Issues writing doubles to files, writing nothing - java

I seem to be missing something when it comes to writing doubles to text files, when I check the file, just blank space is present. When I read from the file and print with System.out.println(); it just prints nothing... What's going wrong here? Do I need to do some converting?
import java.io.*;
import javax.swing.JOptionPane;
public class ReadCalcAveragePrint {
double firstNum;
double secondNum;
double average;
public void readFile() {
try {
File f = new File("numbers.txt");
BufferedReader br = new BufferedReader(new FileReader(f));
String one = br.readLine();
String two = br.readLine();
firstNum = Double.parseDouble(one);
secondNum = Double.parseDouble(two);
average = (firstNum + secondNum) / 2;
JOptionPane.showMessageDialog(null, average, "title", JOptionPane.PLAIN_MESSAGE);
} catch (Exception e) {
e.printStackTrace();
System.out.println(e);
}
}
public void writeFile() {
try {
File f = new File("result.txt");
FileOutputStream fos = new FileOutputStream(f);
DataOutputStream dos = new DataOutputStream(fos);
dos.writeDouble(average);
dos.flush();
fos.close();
System.out.println("Printed.");
} catch (Exception e) {
e.printStackTrace();
System.out.println(e);
}
}
public void readResult() {
try {
File f = new File("result.txt");
BufferedReader br = new BufferedReader(new FileReader(f));
String one = br.readLine();
System.out.println(one);
} catch (Exception e) {
e.printStackTrace();
System.out.println(e);
}
}
public static void main(String[] args) {
new ReadCalcAveragePrint().readFile();
new ReadCalcAveragePrint().writeFile();
new ReadCalcAveragePrint().readResult();
}
}

In the main you are creating 3 different objects, only the first is going to contain the numbers you read from the file.
You should just create and reuse one object:
public static void main(String[] args) {
ReadCalcAveragePrint obj = new ReadCalcAveragePrint();
obj.readFile();
obj.writeFile();
obj.readResult();
}
Also you are writing the result file using DataOutputStream which is meant to write the data in binary form. If you just want to save the result as text you should use FileWriter instead:
File f = new File("result.txt");
FileWriter fw = new FileWriter(f);
fw.write(String.valueOf(average));
fw.close();

see the javadoc of writeDouble:
Converts the double argument to a long using the doubleToLongBits method in class Double, and then writes that long value to the underlying output stream as an 8-byte quantity, high byte first.
you write 8 bytes that may not be assigned to any alphanumeric character. Then you read it a line as a String (characters up to the next 'new line' char).
In this case, the 'new line' char can be anywhere, or nowhere (depending on the result).
8 bytes in file means almost 4 chars, very likely, no one is a "visible character".
Try to read a byte[8] from the InputStream (not from a Buffered one), and then put those 8 bytes into DoubleBuffer, then you can get the double value represented by those bytes and writen to the file before.

Related

Can't read from binary file - read some lines in UTF-8, some in binary

I have this code:
import java.io.*;
import java.nio.charset.StandardCharsets;
public class Main {
public static void main(String[] args) {
zero("zero.out");
System.out.println(zeroRead("zero.out"));
}
public static String zeroRead(String name) {
try (FileInputStream fos = new FileInputStream(name);
BufferedInputStream bos = new BufferedInputStream(fos);
DataInputStream dos = new DataInputStream(bos)) {
StringBuffer inputLine = new StringBuffer();
String tmp;
String s = "";
while ((tmp = dos.readLine()) != null) {
inputLine.append(tmp);
System.out.println(tmp);
}
dos.close();
return s;
}
catch (IOException e) {
e.printStackTrace();
}
return null;
}
public static void zero(String name) {
File file = new File(name);
String text = "König" + "\t";
try (FileOutputStream fos = new FileOutputStream(file);
BufferedOutputStream bos = new BufferedOutputStream(fos);
DataOutputStream dos = new DataOutputStream(bos)) {
dos.write(text.getBytes(StandardCharsets.UTF_8));
dos.writeInt(50);
} catch (IOException e) {
e.printStackTrace();
}
}
}
zero() method writes data into file: the string is written in UTF-8, while the number is written in binary. zeroRead() read the data from file.
The file looks like this after zero() is executed:
This is what zeroRead() returns:
How do I read the real data König\t50 from the file?
DataInputStream's readLine method has javadoc that is almost yelling that it doesn't want to be used. You should heed this javadoc: That method is bad and you should not use it. It doesn't do charset encoding.
Your file format is impossible as stated: You have no idea when to stop reading the string and start reading the binary numbers. However, the way you've described things, it sounds like the string is terminated by a newline, so, the \n character.
There is no easy 'just make this filter-reader and call .nextLine on it available, as they tend to buffer. You can try this:
InputStreamReader isr = new InputStreamReader(bos, StandardCharsets.UTF_8);
However, basic readers do not have a readLine method, and if you wrap this in a BufferedReader, it may read past the end (the 'buffer' in that name is not just there for kicks). You'd have to handroll a method that fetches one character at a time, appending them to a stringbuilder, ending on a newline:
StringBuilder out = new StringBuilder();
for (int c = isr.read(); c != -1 && c != '\n'; c = isr.read())
out.append((char) c);
String line = out.toString();
will get the job done and won't read 'past' the newline and gobble up your binary number.

(Java) Print lines from .txt that match keyboard input [duplicate]

It seems there are different ways to read and write data of files in Java.
I want to read ASCII data from a file. What are the possible ways and their differences?
My favorite way to read a small file is to use a BufferedReader and a StringBuilder. It is very simple and to the point (though not particularly effective, but good enough for most cases):
BufferedReader br = new BufferedReader(new FileReader("file.txt"));
try {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
} finally {
br.close();
}
Some has pointed out that after Java 7 you should use try-with-resources (i.e. auto close) features:
try(BufferedReader br = new BufferedReader(new FileReader("file.txt"))) {
StringBuilder sb = new StringBuilder();
String line = br.readLine();
while (line != null) {
sb.append(line);
sb.append(System.lineSeparator());
line = br.readLine();
}
String everything = sb.toString();
}
When I read strings like this, I usually want to do some string handling per line anyways, so then I go for this implementation.
Though if I want to actually just read a file into a String, I always use Apache Commons IO with the class IOUtils.toString() method. You can have a look at the source here:
http://www.docjar.com/html/api/org/apache/commons/io/IOUtils.java.html
FileInputStream inputStream = new FileInputStream("foo.txt");
try {
String everything = IOUtils.toString(inputStream);
} finally {
inputStream.close();
}
And even simpler with Java 7:
try(FileInputStream inputStream = new FileInputStream("foo.txt")) {
String everything = IOUtils.toString(inputStream);
// do something with everything string
}
ASCII is a TEXT file so you would use Readers for reading. Java also supports reading from a binary file using InputStreams. If the files being read are huge then you would want to use a BufferedReader on top of a FileReader to improve read performance.
Go through this article on how to use a Reader
I'd also recommend you download and read this wonderful (yet free) book called Thinking In Java
In Java 7:
new String(Files.readAllBytes(...))
(docs)
or
Files.readAllLines(...)
(docs)
In Java 8:
Files.lines(..).forEach(...)
(docs)
The easiest way is to use the Scanner class in Java and the FileReader object. Simple example:
Scanner in = new Scanner(new FileReader("filename.txt"));
Scanner has several methods for reading in strings, numbers, etc... You can look for more information on this on the Java documentation page.
For example reading the whole content into a String:
StringBuilder sb = new StringBuilder();
while(in.hasNext()) {
sb.append(in.next());
}
in.close();
outString = sb.toString();
Also if you need a specific encoding you can use this instead of FileReader:
new InputStreamReader(new FileInputStream(fileUtf8), StandardCharsets.UTF_8)
Here is a simple solution:
String content = new String(Files.readAllBytes(Paths.get("sample.txt")));
Or to read as list:
List<String> content = Files.readAllLines(Paths.get("sample.txt"))
Here's another way to do it without using external libraries:
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
public String readFile(String filename)
{
String content = null;
File file = new File(filename); // For example, foo.txt
FileReader reader = null;
try {
reader = new FileReader(file);
char[] chars = new char[(int) file.length()];
reader.read(chars);
content = new String(chars);
reader.close();
} catch (IOException e) {
e.printStackTrace();
} finally {
if(reader != null){
reader.close();
}
}
return content;
}
I had to benchmark the different ways. I shall comment on my findings but, in short, the fastest way is to use a plain old BufferedInputStream over a FileInputStream. If many files must be read then three threads will reduce the total execution time to roughly half, but adding more threads will progressively degrade performance until making it take three times longer to complete with twenty threads than with just one thread.
The assumption is that you must read a file and do something meaningful with its contents. In the examples here is reading lines from a log and count the ones which contain values that exceed a certain threshold. So I am assuming that the one-liner Java 8 Files.lines(Paths.get("/path/to/file.txt")).map(line -> line.split(";")) is not an option.
I tested on Java 1.8, Windows 7 and both SSD and HDD drives.
I wrote six different implementations:
rawParse: Use BufferedInputStream over a FileInputStream and then cut lines reading byte by byte. This outperformed any other single-thread approach, but it may be very inconvenient for non-ASCII files.
lineReaderParse: Use a BufferedReader over a FileReader, read line by line, split lines by calling String.split(). This is approximatedly 20% slower that rawParse.
lineReaderParseParallel: This is the same as lineReaderParse, but it uses several threads. This is the fastest option overall in all cases.
nioFilesParse: Use java.nio.files.Files.lines()
nioAsyncParse: Use an AsynchronousFileChannel with a completion handler and a thread pool.
nioMemoryMappedParse: Use a memory-mapped file. This is really a bad idea yielding execution times at least three times longer than any other implementation.
These are the average times for reading 204 files of 4 MB each on an quad-core i7 and SSD drive. The files are generated on the fly to avoid disk caching.
rawParse 11.10 sec
lineReaderParse 13.86 sec
lineReaderParseParallel 6.00 sec
nioFilesParse 13.52 sec
nioAsyncParse 16.06 sec
nioMemoryMappedParse 37.68 sec
I found a difference smaller than I expected between running on an SSD or an HDD drive being the SSD approximately 15% faster. This may be because the files are generated on an unfragmented HDD and they are read sequentially, therefore the spinning drive can perform nearly as an SSD.
I was surprised by the low performance of the nioAsyncParse implementation. Either I have implemented something in the wrong way or the multi-thread implementation using NIO and a completion handler performs the same (or even worse) than a single-thread implementation with the java.io API. Moreover the asynchronous parse with a CompletionHandler is much longer in lines of code and tricky to implement correctly than a straight implementation on old streams.
Now the six implementations followed by a class containing them all plus a parametrizable main() method that allows to play with the number of files, file size and concurrency degree. Note that the size of the files varies plus minus 20%. This is to avoid any effect due to all the files being of exactly the same size.
rawParse
public void rawParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
overrunCount = 0;
final int dl = (int) ';';
StringBuffer lineBuffer = new StringBuffer(1024);
for (int f=0; f<numberOfFiles; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
FileInputStream fin = new FileInputStream(fl);
BufferedInputStream bin = new BufferedInputStream(fin);
int character;
while((character=bin.read())!=-1) {
if (character==dl) {
// Here is where something is done with each line
doSomethingWithRawLine(lineBuffer.toString());
lineBuffer.setLength(0);
}
else {
lineBuffer.append((char) character);
}
}
bin.close();
fin.close();
}
}
public final void doSomethingWithRawLine(String line) throws ParseException {
// What to do for each line
int fieldNumber = 0;
final int len = line.length();
StringBuffer fieldBuffer = new StringBuffer(256);
for (int charPos=0; charPos<len; charPos++) {
char c = line.charAt(charPos);
if (c==DL0) {
String fieldValue = fieldBuffer.toString();
if (fieldValue.length()>0) {
switch (fieldNumber) {
case 0:
Date dt = fmt.parse(fieldValue);
fieldNumber++;
break;
case 1:
double d = Double.parseDouble(fieldValue);
fieldNumber++;
break;
case 2:
int t = Integer.parseInt(fieldValue);
fieldNumber++;
break;
case 3:
if (fieldValue.equals("overrun"))
overrunCount++;
break;
}
}
fieldBuffer.setLength(0);
}
else {
fieldBuffer.append(c);
}
}
}
lineReaderParse
public void lineReaderParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
String line;
for (int f=0; f<numberOfFiles; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
FileReader frd = new FileReader(fl);
BufferedReader brd = new BufferedReader(frd);
while ((line=brd.readLine())!=null)
doSomethingWithLine(line);
brd.close();
frd.close();
}
}
public final void doSomethingWithLine(String line) throws ParseException {
// Example of what to do for each line
String[] fields = line.split(";");
Date dt = fmt.parse(fields[0]);
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCount++;
}
lineReaderParseParallel
public void lineReaderParseParallel(final String targetDir, final int numberOfFiles, final int degreeOfParalelism) throws IOException, ParseException, InterruptedException {
Thread[] pool = new Thread[degreeOfParalelism];
int batchSize = numberOfFiles / degreeOfParalelism;
for (int b=0; b<degreeOfParalelism; b++) {
pool[b] = new LineReaderParseThread(targetDir, b*batchSize, b*batchSize+b*batchSize);
pool[b].start();
}
for (int b=0; b<degreeOfParalelism; b++)
pool[b].join();
}
class LineReaderParseThread extends Thread {
private String targetDir;
private int fileFrom;
private int fileTo;
private DateFormat fmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
private int overrunCounter = 0;
public LineReaderParseThread(String targetDir, int fileFrom, int fileTo) {
this.targetDir = targetDir;
this.fileFrom = fileFrom;
this.fileTo = fileTo;
}
private void doSomethingWithTheLine(String line) throws ParseException {
String[] fields = line.split(DL);
Date dt = fmt.parse(fields[0]);
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCounter++;
}
#Override
public void run() {
String line;
for (int f=fileFrom; f<fileTo; f++) {
File fl = new File(targetDir+filenamePreffix+String.valueOf(f)+".txt");
try {
FileReader frd = new FileReader(fl);
BufferedReader brd = new BufferedReader(frd);
while ((line=brd.readLine())!=null) {
doSomethingWithTheLine(line);
}
brd.close();
frd.close();
} catch (IOException | ParseException ioe) { }
}
}
}
nioFilesParse
public void nioFilesParse(final String targetDir, final int numberOfFiles) throws IOException, ParseException {
for (int f=0; f<numberOfFiles; f++) {
Path ph = Paths.get(targetDir+filenamePreffix+String.valueOf(f)+".txt");
Consumer<String> action = new LineConsumer();
Stream<String> lines = Files.lines(ph);
lines.forEach(action);
lines.close();
}
}
class LineConsumer implements Consumer<String> {
#Override
public void accept(String line) {
// What to do for each line
String[] fields = line.split(DL);
if (fields.length>1) {
try {
Date dt = fmt.parse(fields[0]);
}
catch (ParseException e) {
}
double d = Double.parseDouble(fields[1]);
int t = Integer.parseInt(fields[2]);
if (fields[3].equals("overrun"))
overrunCount++;
}
}
}
nioAsyncParse
public void nioAsyncParse(final String targetDir, final int numberOfFiles, final int numberOfThreads, final int bufferSize) throws IOException, ParseException, InterruptedException {
ScheduledThreadPoolExecutor pool = new ScheduledThreadPoolExecutor(numberOfThreads);
ConcurrentLinkedQueue<ByteBuffer> byteBuffers = new ConcurrentLinkedQueue<ByteBuffer>();
for (int b=0; b<numberOfThreads; b++)
byteBuffers.add(ByteBuffer.allocate(bufferSize));
for (int f=0; f<numberOfFiles; f++) {
consumerThreads.acquire();
String fileName = targetDir+filenamePreffix+String.valueOf(f)+".txt";
AsynchronousFileChannel channel = AsynchronousFileChannel.open(Paths.get(fileName), EnumSet.of(StandardOpenOption.READ), pool);
BufferConsumer consumer = new BufferConsumer(byteBuffers, fileName, bufferSize);
channel.read(consumer.buffer(), 0l, channel, consumer);
}
consumerThreads.acquire(numberOfThreads);
}
class BufferConsumer implements CompletionHandler<Integer, AsynchronousFileChannel> {
private ConcurrentLinkedQueue<ByteBuffer> buffers;
private ByteBuffer bytes;
private String file;
private StringBuffer chars;
private int limit;
private long position;
private DateFormat frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
public BufferConsumer(ConcurrentLinkedQueue<ByteBuffer> byteBuffers, String fileName, int bufferSize) {
buffers = byteBuffers;
bytes = buffers.poll();
if (bytes==null)
bytes = ByteBuffer.allocate(bufferSize);
file = fileName;
chars = new StringBuffer(bufferSize);
frmt = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
limit = bufferSize;
position = 0l;
}
public ByteBuffer buffer() {
return bytes;
}
#Override
public synchronized void completed(Integer result, AsynchronousFileChannel channel) {
if (result!=-1) {
bytes.flip();
final int len = bytes.limit();
int i = 0;
try {
for (i = 0; i < len; i++) {
byte by = bytes.get();
if (by=='\n') {
// ***
// The code used to process the line goes here
chars.setLength(0);
}
else {
chars.append((char) by);
}
}
}
catch (Exception x) {
System.out.println(
"Caught exception " + x.getClass().getName() + " " + x.getMessage() +
" i=" + String.valueOf(i) + ", limit=" + String.valueOf(len) +
", position="+String.valueOf(position));
}
if (len==limit) {
bytes.clear();
position += len;
channel.read(bytes, position, channel, this);
}
else {
try {
channel.close();
}
catch (IOException e) {
}
consumerThreads.release();
bytes.clear();
buffers.add(bytes);
}
}
else {
try {
channel.close();
}
catch (IOException e) {
}
consumerThreads.release();
bytes.clear();
buffers.add(bytes);
}
}
#Override
public void failed(Throwable e, AsynchronousFileChannel channel) {
}
};
FULL RUNNABLE IMPLEMENTATION OF ALL CASES
https://github.com/sergiomt/javaiobenchmark/blob/master/FileReadBenchmark.java
Here are the three working and tested methods:
Using BufferedReader
package io;
import java.io.*;
public class ReadFromFile2 {
public static void main(String[] args)throws Exception {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
BufferedReader br = new BufferedReader(new FileReader(file));
String st;
while((st=br.readLine()) != null){
System.out.println(st);
}
}
}
Using Scanner
package io;
import java.io.File;
import java.util.Scanner;
public class ReadFromFileUsingScanner {
public static void main(String[] args) throws Exception {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
Scanner sc = new Scanner(file);
while(sc.hasNextLine()){
System.out.println(sc.nextLine());
}
}
}
Using FileReader
package io;
import java.io.*;
public class ReadingFromFile {
public static void main(String[] args) throws Exception {
FileReader fr = new FileReader("C:\\Users\\pankaj\\Desktop\\test.java");
int i;
while ((i=fr.read()) != -1){
System.out.print((char) i);
}
}
}
Read the entire file without a loop using the Scanner class
package io;
import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;
public class ReadingEntireFileWithoutLoop {
public static void main(String[] args) throws FileNotFoundException {
File file = new File("C:\\Users\\pankaj\\Desktop\\test.java");
Scanner sc = new Scanner(file);
sc.useDelimiter("\\Z");
System.out.println(sc.next());
}
}
The methods within org.apache.commons.io.FileUtils may also be very handy, e.g.:
/**
* Reads the contents of a file line by line to a List
* of Strings using the default encoding for the VM.
*/
static List readLines(File file)
I documented 15 ways to read a file in Java and then tested them for speed with various file sizes - from 1 KB to 1 GB and here are the top three ways to do this:
java.nio.file.Files.readAllBytes()
Tested to work in Java 7, 8, and 9.
import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
public class ReadFile_Files_ReadAllBytes {
public static void main(String [] pArgs) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
File file = new File(fileName);
byte [] fileBytes = Files.readAllBytes(file.toPath());
char singleChar;
for(byte b : fileBytes) {
singleChar = (char) b;
System.out.print(singleChar);
}
}
}
java.io.BufferedReader.readLine()
Tested to work in Java 7, 8, 9.
import java.io.BufferedReader;
import java.io.FileReader;
import java.io.IOException;
public class ReadFile_BufferedReader_ReadLine {
public static void main(String [] args) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
FileReader fileReader = new FileReader(fileName);
try (BufferedReader bufferedReader = new BufferedReader(fileReader)) {
String line;
while((line = bufferedReader.readLine()) != null) {
System.out.println(line);
}
}
}
}
java.nio.file.Files.lines()
This was tested to work in Java 8 and 9 but won't work in Java 7 because of the lambda expression requirement.
import java.io.File;
import java.io.IOException;
import java.nio.file.Files;
import java.util.stream.Stream;
public class ReadFile_Files_Lines {
public static void main(String[] pArgs) throws IOException {
String fileName = "c:\\temp\\sample-10KB.txt";
File file = new File(fileName);
try (Stream linesStream = Files.lines(file.toPath())) {
linesStream.forEach(line -> {
System.out.println(line);
});
}
}
}
What do you want to do with the text? Is the file small enough to fit into memory? I would try to find the simplest way to handle the file for your needs. The FileUtils library is very handle for this.
for(String line: FileUtils.readLines("my-text-file"))
System.out.println(line);
Below is a one-liner of doing it in the Java 8 way. Assuming text.txt file is in the root of the project directory of the Eclipse.
Files.lines(Paths.get("text.txt")).collect(Collectors.toList());
The most intuitive method is introduced in Java 11 Files.readString
import java.io.*;
import java.nio.file.Files;
import java.nio.file.Paths;
public class App {
public static void main(String args[]) throws IOException {
String content = Files.readString(Paths.get("D:\\sandbox\\mvn\\my-app\\my-app.iml"));
System.out.print(content);
}
}
PHP has this luxury for decades! ☺
The buffered stream classes are much more performant in practice, so much so that the NIO.2 API includes methods that specifically return these stream classes, in part to encourage you always to use buffered streams in your application.
Here is an example:
Path path = Paths.get("/myfolder/myfile.ext");
try (BufferedReader reader = Files.newBufferedReader(path)) {
// Read from the stream
String currentLine = null;
while ((currentLine = reader.readLine()) != null)
//do your code here
} catch (IOException e) {
// Handle file I/O exception...
}
You can replace this code
BufferedReader reader = Files.newBufferedReader(path);
with
BufferedReader br = new BufferedReader(new FileReader("/myfolder/myfile.ext"));
I recommend this article to learn the main uses of Java NIO and IO.
Using BufferedReader:
import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
BufferedReader br;
try {
br = new BufferedReader(new FileReader("/fileToRead.txt"));
try {
String x;
while ( (x = br.readLine()) != null ) {
// Printing out each line in the file
System.out.println(x);
}
}
catch (IOException e) {
e.printStackTrace();
}
}
catch (FileNotFoundException e) {
System.out.println(e);
e.printStackTrace();
}
This is basically the exact same as Jesus Ramos' answer, except with File instead of FileReader plus iteration to step through the contents of the file.
Scanner in = new Scanner(new File("filename.txt"));
while (in.hasNext()) { // Iterates each line in the file
String line = in.nextLine();
// Do something with line
}
in.close(); // Don't forget to close resource leaks
... throws FileNotFoundException
Probably not as fast as with buffered I/O, but quite terse:
String content;
try (Scanner scanner = new Scanner(textFile).useDelimiter("\\Z")) {
content = scanner.next();
}
The \Z pattern tells the Scanner that the delimiter is EOF.
The most simple way to read data from a file in Java is making use of the File class to read the file and the Scanner class to read the content of the file.
public static void main(String args[])throws Exception
{
File f = new File("input.txt");
takeInputIn2DArray(f);
}
public static void takeInputIn2DArray(File f) throws Exception
{
Scanner s = new Scanner(f);
int a[][] = new int[20][20];
for(int i=0; i<20; i++)
{
for(int j=0; j<20; j++)
{
a[i][j] = s.nextInt();
}
}
}
PS: Don't forget to import java.util.*; for Scanner to work.
You can use readAllLines and the join method to get whole file content in one line:
String str = String.join("\n",Files.readAllLines(Paths.get("e:\\text.txt")));
It uses UTF-8 encoding by default, which reads ASCII data correctly.
Also you can use readAllBytes:
String str = new String(Files.readAllBytes(Paths.get("e:\\text.txt")), StandardCharsets.UTF_8);
I think readAllBytes is faster and more precise, because it does not replace new line with \n and also new line may be \r\n. It is depending on your needs which one is suitable.
I don't see it mentioned yet in the other answers so far. But if "Best" means speed, then the new Java I/O (NIO) might provide the fastest preformance, but not always the easiest to figure out for someone learning.
http://download.oracle.com/javase/tutorial/essential/io/file.html
Guava provides a one-liner for this:
import com.google.common.base.Charsets;
import com.google.common.io.Files;
String contents = Files.toString(filePath, Charsets.UTF_8);
Cactoos give you a declarative one-liner:
new TextOf(new File("a.txt")).asString();
This might not be the exact answer to the question. It's just another way of reading a file where you do not explicitly specify the path to your file in your Java code and instead, you read it as a command-line argument.
With the following code,
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.IOException;
public class InputReader{
public static void main(String[] args)throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String s="";
while((s=br.readLine())!=null){
System.out.println(s);
}
}
}
just go ahead and run it with:
java InputReader < input.txt
This would read the contents of the input.txt and print it to the your console.
You can also make your System.out.println() to write to a specific file through the command line as follows:
java InputReader < input.txt > output.txt
This would read from input.txt and write to output.txt.
For JSF-based Maven web applications, just use ClassLoader and the Resources folder to read in any file you want:
Put any file you want to read in the Resources folder.
Put the Apache Commons IO dependency into your POM:
<dependency>
<groupId>org.apache.commons</groupId>
<artifactId>commons-io</artifactId>
<version>1.3.2</version>
</dependency>
Use the code below to read it (e.g. below is reading in a .json file):
String metadata = null;
FileInputStream inputStream;
try {
ClassLoader loader = Thread.currentThread().getContextClassLoader();
inputStream = (FileInputStream) loader
.getResourceAsStream("/metadata.json");
metadata = IOUtils.toString(inputStream);
inputStream.close();
}
catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
return metadata;
You can do the same for text files, .properties files, XSD schemas, etc.
try {
File f = new File("filename.txt");
Scanner r = new Scanner(f);
while (r.hasNextLine()) {
String data = r.nextLine();
JOptionPane.showMessageDialog(data);
}
r.close();
} catch (FileNotFoundException ex) {
JOptionPane.showMessageDialog("Error occurred");
ex.printStackTrace();
}
Use Java kiss if this is about simplicity of structure:
import static kiss.API.*;
class App {
void run() {
String line;
try (Close in = inOpen("file.dat")) {
while ((line = readLine()) != null) {
println(line);
}
}
}
}
import java.util.stream.Stream;
import java.nio.file.*;
import java.io.*;
class ReadFile {
public static void main(String[] args) {
String filename = "Test.txt";
try(Stream<String> stream = Files.lines(Paths.get(filename))) {
stream.forEach(System.out:: println);
} catch (IOException e) {
e.printStackTrace();
}
}
}
Just use java 8 Stream.
In case you have a large file you can use Apache Commons IO to process the file iteratively without exhausting the available memory.
try (LineIterator it = FileUtils.lineIterator(theFile, "UTF-8")) {
while (it.hasNext()) {
String line = it.nextLine();
// do something with line
}
}
try (Stream<String> stream = Files.lines(Paths.get(String.valueOf(new File("yourFile.txt"))))) {
stream.forEach(System.out::println);
} catch (IOException e) {
e.printStackTrace();
}
new File(<path_name>)
Creates a new File instance by converting the given pathname string into an abstract pathname. If the given string is the empty string, then the result is the empty abstract pathname.
Params:
pathname – A pathname string
Throws:
NullPointerException – If the pathname argument is null
Files.lines returns a stream of String
Stream<String> stream = Files.lines(Paths.get(String.valueOf(new File("yourFile.txt"))))
can throw nullPointerExcetion , FileNotFoundException so, keepint it inside try will take care of Exception in runtime
stream.forEach(System.out::println);
This is used to iterate over the stream and print in console
If you have different use case you can provide your custome function to manipulate the stream of lines
My new favorite approach to simply read a whole text file from a BufferedReader input goes:
String text = input.lines().collect(Collectors.joining(System.lineSeparator())));
This will read the whole file by adding new line (lineSeparator) behind each line. Without the separator it would join all lines together as one.
This appears to have existed since Java 8.
For Android developers ending up here (who use Kotlin):
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val text = myFileUrl.readText() // Not recommended for huge files
println(text)
Other solution:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
val lines = file.readLines() // Not recommended for huge files
lines.forEach(::println)
Another good solution which can be used for huge files as well:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
file
.bufferedReader()
.lineSequence()
.forEach(::println)
Or:
val myFileUrl = object{}.javaClass.getResource("/vegetables.txt")
val file = File(myFileUrl.toURI())
file.useLines { lines ->
lines.forEach(::println)
}
Notes:
The vegetables.txt file should be in your classpath (for example, in src/main/resources directory)
The above solutions all treat the file encodings as UTF-8 by default. You can specify your desired encoding as the argument for the functions.
The above solutions do not need any further action like closing the files or readers. They are automatically taken care of by the Kotlin standard library.

How to use DataInputStream to read binary data from a file and print to the console?

This was the question asked: Write a program to read planet details from binary.txt using DataInputStream and print planet details on the standard output.
However, the program below throws an IOException. I can't figure out the problem. Any help would be appreciated.
import java.io.*;
public class LA4ex2b {
public static void main(String[] args) throws IOException {
DataInputStream input=null;
try
{
input= new DataInputStream(new FileInputStream("C:/Users/user/workspace/LA4ex2a/binary.txt"));
String str;
// read until the string read is null i.e. read till end of file
while ((str = input.readUTF()) != null) {
String token[] = str.split(" "); // tokenizes the string with
// space as a delimeter
for (int i = 0; i <token.length; i++)
{
if (IsDouble.IsaDouble(token[i]))
System.out.print(Double.parseDouble(token[i]));
else
System.out.print(token[i]);
}
}
}
catch (IOException e) {
e.printStackTrace();
}
finally
{
if (input!= null)
input.close();
}
}
}
if you're reading a binary file, you cannot assume it´s stored as text.
instead, you must know beforehand what are each field data type and read them like
DataInputStream input= new DataInputStream(new FileInputStream(new File("xyz")));
double d = input.readDouble();
int i = input.readInt();
char c = input.readChar();
As you can see there is "Mercury" - planet name - but no text representation of a double "1.23", so it is really binary data. Maybe input.readDouble? Always do an internet search for the javadoc.

How do i put these letter grades into a new file instead of putting it on the console?

This code creates a file with students and their scores. I have calculated their letter grade but it goes on the console. How can i get their letter grades into a new file? Also how can i print on the console the averages for each test/quiz because right now I have them all in a for loop.
import java.io.*;
import java.util.InputMismatchException;
import java.lang.*;
import java.util.*;
public class ReadFile {
private Scanner x;
public void openFile(){
try{
x = new Scanner (new File ("grades.txt"));
}
catch(Exception e){
System.out.println("could not find file");
}}
public void createFile()throws IOException {
try{
File file = new File("grades.txt");
Scanner s = new Scanner(file);
while(s.hasNext()){
{
String [] split = s.nextLine().split(", ");
String fname = split[0];
Double q1 = Double.parseDouble (split[1]);
Double q2 = Double.parseDouble (split[2]);
Double q3 = Double.parseDouble (split[3]);
Double q4 = Double.parseDouble (split[4]);
Double proji = Double.parseDouble (split[5]);
Double projii = Double.parseDouble (split[6]);
Double projiii = Double.parseDouble (split[7]);
double studentgrade = (q1 *0.1) + (q2 *0.1) +(q3 *0.1) + (q4 *0.1) +(proji*0.15) + (projii * 0.2) + (projiii *0.25);
if(studentgrade>90)
System.out.printf("%s got an A\n", fname);
else if(studentgrade>80)
System.out.printf("%s got a B\n", fname);
else if(studentgrade>70)
System.out.printf("%s got a C\n", fname);
else if(studentgrade>60)
System.out.printf("%s got a D\n", fname);
else if(studentgrade>50)
System.out.printf("%s got a F\n", fname);
}}}catch(Exception e){
e.printStackTrace();
}
}
public void closeFile(){
x.close();
}
}
Create a Buffered Writer. Something like this,
String fileName = outputName;
BufferedWriter writer = null;
try {
// create a temporary file
File outFile = new File(fileName);
// This will output the full path where the file will be written
// to...
String inFile = new File(inFileName).getAbsolutePath();
File in = new File(inFile);
writer = new BufferedWriter(new FileWriter(outputName, true));
writer.write(DATA THAT YOU WANT TO WRITE(Possibly an Method Argument Value));
} catch (Exception e) {
e.printStackTrace();
} finally {
try {
// Close the writer regardless of what happens...
writer.close();
} catch (Exception e) {
}
}
Your outputName is an argument taken by the method (from the code I wrote in one of my programs) that is the name of the file you want to write.
inFileName is the other argument taken and it is the name of the original file you wrote. It will require more work to use this exact code, otherwise,
*The Main Answer: *
Use a BufferedWriter!
*EDIT: *
Just as a side note, when you are initiating the BufferedWriter, you are giving it two arguments, outputName and true. The output name is obviously the name that you want to output the file as, and the true means that you want to append to the text file (can add to existing data without overwriting the current text file)
If you have this:
PrintWriter writer = new PrintWriter("output.txt", "UTF-8");
before your loop and then replace all your System.out.println(...) statements inside the loop with writer.println(...), closing the PrintWriter after the loop (with writer.close()), you will get the output file with the desired text. But do read up properly on Java IO.

Write problem - lossing the original data

Every time I write to the text file I will lose the original data, how can I read the file and enter the data in the empty line or the next line which is empty?
public void writeToFile()
{
try
{
output = new Formatter(myFile);
}
catch(SecurityException securityException)
{
System.err.println("Error creating file");
System.exit(1);
}
catch(FileNotFoundException fileNotFoundException)
{
System.err.println("Error creating file");
System.exit(1);
}
Scanner scanner = new Scanner (System.in);
String number = "";
String name = "";
System.out.println("Please enter number:");
number = scanner.next();
System.out.println("Please enter name:");
name = scanner.next();
output.format("%s,%s \r\n", number, name);
output.close();
}
You must open the file for append.
You need to open myFile in append mode. See this link for an example.
As others have said, use the append option.
This code can write data in the default platform encoding:
private static void appendToFile() throws IOException {
boolean append = true;
OutputStream out = new FileOutputStream("TextAppend.txt", append);
Closeable resource = out;
try {
PrintWriter pw = new PrintWriter(out);
resource = pw;
pw.format("%s,%s %n", "foo", "bar");
} finally {
resource.close();
}
}
There are a number of classes you can wrap around an OutputStream to achieve the same effect. Be aware that the above approach can lose data when the code is run on a platform that doesn't use a Unicode default encoding (like Windows) and may produce different output on different PCs.
One case in which care is need is if the encoding inserts a byte order mark. If you wanted to write lossless Unicode text in UTF-16 marked with a little-endian BOM, you would need to check the file for existing data.
private static void appendUtf16ToFile() throws IOException {
File file = new File("TextAppend_utf16le.txt");
String encoding = (file.isFile() && file.length() > 0) ?
"UnicodeLittleUnmarked" : "UnicodeLittle";
boolean append = true;
OutputStream out = new FileOutputStream(file, append);
Closeable resource = out;
try {
Writer writer = new OutputStreamWriter(out, encoding);
resource = writer;
PrintWriter pw = new PrintWriter(writer);
resource = pw;
pw.format("%s,%s %n", "foo", "bar");
} finally {
resource.close();
}
}
Supported encodings:
Java 6
Java 5
We're you've got: new Formatter(myFile); you'll want to use new Formatter(new FileWriter(myfile, true). The true indicates you want to append to that file.

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