Develop Reference

How to download files using DownloadManager and Log their name and path (Android)?

I am able to download files ( mp4 videos) in Android using DownloadManager set to a specific path, but when I try to get the file names from the path it outputs a ".lock" file as the name of my files. I want the name of the files I have downloaded:
File[] files = fileDirectoy.listFiles();
This statement (as below) returns null for the files array. The folder does contain four .mp4 videos
The code that I used is listed below.
File fileDirectoy = Environment.getExternalStorageDirectory();
DownloadManager.Request request = new DownloadManager.Request(uriVideo);
request.setNotificationVisibility(DownloadManager.Request.VISIBILITY_VISIBLE_NOTIFY_COMPLETED);
request.setDestinationInExternalFilesDir(getApplicationContext(), fileDirectoy.toString(), myListOfDocuments.get(i).get("name").toString() + ".mp4");
//todo: Enable this to download videos downloadManager.enqueue(request);
//Lists Files in Local Storage
if(fileDirectoy.exists()) {
File[] files = fileDirectoy.listFiles();
for(File file : files) {
Log.d("MyLog","File name: "+file.getName());
Log.d("MyLog","File path: "+file.getAbsolutePath());
Log.d("MyLog","Size :"+file.getTotalSpace());
}
} else {
Log.d("MyLog", "File directory does not exist");
}
Not sure why this behavior is taking place.

Unable to save the uploaded file into specific directory

I want to upload files and save them into specific directory.And i am new to files concept.When i uploading files from my page they are saved in another directory(C:\Users\ROOTCP~1\AppData\Local\Temp\multipartBody989135345617811478asTemporaryFile) and not in specified directory.I am unable to set it.Please help me in finding a solution.For all help thanks in advance.
public static Result uploadHoFormsByHeadOffice() throws Exception {
Logger.info("#C HoForms -->> uploadHoFormsByHeadOffice() -->> ");
final String basePath = System.getenv("INVOICE_HOME");
play.mvc.Http.MultipartFormData body = request().body()
.asMultipartFormData(); // get Form Body
StringBuffer fileNameString = new StringBuffer(); // to save file path
// in DB
String formType = body.asFormUrlEncoded().get("formType")[0];// get formType from select Box
FilePart upFile = body.getFile("hoFiles");//get the file details
String fileName = upFile.getFilename();//get the file name
String contentType = upFile.getContentType();
File file = upFile.getFile();
//fileName = StringUtils.substringAfterLast(fileName, ".");
// path to Upload Files
File ftemp= new File(basePath +"HeadOfficeForms\\"+formType+"");
//File ftemp = new File(basePath + "//HeadOfficeForms//" + formType);
File f1 = new File(ftemp.getAbsolutePath());// play
ftemp.mkdirs();
file.setWritable(true);
file.setReadable(true);
f1.setWritable(true);
f1.setReadable(true);
//HoForm.create(fileName, new Date(), formType);
Logger.info("#C HoForms -->> uploadHoFormsByHeadOffice() <<-- Redirecting to Upload Page for Head Office");
return redirect(routes.HoForms.showHoFormUploadPage());
}
}
I really confused why the uploaded file is saved in this(C:\Users\ROOTCP~1\AppData\Local\Temp\multipartBody989135345617811478asTemporaryFile) path.

You're almost there.
File file = upFile.getFile(); is the temporary File you're getting through the form input. All you've got to do is move this file to your desired location by doing something like this: file.renameTo(ftemp).
Your problem in your code is that you're creating a bunch of files in memory ftemp and f1, but you never do anything with them (like writing them to the disk).
Also, I recommend you to clean up your code. A lot of it does nothing (aforementioned f1, also the block where you're doing the setWritable's). This will make debugging a lot easier.

I believe when the file is uploaded, it is stored in the system temporary folder as the name you've provided. It's up to you to copy that file to a name and location that you prefer. In your code you are creating the File object f1 which appears to be the location you want the file to end up in.
You need to do a file copy to copy the file from the temporary folder to the folder you want. Probably the easiest way is using the apache commons FileUtils class.
File fileDest = new File(f1, "myDestFileName.txt");
try {
FileUtils.copyFile(ftemp, fileDest);
}
catch(Exception ex) {
...
}

save uploaded file at server

I have uploaded a file from my system, I have converted the file in bytes. Now I want to save that file at server. How can I do this. I have searched through the internet but found nothing. Is there any solution of this problem?
I am uploading file using JSP.

If you are talking about UploadedFile, here is how I achieved this after a huge internet search:
/**
* Save uploaded file to server
* #param path Location of the server to save file
* #param uploadedFile Current uploaded file
*/
public static void saveUploadedFile(String path, UploadedFile uploadedFile) {
try {
//First, Generate file to make directories
String savedFileName = path + "/" + uploadedFile.getFileName();
File fileToSave = new File(savedFileName);
fileToSave.getParentFile().mkdirs();
fileToSave.delete();
//Generate path file to copy file
Path folder = Paths.get(savedFileName);
Path fileToSavePath = Files.createFile(folder);
//Copy file to server
InputStream input = uploadedFile.getInputstream();
Files.copy(input, fileToSavePath, StandardCopyOption.REPLACE_EXISTING);
} catch (Exception e) {
logger.error(e.getMessage());
} finally {
}
}

How to store uploaded mulitple pdf file to a specific location in java?

i want to store uploaded file in a specific location in java. if i upload a.pdf then i want it to store this at "/home/rahul/doc/upload/". i went through some questions and answers of stack overflow but i am not satisfied with solutions.
i am working with Play Framework 2.1.2. i am not working with servlet.
i am uploading but it is storing file into temp directory but i want that file store into a folder as not a temp file i want that file like a.pdf in folder not like temp file.
public static Result upload() {
MultipartFormData body = request().body().asMultipartFormData();
FilePart filePart1 = body.getFile("filePart1");
File newFile1 = new File("path in computer");
File file1 = filePart1.getFile();
InputStream isFile1 = new FileInputStream(file1);
byte[] byteFile1 = IOUtils.toByteArray(isFile1);
FileUtils.writeByteArrayToFile(newFile1, byteFile1);
isFile1.close();
}
but i am not satisfied with this solution and i am uploading multiple doc files.
for eg. i upload one doc ab.docx then after upload it is storing temp directory and file is this:
and it's location is this: /tmp/multipartBody5886394566842144137asTemporaryFile
but i want this: /upload/ab.docx
tell me some solution to fix this.

Everything's correct as a last step you need to renameTo the temporary file into your upload folder, you don't need to play around the streams it's as simple as:
public static Result upload() {
Http.MultipartFormData body = request().body().asMultipartFormData();
FilePart upload = body.getFile("picture");
if (upload != null) {
String targetPath = "/your/target/upload-dir/" + upload.getFilename();
upload.getFile().renameTo(new File(targetPath));
return ok("File saved in " + targetPath);
} else {
return badRequest("Something Wrong");
}
}
BTW you should implement some checking if targetPath doesn't exist to prevent errors and/or overwrites. Typical approach is incrementing the file name if file with the same name already exists, for an example sending a.pdf three times should save the files as a.pdf, a_01.pdf, a_02.pdf, etc.

i just completed it. My solution is working fine.
My solution of uploading multiple files is :
public static Result up() throws IOException{
MultipartFormData body = request().body().asMultipartFormData();
List<FilePart> resourceFiles=body.getFiles();
InputStream input;
OutputStream output;
File part1;
String prefix,suffix;
for (FilePart picture:resourceFiles) {
part1 =picture.getFile();
input= new FileInputStream(part1);
prefix = FilenameUtils.getBaseName(picture.getFilename());
suffix = FilenameUtils.getExtension(picture.getFilename());
part1=new File("/home/rahul/Documents/upload",prefix+"."+suffix);
part1.createNewFile();
output = new FileOutputStream(part1);
IOUtils.copy(input, output);
Logger.info("Uploaded file successfully saved in " + part1.getAbsolutePath());
}

android- Is it possible to play swf files directly from the zip folder without unzipping it

I'm trying to play swf files from a password protected zip folder. I am using (zip4j_1.3.1 library) & the following code to extract it to a seperate location then I'm playing it using webview.
String source = "/sdcard/Test.zip";
String destination = "/sdcard";
String password = "dhinesh";
try {
ZipFile zipFile = new ZipFile(source);
if (zipFile.isEncrypted()) {
zipFile.setPassword(password);
}
zipFile.extractAll(destination);
mWebView.loadUrl("/sdcard/catmouse.swf");
} catch (net.lingala.zip4j.exception.ZipException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
I tried to play file using the following code to play it directly from the zip folder itself and it is not working. Im doing this because so that it can be secured way.
String source = "/sdcard/Test.zip";
String password = "dhinesh";
try {
ZipFile zipFile = new ZipFile(source);
if (zipFile.isEncrypted()) {
zipFile.setPassword(password);
mWebView.loadUrl("/sdcard/Test.zip!/catmouse.swf");
}
Is there any way to play the swf file from password protected zip file without unzipping it...?

That's not how the zip file format works. Even on a desktop computer, when you "directly open" a file form a zip, it's uncompressed from the archive in a temporary folder and then opened. You definitely have to unzip it first.