play android developer api, you need to pass the
previous refresh token to get access token
private String getAccessToken(String refreshToken){
HttpClient client = new DefaultHttpClient();
HttpPost post = new HttpPost("https://accounts.google.com/o/oauth2/token");
try
{
List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(4);
nameValuePairs.add(new BasicNameValuePair("grant_type", "refresh_token"));
nameValuePairs.add(new BasicNameValuePair("client_id", GOOGLE_CLIENT_ID));
nameValuePairs.add(new BasicNameValuePair("client_secret", GOOGLE_CLIENT_SECRET));
nameValuePairs.add(new BasicNameValuePair("refresh_token", refreshToken));
post.setEntity(new UrlEncodedFormEntity(nameValuePairs));
org.apache.http.HttpResponse response = client.execute(post);
BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
StringBuffer buffer = new StringBuffer();
for (String line = reader.readLine(); line != null; line = reader.readLine())
{
buffer.append(line);
}
JSONObject json = new JSONObject(buffer.toString());
String accessToken = json.getString("access_token");
return accessToken;
}
catch (IOException e) { e.printStackTrace(); }
return null;
}
Resource Link:
Unable to get the subscription information from Google Play Android Developer API
Using java.net.URLConnection to fire and handle HTTP requests
How to send HTTP request GET/POST in Java
Hope that, this samples and resource link will help you to solve your issue and get access of access token.
What is 400 bad request?
Ans: It indicates that the query was invalid. Parent ID was missing or the combination of dimensions or metrics requested was not valid.
Recommended Action: You need to make changes to the API query in order for it to work.
For HTTP/1.1 400 Bad Request error, you can go through my another
answer. It will help you to make sense about which host you
need to use and which conditions you need to apply.
Why token expires? What is the limit of token?
A token might stop working for one of these reasons:
The user has revoked access.
The token has not been used for six months.
The user changed passwords and the token contains Gmail, Calendar,
Contacts, or Hangouts scopes.
The user account has exceeded a certain number of token requests.
There is currently a limit of 25 refresh tokens per user account per client. If the limit is reached, creating a new token automatically invalidates the oldest token without warning. This limit does not apply to service accounts.
Which precautions should be followed?
Precautions - 1:
Some requests require an authentication step where the user logs in
with their Google account. After logging in, the user is asked whether
they are willing to grant the permissions that your application is
requesting. This process is called user consent.
If the user grants the permission, the Google Authorization Server
sends your application an access token (or an authorization code that
your application can use to obtain an access token). If the user does
not grant the permission, the server returns an error.
Precautions - 2:
If an access token is issued for the Google+ API, it does not grant
access to the Google Contacts API. You can, however, send that access
token to the Google+ API multiple times for similar operations.
Precautions - 3:
An access token typically has an expiration date of 1 hour, after
which you will get an error if you try to use it. Google Credential
takes care of automatically "refreshing" the token, which simply means
getting a new access token.
Save refresh tokens in secure long-term storage and continue to use
them as long as they remain valid. Limits apply to the number of
refresh tokens that are issued per client-user combination, and per
user across all clients, and these limits are different. If your
application requests enough refresh tokens to go over one of the
limits, older refresh tokens stop working.
You are not using the right endpoint. Try to change the authURL to https://www.googleapis.com/oauth2/v4/token
From the documentation:
To make this token request, send an HTTP POST request to the /oauth2/v4/token endpoint
The actual request might look like the following:
POST /oauth2/v4/token HTTP/1.1
Host: www.googleapis.com
Content-Type: application/x-www-form-urlencoded
code=4/v6xr77ewYqhvHSyW6UJ1w7jKwAzu&
client_id=8819981768.apps.googleusercontent.com&
client_secret=your_client_secret&
redirect_uri=https://oauth2-login-demo.appspot.com/code&
grant_type=authorization_code
Reference https://developers.google.com/identity/protocols/OAuth2InstalledApp#handlingtheresponse
For me your request is fine, I tried it using Curl, I also get a 'HTTP/1.1 400 Bad Request' with the reason why it failed 'invalid_grant' :
curl -X POST https://www.googleapis.com/oauth2/v4/token -d 'code=4/SVisuz_x*********************&client_id=*******************7vet.apps.googleusercontent.com&client_secret=***************&redirect_uri=https://oauth2-login-demo.appspot.com/code&grant_type=authorization_code'
I receive (HTTP/1.1 400 Bad Request) :
{
"error": "invalid_grant",
"error_description": "Code was already redeemed."
}
Now using HttpClient from Apache :
URL obj = new URL(authURL);
HttpClient client = HttpClientBuilder.create().build();
HttpPost post = new HttpPost(authURL);
post.addHeader("Content-Type", "application/x-www-form-urlencoded");
post.addHeader("Host", "www.googleapis.com");
post.setEntity(new StringEntity(strBuild.toString()));
HttpResponse resp = client.execute(post);
System.out.println(resp.getStatusLine());
System.out.println(EntityUtils.toString(resp.getEntity()));
I see in my console :
HTTP/1.1 400 Bad Request
{
"error": "invalid_grant",
"error_description": "Code was already redeemed."
}
Are you sure the code you are using is still valid ? Can you try with a new one ?
Firstly, you must look this page :
https://developers.google.com/gmail/api/auth/web-server#create_a_client_id_and_client_secret
The value you see in the query parameter code is a string you have to post to google in order to get the access token.
After the web server receives the authorization code, it may exchange the authorization code for an access token and a refresh token. This request is an HTTPS POST to the URL https://www.googleapis.com/oauth2/v3/token
POST /oauth2/v3/token HTTP/1.1
content-type: application/x-www-form-urlencoded
code=4/v4-CqVXkhiTkn9uapv6V0iqUmelHNnbLRr1EbErzkQw#&redirect_uri=&client_id=&scope=&client_secret=************&grant_type=authorization_code
https://developers.google.com/identity/protocols/OAuth2WebServer
I think I understand what's wrong:
as #newhouse said, you should POST to https://www.googleapis.com/oauth2/v4/token and not https://accounts.google.com/o/oauth2/token (#newhouse I gave you a +1 :) )
(https://www.googleapis.com/oauth2/v4/token is for getting the authorization_code and https://accounts.google.com/o/oauth2/token is for getting the code).
You can't use the same code more than once.
Everything else seems in order so, if you keep getting 400, you are probably trying to use the code you got more than one time (then you'll get 400 every time, again and again).
* You should also lose the con.setRequestProperty("Host", "www.googleapis.com");
Refer : https://developers.google.com/android-publisher/authorization
You already have authorization code that is called "refresh token". Please keep it in safe place. You can use "refresh token" to generate "access token".
To get "access token", please make a post request to following URL
https://accounts.google.com/o/oauth2/token
Parameters:
grant_type
client_id
client_secret
refresh_token
where "grant_type" should be "refresh_token"
We are using PHP to do same, here is PHP's code for your reference
$curl = curl_init();
curl_setopt_array($curl, array(
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_URL => 'https://accounts.google.com/o/oauth2/token',
CURLOPT_USERAGENT => 'Pocket Experts Services',
CURLOPT_POST => 1,
CURLOPT_POSTFIELDS => array(
"grant_type" => "refresh_token",
"client_id" => $GOOGLE_CLIENT_ID,
"client_secret" => $GOOGLE_CLIENT_SECRET,
"refresh_token" => $GOOGLE_REFRESH_TOKEN,
)));
// Send the request & save response to $resp
$resp = curl_exec($curl);
Hope it will help you.
the low security methode was temporary and i couldn't use it in production but I found an article that made it easier using node here
with an example code and it works perfect
I am trying to retrieve some html texts from a list of google returned pages. most of them work fine, but for urls such as https://www.google.com/patents/US6034687 always gives 401 error see below
Server returned HTTP response code: 401 for URL: https://www.google.com/patents/US6034687
I am using java and I did look up on this error code, it seems authentication related, but this kind of URL can be accessed from any browsers without asking for login. So I am confused, how come only this kind of URL does not work for me.
here is my code for retrieving html
URL u=new URL(url);
StringBuilder html =new StringBuilder();
HttpURLConnection conn = (HttpURLConnection) u.openConnection();
conn.setRequestMethod("GET");
conn.setRequestProperty("Accept", "text/html");
BufferedReader br;
try {
br = new BufferedReader(new InputStreamReader((conn.getInputStream())));
String out="";
while ((out= br.readLine()) != null) {
// System.out.println(out);
html.append(out+"\n");
}
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
Any idea?
thanks
Try sending a User-Agent header in the request. That 401 status is misleading. Some servers do not allow requests from non-browser clients.
conn.setRequestProperty("User-Agent", "Mozilla/5.0 (Windows NT 5.2; rv:21.0) Gecko/20100101 Firefox/21.0");
BTW, when you do openConnection() for an https scheme, the return value is HttpsURLConnection, which extends HttpURLConnection.
The request requires user authentication. The response MUST include a WWW-Authenticate header field containing a challenge applicable to the requested resource. The client MAY repeat the request with a suitable Authorization header field. If the request already included Authorization credentials, then the 401 response indicates that authorization has been refused for those credentials. If the 401 response contains the same challenge as the prior response, and the user agent has already attempted authentication at least once, then the user SHOULD be presented the entity that was given in the response, since that entity might include relevant diagnostic information. HTTP access authentication is explained in "HTTP Authentication: Basic and Digest Access Authentication
I am trying to make a HTTPS call using Java to a browser that uses the native login prompt.
http://blog.stevensanderson.com/2008/08/25/using-the-browsers-native-login-prompt/
Currently I'm using the below for HTTP and it works fine for other websites since I know the parameters to put in...however it fails for the above type of login (I am not sure how to capture the parameters...it's a login pop up..or if this is even the correct approach)....any ideas??..thanks
HttpUtility.sendPostRequest(requestURL, params);
String[] response = HttpUtility.readMultipleLinesRespone();
The server should respond to your first request with a WWW-Authenticate header and a status of 401. The header will contain details of the kind of authentication it's expecting.
Then you can try again after adding an Authorization header to your request in the correct format.
#alex: OK...I managed to make the HTTPS connection following your suggestion with this:
URL url = new URL("https://www.example.com/Login");
URLConnection urlConnection = url.openConnection();
urlConnection.setRequestProperty("Authorization", "Basic " + authString);
InputStream is = urlConnection.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
//then I read the input stream..
But when I tried to make another connection (say go to a different page after login) with this code in another method...taking URLConnection as the parameter:
//Below is in a method called account(URLConnection urlConnection)
URL url = new URL("https://www.example.com/account.aspx");
urlConnection = url.openConnection();
InputStream is = urlConnection.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
//again I read the input stream..
...it throws the below exception...same exception before logging in..how can I rectify?
Server returned HTTP response code: 401 for URL: https://www.example.com/account.aspx
You have probably moved on from this problem, but I recently had an issue that involved achieving functionality similar to the browser's native login prompt. I have solved it and written a post about it. Steven Sanderson's post was helpful for me too, in helping me understand certain concepts.
http://captaindanko.blogspot.com.au/2015/04/how-does-browsers-native-login-prompt.html