I have a class with some fields and extra data of type string that will store a json object. I want it to not be deserialized, but after looking for more than an hour, the only thing I found was:
#Expose(deserialize=false)
But It doesn't work.
The following is an example:
public class Employee implements Serializable
{
private static final long serialVersionUID = 1L;
#Expose
public Long id;
#Expose
public String name;
... some more fields
#SerializedName("extraData")
#Expose(deserialize = false)
public String extraData;
}
Then on my service I do the following:
final GsonBuilder builder = new GsonBuilder();
final Gson gson = builder.create();
Employee emp = gson.fromJson(json, Employee.class);
The object I am receiving from the frontend is:
{
"id":1,
"name": "John Doe",
"extraData": {"someField1":"someValue1","someField2":"someValue2"}
}
And I get this error:
java.lang.IllegalStateException: Expected a string but was BEGIN_OBJECT at line 1 column 48 path $.extraData
When I just want to get "extraData" as an string with the value
{"someField1":"someValue1","someField2":"someValue2"}
Other solutions are not accepted because it is the spec i was given.
It does not harm if you change the type of extraData like (assuming it is possible and the extra data follows the pattern you described)
public Map<String, String> extraData;
and compose a String of it.
Still what Jaron F suggested might be better in whole. For using type adapter see this answer
You should use TypeAdapters for this and then add the TypeAdapter into your gson builder during the object creation.
https://google.github.io/gson/apidocs/com/google/gson/TypeAdapter.html
Related
I am trying to make a java program that will need to work with json, I have choose gson as my library to handle managing JSON
But when I try to deserialize my json the messagereturn.text value and the messagereturn.extra.text value both get set as null, I have tried to fix this but I am unable to.
An example of the json that i am trying to deserialize is
{
"text":"",
"extra":[{
"text":"eee joined the game",
"color":"yellow"
}]
}
And this is how I am calling gson
Message messagepacket = event.<ServerChatPacket>getPacket().getMessage();
//this gets the json data
messagereturn messagereturn = gson.fromJson(String.valueOf(messagepacket), messagereturn.class);
System.out.println(messagereturn.returnmethod());
Here is the class I am trying to deserialize too
public class messagereturn {
String text;
public class extra{
String text;
}
public String returnmethod() {
extra extra = new extra();
return text + extra.text;
}
}
Thank you, if there is any more informaton needed let me know, thanks
There is a problem understanding your JSON (and creating the Java classes by the way). These marks [] means that is a list.
So you have an object with atributes text, type String and extra, type List<Object>.
This list contains another object (note that the object is defined by {} and list by []).
The object into the list has another two attributes: text and color both with primitive types; String.
So your java class should be like this:
public class Messagereturn {
private String text;
private List<Extra> extra;
//getters and setters and other methods
}
And the class Extra:
public class Extra {
private String text;
private String color;
//getters and setters
}
With this data model you can call your Gson with these structure.
Also, you don't need to call returnMethod to create Extra object, it is created by Gson.
Using this line of code:
Messagereturn mr = new Gson().fromJson(txt, Messagereturn.class);
And your JSON example, this is the value stored when run in debug mode:
As you can see, tha values from JSON has been created and loaded into memory.
After multiple researches on Google and Stack Overflow, i haven't found a similar case to mine.
I need to use Gson library to convert a Java object to Json. The fact is that this object contains a field with a custom generic type, as follow :
SendData.java :
public class SendData {
private SendDataRequestObject<?> sendData;
// Constructor + Getters and Setters
}
Here is the class definition of SendDataRequestObject :
public class SendDataRequestObject<T> {
private String actionType;
private T parameters;
private CustomClass customClass;
//Constructor + Getters and Setters
}
And finally, the class definition of MyRequest which may be injected in SendDataRequestObject as the T parameter
public class MyRequest {
private Map<Integer, String> myMap;
private String myString1;
private String myString2;
//Constructor + Getters and Setters
}
Actually, I'm able to parse SendDataRequestObject with Gson library as follow :
SendDataRequestObject<MyRequest> requestObject = new SendDataRequestObject<MyRequest>();
//...
//Initializing and adding fields to requestObject
//...
Type token = new TypeToken<SendDataRequestObject<MyRequest>>(){}.getType();
System.out.println(new GsonBuilder().create().toJson(requestObject, token));
The output is properly set and every fields, even the generic one, are included into the final json string :
{"actionType":"verify","parameters":{"myMap":{"15789":"hreher-489hre-gdsf","13057":"rtyuiop-4g8ezg","16741":"gfd456-uiop789"},"myString1":"myStringValue1","myString2":"myStringValue2"},"customClas":{"attr1":"value1","attr2":"value2"}}
But what I need is to parse SendData class, not SendDataRequestObject class. When I try to convert this class into json string, I obtain this output :
{"sendData":{"actionType":"verify","parameters":{},"customClass":{"attr1":"value1","attr2":"value2"}}}
So, we can see that parameters field of SendDataRequestObject is not converted to Json, probably because this is a generic class.
If anybody has an idea of how to do it, I would be very grateful !
You can't do this without somehow knowing the type T at compile time in some manner due to Java's type erasure.
One option for this is the JSON can contain some information specifying the type, e.g.
{
"sendDataType": "MyRequest",
"sendData": {
...
}
}
If you then make SendData generic e.g.
SendData<T> {
private SendDataRequestObject<T> sendData;
}
you can then parse the JSON once to find out the sendDataType:
SendData<?> genericSendData = new GsonBuilder().create().toJson(requestObject, new TypeToken<SendData<?>>(){});
String sendDataType = genericSendData.sendDataType;
and use that to create a TypeToken of the right type:
switch(sendDataType) {
case "MyRequest":
return new TypeToken<MyRequest>(){};
}
And then parse the JSON again specifying the generic type now that you know it:
SendData<?> myRequestSendData = new GsonBuilder().create().toJson(requestObject, typeToken);
This works because our switch statement knows the possible types at compile time and can create TypeTokens for them.
This is an example of the kind JSON I'm trying to consume using GSON:
{
"person": {
"name": "Philip"
"father.name": "Yancy"
}
}
I was wondering if it were possible to deserialize this JSON into the following structure:
public class Person
{
private String name;
private Father father;
}
public class Father
{
private String name;
}
So that:
p.name == "Philip"
p.father.name == "Yancy"
Currently I am using #SerializedName to obtain property names containing a period, e.g.:
public class Person
{
private String name;
#SerializedName("father.name")
private String fathersName;
}
However, that's not ideal.
From looking at the documentation it doesn't appear to be immediately possible but there may be something I have missed - I'm new to using GSON.
Unfortunately I cannot change the JSON I'm consuming and I'm reluctant to switch to another JSON parsing library.
As far as I understand you can't do it in a direct way, because Gson will understand father.name as a single field.
You need to write your own Custom Deserializer. See Gson user's guide instructions here.
I've never tried it, but it doesn't seem to be too difficult. This post could be also helpful.
Taking a look at Gson's user guide and the code in that post, you'll need something like this:
private class PersonDeserializer implements JsonDeserializer<Person> {
#Override
public Person deserialize(JsonElement json, Type type,
JsonDeserializationContext context) throws JsonParseException {
JsonObject jobject = (JsonObject) json;
Father father = new Father(jobject.get("father.name").getAsString());
return new Person(jobject.get("name").getAsString(), father);
}
}
Assuming that you have suitable constructors...
And then:
GsonBuilder gsonBuilder = new GsonBuilder();
gsonBuilder.registerTypeAdapter(Person.class, new PersonDeserializer());
Gson gson = gsonBuilder.create();
Person person = gson.fromJson(jsonString, Person.class);
And Gson will call your deserializer in order to deserialize the JSON into a Person object.
Note: I didn't try this code, but it should be like this or something very similar.
I couldn't do this with just Gson. I need a new library 'JsonPath'. I used Jackson's ObjectMapper to convert the object to string but you can easily use Gson for this.
public static String getProperty(Object obj, String prop) {
try {
return JsonPath.read(new ObjectMapper().writeValueAsString(obj), prop).toString();
} catch (JsonProcessingException|PathNotFoundException ex) {
return "";
}
}
// 2 dependencies needed:
// https://mvnrepository.com/artifact/com.fasterxml.jackson.core/jackson-core
// https://mvnrepository.com/artifact/com.jayway.jsonpath/json-path
// usage:
String motherName = getProperty(new Person(), "family.mother.name");
// The Jackson can be easily replaced with Gson:
new Gson().toJson(obj)
I'm using Gson 2.2's toJson() method to serialize a java object into a json string. The java object is of type:
public class LOB implements Serializable{
private int id;
private LOBType type;
private TypeSpecificData data;
public class TypeSpecificData {
private String a;
private int b;
}
}
All fields of the object are serialized except for data field of type TypeSpecificData.
How do I include this field as well in the json string ?
Currently I'm serializing like shown below:
String jsonString = new Gson().toJson(lob_instance);
By default Gson will not serialize null objects refereces. Please check it.
Link to GSON documentation
Let's imagine I have a Java class of the type:
public class MyClass
{
public String par1;
public Object par2;
}
Then I have this:
String json = "{"par1":"val1","par2":{"subpar1":"subval1"}}";
Gson gson = new GsonBuilder.create();
MyClass mClass = gson.fromJson(json, MyClass.class);
The par2 JSON is given to me from some other application and I don't ever know what are it's parameter names, since they are dynamic.
My question is, what Class type should par2 variable on MyClass be set to, so that the JSON String variable is correctly deserialized to my class object?
Thanks
Check out Serializing and Deserializing Generic Types from GSON User Guide:
public class MyClass<T>
{
public String par1;
public T par2;
}
To deserialize it:
Type fooType = new TypeToken<Myclass<Foo>>() {}.getType();
gson.fromJson(json, fooType);
Hope this help.
See the answer from Kevin Dolan on this SO question: How can I convert JSON to a HashMap using Gson?
Note, it isn't the accepted answer and you'll probably have to modify it a bit. But it's pretty awesome.
Alternatively, ditch the type safety of your top-level object and just use hashmaps and arrays all the way down. Less modification to Dolan's code that way.
if you object has dynamic name inside lets say this one:
{
"Includes": {
"Products": {
"blablabla": {
"CategoryId": "this is category id",
"Description": "this is description",
...
}
you can serialize it with:
MyFunnyObject data = new Gson().fromJson(jsonString, MyFunnyObject.class);
#Getter
#Setter
class MyFunnyObject {
Includes Includes;
class Includes {
Map<String, Products> Products;
class Products {
String CategoryId;
String Description;
}
}
}
later you can access it:
data.getIncludes().get("blablabla").getCategoryId()
this code:
Gson gson = new GsonBuilder.create();
should be:
Gson gson=new Gson()
i think(if you are parsing a json doc).