Line Scanner Loop [duplicate] - java

This question already has an answer here:
How to use java.util.Scanner to correctly read user input from System.in and act on it?
(1 answer)
Closed 5 years ago.
I'm trying to print out "YES" for each line in a file (dna.txt) that starts with "ATG" and ends with "TAA", "TAG", or "TGA", and "NO" when this isn't the case. It should stop after the lines in the file are done, but I've created some kind of loop in my code where nothing is printed to the output file (hi.txt) but "NO"...endlessly. I know it should have some "YES"ses too, but my problem is clearly larger than just not reading the tokens of the file correctly.
My code:
public static void Results(Scanner console) throws
FileNotFoundException {
System.out.print("Input file name? ");
Scanner input = new Scanner(new File("dna.txt"));
System.out.print("Output file name: ");
File outputFile = new File("hi.txt");
System.out.println();
PrintStream outputRead = new PrintStream(outputFile);
String isProtein = "NO";
while (input.hasNextLine()) {
String line = input.nextLine().toUpperCase();
Scanner lineScan = new Scanner(line);
while (lineScan.hasNext()) {
if (line.startsWith("ATG")) {
if (line.endsWith("TAA") || line.endsWith("TAG") ||
line.endsWith("TGA")) {
isProtein = "YES";
}
}
}
outputRead.println(isProtein);
}
System.out.println(isProtein);
}
Text file (though it should work with any text file, and it isn't):
protein?
ATGCCACTATGGTAG
protein?
ATgCCAACATGgATGCCcGATAtGGATTgA
protein?
CCATt-AATgATCa-CAGTt
protein?
ATgAG-ATC-CgtgatGTGgg-aT-CCTa-CT-CATTaa
protein?
AtgC-CaacaTGGATGCCCTAAG-ATAtgGATTagtgA
protein?
atgataattagttttaatatcaga-ctgtaa
Do you have any idea where this loop is forming? If so, please just give me hints as to how I should fix this.
Thanks!

Just Modified few lines,
Changes
1.) Commented Scanner lineScan = new Scanner(line);
2.) Need to reset value for isProtein, in loop, for next iteration.
o/p is printed in text file hi.txt. BTW i have used text file for R/W operations so commented out scanner part.
Code
public static void Results() throws FileNotFoundException {
//System.out.print("Input file name? ");
Scanner input = new Scanner(new File("dna.txt"));
//System.out.print("Output file name: ");
File outputFile = new File("hi.txt");
//System.out.println();
PrintStream outputRead = new PrintStream(outputFile);
String isProtein = "NO";
while (input.hasNextLine()) {
String line = input.nextLine().toUpperCase();
//Scanner lineScan = new Scanner(line);
//while (lineScan.hasNext()) {
if (line.startsWith("ATG")) {
if (line.endsWith("TAA") || line.endsWith("TAG") || line.endsWith("TGA")) {
isProtein = "YES";
}
}else{
isProtein = "NO";
}
//}
outputRead.println(isProtein);
isProtein = "NO";
}
//System.out.println(isProtein);
}
Output
NO
YES
NO
YES
NO
NO
NO
YES
NO
YES
NO
YES

Related

Reading Text File into Array using Java generates Exception

Even though the file Movie_db.txt isn't empty, I get the following exception:
the text file consists of this:
hank horror 20.0 18 1
public void syncDB(List<Movie> movieList) throws IOException {
Scanner scanner = new Scanner("Movie_db.txt");
BufferedReader reader = null;
try {
String line = null;
String title;
String genre;
double movieDuration;
int ageRestriction;
int id;
while (scanner.hasNext()) {
title = scanner.next();
genre = scanner.next();
movieDuration = scanner.nextDouble();
ageRestriction = scanner.nextInt();
id = scanner.nextInt();
movieList.add(new Movie(title, genre, movieDuration, ageRestriction, id));
}
} catch (Exception e) {
System.out.println("List is empty");
}
}
Considering your path is correct, there is a problem in your code. I'd change this line
Scanner scan = new Scanner("Movie_db.txt");
with this one
Scanner scan = new Scanner(Paths.get("Movie_db.txt"));
The reason is that in your snippet the Scanner only reads the string "Movie_db.txt" and in the second snippet it recognizes as the path to file.
Read Scanner documentation for more info
genre = scan.next(); line is throwing exception because nothing is left to read from file now, which causes catch block to execute.
You are providing a string to Scanner which is a valid input for scanner. Hence, it never reads the file.
Scanner scan = new Scanner(new File("full_path_to_container_dir/Movie_db.txt"));
Please have a look at this blog on how to read from a file using scanner - https://www.java67.com/2012/11/how-to-read-file-in-java-using-scanner-example.html.

Scanner issue! Code is skipping the first user input and printing twice instead of once ONLY on the first iteration

https://courses.cs.washington.edu/courses/cse142/15sp/homework/6/spec.pdf
EDIT* Input Files are here:(sorry i'm new to stack overflow, hopefully this works)
I've also tried console.next() but it gives different errors than console.nextLine() in the rePlaceholder method. **
tarzan.txt - https://pastebin.com/XDxnXYsM
output for tarzan should look like this: https://courses.cs.washington.edu/courses/cse142/17au/homework/madlibs/expected_output_1.txt
simple.txt https://pastebin.com/Djc2R0Vz
clothes.txt https://pastebin.com/SQB8Q7Y8
this code should print to an output file you name.
Hello, I have a question about scanners because I don't understand why the code
is skipping the user input on the first iteration but works fine on the rest.
I'm writing a code to create a madlib program and the link will provide the explanation to the program but pretty much you have these placeholders in a text file and when you see one, you prompt for user input to replace it with your own words. However, my program always go through TWO placeholders first and only ask the user input for one, completely skipping the first placeholder. What is wrong with my code??? Also, how do you fix this? Everything else is running perfectly fine, only that the first line is consuming two placeholders so I'm always off by one.
Welcome to the game of Mad Libs.
I will ask you to provide various words
and phrases to fill in a story.
The result will be written to an output file.
(C)reate mad-lib, (V)iew mad-lib, (Q)uit? c
Input file name: tarzan.txt
Output file name: test.txt
Please type an adjective: Please type a plural noun: DD DDDD <--- why is it like this
Please type a noun: DDDD
Please type an adjective: DD
Please type a place:
========================================================================
package MadLibs;
import java.util.*;
import java.io.*;
public class MadLibs2 {
public static void main(String[] args) throws FileNotFoundException {
Scanner console = new Scanner(System.in);
intro();
boolean isTrue = true;
while(isTrue) {
System.out.print("(C)reate mad-lib, (V)iew mad-lib, (Q)uit? ");
String choice = console.next();
if (choice.equalsIgnoreCase("c")) {
create(console);
}
else if (choice.equalsIgnoreCase("v")) {
view(console);
}
else if (choice.equalsIgnoreCase("q")) {
System.exit(0);
}
}
}
public static void view(Scanner console) throws FileNotFoundException {
System.out.print("Input file name: ");
String viewFile = console.next();
File existingMadLib = new File(viewFile);
Scanner printText = new Scanner(existingMadLib);
while(printText.hasNextLine()) {
System.out.println(printText.nextLine());
}
}
public static void create(Scanner console) throws FileNotFoundException {
System.out.print("Input file name: ");
String inputFile = console.next();
File newMadLib = new File(inputFile);
while(!newMadLib.exists()) {
System.out.print("File not found. Try again: ");
inputFile = console.next();
newMadLib = new File(inputFile);
}
System.out.print("Output file name: ");
String outputFile = console.next();
System.out.println();
PrintStream output = new PrintStream(new File(outputFile));
Scanner input = new Scanner(newMadLib);
while(input.hasNextLine()) {
String line = input.nextLine();
outputLines(line, output, console);
}
}
public static void outputLines(String line, PrintStream output, Scanner console) throws FileNotFoundException{
String s = "";
Scanner lineScan = new Scanner(line);
while(lineScan.hasNext()){
s = lineScan.next();
if(s.startsWith("<") || s.endsWith(">")) {
s = rePlaceholder(console, lineScan, s);
}
output.print(s + " ");
}
output.println();
}
public static String rePlaceholder(Scanner console, Scanner input, String token) {
String placeholder = token;
placeholder = placeholder.replace("<", "").replace(">", "").replace("-", " ");
if (placeholder.startsWith("a") || placeholder.startsWith("e") || placeholder.startsWith("i")
|| placeholder.startsWith("o") || placeholder.startsWith("u")) {
System.out.print("Please type an " + placeholder + ": ");
} else {
System.out.print("Please type a " + placeholder + ": ");
}
String change = console.nextLine();
return change;
}
public static void intro() {
System.out.println("Welcome to the game of Mad Libs.");
System.out.println("I will ask you to provide various words");
System.out.println("and phrases to fill in a story.");
System.out.println("The result will be written to an output file.");
}
}
in your rePlaceholder, change this line:
String change = console.nextLine();
Into this
String change = console.next();
Your problem is that nextLine doesn't wait for your output, just reads what it has in the console, waiting for a new line.
This is from the documentation to be a bit more precise on the explanation:
Since this method continues to search through the input looking for a
line separator, it may buffer all of the input searching for the line
to skip if no line separators are present.
UPDATE
After reading the comment, the previous solution will not work for multiple words.
After reading the output file, you are using next().
You need to make another call to nextLine() to clean the buffer of any newlines.
System.out.print("Output file name: ");
String outputFile = console.next();
console.nextLine(); // dummy call
System.out.println();

Scanner only recognizes certain lines in a text file but not others

I have a txt file of names and genders that I imported for this java program. The scanners are supposed take a user input (name and gender) and compare it line by line to find it within the text file and then print the line at which the name was found. However, only some names work and not others. I think it may be because the program only reads every other line but im not sure if thats the problem, or how to fix it.
Link to the name file: http://courses.cs.washington.edu/courses/cse142/16au/homework/names.txt
public static void fileSearch() throws FileNotFoundException {
System.out.println("What name are you looking for?");
Scanner scan = new Scanner(System.in);
String name = scan.nextLine();
String gender = scan.nextLine();
File file = new File("names.txt");
Scanner fileScan = new Scanner(file);
while (fileScan.hasNextLine()) {
String line = fileScan.nextLine();
Scanner lineScan = new Scanner(line);
String nameText = lineScan.next();
String genderText = lineScan.next();
if (name.equalsIgnoreCase(nameText) && gender.equalsIgnoreCase(genderText)) {
System.out.println(line);
}
}
}
}

How to skip reading a line with scanner

I have read in a text file and am scanning said file. The question I have is how would I skip over lines that include a certain character (in my case lines that start with " // " and " " (whitespace).
Here is my code at the moment. Can someone point me in the right direction?
File dataFile = new File(filename);
Scanner scanner = new Scanner(dataFile);
while(scanner.hasNext())
{
String lineOfText = scanner.nextLine();
if (lineOfText.startsWith("//")) {
System.out.println(); // not sure what to put here
}
System.out.println(lineOfText);
}
scanner.close();
You will only want to execute the code within the while-loop if the line of text doesn't start with a / or whitespace. You can filter these out as seen below:
while(scanner.hasNext()) {
String lineOfText = scanner.nextLine();
if (lineOfText.startsWith("//") || lineOfText.startsWith(" ")) {
continue; //Exit this iteration if line starts with space or /
}
System.out.println(lineOfText);
}
As you are iterating over the lines of text in the file, use String's startsWith() method to check if the line starts with the sequences you are trying to avoid.
If it does, continue to the next line. Otherwise, print it.
while (scanner.hasNext()) {
String lineOfText = scanner.nextLine();
if (lineOfText.startsWith("//") || lineOfText.startsWith(" ") ) {
continue;
}
System.out.println(lineOfText);
}
Just use a continue like -
if (lineOfText.startsWith("//")) {
continue; //would skip the loop to next iteration from here
}
Detials - What is the "continue" keyword and how does it work in Java?
If you're just interested in printing out the lines of code that begin with a "//" then you should just use the continue keyword in java.
String lineOfText = scanner.nextLine();
if (lineOfText.startsWith("//")) {
continue;
}
See this post for more information regarding the "continue" keyword.
You can just insert "else" in your code like:
public static void main(String[] args) throws FileNotFoundException {
File dataFile = new File("testfile.txt");
Scanner scanner = new Scanner(dataFile);
while(scanner.hasNext())
{
String lineOfText = scanner.nextLine();
if (lineOfText.startsWith("//")) {
System.out.println();
}
else
System.out.println(lineOfText);
}
scanner.close();
}
}

Why I get the java.lang.NullPointerException? [duplicate]

This question already has answers here:
System.console() returns null
(13 answers)
Closed 7 years ago.
I want to input a name and to print the first char ....
public class Test {
public static void main(String[] args) {
Console console = System.console();
System.out.println("Type your name : ");
String inputChar = console.readLine();
char firstChar = inputChar.charAt(0);
System.out.println(firstChar);
}
}
Some IDEs will return NPE for Console class. you can use the Scanner class and do it easily:
try this:
Scanner scan = new Scanner(System.in);
System.out.println("Enter a Name:");
String s = scan.next();
System.out.println(s.charAt(0));
this will print the first letter of your input String.
Using the Console class can a bit unreliable at times.
For reading console input, it would be preferrable to use either the Scanner class or a BufferedReader.
You can use a Scanner like :
Scanner scanner = new Scanner(System.in); // System.in is the console's inputstream
System.out.print("Enter text : ");
String input = scanner.nextLine();
// ^^ This reads the entire line. Use this if you expect spaces in your input
// Otherwise, you can use scanner.next() if you only want to read the next token
System.out.println(input);
You can also use BufferedReader like :
pre Java 7 syntax
try {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Enter text : ");
String input = br.readLine();
System.out.println(input);
br.close();
} catch (Exception e) {
e.printStackTrace();
}
Java 7 syntax
try (BufferedReader br = new BufferedReader(new InputStreamReader(System.in))) {
System.out.print("Enter text : ");
String input = br.readLine();
System.out.println(input);
} catch (Exception e) {
e.printStackTrace();
}
Note: You need to use a try-catch statement when calling br.readLine() because it throws an IOException.
You can use Scanner if you want to read tokens (chunks of text separated by spaces). Use a BufferedReader if you want to simply read from the InputStream.

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