In my simple Java Client-Server program, when sending a message to the server and reading it there, readInt() reads indefinitely, making the program stick there.
I made sure I was only sending and receiving an int, nothing else, as you can tell by the code (I also tried with and without appending \n to the message sent to see if it would end):
Relevant Client Code
Socket server = new Socket("127.0.0.1", 2424);
DataOutputStream outputStream = new DataOutputStream(server.getOutputStream());
DataInputStream inputStream = new DataInputStream(server.getInputStream());
outputStream.writeInt(Protocol.Message.HANDSHAKE);
outputStream.write('\n'); // I tried with and without this
outputStream.flush();
Relevant Server Code
ServerSocket socket = new ServerSocket(2424);
System.out.println("Listening on port 2424");
while (connected) {
Socket client = socket.accept();
System.out.println("SERVER: Going to read a message"); // This shows
int messageType = (new DataInputStream(client.getInputStream())).readInt();
System.out.println("SERVER: Received a message (" + messageType + ")"); // This does not
commands.execute(messageType);
}
The message that should be printed after readInt() is never seen. I thought it would since I was only sending an int and receiving an int (4 bytes), it's not like I was sending more data than expected.
How should I go about making the readInt() end? Do I have to send a null byte or something else?
EDIT: Actual Server code (using Threads).
ServerSocket socket = new ServerSocket(2424);
System.out.println("Listening on port 2424");
while (connected) {
Socket client = socket.accept();
Worker worker = new Worker(client);
worker.start();
}
Worker Thread
public class Worker extends Thread {
private final Socket client;
private final Commands commands;
private final DataOutputStream outputStream;
private final DataInputStream inputStream;
public Worker(Socket client) throws IOException {
System.out.println("SERVER: Handling client message");
this.client = client;
outputStream = new DataOutputStream(client.getOutputStream());
inputStream = new DataInputStream(client.getInputStream());
commands = new Commands();
commands.addCommand(Protocol.Message.HANDSHAKE, new HandshakeCommand());
//commands.addCommand(Protocol.Message.RECEIVE_FILE, new ReceiveFileCommand());
}
#Override
public void run() {
System.out.println("SERVER: Running thread for client message");
try {
int messageType = inputStream.readInt();
System.out.println("SERVER: Received a message (ID " + messageType + ")");
commands.execute(messageType);
} catch (IOException | UnknownCommandException ex) {
System.out.println(ex);
}
}
}
The reason it was never reading is because nothing was being sent, as xander said.
And it was my fault I didn't include the actual client code, just the server code and a minimized version of the client code.
I was trying to send the message after the while() loop in the client (it also waits for messages from the server).
The solution was to delegate the the client's listening part into another thread so it didn't block the main thread that needed to send the message to the server.
Related
I am working with Java sockets. I have a server socket and two client sockets. My problem is, that the first client socket submits its message to my server socket, and the message from the second client socket is not arriving at the server socket. That means, that for the first client socket the while loop is interrupted after a succesful message, and the second client ends in an infinite while loop. If I test each client socket seperately in a test class, each client socket is submitting its message correctly to my server socket. By watching TCPView I noticed, that the client socket does not respond, as long as my port is used.
I read, that the second client socket should still respond its message, even if the port was used. In my case, the second client socket should always respond about a second after the first one. But I can't get them to work one after another.
So, here is my code for the method, which is waiting for client messages:
public void listenToSocket()
{
serverSocket = null;
thread = null;
SocketAddress adress = new InetSocketAddress(CommunicationValues.SOCKET_PORT);
try {
serverSocket = new ServerSocket();
serverSocket.setReuseAddress(true);
serverSocket.bind(adress);
} catch (IOException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
System.exit(0);
}
while(true){
try
{
Socket clientSocket = serverSocket.accept();
thread = new SocketMessageThread(clientSocket);
thread.start();
} catch (IOException e) {
System.out.println("MyServerSocket caught an error: \n" + e.getMessage());
e.printStackTrace();
}
}
}
This method is called in a thread. The structure looks like this:
SocketListenerThread calls the method listenToSocket() from class SocketListener
listenToSocket() is described above
The SocketMessageThread is handling the message output of the client socket in its run()-method.
EDIT
Here is the code of my SocketMessageThread:
public class SocketMessageThread extends Thread{
private Socket clientSocket;
private static int nameCounter = 0;
public SocketMessageThread(Socket clientSocket) {
this.clientSocket = clientSocket;
this.setDaemon(true);
this.setName("SocketMessageThread" + (nameCounter++));
}
public void run() {
try (
BufferedReader in = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));)
{
while (in.ready())
{
String inLine = in.readLine();
CommunicationValues.MESSAGE_MEMORIZER = inLine;
}
clientSocket.close();
} catch (IOException e) {
e.printStackTrace();
}
}}
EDIT 2
Both clients only communicate with one particular message. E.g. when a client is started up, it mentioned, that the startup was successful with a single message. There are no repeating messages coming from the client sockets until the server sockets catches them. So if the server socket doesn't catch that one message, it's gone, and it won't be sent again by the client socket.
while (in.ready())
{
// ...
}
Classic misuse of ready(). Exchange all this for:
String inLine;
while ((inLine = in.readLine()) != null)
{
CommunicationValues.MESSAGE_MEMORIZER = inLine;
}
Presumably there is more code that you haven't shown us: otherwise all this will do is memorize the last line sent.
I'm learning about java sockets in a class of mine. I'm having issues with the communication between the peers. My question is why am I receiving this exception:
Exception java.net.ConnectionException: Connection refused: connect
for example:
in my main thread
ServerSocket listenSock = new ServerSocket(Integer.parseInt(argv[2]),0,InetAddress,getByName(null));
//Create Server loop to process inbound connections
while(true){
//accept an incoming client by saving it to a socket to use to communicate with it
Socket clientSock = listenSock.accept();
/waa/create a thread to handle the inbound client so that we can return to accept()
InboundHandler inboundMsg = new InboundHandler(clientSock); // listens to the peers outbound socket
Thread inThread = new Thread(inboundMsg);
inThread.start();
// add the peer to the list.
}
in a seperate thread I have a
public InboundHandler(Socket socket) throws Exception{
this.socket = socket; //save the socket object to "this" instance of the class
input = new BufferedReader(new InputStreamReader(socket.getInputStream())); // listens from the clients speaking socket
}
public void run(){
while(true){
try{
String line = input.readLine();
System.out.println(line);
}catch(IOException e){
System.out.println("Could not read input. " + e);
}
}
and finally I have a thread that sends out messages
for(int i=0;i<portList.size(); i++){
if(nameList.get(i)!=Username){
Socket peerSocket= new Socket(InetAddress.getByName(null),portList.get(i));
writer = new BufferedWriter(new OutputStreamWriter(peerSocket.getOutputStream()));
writer.write(Username + " has connected");
writer.flush();
}
}
}
catch(IOException e){
System.out.println("Some IO problem. " + e);
}
My program compiles, and when I run it, I receive the Exception
java.net.ConnectionException: Connection refused: connect
From what it's sounding like, is the port that my one peer is trying to speak to, isn't being heard by the other peers. But this is more guessing
As for the while(true) I am going to change that later, with a boolean statement.
I am trying to create a multiclient chat sort of server in which we have multiple clients connecting to server and whatever message a client enters, it gets displayed to all the clients(including the client who sent the message). I am not getting this output, instead the message just echoes only on the sender client and no other client. Code is quite long, hence i am displaying snippets of whichever code i think will help you understand error. In case, it is not enough, just comment which part you require. Thanks in advance. I am stuck on this since about hour and half, so i appreciate whatever help i would get.
The Server Class
public class Multiserver {
ServerSocket serversocket;
Socket socket;
ArrayList<Socket> al = new ArrayList<Socket>();
DataInputStream dis;
DataOutputStream dos;
Multiserver() throws IOException
{
serversocket = new ServerSocket(1036);
System.out.println("Server started on port 1036");
while(true)
{
socket = serversocket.accept();
System.out.println(socket);
al.add(socket);
Mythread thread = new Mythread(socket, al);
thread.start();
}
}
Thread used in server class
public class Mythread extends Thread{
Socket socket;
ArrayList al;
DataInputStream dis;
DataOutputStream dos;
Mythread(Socket socket, ArrayList al)
{
this.socket = socket;
this.al = al;}
public void run()
{
try{
String data ="";
dis = new DataInputStream(socket.getInputStream());
data = dis.readUTF();
if(!data.equals("stop"))
{
broadcast(data);
}
else
{
dos = new DataOutputStream(socket.getOutputStream());
// data = dos.readUTF();
dos.writeUTF(data);
dos.flush();
//dos.close();
}
}
catch(Exception e){
System.out.println("Run "+e);
}
}
public void broadcast(String data)
{
try{
Iterator it = al.iterator();
while(it.hasNext())
{
Socket socket1 = (Socket)it.next();
dos = new DataOutputStream(socket1.getOutputStream());
dos.writeUTF(data);
dos.flush();
}
}
catch(Exception e){
System.out.println("Broadcast running "+ e);
}
}
}
The client class
public class Multiclient {
Socket socket;
DataInputStream dis;
DataOutputStream dos;
Multiclient() throws IOException
{
socket = new Socket("127.0.0.1", 1036);
System.out.println(socket);
Mythreadc my = new Mythreadc(socket);
my.start();
}
Thread used in client class
public class Mythreadc extends Thread{
DataInputStream dis;
DataOutputStream dos;
Socket socket;
Mythreadc(Socket socket)throws IOException
{
this.socket = socket;}
public void run()
{
BufferedReader br = null;
try{
br = new BufferedReader(new InputStreamReader (System.in));
dos = new DataOutputStream(socket.getOutputStream());
String data = "";
do{
data = br.readLine();
dos.writeUTF(data);
System.out.println(data);
dos.flush();
}
while(!data.equals("stop"));
}
catch(Exception e)
{
System.out.println("Client input "+e);
}
finally{
try{
br.close();
dis.close();
dos.close();
}
catch(Exception e)
{
System.out.println("Closing "+e);
}
}
}
}
I am sorry i have put on such a long code, almost all the program. But i feel it is necessary to understand where the problem lies.I have tried and i think it lies in the part where we display data written in the client's socket in the client thread class but i don't know what it is ???
#EDIT: Forgot to mention. The client stops when he sends the message "Stop"!
There are two problems with your code that are preventing the clients from displaying more than one message.
Problem one: Your client code never actually displays or prints out the messages it receives from the server. The line
dos = new DataOutputStream(socket.getOutputStream());
creates an OutputStream you can use to write data to the socket, i.e. send messages to the server. But you never use the socket's InputStream, which is what you need to do to read data from the socket, i.e. receive messages from the server. When you see a message printed out on the client, you're actually just seeing the result of
System.out.println(data);
which has your client print the message it just sent.
In order for the client to accept input from the user and read messages from the server at the same time, you should probably use two threads on the client. One thread can just be the client thread you already wrote, since it takes care of accepting input from the user. The other thread should look something like this:
public class ClientReaderThread extends Thread {
Socket socket;
ClientReaderThread(Socket socket) {
this.socket = socket;
}
public void run() {
try (BufferedReader serverReader = new BufferedReader(
new InputStreamReader(socket.getInputStream()))){
String fromServer = serverReader.readLine();;
while(fromServer != null) {
if (fromServer.equals("stop"))
break;
System.out.println(fromServer);
fromServer = serverReader.readLine();
}
} catch (IOException e) {
System.out.println("Client error! Got exception: " + e);
}
}
}
(Note that I use the try-with-resources statement to construct the reader, which takes care of closing it when the client stops).
Then in your main client class, start both threads with the same socket:
Multiclient() throws IOException
{
socket = new Socket("127.0.0.1", 1036);
System.out.println(socket);
Mythreadc my = new Mythreadc(socket);
ClientReaderThread reader = new ClientReaderThread(socket);
my.start();
reader.start();
}
Problem two: Your server only reads and echoes a single line from each client, because the socket thread that handles each client (Mythread) doesn't contain a loop. With your setup of creating a single thread per client, run() only gets called once per client, so that run() method needs to handle every message that client sends.
Here's how the run() method in the server's thread should look:
public void run() {
try (BufferedReader inStream = new BufferedReader(
new InputStreamReader(socket.getInputStream()))){
String data = inStream.readLine();
while(data != null) {
if(data.equals("stop"))
break;
broadcast(data);
data = inStream.readLine();
}
}
catch(Exception e){
System.out.println("Run exception "+e);
} finally {
al.remove(socket); //This is important to do
}
}
I made an additional important change here: at the end of the run() method, when either the client disconnected or an exception happened, the thread removes its socket from the ArrayList. This ensures that other server threads, which all reference the same ArrayList, don't try to broadcast to the socket of a client that has disconnected. If you neglect to do this, you'll get an exception when a client sends a message to the server after another client has disconnected.
Miscellaneous notes
As I mentioned in my comment, you should give al a type of ArrayList<Socket> inside the thread class, and use a for-each loop instead of an Iterator to iterate over it in broadcast().
I'm using BufferedReader instead of DataInputStream to read from the socket. That's because DataInputStream.readUTF() and writeUTF() are deprecated, and have been replaced with BufferedReader.readLine() and PrintWriter.println().
The streams like dis and dos don't need to be instance variables in your thread classes, since they are only ever used inside the run() method. They can be local variables inside run(), like I did with inStream in my new run() method.
I think you just missed passing the ArrayList of Sockets Users Currently Connected to The Server to the thread
and Instead of Posting your Server Class You have just posted Client Program 2 times anyway ,
Your ServerClass should be build in this way : -
As soon as ServerClass recieves the request from any client, Server Class should add the Socket into ArrayList and create New Thread and just pass both to the MyThread Class
Edit :
It seems you haven't written code for Displaying the data you will get from the server .
At Client Side for Sending the Message You can simple write that in Main Thread that is under Your Client Class's Main Mehtod
You actually needed Thread at client side not for sending the message but rather for Listening the Message from the server,
because you never known when anyone can send you the message but you will always know when you want to send message to anybody connected to this chat App
Now coming to the Coding Part :
Client Class
public class Multiclient {
Socket socket;
DataInputStream dis;
DataOutputStream dos;
Multiclient() throws IOException
{
socket = new Socket("127.0.0.1", 1036);
System.out.println(socket);
Mythreadc my = new Mythreadc(socket);
my.start();
/**
* Here write out the code for taking input from Standard Console
*/
BufferedReader br = null;
try{
br = new BufferedReader(new InputStreamReader (System.in));
dos = new DataOutputStream(socket.getOutputStream());
String data = "";
do{
data = br.readLine();
dos.writeUTF(data);
System.out.println(data);
dos.flush();
}
while(!data.equals("stop"));
}
catch(Exception e)
{
System.out.println("Client input "+e);
}
}
Client Thread
try{
String data ="";
dis = new DataInputStream(socket.getInputStream());
while(data.equalsIgnorCase("stop")){
data = dis.readUTF();
System.out.println("Server Message : "+data);
}
}
catch(Exception e){
System.out.println("Run "+e);
}
Client Thread is not complete but i think this information is sufficient enough .
Hope It help you out , Your problem do remind me of College Days :)
There's a million examples on using Java sockets out there - and every one is the same!
Every one shows a client socket being created, some text being sent, and the socket closed.
I am writing some test code. I want my client to loop round and send quite a few messages. It seems silly to close the client socket each time and re-create, so I thought I would just create one client socket, loop round and send data on the same socket. The thing is though - my server socket does not print out what it has received until the last message has been sent by the client and the client socket closed.
Server:
Socket sock;
ClientConnection client;
ServerSocket ss = new ServerSocket(portNumber);
ss.setSoTimeout(0); // 0=infinite
while (true) {
sock = ss.accept();
client = new ClientConnection(sock);
new Thread(client).start();
// ClientConnection reads from sock, prints, and closes sock
}
ClientConnection (a separate class on the Server side):
public class ClientConnection implements Runnable
{
private Socket m_socket;
private BufferedReader m_in = null;
public ClientConnection(Socket socket)
{
m_socket = socket;
try {
InputStream inStream = socket.getInputStream();
m_in = new BufferedReader(new InputStreamReader(inStream));
}
catch (IOException ioe) {
ioe.printStackTrace();
}
}
public String getMessage()
{
String line = null;
StringBuffer completeMessage = new StringBuffer();
try {
while ((line = m_in.readLine()) != null)
{
completeMessage.append(line);
}
}
catch (IOException ioe) {
ioe.printStackTrace();
return "";
}
return completeMessage.toString();
}
public void run()
{
try {
String message = getMessage();
System.out.println("Received: " +message);
}
finally
{
try {
m_socket.close();
}
catch (IOException ioe) {
ioe.printStackTrace();
}
}
}
}
Client:
socket = new java.net.Socket(m_destination, m_portNumber);
outputStream = socket.getOutputStream();
printStream = new java.io.PrintStream(outputStream);
while (more-stuff-to-send)
{
printStream.print(text);
printStream.print("\n");
printStream.flush();
}
prinStream.close();
socket.close();
ClientConnection is created by the server when I start the client, but it does not print what has been sent until the client is done sending.
I feel like I'm missing the point somewhere along the line. Chat examples are quite common, so if I had a chat client then every message it wanted to send to a chat server it would create a client socket, send the message, and close the socket? Just doesn't seem right somehow.
Thank you.
client = new ClientConnection(sock);
You are passing the socket in constructor.
so you shouldn't do:
socket = new java.net.Socket(m_destination, m_portNumber);
just cache that vatiable from contructor as : this.sock = sock;
getting the reader and the writer is ok, also the server is ok.
I would use a Vector to be synchromized queue for sending messages, and the while (more-stuff-to-send) loop would check the queue and id empty than sleep, if has something to send, than pop the first and sent it while he must do stuff, or socket is closed my the client.
EDIT: The code below throws no exception but has no output and hangs. It should output "Test message". In main(), we start a thread that's given a server socket listening on a random port. The main thread the tries to connect and communicate with the ServerSocket on that same random port, but is apparently failing. Why?
public class IntraProcSockTest {
private static int port;
private class Listener extends Thread {
public Listener() {
}
public void run() {
try {
ServerSocket serverSocket = new ServerSocket(0);
port = serverSocket.getLocalPort();
Socket socket = serverSocket.accept();
BufferedReader in;
String fromClient;
in = new BufferedReader(new InputStreamReader(
socket.getInputStream()));
while ((fromClient = in.readLine()) != null) {
System.out.println("From client: " + fromClient);
}
} catch (IOException e) {
e.printStackTrace();
}
}
}
public IntraProcSockTest() {
new Listener().start();
}
public static void main(String[] args) {
new IntraProcSockTest();
try {
Thread.sleep(5000);
Socket socket = new Socket("localhost", port);
PrintWriter socketOut = new PrintWriter(socket.getOutputStream());
socketOut.println("Test message");
} catch (UnknownHostException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
A process can connect to a socket created by itself, there is no problem. Show us the code that throws an exception and/or more details about the exception.
First of all, be careful not to specify a local port for the client socket (the one connecting to the other which is listening). Let the OS choose a random port. Remember that any socket is identified by four elements (remote host, local host, remote port, local port), if you bind both the server socket and the client socket on the same local port, let it be 4498, both sockets are defined as follows: (localhost, localhost, 4498, 4498) and this doesn't work. I suspect this might be your problem.
To avoid such problems, client sockets are often bound to a random port, chosen by the OS. Show us your code, expecially the part in which the client sockets gets created and connects to the server socket.
And about IPC, it is not always bad to use sockets as an inter-process or even intra-process communication technique. The performance is worse, obviously, and you might loose some code readability, but your software will be easily portable to a network (distributed) application. It's up to your plans, it's not like IPC sockets == bad.
To create a Socket connection in one thread you can.
ServerSocket ss = new ServerSocket(0); // open a random free port.
Socket c = new Socket(ss.getInetAddress(), ss.getLocalPort());
Socket s = ss.accept();
ss.close();
final byte[] bytes = "Hello World!".getBytes();
final OutputStream out = c.getOutputStream();
out.write(bytes.length);
out.write(bytes);
final DataInputStream in = new DataInputStream(s.getInputStream());
int len = in.read();
final byte[] b = new byte[len];
in.readFully(b);
System.out.println(new String(b));
c.close();
s.close();
If all you want is IPC within a Process, a socket is not the fastest or simplest way to go. Try using a Pipe (NIO) or PipeInput/OutputStream (IO). Its faster and simpler.
Pipe pipe = Pipe.open();
SinkChannel sink = pipe.sink();
SourceChannel source = pipe.source();
or
PipedOutputStream output = new PipedOutputStream();
PipedInputStream input = new PipedOutputStream(output);
BTW: You can connect a client and server Socket in the same thread, however
Using an Exchanger is 10x faster, and using a ring buffer is faster again.
If you want convenience, using an ExecutorService is the best way to deleagte work to a background pool of threads. This can still perform millions of tasks per second.