Change JDK Home on Netbeans 8.2 - java

Recently I copied Netbeans 8.2 to new computer and unfortunately the java path are different from previous. My machine running on Windows 10 x64. And when I running netbeans64.exe on bin folder than two popups appear
cannot locate java installation in specified jdkhome:C:\Users\root\Workspace\root\idk\java\jdk\1.8\bin\
After that, I choose to use default version, than another popup appear
cannot find java 1.8 or higher
I've follow instruction to change on /etc/netbeans.conf as below
netbeans_jdkhome="C:\Users\root\Workspace\root\idk\java\jdk\1.8\bin\"
But it doesn't works. I can assuring you that inside the folder contains java.exe which is version 1.8
java version "1.8.0_152"
Java(TM) SE Runtime Environment (build 1.8.0_152-b16)
Java HotSpot(TM) 64-Bit Server VM (build 25.152-b16, mixed mode)
I had registered that path above on System Environment Variables
I have tried to use parameter --jdkhome but still got the same result.
What wrong with my Netbeans? Any other suggestion?
Thanks

jdkhome should point to the root of the JDK folder, not the bin folder inside it.
So it should be:
netbeans_jdkhome="C:\Users\root\Workspace\root\idk\java\jdk\1.8\"
or
--jdkhome C:\Users\root\Workspace\root\idk\java\jdk\1.8

Related

I can see java 11 when I am checking version through command prompt but why it's showing java 17 when I am checking version in Eclipse

its showing below details while checking 'java -version' in CMD
java version "11.0.15" 2022-04-19 LTS
Java(TM) SE Runtime Environment 18.9 (build 11.0.15+8-LTS-149)
Java HotSpot(TM) 64-Bit Server VM 18.9 (build 11.0.15+8-LTS-149, mixed mode)
I am getting below response in Eclipse while using 'System.getProperty("java.version")'
Java Version is: 17.0.2
The CMD uses the PATH environment variable to search for executables (java.exe). The executable is searched in the directories listed in that variable, in the given order. The first one found, is the one that is executed.
Eclipse uses its own settings:
the JRE used to start Eclipse can be specified in the eclipse.ini file; if not specified there, the OS default will be used (usually the same as the CMD, see above);
the JRE used to execute an application inside Eclipse, is specified by the Run/Debug configurations (Run-Run Configurations.../Run-Debug Configurations...), the respective project properties (Project-Properties) and Eclipse preferences (Window-Preferences-Java-Installed JREs).
When I chose "Use Default Workspace JRE" inside Java Build Path->JRE System Library it is showing Java 11.0.15 in eclipse

How to use the latest Java SE version?

I had Java SE (version 8) installed on my computer (Windows 10). Now, I have downloaded version 13. I have also added the path
C:\Program Files\Java\jdk-13.0.1\bin
in Environment Variables -> System Variables -> Path
But still when I write
java -version
on cmd, I get the path of the older version.
java version "1.8.0_231"
Java(TM) SE Runtime Environment (build 1.8.0_231-b11)
Java HotSpot(TM) 64-Bit Server VM (build 25.231-b11, mixed mode)
Upon writing
where java
I got the following result
C:\Program Files (x86)\Common Files\Oracle\Java\javapath\java.exe
C:\ProgramData\Oracle\Java\javapath\java.exe
C:\Program Files\Java\jdk-13.0.1\bin\java.exe
In the environment variables ->
I get the following relevant paths:
C:\ProgramData\Oracle\Java\javapath
C:\Program Files\Java\jdk-13.0.1\bin
Note: doesn't have the path of Java 8 as I deleted it.
Interestingly, I am still able to run the Java code.
I am confused now..
Move C:\Program Files\Java\jdk-13.0.1\bin to the top in the list of environment variables. Then, open a new command prompt and execute java -version.
If you don’t explicitly add the directory to your PATH environment variable, you get the java binary installed at system level.
This was typically done by the browser java plugin installer, which is not used anymore so you get to keep the old version. I would suggest uninstalling it.

JDK not found on Debian 8.5

I want to make a python-android-app using this software. I have installed java JDK, when i run java -version i get:
java version "1.8.0_91"
Java(TM) SE Runtime Environment (build 1.8.0_91-b14)
Java HotSpot(TM) 64-Bit Server VM (build 25.91-b14, mixed mode)
However running the line python android.py installsdk from witin rapt directory (as described in the tutorial) tells me that i have no JDK:
I'm compiling a short test program, to see if you have a working JDK
on your system.
I was unable to use javac to compile a test file. If you haven't
installed the Java Development Kit yet, please download it from:
http://www.oracle.com/technetwork/java/javase/downloads/index.html
The JDK is different from the JRE, so it's possible you have Java
without having the JDK. Without a working JDK, I can't continue.
You need to set your jdk to be accesible, and within path / java home :)
Here help from google:
To set JAVA_HOME environment variable, do the following: Launch
Terminal by pressing Ctrl + Alt + T on your keyboard. Depending on
where you installed your Java, you will need to provide the full path.
For this example, I installed Oracle JDK 7 in the
/usr/lib/jvm/java-7-oracle directory.Aug 13, 2012

How to specify a version of JDK on windows7?

The thing is i have jdk1.6.0_45, jdk1.7.0_09 installed on my computer.
Normally i use JDK7 as my work environment with following system variable setting:
JAVA_HOME=C:\Program Files\Java\jdk1.7.0_09;
classpath=%JAVA_HOME%\lib\dt.jar;%JAVA_HOME%\lib\tools.jar;
path=%JAVA_HOME%\bin;
And when i execute java -version in cmd, it displays the version correctly:
java version "1.7.0_09"
Java(TM) SE Runtime Environment (build 1.7.0_09-b05)
Java HotSpot(TM) 64-Bit Server VM (build 23.5-b02, mixed mode)
Here i encounter a problem, i need to switch to JDK6 for another project. So i changed system variable JAVA_HOME to C:\Program Files\Java\jdk1.6.0_45, i supposed that it should works for the new setting. But actually not, when i executed java -version, it still shows the currently using jdk is 1.7.0_09.
Is this alright?
Finally i found what the problem is.
There is a java.exe(which is jdk7) under system32 folder.
The full path system variable is path=C:\Windows\system32;%JAVA_HOME%\bin;. Which means the unexpected java7 will always be the selected version on my computer even i have specified another version(like jdk6). It might came along with some browser plugin/applet. When i removed this java.exe, everything goes fine.

How do I set the default Java installation/runtime (Windows)?

I'm in the situation where I've installed the JDK, but I can't run applets in browsers (I may not have installed the JRE).
However, when I install the JRE, it clobbers my JDK as the default runtime. This breaks pretty much everything (Eclipse, Ant) - as they require a server JVM.
There's no JAVA_HOME environment variable these days - it just seems to use some registry magic (setting the system path is of no use either). Previously, I've just uninstalled the JRE after I've used it to restore the JDK. This time I want to fix it properly.
This also manifests itself with the jre autoupdater - once upon a time, I had a working setup with the JDK and JRE, but it updated and bust everything.
This is a bit of a pain on Windows. Here's what I do.
Install latest Sun JDK, e.g. 6u11, in path like c:\install\jdk\sun\6u11, then let the installer install public JRE in the default place (c:\program files\blah). This will setup your default JRE for the majority of things.
Install older JDKs as necessary, like 5u18 in c:\install\jdk\sun\5u18, but don't install the public JREs.
When in development, I have a little batch file that I use to setup a command prompt for each JDK version. Essentially just set JAVA_HOME=c:\jdk\sun\JDK_DESIRED and then set PATH=%JAVA_HOME%\bin;%PATH%. This will put the desired JDK first in the path and any secondary tools like Ant or Maven can use the JAVA_HOME variable.
The path is important because most public JRE installs put a linked executable at c:\WINDOWS\System32\java.exe, which usually overrides most other settings.
I have patched the behaviour of my eclipse startup shortcut in the properties dialogue
from
"E:\Program Files\eclipse\eclipse.exe"
to
"E:\Program Files\eclipse\eclipse.exe" -vm "E:\Program Files\Java\jdk1.6.0_30\bin"
as described in the Eclipse documentation
It is a patch only, as it depends on the shortcut to fix things...
The alternative is to set the parameter permanently in the eclipse initialisation file.
I just had that problem (Java 1.8 vs. Java 9 on Windows 7) and my findings are:
short version
default seems to be (because of Path entry)
c:\ProgramData\Oracle\Java\javapath\java -version
select the version you want (test, use tab completing in cmd, not sure what those numbers represent), I had 2 options, see longer version for details
c:\ProgramData\Oracle\Java\javapath_target_[tab]
remove junction/link and link to your version (the one ending with 181743567 in my case for Java 8)
rmdir javapath
mklink /D javapath javapath_target_181743567
longer version:
Reinstall Java 1.8 after Java 9 didn't work. The sequence of installations was jdk1.8.0_74, jdk-9.0.4 and attempt to make Java 8 default with jdk1.8.0_162...
After jdk1.8.0_162 installation I still have
java -version
java version "9.0.4"
Java(TM) SE Runtime Environment (build 9.0.4+11)
Java HotSpot(TM) 64-Bit Server VM (build 9.0.4+11, mixed mode)
What I see in path is
Path=...;C:\ProgramData\Oracle\Java\javapath;...
So I checked what is that and I found it is a junction (link)
c:\ProgramData\Oracle\Java>dir
Volume in drive C is OSDisk
Volume Serial Number is DA2F-C2CC
Directory of c:\ProgramData\Oracle\Java
2018-02-07 17:06 <DIR> .
2018-02-07 17:06 <DIR> ..
2018-02-08 17:08 <DIR> .oracle_jre_usage
2017-08-22 11:04 <DIR> installcache
2018-02-08 17:08 <DIR> installcache_x64
2018-02-07 17:06 <JUNCTION> javapath [C:\ProgramData\Oracle\Java\javapath_target_185258831]
2018-02-07 17:06 <DIR> javapath_target_181743567
2018-02-07 17:06 <DIR> javapath_target_185258831
Those hashes doesn't ring a bell, but when I checked
c:\ProgramData\Oracle\Java\javapath_target_181743567>.\java -version
java version "1.8.0_162"
Java(TM) SE Runtime Environment (build 1.8.0_162-b12)
Java HotSpot(TM) 64-Bit Server VM (build 25.162-b12, mixed mode)
c:\ProgramData\Oracle\Java\javapath_target_185258831>.\java -version
java version "9.0.4"
Java(TM) SE Runtime Environment (build 9.0.4+11)
Java HotSpot(TM) 64-Bit Server VM (build 9.0.4+11, mixed mode)
so to make Java 8 default again I had to delete the link as described here
rmdir javapath
and recreate with Java I wanted
mklink /D javapath javapath_target_181743567
tested:
c:\ProgramData\Oracle\Java>java -version
java version "1.8.0_162"
Java(TM) SE Runtime Environment (build 1.8.0_162-b12)
Java HotSpot(TM) 64-Bit Server VM (build 25.162-b12, mixed mode)
** update (Java 10) **
With Java 10 it is similar, only javapath is in c:\Program Files (x86)\Common Files\Oracle\Java\ which is strange as I installed 64-bit IMHO
.\java -version
java version "10.0.2" 2018-07-17
Java(TM) SE Runtime Environment 18.3 (build 10.0.2+13)
Java HotSpot(TM) 64-Bit Server VM 18.3 (build 10.0.2+13, mixed mode)
After many attempts, I found the junction approach more convenient. This is very similar on how this problem is solved in linux.
Basically it consists of having a link between c:\tools\java\default and the actual version of java you want to use as default in your system.
How to set it:
Download junction and make sure to put it in your PATH
environment variable
Set your environment this way:
- PATH pointing to ONLY to this jre c:\tools\java\default\bin
- JAVA_HOME pointing to `c:\tools\java\default
Store all your jre-s in one folder like (if you do that in your Program FIles folder you may encounter some
C:\tools\Java\JRE_1.6
C:\tools\Java\JRE_1.7
C:\tools\Java\JRE_1.8
Open a command prompt and cd to C:\tools\Java\
Execute junction default JRE_1.6
This will create a junction (which is more or less like a symbolic link in linux) between C:\tools\java\default and C:\tools\java\JRE_1.6
In this way you will always have your default java in c:\tools\java\default.
If you then need to change your default java to the 1.8 version you just need to execute
junction -d default
junction default JRE_1.8
Then you can have batch files to do that without command prompt like
set_jdk8.bat
set_jdk7.bat
As suggested from #СӏаџԁеМаятіи
EDIT: From windows vista, you can use mklink /J default JRE_1.8
I simply install all the versions of JDK I need and the latest installed becomes default, so I just reinstall the one I want to be default if necessary.
I have several JDK (1.4, 1.5, 1.6) installed in C:\Java with their JREs. Then I let Sun update the public JRE in C:\Program Files\Java.
Lately there is an improvement, installing in jre6. Previously, there was a different folder per new version (1.5.0_4, 1.5.0_5, etc.), which was taking lot of space
an alterable way to run an .jar app is create an .bat cmd for it.
for example, you have jre10 and jre8 installed on your pc,and jre10 is your default jre.
but your jar is specified to work with jre8,following cmd will work:
"C:\Program Files\Java\jre1.8.0_181\bin\java.exe" -jar JabRef-4.3.1.jar
Need to remove C:\Program Files (x86)\Common Files\Oracle\Java\javapath from environment and replace by JAVA_HOME which is works fine for me
Stacked by this issue and have resolved it in 2020, in Windows 10. I'm using Java 8 RE and 14.1 JDK and it worked well until Eclipse upgrade to version 2020-09. After that I can't run Eclipse because it needed to use Java 11 or newer and it found only 8 version. It was because of order of environment variables of "Path":
I suppose C:\Program Files (x86)\Common Files\Oracle\Java\javapath is path to link to installed JRE exe files (in my case Java 8) and the issue was resolved by move down this link after %JAVA_HOME%, what leads to Java 14.1/bin folder.
It seems that order of environment variables affects order of searched folders while executable file is requested.
Thanks for your comment or better explanation.

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