Develop Reference

Checking if item lore contains contains string (loren.contains("§eSigned from "))

I only want to check for:
if (lore.contains("§eSigned of ")) {
but it doesn't get that it does contain "§eSigned of "
I wrote a Minecraft Command /sign you can add a lore to an item ("Signed of playerrank | playername").
Then i wanted to add an /unsign command to remove this lore.
ItemStack is = p.getItemInHand();
ItemMeta im = is.getItemMeta();
List<String> lore = im.hasLore() ? im.getLore() : new ArrayList<String>();
if (lore.contains("§eSigned of " + getChatName(p))) { // this line is important!
for (int i = 0; i < 3; i++) {
int size = lore.size();
lore.remove(size - 1);
}
im.setLore(lore);
is.setItemMeta(im);
p.setItemInHand(is);
sendMessage(p, "§aThis item is no longer signed");
} else {
sendMessage(p, "§aThis item is not signed!");
}
return CommandResult.None;
Everything works fine until you e.g. change your name. than you can't remove the sign because getChatName(p) has changed.
To fix this i only want to check
if (lore.contains("§eSigned of ")) {
but than it doesn't get it and returns false. (it says lore does not contain "§eSigned of ")
I tried a lot but it only works with the string "§eSigned of " and getChatName(p).
As the documentation "contains" searches for the specific string so it should work as I thought right?
Add:
getChatName(p) returns the rank of the player and the playername like: "Member | domi"
sendMessage(p, "") sends a simple message in the Minecraft chat

The problem you run into is that contains(String) looks for a matching string. What you search for is a check if any string in the list starts with "§eSigned of ".
I would suggest adding a function isSignedItem like this:
private boolean isSignedItem(List<String> lore) {
for (String st : lore)
if (st.startsWith("§eSigned of "))
return true;
return false;
}
and then to use this function to check if the item is signed or not:
[...]
List<String> lore = im.hasLore() ? im.getLore() : new ArrayList<String>();
if (isSignedItem(lore)) { // this line is important!
for (int i = 0; i < 3; i++) {
int size = lore.size();
lore.remove(size - 1);
}
[...]

How to use Jsoup to get href link without the extra characters?

I have an Element list of which i'm using jsoup's method attr() to get the href attribute.
Here is part of my code:
String searchTerm = "tutorial+programming+"+i_SearchPhrase;
int num = 10;
String searchURL = GOOGLE_SEARCH_URL + "?q="+searchTerm+"&num="+num;
Document doc = Jsoup.connect(searchURL).userAgent("chrome/5.0").get();
Elements results = doc.select("h3.r > a");
String linkHref;
for (Element result : results) {
linkHref = result.attr("href").replace("/url?q=","");
//some more unrelated code...
}
So for example, when i use the search prase "test", the attr("href") produces (first in the list):
linkHref = https://www.tutorialspoint.com/software_testing/&sa=U&ved=0ahUKEwi_lI-T69jTAhXIbxQKHU1kBlAQFggTMAA&usg=AFQjCNHr6EzeYegPDdpHJndLJ-889Sj3EQ
where i only want: https://www.tutorialspoint.com/software_testing/
What is the best way to fix this? Do i just add some string operations on linkHref (which i know how) or is there a way to make the href attribute contain the shorter link to begin with?
Thank you in advanced

If you always want to remove the query parameters you can make use of String.indexOf() e.g.
int lastPos;
if(linkHref.indexOf("?") > 0) {
lastPos = linkHref.indexOf("?");
} else if (linkHref.indexOf("&") > 0){
lastPos = linkHref.indexOf("&");
}
else lastPos = -1;
if(lastPos != -1)
linkHref = linkHref.subsring(0, lastPos);

Nested loop creates duplicate entries when ran, cannot find issue?

When the code is ran the nested loop causes it to create occasional duplicate entries to the system, i have spent a while looking through this but still cant find what is causing this, would greatly appreciate any help?
for(int i = 0; i < subWorkItemElement.getChildNodes().getLength(); i++) {
Boolean test = false;
WorkItemCommon existingChild = null;
String summary = null;
if(subWorkItemElement.getChildNodes().item(i).getNodeName().equals("workitem")) {
// We know it's a work item - but is it in the existing list?
Element childWorkItem = (Element) subWorkItemElement.getChildNodes().item(i);
for(int j = 0; j < subWorkItemElement.getChildNodes().getLength(); j++) {
if(childWorkItem.getChildNodes().item(j) instanceof Element) {
if(((Element)childWorkItem.getChildNodes().item(j)).getNodeName().equals("details")) {
summary = ((Element) childWorkItem.getChildNodes().item(j)).getElementsByTagName("summary")
.item(0).getTextContent();
for(String k : userInfoHashMap.keySet()) {
summary = summary.replace("${" + k + "}", userInfoHashMap.get(k));
}
if(childHashTable.containsKey(summary)) {
test = true;
existingChild = childHashTable.get(summary);
IWorkItem workItem = existingChild.getWorkItem();
System.out.println("INFO: The task with summary \"" + summary + "\" already exists. Skipping creation.");
System.out.println("this task is work item: " + workItem.getId());
//either check the tasks in the xml for updated details and then modify the existing workitem
//or just modify the work item without checking for updates
makeChildTask(childWorkItem, existingChild, childHashTable, userInfoHashMap, workItemHashMap, rtc, false);
break;
}
}
}
}
if(!test) {
System.out.println("INFO: The task with summary " + summary + " does not currently exist. Creating.");
makeChildTask(childWorkItem, thisItem, childHashTable, userInfoHashMap, workItemHashMap, rtc, true);
} else makeFromExistingChildTask(childWorkItem, existingChild, userInfoHashMap, workItemHashMap, rtc);
}
}

You are possibly (not sure what makeChildTask() does) changing an XML structure while iterating through the children list. While not necessarily incorrect, this can mean you get entries inserted while you process the list. Since you call the subWorkItemElement.getChildNodes().getLength() each time instead of cache'ing it, this might result in the length changing in between the loop iterations.

hasNext skips first value in HashMap

I'm trying to implement an expandable listview with data from a remote server. I've already have the JSON part covered. My sample has three value sets returned (confirmed by checking logcat on the original JSON response). My problem now is while dividing the JSON return into header and child datas, the first value set is skipped. My code is as follows:
int lisDataHeaderCounter = 0;
String searchKey;
for (int i = 0; i < components.length(); i++) {
List<String> component_value = new ArrayList<String>();
searchKey = main_components.get(i);
if (!listDataHeader.contains(searchKey)) {
listDataHeader.add(searchKey);
Iterator<Map.Entry<String, String>> entries = sub_components.entrySet().iterator();
while (entries.hasNext()) {
Map.Entry<String, String> entry = entries.next();
Log.d("getValue() ", "+ " + entry.getValue());
if (searchKey == entry.getKey())
component_value.add(entry.getValue());
}
listDataChild.put(listDataHeader.get(lisDataHeaderCounter), component_value);
lisDataHeaderCounter++;
}
}
I've also tried the code below and it still has the same result.
for (Map.Entry<String, String> entry : sub_components.entrySet()) {
if (searchKey == entry.getKey())
component_value.add(entry.getValue());
}
Here is a sample of the JSON response that is being process by the above codes:
[{"activity_code":"1","activity_name":"Midterm Exam"},
{"activity_code":"1","activity_name":"Final Exam"},
{"activity_code":"2","activity_name":"Project"}]
With the current codes, in the for loop, the first value of searchKey is '1'. When I placed a Log.d(); in the while loop to check what the first value is read, I found that it is "Final Exam" and not "Midterm Exam". Is there a way for me to get the value of the first data set before it goes into the while loop?
Here is a workaround I've made to ensure that the first value would be included to the sub_components. But I guess it doesn't look neat. If anyone has a better solution, please feel free to share.
for (int i = 0; i < components.length(); i++) {
JSONObject c = components.getJSONObject(i);
String formula_code = c.getString(TAG_FORMULA_CODE);
String component_name = c.getString(TAG_ACTIVITY_NAME);
main_components.add(formula_code);
sub_components.put(formula_code, component_name);
if (!listDataHeader.contains(formula_code))
listDataHeader.add(formula_code);
if (i == 0) {
component_value.add(component_name);
}
}
for (int i = 0; i < listDataHeader.size(); i++) {
for (Map.Entry<String, String> entry : sub_components.entrySet()) {
if (listDataHeader.get(i) == entry.getKey())
component_value.add(entry.getValue());
}
listDataChild.put(listDataHeader.get(i), component_value);
component_value = new ArrayList<String>();
}

I can't see any off by one error on the two, but perhaps it's the searchKey == entry.getKey(), that might have to be searchKey.equals(entry.getKey()), but I would need to see more code to know for sure.

How to check if the subdomain is also from same domain using java

i have a list of url's i need to filter specific domain and subdomain. say i have some domains like
http://www.example.com
http://test.example.com
http://test2.example.com
I need to extract urls which from domain example.com.

Working on project that required me to determine if two URLs are from the same sub domain (even when there are nested domains). I worked up a modification from the guide above. This holds out pretty well thus far:
public static boolean isOneSubdomainOfTheOther(String a, String b) {
try {
URL first = new URL(a);
String firstHost = first.getHost();
firstHost = firstHost.startsWith("www.") ? firstHost.substring(4) : firstHost;
URL second = new URL(b);
String secondHost = second.getHost();
secondHost = secondHost.startsWith("www.") ? secondHost.substring(4) : secondHost;
/*
Test if one is a substring of the other
*/
if (firstHost.contains(secondHost) || secondHost.contains(firstHost)) {
String[] firstPieces = firstHost.split("\\.");
String[] secondPieces = secondHost.split("\\.");
String[] longerHost = {""};
String[] shorterHost = {""};
if (firstPieces.length >= secondPieces.length) {
longerHost = firstPieces;
shorterHost = secondPieces;
} else {
longerHost = secondPieces;
shorterHost = firstPieces;
}
//int longLength = longURL.length;
int minLength = shorterHost.length;
int i = 1;
/*
Compare from the tail of both host and work backwards
*/
while (minLength > 0) {
String tail1 = longerHost[longerHost.length - i];
String tail2 = shorterHost[shorterHost.length - i];
if (tail1.equalsIgnoreCase(tail2)) {
//move up one place to the left
minLength--;
} else {
//domains do not match
return false;
}
i++;
}
if (minLength == 0) //shorter host exhausted. Is a sub domain
return true;
}
} catch (MalformedURLException ex) {
ex.printStackTrace();
}
return false;
}
Figure I'd leave it here for future reference of a similar problem.

I understand you are probably looking for a fancy solution using URL class or something but it is not required. Simply think of a way to extract "example.com" from each of the urls.
Note: example.com is essentially a different domain than say example.net. Thus extracting just "example" is technically the wrong thing to do.
We can divide a sample url say:
http://sub.example.com/page1.html
Step 1: Split the url with delimiter " / " to extract the part containing the domain.
Each such part may be looked at in form of the following blocks (which may be empty)
[www][subdomain][basedomain]
Step 2: Discard "www" (if present). We are left with [subdomain][basedomain]
Step 3: Split the string with delimiter " . "
Step 4: Find the total number of strings generated from the split. If there are 2 strings, both of them are the target domain (example and com). If there are >=3 strings, get the last 3 strings. If the length of last string is 3, then the last 2 strings comprise the domain (example and com). If the length of last string is 2, then the last 3 strings comprise the domain (example and co and uk)
I think this should do the trick (I do hope this wasn't a homework :D )
//You may clean this method to make it more optimum / better
private String getRootDomain(String url){
String[] domainKeys = url.split("/")[2].split("\\.");
int length = domainKeys.length;
int dummy = domainKeys[0].equals("www")?1:0;
if(length-dummy == 2)
return domainKeys[length-2] + "." + domainKeys[length-1];
else{
if(domainKeys[length-1].length == 2) {
return domainKeys[length-3] + "." + domainKeys[length-2] + "." + domainKeys[length-1];
}
else{
return domainKeys[length-2] + "." + domainKeys[length-1];
}
}
}