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Cannot deserialize instance of object out of START_ARRAY token in Spring Webservice
(4 answers)
Closed 5 years ago.
Good Morning,
I'm relatively new to java and trying to to work through a project, but I'm running into issues. My program uses SQL to build a URL to call a web-service, this service will return the following JSON:
[{
"MmisItemNo": "106552",
"CatalogNo": "UM18840041R",
"ContractOn": "False"
}
]
What I need to do is strip off the "False" or "True" value at the end to do additional logic depending on its result.
I keep getting the following error:
.WebCall -com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot
deserialize instance of `.LightswitchResponse` out of START_ARRAY token at [Source: (String)"[{"MmisItemNo":"106552","CatalogNo":"UM18840041R","ContractOn":"False"}]"; line: 1, column: 1]
Here is my code currently after the URL is built in the WebCall.java class:
BufferedReader in = new BufferedReader(
new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
System.out.println(response.toString());
ObjectMapper mapper = new ObjectMapper();
LightswitchResponse lightswitchResponse = mapper.readValue(response.toString(), LightswitchResponse.class);
System.out.println(lightswitchResponse.ContractOn);
In my second class the code is as follows:
public class LightswitchResponse {
String MmisItemNo;
String CatalogNo;
boolean ContractOn;
public String getMmisItemNo() {
return MmisItemNo;
}
public void setMmisItemNo(String mmisItemNo) {
MmisItemNo = mmisItemNo;
}
public String getCatalogNo() {
return CatalogNo;
}
public void setCatalogNo(String catalogNo) {
CatalogNo = catalogNo;
}
public boolean ContractOn() {
return ContractOn;
}
public void setContractOn(boolean contractOn) {
ContractOn = contractOn;
}
}
Any ideas on what might be going wrong? I feel like it might have something to do with the [] on the JSON response, but not 100% sure.
You are right it is because of the [] on the JSON response. This means that the JSON object that is being returned is an array of objects.
Hence to get Jackson to map it correctly you should be doing this:
LightswitchResponse[] lightswitchResponses =
mapper.readValue(response.toString(), LightswitchResponse[].class);
You can then read the first element off this to get your desired LightSwitchResponse object:
LightswitchResponse lightswitchResponse = lightswitchResponses[0];
Related
This is my first time using jackson/consuming apis/httpclient. I'm getting this error com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize value of type java.util.ArrayList<WallHaven> from Object value (token JsonToken.START_OBJECT) . The api I'm trying to consume is https://wallhaven.cc/help/api
try {
HttpClient client = HttpClient.newHttpClient();
HttpRequest request = HttpRequest.newBuilder()
.GET()
.uri(URI.create("https://wallhaven.cc/api/v1/w/pkgkkp"))
.build();
HttpResponse<String> response = client.send(request, HttpResponse.BodyHandlers.ofString());
ObjectMapper mapper = new ObjectMapper();
List<WallHaven> posts = mapper.readValue(response.body(), new TypeReference<List<WallHaven>>() {
});
posts.forEach(System.out::println);
} catch (Exception e) {
e.printStackTrace();
}
The api json format is https://pastebin.com/tbSaVJ1T
Here's my WallHaven class
public class WallHaven {
public Data data;
public WallHaven(Data data) {
this.data = data;
}
public WallHaven() {
}
#Override
public String toString() {
return "WallHaven{" +
"data=" + data.getPath() +
'}';
}
}
Data contains all the other classes/variables
This is happening because you're trying to deserialize a Json Object into a List in java. The error message explains it by saying that the starting character (JsonToken.START_OBJECT) is the start of a json object not a json array, so you can't deserialize it directly into a List, but should deserialize it into an object.
Try changing:
List<WallHaven> posts = mapper.readValue(response.body(), new TypeReference<List<WallHaven>>())
into
WallHaven post = mapper.readValue(response.body(), new TypeReference<WallHaven>())
I am a receiving a JSON object and I need to save the values to my DB. But I'm having an issue figuring out how to retrieve the particular values in the JSON object.
In this case, I want to retrieve the values of 'originationNumber' and 'messageBody'
The response object -
{"originationNumber":"***","destinationNumber":"***","messageKeyword":"KEYWORD_***","messageBody":"Answer ","previousPublishedMessageId":"1slamq6mdpucd8q4i7iabf1sikc629ga253tr6o0","inboundMessageId":"88bc02fc-aff3-4277-ac1d-f27b6d3b6abb"}
Method to receive message -
public String getReceivedMessages(Messaging receivedMessage) {
BasicAWSCredentials awsCredentials = new BasicAWSCredentials(awsAccessKey, awsSecretKey);
AmazonSQS sqsClient = AmazonSQSClientBuilder.standard()
.withCredentials(new AWSStaticCredentialsProvider(awsCredentials))
.withRegion(String.valueOf(awsRegion)).build();
StringBuilder sb = new StringBuilder();
String queueUrl = "https://sqs.us-east-1.amazonaws.com/1234567/GetReceivedMessages";
List<Message> messages = sqsClient.receiveMessage(new ReceiveMessageRequest(queueUrl)
.withMaxNumberOfMessages(1).withWaitTimeSeconds(20)).getMessages();
for (Message message : messages) {
sb.append(message.getBody());
sqsClient.deleteMessage(queueUrl, message.getReceiptHandle());
}
// Save messages to DB
String userId = connectionRequestRepository.getUserId();
Date date = new Date();
Timestamp now = new Timestamp(date.getTime());
receivedMessage.setUserId(userId);
receivedMessage.setOriginationNumber("");
receivedMessage.setDestinationNumber("***");
receivedMessage.setMessageBody("");
receivedMessage.setMessageType("RECEIVED");
receivedMessage.setCreatedAt(now);
messagingRepository.save(receivedMessage);
System.out.println(sb); <--- Prints response object to console
return sb.toString();
}
You can use jackson library for that.
Solution 1: You can use ObjectMapper as below:
Message Class to map JSON to Java Object:
public class Message {
private String originationNumber;
private String messageBody;
// public getter and setters methods
}
Create Object From JSON String:
Message message = null;
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
try {
message = objectMapper.readValue(payload, Message.class);
} catch (JsonProcessingException e) {
// Log Or do some action as per need
}
Here message will have those values. DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES is used here to skip exception as there are other fields also in JSON and not present in Java Class (as we don't need them).
Solution 2: Alternatively you can use JsonNode from same Jackson library and read nodes one by one as below:
ObjectMapper mapper = new ObjectMapper();
JsonNode actualObj = mapper.readTree("{\"originationNumber\":\"***\",\"destinationNumber\":\"***\",\"messageKeyword\":\"KEYWORD_***\",\"messageBody\":\"Answer \",\"previousPublishedMessageId\":\"1slamq6mdpucd8q4i7iabf1sikc629ga253tr6o0\",\"inboundMessageId\":\"88bc02fc-aff3-4277-ac1d-f27b6d3b6abb\"}");
String originationNumber = actualObj.get("originationNumber");
String messageBody = actualObj.get("messageBody");
In this approach you won't need to create Message class.
You can convert the json string into a json object
https://www.javatpoint.com/how-to-convert-string-to-json-object-in-java
String string = "{\"originationNumber\":\"***\",\"destinationNumber\":\"***\",\"messageKeyword\":\"KEYWORD_***\",\"messageBody\":\"Answer \",\"previousPublishedMessageId\":\"1slamq6mdpucd8q4i7iabf1sikc629ga253tr6o0\",\"inboundMessageId\":\"88bc02fc-aff3-4277-ac1d-f27b6d3b6abb\"}";
JSONObject json = new JSONObject(string);
System.out.println(json.toString());
String destinationNumber = json.getString("destinationNumber");
System.out.println(destinationNumber);
where ur json like
{"originationNumber":"***",
"destinationNumber":"***",
"messageKeyword":"KEYWORD_***",
"messageBody":"Answer","previousPublishedMessageId":"1slamq6mdpucd8q4i7iabf1sikc629ga253tr6o0",
"inboundMessageId":"88bc02fc-aff3-4277-ac1d-f27b6d3b6abb"
}
it like
"key":Value
i think ur code will be like
receivedMessage.setUserId(userId);
receivedMessage.setOriginationNumber("originationNumber");
receivedMessage.setDestinationNumber("destinationNumber");
receivedMessage.setMessageBody("messageBody");
receivedMessage.setMessageType("RECEIVED");
receivedMessage.setCreatedAt(now);
messagingRepository.save(receivedMessage);
I have a simple requirement where, if application encounters an exception, my JAX-RS Rest endpoint should return a custom JSON response with 500 HTTP header status.
Data needed to construct the response comes from an object with several properties (see below). The problem is, I am only interested in one or two values from each property (out of several dozens). And I cannot modify any of these models/classes (some have a Jackson annotation for JSON processing, e.g. null properties should be discarded during serialization).
public class MainObject {
private FirstProperty firstProperty;
private SecondProperty secondProperty;
private ThirdProperty thirdProperty;
// other codes
public String toString() {
ObjectMapper mapper = new ObjectMapper();
try { return mapper.writeValueAsString(this); }
catch (Exception e) { return null; }
}
}
public class FirstProperty {
private boolean bol = true;
private double dob = 5.0;
private List<String> subProperty;
// other properties
public String toString() {
ObjectMapper mapper = new ObjectMapper();
try { return mapper.writeValueAsString(this); }
catch (Exception e) { return null; }
}
}
#JsonSerialize(include=JsonSerialize.Inclusion.NON_NULL)
public class SecondProperty {
private String str;
private List<String> subProperty;
// other properties
public String toString() {
ObjectMapper mapper = new ObjectMapper();
try { return mapper.writeValueAsString(this); }
catch (Exception e) { return null; }
}
}
#JsonSerialize(include=JsonSerialize.Inclusion.NON_NULL)
public class ThirdProperty {
private int intProp = true;
private List<String> subProperty;
// other properties
public String toString() {
ObjectMapper mapper = new ObjectMapper();
try { return mapper.writeValueAsString(this); }
catch (Exception e) { return null; }
}
}
The expected JSON that I should be seeing coming back is on the client side (say, a browser -- testing in Edge):
{
"firstProperty" : { "subProperty" : [ "val1" ] },
"secondProperty" : { "str" : "val2", "subproperty" : [ "val3", "val6" ] },
"thirdProperty" : { "subProperty" : [ "val4" ] }
}
Instead, all my field names and their values have their quotations escaped, and extra double quotes around the entire value, e.g.:
{
"firstProperty" : "{ \"subProperty\" : [ \"val1\" ] }",
"secondProperty" : "{ \"str\" : \"val2\", \"subproperty\" : [ \"val3\", \"val6\" ] }",
"thirdProperty" : "{ \"subProperty\" : [ \"val4\" ] }"
}
Please note the extra " before and after the curly brackets. My environment is:
Java 1.8.45
FasterXML Jackson 2.9.8
Spring Boot 2.0.1
RestEasy (JBoss) JAX-RS
JBoss 6.4
I eliminated the majority of "noise" in the code to see at what point this happens. This is the controller:
#Path("/")
public class MainController {
#GET
#Produces(MediaType.APPLICATION_JSON)
#Path("/rest/path")
public MainObject getMainObject throws MyCustomException {
// A service call that throws MyCustomException
}
}
And JAX-RS ExceptionMapper where I send the response back:
#Provider
public class MyCustomExceptionMapper extends ExceptionMapper<MyCustomException> {
#Override
public Response toResponse(MyCustomException ex) {
HashMap<String, Object> responseBody = new HashMap<>();
String strEx = ex.getStrEx(); // Comes from SecondProperty.str stored in MyCustomException, not that it matters
// Instantiate an empty object that contains
MainObject obj = new MainObject();
obj.getFirstProperty().setSubProperty(ex.getStrs());
obj.getSecondProperty().setStr(strEx);
obj.getSecondProperty().setSubProperty(ex.getStrs());
obj.getThirdProperty().setSubProperty(ex.getStrs());
responseBody.put("firstProperty", serializeFirstProperty(obj.getFirstProperty()));
responseBody.put("secondProperty", serializeSecondProperty(obj.getSecondProperty()));
responseBody.put("thirdProperty", serializeThirdProperty(obj.getThirdProperty()));
Response response = Response.status(/* 500 status */).entity(responseBody).build();
return response;
}
}
Since I only need to send back a very small subset of overall properties from each of my types, I created a custom StdSerializer that would only populate a needed property. For brevity, I only do serializeFirstProperty() but they are all more or less identical:
private StdSerializer<FirstProperty> getFPSerializer(FirstProperty firstProperty) {
return new StdSerializer<FirstProperty>(FirstProperty.class) {
#Override
public void serialize(FirstProperty value, JsonGenerator gen, SerializerProvider provider) throws IOException {
gen.writeStartObject();
if (/* there are items in FirstProperty.subProperty */) {
gen.writeArrayFieldStart("subProperty");
for (String str : value.getSubProperty()) {
gen.writeString(str);
}
gen.writeEndArray();
}
gen.writeEndObject();
}
}
private <T> ObjectMapper getCustomOM(StdSerializer<?> serializer) {
ObjectMapper mapper = new ObjectMapper();
SimpleModule sm = new SimpleModule();
sm.addSerializer(serializer);
mapper.registerModule(module);
return mapper;
}
Then use these helper methods like:
private String serializeFirstProperty(FirstProperty firstProperty) {
ObjectMapper mapper = getCustomOM(getFPSerializer(firstProperty));
String ser = null;
try { ser = mapper.writeValueAsString(firstProperty); }
catch (JsonProcessingException e) { return null; }
return ser;
}
I have tried countless of configurations with ObjectMapper, e.g. disable(JsonParser.Feature.ALLOW_BACKLASH_ESCAPING_ANY_CHARACTER) (couldn't find any relevant flag for JsonGenerator which I really want to disable in a similar fashion).
Or explicitly returning Object from serializeFirstProperty(), or replacing all the \" with " in serializeFirstProperty() when ser is returned.
Or set custom StdSerializer's JsonGenerator.setCharacterEscapes(new CharacterEscapes() { //... } or play around with JAX-RS Response at no avail. I always seem to get a "string" value with quotations, e.g.:
"firstProperty" : "{ \"subProperty\" : [ \"val1\" ] }"
If I simply just do
responseBody.put("firstProperty", mapper.writeValueAsString(obj.getFirstProperty()));
somehow this produces the right JSON output, however, it includes a lot of unnecessary properties which I don't want in this exception handling case.
Funny thing is, when I peer into response (or responseBody map), everything looks right (I don't see values having double quotations).
Please also note that not only I can't modify the models, but some of their properties are instantiated during creation with default values, so not-null inclusion doesn't work, and they will appear in the final JSON if I don't use a custom serialization.
Does anyone know what's causing this escaped and extra quotations?
I think I misunderstood the question in the first attempt of answering it.
The problem is that you serialize a property as string (using mapper.writeValueAsString(this) and then add it to the responseBody which you think of being string to json object map but it is a string to Java object map. In your case at runtime it is a string mapping to another string (the serialized json object is represented as Java string) and a Java string is a Java object as well.
What you want to do instead is to construct a Java object responseBody instead of a map. It should act as a DTO having all the specific properties etc and then serializing it in in one action using the mapper. Because if you first serialize a property to a json string than it it is just a string from the Java point of view and the mapper has no chance to interpret it as a json object.
I am writing automation script to validate json responses of REST APIs and i am using faster xml to serialize and convert java object to json format.
I have a user case where I have to get the json response and add a new array element to an existing array and post it back.
The json response after GET looks like this :
{
"name":"test",
"id":"1234",
"nodes":[
{
"nodeId":"node1"
},
{
"nodeId":"node2"
}
]
}
To this json response, I need to add a third entry for nodes array
{ "nodeId": "node3" } and then post this.
Can someone please help me understand how to add a new array element to an existing array?
You can try:
//Your JSON response will be in this format
String response = "{ \"name\":\"test\", \"id\":\"1234\", \"nodes\":[ { \"nodeId\":\"node1\" }, { \"nodeId\":\"node2\" } ] }";
try {
JSONObject jsonResponse = new JSONObject(response);
JSONArray nodesArray = jsonResponse.getJSONArray("nodes");
JSONObject newEntry = new JSONObject();
newEntry.put("nodeId","node3");
nodesArray.put(newEntry);
jsonResponse.put("nodes",nodesArray);
} catch (JSONException e) {
e.printStackTrace();
}
Now you can post your jsonResponse.toString() as required.
I would rather go for cleaner approach, create Object with below structure -
public class Response{
private String name;
private int id;
private List<Node> nodes;
<Getter & Setter>
}
public class Node{
private String nodeId;
}
Serialize the json -
Response response = objectMapper.readValue(responseJson,
Response.class);
Add the new incoming node object to response -
response.getNodes().add(New Node("{new node Value}"));
Deserialize before post -
objectMapper.writeValueAsString(response);
I have a simple JSON file I'd like to parse (units.json) using gson and Java:
{"user_name": "happyman", "status": {"hp": 20, "karma": 7, "mp": 10}, "gold": 5.25,}
{"user_name": "sadman", "status": {"hp": 10, "karma": 2, "mp": 6}, "gold": 0.5,}
...
The problem I have is, how do I parse this file as it is not in an array format?
Currently I have a Filereader to the path being called by the JsonReader
FileReader fileReader = new FileReader(jsonFilePath);
JsonReader jsonReader = new JsonReader(fileReader);
jsonReader.beginObject();
while (jsonReader.hasNext()) {
String name = jsonReader.nextName();
if (name.equals("user_name")) {
System.out.println("user_id: "+jsonReader.nextString());
}
//...checks for other equals
However, with this code, I'm only able to get the first line.
I have a feeling it has something to do with the "hasNext()" not being the right method call in the while loop.
I appreciate the help! Thanks.
You can use this code with GSON library:
ObjectMapper mapr = new ObjectMapper();
Map<String,Object> map = mapr.readValue(jsonString, Map.class);
or
public class Units {
#JsonProperty("user_name")
public String user_name;
#JsonProperty("status")
public List<Attr> attrs;
..
}
public class Attr {
#JsonProperty("hp")
public String hp;
#JsonProperty("karma")
public String karma;
#JsonProperty("mp")
public String mp;
}
ObjectMapper mapr = new ObjectMapper();
Units unit = mapr.readValue(jsonString, Units.class);
for both you can use jsonString to define each json unit in your file.