I have been struggling to find the matched string(s) with Java Regular expression for the syntax {//<some string>/<some String>}
My regular expression should return with these matched cases: {//data/process_id}
Below is the String which i want to find matched syntax:
#process_id={//data/process_id}##history_id={//data/history_id}##Pdataxml={//data/dataxml}##Prules =_UNESCAPEXMLVALUE({//data/rules})##submitted_by={//data/submitted_by}##table_definition={//data/table_definition}
I have tried with below regx pattern but it did not work:
[a-zA-Z_/\\[\\]\\(\\)0-9|]+
Can someone please help me to solve this issue?
You can use the following regex:
\{\/\/[^\/{}\s]*\/[^\/{}\s]*\}
Demo on regex101
code:
String input = "#process_id={//data/process_id}##history_id={//data/history_id}##Pdataxml={//data/dataxml}##Prules =_UNESCAPEXMLVALUE({//data/rules})##submitted_by={//data/submitted_by}##table_definition={//data/table_definition}";
List<String> allMatches = new ArrayList<String>();
Matcher m = Pattern.compile("\\{\\/\\/[^\\/{}\\s]*\\/[^\\/{}\\s]*\\}").matcher(input);
while (m.find()) {
allMatches.add(m.group());
}
System.out.println(allMatches);
output:
[{//data/process_id}, {//data/history_id}, {//data/dataxml}, {//data/rules}, {//data/submitted_by}, {//data/table_definition}]
Try this regex with a Matcher:
"\\{//([^/]+)/([^/}]+)}"
The parts are captured in groups 1 and 2.
Like this:
Matcher m = Pattern.compile("\\{//([^/]+)/([^/}]+)}").matcher(str);
while (m.find()) {
String part1 = m.group(1);
String part2 = m.group(2);
// do something with the parts
}
To just grab the whole thing, which would be got from m.group(), use this regex:
"(?<=\\{)//[^/]+/[^/}]+(?=})"
Related
String str = "POLYGON((39.4189453125 37.418708616699824,42.0556640625 37.418708616699824,43.4619140625 34.79181436843146,38.84765625 33.84817790215085,39.4189453125 37.418708616699824))";
I have tried to get only 39.4189453125 37.418708616699824,42.0556640625 37.418708616699824,43.4619140625 34.79181436843146,38.84765625 33.84817790215085,39.4189453125 37.418708616699824
with
final String coordsOnly = str.replaceAll("\\D\\(\\(\\w\\)\\)", "$2");
but i get coordsOnly = "POLYGON((39.4189453125 37.418708616699824,42.0556640625 37.418708616699824,43.4619140625 34.79181436843146,38.84765625 33.84817790215085,39.4189453125 37.418708616699824))"
what am i missing?
One reasonable approach here would be to match the following pattern and then replace all with the first capture group:
POLYGON\(\((.*?)\)\)
Sample code:
final String coordsOnly = str.replaceAll("POLYGON\\(\\((.*?)\\)\\)", "$1");
Demo
Edit:
If you also need to isolate the pairs of numbers, you can just use String#split() on comma. Actually, this looks like output from a database query, and I suspect that the database may offer a better way of getting out the individual values. But the answers given here are an option for you in case you can't get the exact output you need already.
Actually, a lot.
"\\D" // Matches a non-digit character, but it only matches one,
// while you need to match a word "POLYGON";
"\\(\\(" // Good. Matches the double left parentheses ((
"\\w" // One word character? Same issue, you need to match multiple chars. And what about '.'?
"\\)\\)" // Good. Matches the double right parentheses ))
And escaped () doesn't create matching groups; and \\w matches only one word character [a-zA-Z_0-9], it even won't match ..
I believe you should try something like this:
String coords = str.replaceAll("POLYGON\\(\\(([^)]+)\\)\\)", "$1");
Maybe this is what you want?:
String rex = "[+-]?([0-9]*[.])?[0-9]+";
Pattern p = Pattern.compile(rex);
String input = "POLYGON((39.4189453125 37.418708616699824,42.0556640625 37.418708616699824,43.4619140625 34.79181436843146,38.84765625 33.84817790215085,39.4189453125 37.418708616699824))";
Matcher matcher = p.matcher(input);
while(matcher.find()) {
System.out.println(matcher.group());
}
Try this version:
str = str.replaceAll("[^\\d\\.\\s,]", "");
String str = "POLYGON((39.4189453125 37.418708616699824,42.0556640625 37.418708616699824,43.4619140625 34.79181436843146,38.84765625 33.84817790215085,39.4189453125 37.418708616699824))";
String sp = "(([0-9]+[.])?[0-9]+[,]?\\s*)+";
Pattern p = Pattern.compile(sp);
Matcher matcher = p.matcher(str);
if (matcher.find()) {
System.out.println(matcher.group());
}
output:
39.4189453125 37.418708616699824,42.0556640625 37.418708616699824,43.4619140625 34.79181436843146,38.84765625 33.84817790215085,39.4189453125 37.418708616699824
Another alternative is replace all non-digit, space, dot or comma:
str.replaceAll("[\\D&&\\S&&[^,\\.]]", "")
Output:
39.4189453125 37.418708616699824,42.0556640625 37.418708616699824,43.4619140625 34.79181436843146,38.84765625 33.84817790215085,39.4189453125 37.418708616699824
Hi I am trying to build one regex to extract 4 digit number from given string using java. I tried it in following ways:
String mydata = "get the 0025 data from string";
Pattern pattern = Pattern.compile("^[0-9]+$");
//Pattern pattern = Pattern.compile("^[0-90-90-90-9]+$");
//Pattern pattern = Pattern.compile("^[\\d]+$");
//Pattern pattern = Pattern.compile("^[\\d\\d\\d\\d]+$");
Matcher matcher = pattern.matcher(mydata);
String val = "";
if (matcher.find()) {
System.out.println(matcher.group(1));
val = matcher.group(1);
}
But it's not working properly. How to do this. Need some help. Thank you.
Change you pattern to:
Pattern pattern = Pattern.compile("(\\d{4})");
\d is for a digit and the number in {} is the number of digits you want to have.
If you want to end up with 0025,
String mydata = "get the 0025 data from string";
mydata = mydata.replaceAll("\\D", ""); // Replace all non-digits
Pattern pattern = Pattern.compile("\\b[0-9]+\\b");
This should do it for you.^$ will compare with the whole string.It will match string with only numbers.
Remove the anchors.. put paranthesis if you want them in group 1:
Pattern pattern = Pattern.compile("([0-9]+)"); //"[0-9]{4}" for 4 digit number
And extract out matcher.group(1)
Many better answers, but if you still have to use in the same way.
String mydata = "get the 0025 data from string";
Pattern pattern = Pattern.compile("(?<![-.])\\b[0-9]+\\b(?!\\.[0-9])");
Matcher matcher = pattern.matcher(mydata);
String val = "";
if (matcher.find()) {
System.out.println(matcher.group(0));
val = matcher.group(0);
}
changed matcher.group(1); to matcher.group(0);
You can go with \d{4} or [0-9]{4} but note that by specifying the ^ at the beginning of regex and $ at the end you're limiting yourself to strings that contain only 4 digits.
My recomendation: Learn some regex basics.
Scanner sc=new Scanner(System.in);
HashMap<String,String> a=new HashMap<>();
ArrayList<String> b=new ArrayList<>();
String s=sc.nextLine();
Pattern p=Pattern.compile("\\d{4}");
Matcher m=p.matcher(s);
while(m.find())
{
String x="";
x=x+(m.group(0));
a.put(x,"0");
b.add(x);
}
System.out.println(a.size());
System.out.println(b);
You can find all matched digit patterns and unique patterns (for unique use Set<String> k=b.keySet();)
If you want to match any number of digits then use pattern like the following:
^\D*(\d+)\D*$
And for exactly 4 digits go for
^\D*(\d{4})\D*$
The following returns no matches:
String patternStr = "((19\\d{2}|20\\d{2})-([0-2]\\d{2}|3[0-5]\\d)-(([0-1]\\d|2[0-3])[0-5]\\d[0-5]\\d))";
String fullPath = aFile.getAbsolutePath();
// fullPath should expand to this: "/home/user1/2013-023-135159_abcd_001/File.txt"
Pattern p = Pattern.compile(patternStr);
Matcher m = p.matcher(fullPath);
if (m.matches())
{
System.out.println("Matches found");
}
It should match the date portion, 2013-023-135159. I tested it online and the regex looks OK.
You will need to use:
m.find()
instead of:
m.matches()
As your regex is matching the parts of the input string not fully as expected by m.matches()
RegEx Demo
How could I get the first and the second text in "" from the string?
I could do it with indexOf but this is really boring ((
For example I have a String for parse like: "aaa":"bbbbb"perhapsSomeOtherText
And I d like to get aaa and bbbbb with the help of Regex pattern - this will help me to use it in switch statement and will greatly simplify my app/
If all that you have is colon delimited string just split it:
String str = ...; // colon delimited
String[] parts = str.split(":");
Note, that split() receives regex and compilies it every time. To improve performance of your code you can use Pattern as following:
private static Pattern pColonSplitter = Pattern.compile(":");
// now somewhere in your code:
String[] parts = pColonSplitter.split(str);
If however you want to use pattern for matching and extraction of string fragments in more complicated cases, do it like following:
Pattert p = Patter.compile("(\\w+):(\\w+):");
Matcher m = p.matcher(str);
if (m.find()) {
String a = m.group(1);
String b = m.group(2);
}
Pay attention on brackets that define captured group.
Something like this?
Pattern pattern = Pattern.compile("\"([^\"]*)\"");
Matcher matcher = pattern.matcher("\"aaa\":\"bbbbb\"perhapsSomeOtherText");
while (matcher.find()) {
System.out.println(matcher.group(1));
}
Output
aaa
bbbbb
String str = "\"aaa\":\"bbbbb\"perhapsSomeOtherText";
Pattern p = Pattern.compile("\"\\w+\""); // word between ""
Matcher m = p.matcher(str);
while(m.find()){
System.out.println(m.group().replace("\"", ""));
}
output:
aaa
bbbbb
there are several ways to do this
Use StringTokenizer or Scanner with UseDelimiter method
I want to break a string like :
String s = "xyz213123kop234430099kpf4532";
into tokens where each token starts with an alphabet and ends with a number. So the above string can be broken down into 3 tokens :
xyz213123
kop234430099
kpf4532
This string s could be very big but the pattern will remain the same, i.e each token will start with 3 alphabets and end with a number.
How do I split them ?
Try this:
\w+?\d+
Java Matcher:
Pattern pattern = Pattern.compile("\\w+?\\d+"); //compiles the pattern we want to use
Matcher matcher = pattern.matcher("xyz213123kop234430099kpf4532"); //we create the matcher on certain string using our pattern
while(matcher.find()) //while the matcher can find the next match
{
System.out.println(matcher.group()); //print it
}
And then you could use Regex.Matches C#:
foreach(Match m in Regex.Matches("xyz213123kop234430099kpf4532", #"\w+?\d+"))
{
Console.WriteLine(m.Value);
}
And for the future this:
RegExr
Do it like this,
String s = "xyz213123kop234430099kpf4532";
Pattern p = Pattern.compile("\\w+?\\d+");
Matcher match = p.matcher(s);
while(match.find()){
System.out.println(match.group());
}
OUTPUT
xyz213123
kop234430099
kpf4532
You can start from such regexp: (\w+?\d+)
http://regexr.com?36utt