I am trying to serialize a list of JSON blobs and put certain keys into a HashTable during the serialization. Here is an example of my JSON:
[
{
"name": "sally",
"id": 1,
"eye_color": "green"
},
{
"name": "jack",
"id": 2,
"eye_color": "blue"
},
{
"name": "jane",
"id": 3,
"eye_color": "brown"
}
]
What I am looking for specifically is a POJO (or set of POJOs) which can serialize the above JSON like so with Jackson assuming the above JSON is in a file called above_json.json:
MyPOJO pojo = objectMapper.readValue(new File("above_json.json"), MyPOJO.class);
I want the result of the serialization to give me a HashTable (or an Object which encapsulates the HashTable) where the HashTable key is the value of name and the Hashtable value is the value of the corresponding id above.
Assuming we serialized the above JSON in this fashion, I would want to access the HashTable like so:
myTable.get("jane")
result: 3
myTable.get("jack")
result: 2
myTable.get("Jill")
result: null
I know how to serialize basic JSON with Jackson. I have an example like below:
JSON Input:
"Parameter":{
"Name":"Parameter-Name",
"Value":"Parameter-Value"
}
POJO to serialize above simple JSON:
public class Parameter {
#JsonProperty("Name")
public String name;
#JsonProperty("Value")
public String value;
}
But obviously this type of setup does not put the results into a HashTable. I need a POJO like what I have in this example which will serialize JSON directly into a HashTable
I don't think that is possible.
You serialize this json into a list of pojos, and have a utility function to generate the hashtable in the way you desire from the list of pojos.
Create a POJO for holding the properties you are interested in.
#JsonIgnoreProperties(ignoreUnknown = true)
private static class MyPOJO {
#JsonProperty("name")
private String name;
#JsonProperty("id")
private Integer id;
public Integer getId() {
return id;
}
public String getName() {
return name;
}
}
Deserialize the contents of the file into List<MyPOJO>
List<MyPOJO> myPOJO = mapper.readValue(new File(".."), new TypeReference<List<MyPOJO>>(){});
Stream the contents of the map to construct a map whose key is the name and value is the id.
Map<String, Integer> map = myPOJO.stream()
.collect(Collectors.toMap(MyPOJO::getName, MyPOJO::getId));
First of all, you probably don't want to use a HashTable, as it's considered to be an obsolete type (see here).
Either use a HashMap or if you want thread safety, a ConcurrentHashMap or a thread-unsafe Map backed by Collections.synchronized[...] and referenced to within synchronized statements.
Secondly, you can use a TypeReference to de-serialize as your desired type.
Finally, your JSON's syntax is incorrect: it starts with a square bracket ([) and ends with a curly bracket (}), which is technically unparseable.
Assuming you want an array of Maps here (e.g. HashMap<String, String>[]), here is some suitable code, provided you replace the last curly bracket with a square one:
// the map array
Map<String, String>[] map = null;
map = om.readValue(yourFile, new TypeReference<HashMap<String, String>[]>() {});
// prints the de-serialized contents
System.out.println(Arrays.toString(map));
Edit
Since you have now edited your JSON to remove the first square bracket and replace it with a curly bracket, no you can't parse as a Map as is.
Edit 2
Since you have now re-edited your JSON to feature square brackets once again instead of curly brackets in the wrapping object, you can once again de-serialize as a Map[]. Until the next edit, I guess...
Related
I have a json with complex nested. values. But there is one unique key value pair in the json.. without traversing , I need to retrieve the value .
for example:
name : "xyz". In the entire complex nested json , I need to return a json with all the values of name key.
I am currently using org.simple.json. but its very complex as I have to traverse through the entire nested json and build JSONArray etc.
maybe you can use java8 stream，the way is very easy to solve your problem.
example：
[
{
"name":"xyz",
"value":"1"
},
{
"name":"xyz",
"value":"2"
},
{
"name":"xyz",
"value":"3"
}
]
and then，you can create a class:
import lombok.Data;
#Data
public class JsonTest {
private String name;
private String value;
}
finally, like this. btw, I am currently using other json package.
List<JsonTest> jsonArray = JSON.parseArray(json, JsonTest.class);
List<String> valueList = jsonArray.stream()
.filter(e -> "xyz".equals(e.getName()))
.map(JsonTest::getValue)
.collect(Collectors.toList());
I want to map JSON Object to Java class with custom structure.
For example:
public class RestAttributesMappingDTO {
Map<String, Object> details = new LinkedHashMap<>();
#JsonAnySetter
void setDetail(String key, Object value) {
details.put(key, value);
}
}
As you can see, annotation #JsonAnySetter have been used for mapping.
Its ok for any flat structure.
But if I want to map object with unlimited (custom) nested structure?
For example:
{
name: "",
age: "",
job: [{
job1: {
title: "",
ZIP: ""
}
}]
}
Arises recursive algorithm of creating map without #JsonAnySetter.
But is there any way to build this unlimited nested map with Jackson?
Jackson by default deserialises:
JSON Object to Map where keys are String-s.
JSON Array to List of objects or primitives.
In your example, you can keep like it is but it would need casting and checking types in runtime. Other option is to use com.fasterxml.jackson.databind.JsonNode class and method could look like:
void setDetail(String key, JsonNode value)
But you can even skip this method and #JsonAnySetter annotation and use it in class directly:
public class RestAttributesMappingDTO {
private JsonNode details;
//getters, setters
}
JsonNode allows to iterate over key-value pairs.
See some other related questions:
Mapping Json Array to POJO using Jackson
How to modify the value of a JsonNode recursively using Jackson
How to convert a JsonNode instance to an actual pojo
I have come across this question on StackOverflow which asks about converting JSON to Java. The answer shows that another class is modelled to represent the JSON data as well as an object being created and I don't understand why.
Does that object now contain all the information after Gson reads the content or only one key/value pair? If it only contains 1 key/value pair, I'm assuming I would need to create multiple objects for the JSON that I have below which I can the use a loop to iterate over and add the values to a drop down menu?
{
"1": "Annie",
"2": "Olaf",
"3": "Galio",
"4": "TwistedFate",
"5": "XinZhao",
"6": "Urgot",
"7": "Leblanc",
"8": "Vladimir",
"9": "FiddleSticks",
"10": "Kayle",
"11": "MasterYi",
"12": "Alistar",
"13": "Ryze",
"14": "Sion",
"15": "Sivir",
"16": "Soraka",
"17": "Teemo",
"18": "Tristana",
"19": "Warwick",
"20": "Nunu"
}
Essentially what I am aiming to do is:
1) Create a list of names with the Values.
2) Sort the list of names (as it comes unsorted) in alphabetical order
3) Loop through the list and add each name to a drop down menu
4) When a name in the drop down menu is selected, the key associated with that value is passed to another url which receives more data.
Sorry if this is unclear. I've spent a couple of hours trying to understand how to get elements from JSON and display it, as well as trying to create a list where I can use the key to display information the name but have had no luck except for using a for-each loop.
Let's use Jackson's feature that allows you to map any property to a single method (you don't really need a getter here I believe). Just swap the key and value in this universal setter, and add to a TreeMap, which is already sorted by key (name). Then you can output the keys (names) in the alphabetical order and get an ID by name easily.
public static void main(String[] args) throws IOException {
String json = "....."; // your JSON string here
com.fasterxml.jackson.databind.ObjectMapper mapper =
new com.fasterxml.jackson.databind.ObjectMapper();
ReverseMap pairs = mapper.readValue(json, ReverseMap.class);
for (Map.Entry<Object, String> entry : pairs.getValues().entrySet()) {
System.out.println(entry.getKey() + ":" + entry.getValue());
}
}
public class ReverseMap {
private TreeMap<Object, String> mapping = new TreeMap<>();
#com.fasterxml.jackson.annotation.JsonAnySetter
public void add(String name, Object value) {
mapping.put(value, name);
}
public Map<Object, String> getValues() {
return mapping;
}
}
Gson Bean Mapping Solution
Okay, what you have is a bit unusual for a JSON object; the keys (the numbers in your case) essentially represent properties of their contained object. That's workable, but you have to understand that, for example, when looking for "Annie" in the JSON object, if you use Gson to map to a "bean" class, which we'll call Data (as in the linked example), then you'd have to create a data object like so:
class Data {
private String _1;
// ...
private String _20;
public String get1() { return _1; }
public void set1(String _1) { this._1 = _1; }
// ...
public String get20() { return _20; }
public void set20(String _20) { this._20 = _20; }
}
And by using Data data = new Gson().fromJson(myJsonString, Data.class); on the given string, you'd be able to find "Annie" by calling... uh... data.get1()?
Clearly, this isn't a good solution.
Better Solutions
Since your data doesn't follow the typical format for a JSON object, you have two options:
If you can, refactor your JSON representation to a more verbose, but better representation for parsing.
Use a different approach to parse the existing JSON.
Solution 1: Changing the JSON representation
Refactoring the JSON would result in an object that (preferably) would look like this:
{
"champions" : [
{
"index" : 1,
"name" : "Annie"
},
{
"index" : 2,
"name" : "Olaf"
},
// ...
]
}
This could map easily to a couple of beans that look like this:
class Data {
private List<Champion> champions;
// TODO getters and setters
}
class Champion {
private int index;
private String name;
// TODO getters and setters
}
However, this adds a lot of unnecessary clutter to the JSON object, and isn't really necessary with only two fields per champion (the name, and their index).
You could simplify that further like so:
{
"champions" : [
"Annie",
"Olaf",
// ...
]
}
The bean class for that would then be:
class Data {
private List<String> champions;
// TODO getters and setters
}
Much simpler, but still requires a change to the JSON you're getting, which in some situations isn't possible. If you used this, though, you could also get rid of the "bean" class entirely, via:
List<String> champions = (List<String>) new Gson().fromJson(myJsonString, new TypeToken<List<String>>(){}.getType());
Solution 2: Changing how the JSON is parsed
The arguably better and cleaner solution is just to change how the JSON is parsed.
The goal here (if I understand you correctly) is to parse the JSON and spit out a collection of strings representing each champion's name, accessible by the numeric index of the champion in the JSON representation.
As such, and because of the way the JSON object is laid out as a simple mapping of strings to strings, we can use Gson to pipe directly into a Map<String, Object>, like so:
Map<String, String> mappedValues = new Gson().fromJson(myJsonString, Map.class);
String anniesName = mappedValues.get("1"); // "Annie"
String olafsName = mappedValues.get("2"); // "Olaf"
boolean hasTwentyOneElements = mappedValues.containsKey("21"); // false
This is shorter, requires no "bean" classes, and keeps the original JSON representation. The downside is that you can't easily tell whether the indices of each entry are correct and consistent; ie. if someone types in the wrong number, or deletes one of the entries.
To get a container of all keys, you just use mappedValues.keySet(), and to get a container of all key-value pairs, you use mappedValues.entrySet(), which gives you a Set<Map.Entry<String, String>>. Both of those can be iterated over, and may be in random order (I'm not sure whether the underlying Map implementation preserves insertion order or not).
To get the index for a given name (ie. champ), you'd use something similar to the following:
String index = null;
for (Map.Entry<String, String> entry : mappedValues.entrySet()) {
if (champ.equals(entry.getValue())) {
index = entry.getKey();
break;
}
}
Of course, you'd have to check to see if index is null after this, and handle that appropriately, but it's easily doable.
EDIT: #vempo's answer provides a cleaner, more efficient lookup strategy by means of inverting the map (although the answer is written for Jackson, instead of Gson); an adaptation of this for Gson is as follows (and yes, there is a vastly superior version in java-8, left out for sake of availability):
public Map<String, String> invertMap(Map<String, String> input) {
Map<String, String> newMap = new LinkedTreeMap<String, String>(); // TODO Pick optimal storage class
for (Map.Entry<String, String> entry : input.entrySet()) {
newMap.put(entry.getValue(), entry.getKey());
}
return newMap;
}
// ...
Map<String, String> mappedValues = invertMap(new Gson().fromJson(myJsonString, Map.class));
String annieIndex = mappedValues.get("Annie"); // "1"
String olafIndex = mappedValues.get("Olaf"); // "2"
It's worth noting that this sacrifices efficiency of constructing the map by effectively building it twice (once by Gson and once more to invert), but it makes value lookup much more efficient.
I have JSON data in the following format.
[{
"id": 16966,
"post": "This is about road!",
"category": "road",
},
.
.
.]
I want to group JSON entries according to their categories. So, I will get all road related entries in one datastructure, (say list). I know that I can put the data into Mongo DB or even a relational database and do querying. Without doing that, is there some easy method to do this?
If you gonna read the entire JSON file, an easy way is to first read all the entries into a List<Data> and then group them in a Map<String, List<Data>>.
class Data {
private int id;
private String post;
private String category;
//getter, equals, hashcode, toString, etc.
}
and then:
public class Test {
public static void main(String args[] ) throws Exception {
Gson gson = new Gson();
List<Data> list = gson.fromJson(new BufferedReader(new FileReader("myJson.json")), new TypeToken<List<Data>>(){}.getType());
Map<String, List<Data>> groupedMap = list.stream().collect(Collectors.groupingBy(Data::getCategory));
groupedMap.forEach((k, v) -> System.out.println(k + " => " + v));
}
}
which outputs:
road => [Data [id=16966, post=This is about road!, category=road], Data [id=16965, post=This is about road!, category=road]]
land => [Data [id=16961, post=This is about land!, category=land]]
I added some entries to the file. I guess you could write your own deserializer too to get rid of the step when you have a temporary list and store directly in the map, but you asked for an easy way :-). Also note that I'm using java-8 and Gson, but you can also achieve this without it (but you'll write more code).
Take a look on JXPath. This library allows running XPath queries on collections of java objects. So, you can map JSON to your java model using one of popular JSON parser (e.g. Jackson or Gson) and then JXPath to run XPath queries on your collection.
For more information refer here: http://commons.apache.org/proper/commons-jxpath/
How can i sort Nested JSON Array? Like for a JSON below...
{
"id":"rtmc05.lax.someabc.net",
"name":"rtmc05.lax.someabc.net",
"tenants":[{
"id":"rtmc",
"name":"rtmc"
},{
"id":"hrs",
"name":"hrs"
},{
"id":"amotelbe1",
"name":"amotelbe"
},{
"id":"cds",
"name":"cds"
},{
"id":"idx-server",
"name":"idx-server",
"tenants":[{
"id":"amotelbe",
"name":"amotelbe",
"tenants":[{
"id":"amotelui",
"name":"amotelui"
}]
}]
}]
}
There's a few parts implicit to your question, and it's not clear where you're having trouble:
How do you take a JSON string and make usable Java objects out of it. (I'm assuming Java, not JavaScript, since you've tagged your question with "java".)
How do you sort those objects after they're made?
How do you handle sorting the nested parts? (In your example, "idx-server" has sub-tenants.)
Not sure exactly which parts of this you're having trouble with, so here's some notes for all three.
Part 1: Getting Java objects
I agree with the other guy that Jackson is a good JSON parser to use. Here's a couple lines of code you could use to parse some JSON:
String jsonString = "..."; // Load this in whatever way makes sense for you
ObjectMapper mapper = new ObjectMapper();
Map<String,Object> parsedJson = mapper.readValue(jsonString, Map.class);
If your JSON string is really huge, then there are other readValue overloads that you can use to avoid reading the whole String into memory.
Part 2: Sorting Java objects
Once you've got the parsed JSON, sorting is just a matter of calling Collections.sort(...), passing in the tenants array. Plus you'll need to write a Comparator that defines the ordering that you want. For example, here's a comparator that sorts by name:
public class NameComparator implements Comparator<Map<String,Object>> {
public int compare(Map<String,Object> o1, Map<String,Object> o2) {
String name1 = (String) o1.get("name");
String name2 = (String) o2.get("name");
return name1.compareTo(name2);
}
}
Then you get the tenants array out (Jackson makes them into ArrayList objects) and call Collections.sort(...). For example,
List<Map<String,Object>> tenants =
(List<Map<String,Object>>) parsedJson.get("tenants");
Collections.sort(tenants, new NameComparator());
Part 3: Handling the nesting
The clearest way to do this is to add some extra code to walk through your JSON looking for any object with a tenants array, and sort it. For example, here's a recursive function that should do it:
public static void recursiveSortTenants(Map<String,Object> jsonObject) {
List<Map<String,Object>> tenants =
(List<Map<String,Object>>) jsonObject.get("tenants");
if (tenants != null) {
Collections.sort(tenants, new NameComparator());
// For each tenant, see if it has sub-tenants. If so,
// call this function again to sort them.
for (Map<String,Object> tenant : tenants) {
if (tenants.containsKey("tenants")) {
recursiveSortTenants(tenant);
}
}
}
}
Hope this helps!
Parse it into (javascript) objects then write a sort function that sorts an array of such javascript objects.
Deserialize it to POJOs(with Gson or Jackson), and write a Comparator for that POJOs.