Develop Reference

how to write code (when pressing enter enter it will show the next) java [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 3 years ago.
Improve this question
Code I wrote is below -
public class Demo{
public static void main(String[] args){
System.out.print(“Hearing in the distance”);
System.out.print(“Two mandolins like creatures in the “);
System.out.print(“dark”);
System.out.print(“Creating the agony of ecstacy.”);
System.out.println(“ - George Barker”);
}
}
I want to show each print one by one after each enter button pressed.
`

use java.util.Scanner
if you call Scanner.nextLine() your app waits until you write something and press enter or you can press enter without writing anything.

You can do like this below - after every enter button press it will print next value of course you can edit the code accordingly
private static void printNext(){
Scanner scanner = new Scanner(System.in);
int count = 3;
while(count> 0) {
if(count == 1){
System.out.println("Hearing in the distance");
}else if(count ==2 ){
System.out.println("Two mandolins like creatures in the");
}else {
System.out.println("Creating the agony of ecstacy.");
}
count--;
if (scanner.hasNextLine()) {
scanner.nextLine();
}
}
}
Hope this will help you.

How to iterate a for loop for a user input amount of times Java [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 4 years ago.
Improve this question
I want to get a user input number to print out "Color 1 Color 2..." etc. depending on what number the input is.
I want to do this but in java, and I'm not quite sure where to find it.
How to iterate a for loop for a user input in Java?

That will do the work, using only standard java classes (java.io.Console):
import java.io.Console;
public class Consoler {
public static void main(String[] args) {
final Console console = System.console();
console.printf("How may times?\n");
final String line = console.readLine();
try {
final int quantity = Integer.parseInt(line);
for (int i = 1; i <= quantity; i++) {
System.out.printf("Color %d ",i);
}
System.out.println();
} catch (final NumberFormatException e) {
System.err.println(line + " is not a number.");
}
}
}

java.util.Scanner is probably what you're looking for. As for the for loop, you should google Java for loop and read up on how they work. Then combine the two concepts.

I want to print an Array ...Was Just checking for sorting but not able to print too? [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
import java.util.*;
class Sort {
public static void main(String..s) {
int a[]=new a[5];
Scanner sc=new Scanner(System.in);
System.out.println("Enter 5 Numbers");
for(int i=0;i<5;i++) {
a[i]=sc.nextInt();
}
for(int i=0;i<5;i++) {
System.out.println("Before Sorting"+ a[i]);
}
}
}

Please change
int a[]=new a[5];
to
int a[]=new int[5];
Also change String..s to String s[]
Please comment for further help.

Try these utility functions:
java.util.Arrays.sort(...): Sorts the specified array
java.util.Arrays.toString(...): Returns a nicely formatted string representation of the array. Don't forget to print it out :-)

the result of using modulo in my java code is not correct why? [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 8 years ago.
Improve this question
this is my code, when I enter 25000 the result being (25000=1,5000=1) while it must be only 25000=1, but if I enter 50,000 the result correct 50,000=2 but only for 25000 is wrong I don't know why it is
import java.util.Scanner;
class Mawa{
public static void main(String[]a){
int bestwpenj,da,penj,num;
Scanner input=new Scanner(System.in);
System.out.println("enter a number");
System.out.println();
num=input.nextInt();
bestwpenj=num/25000;
da=(num%25000)/10000;
penj=(num%10000)/5000;
System.out.println("25000= "+bestwpenj+"\n"+"10000= "+da+"\n"+"5000= "+penj);
}}
thanks for helping.

You mean like this?
import java.util.Scanner;
class Mawa{
public static void main(String[]a){
int bestwpenj,da,penj,num;
Scanner input=new Scanner(System.in);
System.out.println("enter a number");
System.out.println();
num=input.nextInt();
bestwpenj=num/25000;
da=(num%25000)/10000;
penj=(num%25000%10000)/5000;
System.out.println("25000= "+bestwpenj+"\n"+"10000= "+da+"\n"+"5000= "+penj);
}}

how and where to use standard input flush in java? [closed]

Closed. This question needs details or clarity. It is not currently accepting answers.
Want to improve this question? Add details and clarify the problem by editing this post.
Closed 9 years ago.
Improve this question
import java.io.IOException;
import java.util.Scanner;
public class fflush{
public static void main(String [] args) throws IOException{
Scanner input=new Scanner(System.in);
int a;
System.out.print("Enter an integer:");
a = input.nextInt();
String b,c;
System.out.print("Enter a string:");
b = input.nextLine();
System.out.print("Enter another string:");
c = input.nextLine();
}
}
//result is//
Enter an integer:4
Enter a string:Enter a nother string:

You only "flush" the output in Java.
I suspect you mean, when to discard the rest of the line. To do this you can call
input.nextLine();
You need to do this after nextInt() as you expect to be reading from the next line.