I need to get count and sum of my ObjectEntity in one Query form Repository Layer. Count is a Long value, but sum is Double value. It possible to locate result in one DTO Object from Repository method or locate it numeric list object e.g. List ?
Query method look like below
#Query(value = "Select count(f), sum(f.valueToPay) from ObjectEntity f ")
Object[] getData();
POJO Object
#Data
public class ObjectDTO {
Double value;
Long quantity;
}
If I'm understanding the question correctly, you just need the results of the query to go into an object that will give you meaningful and consistent variable names.
All you should need to do is Change Object[] to ObjectDTO so that you have
#Query(value = "Select count(f), sum(f.valueToPay) from ObjectEntity f ")
ObjectDTO getData();
Right now you are mapping to an object array instead of the actual object you want to use.
Use a JPQL Constructor Expression:
#Query(value = "Select NEW com.company.pathToYourDto.ObjectDTO(count(f), sum(f.valueToPay)) from ObjectEntity f ")
ObjectDTO getData();
Related
I am fetching values from table and storing 1st value into "yr" and 2nd value into some other variable but I am not getting proper value while casting object into string.
List<Object[]> listObject = ddeffectiverepository.getDetails("P-to-P", fullImpacted);
String yr = listObject.get(0)[0].toString();
my repository:
#Query("select ed.year, ed.fullimpact from EffectiveImpact ed where ed.part = ?1 and ed.rgn = ?2")
public List<Object[]> getDetails(String part, String rgn);
but while debugging i am getting values into listObject but it is not storing first value into yr. Instead of it is storing some object like "[Ljava.lang.Object;#2d8383cd"
Instead of holding values in Object, hold them into Object Array.
Here is changed code:
repository:
#Query("select ed.year, ed.fullimpact from EffectiveImpact ed where ed.part = ?1 and ed.rgn = ?2")
public List<Object[]> getDetails(String part, String rgn);
Service/business layer :
List<Object[]> listObject = ddeffectiverepository.getDetails("P-to-P", fullImpacted);
String yr = listObject.get(0)[0].toString();
Suppose I have a table which contains all the accounts of user and type.
I want to make a Jpa Repository method which returns an array of total number of each type of user (USER, ADMIN, MASTER).
Here is how I did it in JpaRepository:
#Query(value="SELECT (SELECT COUNT(*) FROM account WHERE account_role='USER'),"
+ "(SELECT COUNT(*) FROM account WHERE account_role='ADMIN'),"
+ "(SELECT COUNT(*) FROM account WHERE account_role='MASTER')"
+ "FROM account LIMIT 1",
nativeQuery=true)
public List<Integer> getTotalAccountType();
The code executed fine, but the result wasn't what I expected.
Result:
[2]
Expected result: [2,10,30]
Any idea how would I use nested SQL with JPQL? Thank you in advance!
If repository method returns List of Integers it means that query result row contains an Integer value. But you expect to get sequence of Integers in one row.
You can get same result different way:
#Query(value="SELECT COUNT(*) FROM account WHERE account_role=?", nativeQuery=true)
public Integer getTotalAccountType(String role);
and then:
Integer userCount = repository.getTotalAccountType("USER");
Integer adminCount = repository.getTotalAccountType("ADMIN");
Integer masterCount = repository.getTotalAccountType("MASTER");
or if you have mapped entity:
create Pair<K,V> class with constructor Pair(K key, V value) or use it from any external library
repository method based on hql query
#Query(value="select new javafx.util.Pair(a.accountRole, count(a)) from Account a group by a.accountRole")
public List<Pair<String, Integer>> getRoleCountList();
convert repository result to a Map<String, Integer> in service
javafx.util.Pair<String, Integer> result = repository.getRoleCountList();
Map<String, Integer> map = result.stream().collect(Collectors.toMap(r-> r.getKey(), r-> r.getValue()));
Try returning Object[] rather than a List<Integer>. I think returning List<Integer> would indicate multiple rows of an Integer value are being returned, whereas you're getting back one row with multiple Intger columns.
From the resulting Object[] you would pull out the first value (indicating a row). This should be another Object[], which will have your values in the order returned.
You can also remove that last "FROM account LIMIT 1" line, as it has no bearing on the result.
I would recommend casting all of this to an object though. As seen here -
How to return a custom object from a Spring Data JPA GROUP BY query
I use JPA 1.0:
Query query;
query = em.createNamedQuery("getThresholdParameters");
query.setParameter(1, Integer.parseInt(circleId));
List<Object[]> resultList = new ArrayList();
resultList = query.getResultList();
Here I get result as List<Object[]>, thus I have to type convert all the parameters of the row to their respective types which is cumbersome.
In JPA 2.0 there is TypedQuery which return an entity object of type one specifies.
But as I am using JPA 1 I can't use it.
How to get result as Entity object of type I want??
EDIT:
QUERY
#Entity
#Table(name="GMA_THRESHOLD_PARAMETERS")
#NamedQuery(
name = "getThresholdParameters",
query = "select gmaTh.minNumberOc, gmaTh.minDurationOc, gmaTh.maxNumberIc, gmaTh.maxDurationIc, gmaTh.maxNumberCellId,"
+ "gmaTh.distinctBnumberRatio, gmaTh.minPercentDistinctBnumber from GmaThresholdParameter gmaTh "
+ "where gmaTh.id.circleId=?1 AND gmaTh.id.tspId=?2 AND gmaTh.id.flag=?3 "
)
Your query selects many fields. Such a query always returns a list of Object arrays. If you want a list containing instances of your GmaThresholdParameter entity, then the query should be
select gmaTh from GmaThresholdParameter gmaTh
where gmaTh.id.circleId=?1 AND gmaTh.id.tspId=?2 AND gmaTh.id.flag=?3
The code to get the list of entities would then be
List<GmaThresholdParameter> resultList = query.getResultList();
You'll get a type safety warning from the compiler, that you can ignore.
I can't respond to this as a comment so I'll just go ahead and make it an answer.
List<Object[]> resultList = new ArrayList(); // CREATE an empty ArrayList object
resultList = query.getResultList(); // getResultList ALSO returns its own ArrayList object
And since you assign the list that getResultList() returns to the same variable as you used for your own empty ArrayList, your application loses any connection to your own empty ArrayList and Java will collect it as garbage. Essentially you created it for absolutely no purpose.
what JB Nizet posted is enough.
List<GmaThresholdParameter> resultList = query.getResultList();
I have done something similar since I was using JPA 1 at that time:
final Collection<YourType> typedResult = new ArrayList<YourType>
for(final Object result : query.getResultList())
{
typedResult.add((YourType) result);
}
return typedResult;
List<GmaThresholdParamerter> result= query.getResultList();
for( GmaThresholdParamerter res : result)
{
System.out.println("" +res.getMinNumberOc());
System.out.println("" +res.getMinDurationOc());
}
I have some very complicated SQL (does some aggregation, some counts based on max value etc) so I want to use SQLQuery rather than Query. I created a very simple Pojo:
public class SqlCount {
private String name;
private Double count;
// getters, setters, constructors etc
Then when I run my SQLQuery, I want hibernate to populate a List for me, so I do this:
Query hQuery = sqlQuery.setResultTransformer(Transformers.aliasToBean(SqlCount.class));
Now I had a problem where depending on what the values are for 'count', Hibernate will variably retrieve it as a Long, Double, BigDecimal or BigInteger. So I use the addScalar function:
sqlQuery.addScalar("count", StandardBasicTypes.DOUBLE);
Now my problem. It seems that if you don't use the addScalar function, Hibernate will populate all of your fields with all of your columns in your SQL result (ie it will try to populate both 'name' and 'count'). However if you use the addScalar function, it only maps the columns that you listed, and all other columns seem to be discarded and the fields are left as null. In this instance, it wouldn't be too bad to just list both "name" and "count", but I have some other scenarios where I need a dozen or so fields - do I really have to list them all?? Is there some way in hibernate to say "map all fields automatically, like you used to, but by the way map this field as a Double"?
Is there some way in hibernate to say "map all fields automatically.
No, check the document here, find 16.1.1. Scalar queries section
The most basic SQL query is to get a list of scalars (values).
sess.createSQLQuery("SELECT * FROM CATS").list();
sess.createSQLQuery("SELECT ID, NAME, BIRTHDATE FROM CATS").list();
These will return a List of Object arrays (Object[]) with scalar values for each column in the CATS table. Hibernate will use ResultSetMetadata to deduce the actual order and types of the returned scalar values.
To avoid the overhead of using ResultSetMetadata, or simply to be more explicit in what is returned, one can use addScalar():
sess.createSQLQuery("SELECT * FROM CATS")
.addScalar("ID", Hibernate.LONG)
.addScalar("NAME", Hibernate.STRING)
.addScalar("BIRTHDATE", Hibernate.DATE)
i use this solution, I hope it will work with you.
with this solution you can populate what you select from the SQL, and return it as Map, and cast the values directly.
since hibernate 5.2 the method setResultTransformer() is deprecated but its work fine to me and works perfect.
if you hate to write extra code addScalar() for each column from the SQL, you can implement ResultTransformer interface and do the casting as you wish.
ex:
lets say we have this Query:
/*ORACLE SQL*/
SELECT
SEQ AS "code",
CARD_SERIAL AS "cardSerial",
INV_DATE AS "date",
PK.GET_SUM_INV(SEQ) AS "sumSfterDisc"
FROM INVOICE
ORDER BY "code";
note: i use double cote for case-sensitive column alias, check This
after create hibernate session you can create the Query like this:
/*Java*/
List<Map<String, Object>> list = session.createNativeQuery("SELECT\n" +
" SEQ AS \"code\",\n" +
" CARD_SERIAL AS \"cardSerial\",\n" +
" INV_DATE AS \"date\",\n" +
" PK.GET_SUM_INV(SEQ) AS \"sumSfterDisc\"\n" +
"FROM INVOICE\n" +
"ORDER BY \"code\"")
.setResultTransformer(new Trans())
.list();
now the point with Trans Class:
/*Java*/
public class Trans implements ResultTransformer {
private SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss", Locale.US);
#Override
public Object transformTuple(Object[] objects, String[] strings) {
Map<String, Object> map = new LinkedHashMap<>();
for (int i = 0; i < strings.length; i++) {
if (objects[i] == null) {
continue;
}
if (objects[i] instanceof BigDecimal) {
map.put(strings[i], ((BigDecimal) objects[i]).longValue());
} else if (objects[i] instanceof Timestamp) {
map.put(strings[i], dateFormat.format(((Timestamp) objects[i])));
} else {
map.put(strings[i], objects[i]);
}
}
return map;
}
#Override
public List transformList(List list) {
return list;
}
}
here you should override the two method transformTuple and transformList, in transformTuple you have two parameters the Object[] objects its the columns values of the row and String[] strings the names of the columns the hibernate Guaranteed the same order of of the columns as you order it in the query.
now the fun begin, for each row returned from the query the method transformTuple will be invoke, so you can build the row as Map or create new object with fields.
I've created a Repository that extends CrudRepository,
this repository has a method with an #Query notation:
Code:
#Query("select itemType, count(*) as count from Item where User_id = :userId group by itemType")
List<Map<String, Long>> countItemsForUser(#Param("userId") Long userId);
The issue I'm having is that this return a ArrayList of Object(s) and not a List of Map.
I've read somewhere that JPA can't return a Map so that's why I stuff the result in a List>.
I don't know what's the best way to work around this issue or to quickly access the result data.
I've tried casting but that didn't work out either:
for(Object item: items) {
Map<String,Long> castedItem = (HashMap<String,Long>)item;
}
See this example in official documentation of Hibernate.Here
for (Object item:items) {
Object[] tuple = (Object[]) item;
String itemType = (String)tuple[0];
Long count = (Long) tuple[1];
}
Most simple way is to use interface. To let Spring wire query alias
to the interface getter. Example can be found here: https://www.baeldung.com/jpa-queries-custom-result-with-aggregation-functions
also there is #SqlResultSetMapping. See:
JPA- Joining two tables in non-entity class