Develop Reference

Wrong order of data when converting a JTable to JSON [duplicate]

I've a problem trying to make my page printing out the JSONObject in the order i want. In my code, I entered this:
JSONObject myObject = new JSONObject();
myObject.put("userid", "User 1");
myObject.put("amount", "24.23");
myObject.put("success", "NO");
However, when I see the display on my page, it gives:
JSON formatted string: [{"success":"NO", "userid":"User 1", "bid":24.23}]
I need it in the order of userid, amount, then success. Already tried re-ordering in the code, but to no avail. I've also tried .append....need some help here thanks!!

You cannot and should not rely on the ordering of elements within a JSON object.
From the JSON specification at https://www.json.org/
An object is an unordered set of
name/value pairs
As a consequence,
JSON libraries are free to rearrange the order of the elements as they see fit.
This is not a bug.

I agree with the other answers. You cannot rely on the ordering of JSON elements.
However if we need to have an ordered JSON, one solution might be to prepare a LinkedHashMap object with elements and convert it to JSONObject.
#Test
def void testOrdered() {
Map obj = new LinkedHashMap()
obj.put("a", "foo1")
obj.put("b", new Integer(100))
obj.put("c", new Double(1000.21))
obj.put("d", new Boolean(true))
obj.put("e", "foo2")
obj.put("f", "foo3")
obj.put("g", "foo4")
obj.put("h", "foo5")
obj.put("x", null)
JSONObject json = (JSONObject) obj
logger.info("Ordered Json : %s", json.toString())
String expectedJsonString = """{"a":"foo1","b":100,"c":1000.21,"d":true,"e":"foo2","f":"foo3","g":"foo4","h":"foo5"}"""
assertEquals(expectedJsonString, json.toString())
JSONAssert.assertEquals(JSONSerializer.toJSON(expectedJsonString), json)
}
Normally the order is not preserved as below.
#Test
def void testUnordered() {
Map obj = new HashMap()
obj.put("a", "foo1")
obj.put("b", new Integer(100))
obj.put("c", new Double(1000.21))
obj.put("d", new Boolean(true))
obj.put("e", "foo2")
obj.put("f", "foo3")
obj.put("g", "foo4")
obj.put("h", "foo5")
obj.put("x", null)
JSONObject json = (JSONObject) obj
logger.info("Unordered Json : %s", json.toString(3, 3))
String unexpectedJsonString = """{"a":"foo1","b":100,"c":1000.21,"d":true,"e":"foo2","f":"foo3","g":"foo4","h":"foo5"}"""
// string representation of json objects are different
assertFalse(unexpectedJsonString.equals(json.toString()))
// json objects are equal
JSONAssert.assertEquals(JSONSerializer.toJSON(unexpectedJsonString), json)
}
You may check my post too: http://www.flyingtomoon.com/2011/04/preserving-order-in-json.html

u can retain the order, if u use JsonObject that belongs to com.google.gson :D
JsonObject responseObj = new JsonObject();
responseObj.addProperty("userid", "User 1");
responseObj.addProperty("amount", "24.23");
responseObj.addProperty("success", "NO");
Usage of this JsonObject doesn't even bother using Map<>
CHEERS!!!

Real answer can be found in specification, json is unordered.
However as a human reader I ordered my elements in order of importance. Not only is it a more logic way, it happened to be easier to read. Maybe the author of the specification never had to read JSON, I do.. So, Here comes a fix:
/**
* I got really tired of JSON rearranging added properties.
* Specification states:
* "An object is an unordered set of name/value pairs"
* StackOverflow states:
* As a consequence, JSON libraries are free to rearrange the order of the elements as they see fit.
* I state:
* My implementation will freely arrange added properties, IN SEQUENCE ORDER!
* Why did I do it? Cause of readability of created JSON document!
*/
private static class OrderedJSONObjectFactory {
private static Logger log = Logger.getLogger(OrderedJSONObjectFactory.class.getName());
private static boolean setupDone = false;
private static Field JSONObjectMapField = null;
private static void setupFieldAccessor() {
if( !setupDone ) {
setupDone = true;
try {
JSONObjectMapField = JSONObject.class.getDeclaredField("map");
JSONObjectMapField.setAccessible(true);
} catch (NoSuchFieldException ignored) {
log.warning("JSONObject implementation has changed, returning unmodified instance");
}
}
}
private static JSONObject create() {
setupFieldAccessor();
JSONObject result = new JSONObject();
try {
if (JSONObjectMapField != null) {
JSONObjectMapField.set(result, new LinkedHashMap<>());
}
}catch (IllegalAccessException ignored) {}
return result;
}
}

from lemiorhan example
i can solve with just change some line of lemiorhan's code
use:
JSONObject json = new JSONObject(obj);
instead of this:
JSONObject json = (JSONObject) obj
so in my test code is :
Map item_sub2 = new LinkedHashMap();
item_sub2.put("name", "flare");
item_sub2.put("val1", "val1");
item_sub2.put("val2", "val2");
item_sub2.put("size",102);
JSONArray itemarray2 = new JSONArray();
itemarray2.add(item_sub2);
itemarray2.add(item_sub2);//just for test
itemarray2.add(item_sub2);//just for test
Map item_sub1 = new LinkedHashMap();
item_sub1.put("name", "flare");
item_sub1.put("val1", "val1");
item_sub1.put("val2", "val2");
item_sub1.put("children",itemarray2);
JSONArray itemarray = new JSONArray();
itemarray.add(item_sub1);
itemarray.add(item_sub1);//just for test
itemarray.add(item_sub1);//just for test
Map item_root = new LinkedHashMap();
item_root.put("name", "flare");
item_root.put("children",itemarray);
JSONObject json = new JSONObject(item_root);
System.out.println(json.toJSONString());

JavaScript objects, and JSON, have no way to set the order for the keys. You might get it right in Java (I don't know how Java objects work, really) but if it's going to a web client or another consumer of the JSON, there is no guarantee as to the order of keys.

Download "json simple 1.1 jar" from this https://code.google.com/p/json-simple/downloads/detail?name=json_simple-1.1.jar&can=2&q=
And add the jar file to your lib folder
using JSONValue you can convert LinkedHashMap to json string

For those who're using maven, please try com.github.tsohr/json
<!-- https://mvnrepository.com/artifact/com.github.tsohr/json -->
<dependency>
<groupId>com.github.tsohr</groupId>
<artifactId>json</artifactId>
<version>0.0.1</version>
</dependency>
It's forked from JSON-java but switch its map implementation with LinkedHashMap which #lemiorhan noted above.

As all are telling you, JSON does not maintain "sequence" but array does, maybe this could convince you:
Ordered JSONObject

For Java code, Create a POJO class for your object instead of a JSONObject.
and use JSONEncapsulator for your POJO class.
that way order of elements depends on the order of getter setters in your POJO class.
for eg. POJO class will be like
Class myObj{
String userID;
String amount;
String success;
// getter setters in any order that you want
and where you need to send your json object in response
JSONContentEncapsulator<myObj> JSONObject = new JSONEncapsulator<myObj>("myObject");
JSONObject.setObject(myObj);
return Response.status(Status.OK).entity(JSONObject).build();
The response of this line will be
{myObject : {//attributes order same as getter setter order.}}

The main intention here is to send an ordered JSON object as response. We don't need javax.json.JsonObject to achieve that. We could create the ordered json as a string.
First create a LinkedHashMap with all key value pairs in required order. Then generate the json in string as shown below.
Its much easier with Java 8.
public Response getJSONResponse() {
Map<String, String> linkedHashMap = new LinkedHashMap<>();
linkedHashMap.put("A", "1");
linkedHashMap.put("B", "2");
linkedHashMap.put("C", "3");
String jsonStr = linkedHashMap.entrySet().stream()
.map(x -> "\"" + x.getKey() + "\":\"" + x.getValue() + "\"")
.collect(Collectors.joining(",", "{", "}"));
return Response.ok(jsonStr).build();
}
The response return by this function would be following:
{"A":"1","B":"2","C":"3"}

Underscore-java uses linkedhashmap to store key/value for json. I am the maintainer of the project.
Map<String, Object> myObject = new LinkedHashMap<>();
myObject.put("userid", "User 1");
myObject.put("amount", "24.23");
myObject.put("success", "NO");
System.out.println(U.toJson(myObject));

I found a "neat" reflection tweak on "the interwebs" that I like to share.
(origin: https://towardsdatascience.com/create-an-ordered-jsonobject-in-java-fb9629247d76)
It is about to change underlying collection in org.json.JSONObject to an un-ordering one (LinkedHashMap) by reflection API.
I tested succesfully:
import java.lang.reflect.Field;
import java.util.LinkedHashMap;
import org.json.JSONObject;
private static void makeJSONObjLinear(JSONObject jsonObject) {
try {
Field changeMap = jsonObject.getClass().getDeclaredField("map");
changeMap.setAccessible(true);
changeMap.set(jsonObject, new LinkedHashMap<>());
changeMap.setAccessible(false);
} catch (IllegalAccessException | NoSuchFieldException e) {
e.printStackTrace();
}
}
[...]
JSONObject requestBody = new JSONObject();
makeJSONObjLinear(requestBody);
requestBody.put("username", login);
requestBody.put("password", password);
[...]
// returned '{"username": "billy_778", "password": "********"}' == unordered
// instead of '{"password": "********", "username": "billy_778"}' == ordered (by key)

Just add the order with this tag
#JsonPropertyOrder({ "property1", "property2"})

Not sure if I am late to the party but I found this nice example that overrides the JSONObject constructor and makes sure that the JSON data are output in the same way as they are added. Behind the scenes JSONObject uses the MAP and MAP does not guarantee the order hence we need to override it to make sure we are receiving our JSON as per our order.
If you add this to your JSONObject then the resulting JSON would be in the same order as you have created it.
import java.io.IOException;
import java.lang.reflect.Field;
import java.util.LinkedHashMap;
import org.json.JSONObject;
import lombok.extern.java.Log;
#Log
public class JSONOrder {
public static void main(String[] args) throws IOException {
JSONObject jsontest = new JSONObject();
try {
Field changeMap = jsonEvent.getClass().getDeclaredField("map");
changeMap.setAccessible(true);
changeMap.set(jsonEvent, new LinkedHashMap<>());
changeMap.setAccessible(false);
} catch (IllegalAccessException | NoSuchFieldException e) {
log.info(e.getMessage());
}
jsontest.put("one", "I should be first");
jsonEvent.put("two", "I should be second");
jsonEvent.put("third", "I should be third");
System.out.println(jsonEvent);
}
}

Just use LinkedHashMap to keep de order and transform it to json with jackson
import com.fasterxml.jackson.databind.ObjectMapper;
import java.util.LinkedHashMap;
LinkedHashMap<String, Object> obj = new LinkedHashMap<String, Object>();
stats.put("aaa", "aaa");
stats.put("bbb", "bbb");
stats.put("ccc", "ccc");
ObjectMapper mapper = new ObjectMapper();
String json = mapper.writerWithDefaultPrettyPrinter().writeValueAsString(obj);
System.out.println(json);
maven dependency
<dependency>
<groupId>com.fasterxml.jackson.core</groupId>
<artifactId>jackson-databind</artifactId>
<version>2.9.10.7</version>
</dependency>

I just want the order for android unit tests that are somehow randomly changing overtime with this cool org.json.JSONObject, even thou it looks like it uses linked map but probably depends on api you compile it with or something, so it has different impl. with different android api probably.
I would suggest something like this:
object Json {
#SuppressLint("DiscouragedPrivateApi")
fun Object() = org.json.JSONObject().apply {
runCatching {
val nameValuePairs: Field = javaClass.getDeclaredField("nameValuePairs")
nameValuePairs.isAccessible = true
nameValuePairs.set(this, LinkedHashMap<String, Any?>())
}.onFailure { it.printStackTrace() }
}
}
Usage:
val jsonObject = Json.Object()
...
This is just some possibility I use it little differently so I modified it to post here. Sure gson or other lib is another option.
Suggestions that specification is bla bla are so shortsighted here, why you guys even post it, who cares about 15 years old json spec, everyone wants it ordered anyway.

How to convert from Json to Protobuf?

I'm new to using protobuf, and was wondering if there is a simple way to convert a json stream/string to a protobuf stream/string in Java?
For example,
protoString = convertToProto(jsonString)
I have a json string that I want to parse into a protobuf message. So, I want to first convert the json string to protobuf, and then call Message.parseFrom() on it.

With proto3 you can do this using JsonFormat. It parses directly from the JSON representation, so there is no need for separately calling MyMessage.parseFrom(...). Something like this should work:
JsonFormat.parser().merge(json_string, builder);

//You can use this for converting your input json to a Struct / any other Protobuf Class
import com.google.protobuf.Struct.Builder;
import com.google.protobuf.Struct;
import com.google.protobuf.util.JsonFormat;
import org.json.JSONObject;
JSONObject parameters = new JSONObject();
Builder structBuilder = Struct.newBuilder();
JsonFormat.parser().merge(parameters.toString(), structBuilder);
// Now use the structBuilder to pass below (I used it for Dialog Flow V2 Context Management)

Since someone asked about getting the exception "com.google.protobuf.InvalidProtocolBufferException: JsonObject" when following Adam's advice--I ran into the same issue. Turns out it was due to the google protobuf timestamps. They are being serialized as an object containing two fields "seconds" and "nanos", since this isn't production code, I just got around this by parsing the JSON using jackson, going through the JSON object recursively and changing every timestamp from an object to a string formatted as per RFC 3339, I then serialized it back out and used the protobuf JSON parser as Adam has shown. This fixed the issue. This is some throwaway code I wrote (in my case all timestamp fields contain the word "timestamp", this could be more robust, but I don't care):
public Map<String, Object> fixJsonTimestamps(Map<String, Object> inMap) {
Map<String, Object> outMap = new HashMap<>();
for(String key : inMap.keySet()) {
Object val = inMap.get(key);
if(val instanceof Map) {
Map<String, Object> valMap = (Map<String, Object>)val;
if(key.toLowerCase().contains("timestamp") &&
valMap.containsKey("seconds") && valMap.containsKey("nanos")) {
if(valMap.get("seconds") != null) {
ZonedDateTime d = ZonedDateTime.ofInstant(Instant.ofEpochSecond((int)valMap.get("seconds")).plusNanos((int)valMap.get("nanos")),
ZoneId.of("UTC"));
val = d.format(DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'"));
}
} else {
val = fixJsonTimestamps(valMap);
}
} else if(val instanceof List && ((List) val).size() > 0 &&
((List) val).get(0) instanceof Map) {
List<Map<String, Object>> outputList = new ArrayList<>();
for(Map item : (List<Map>)val) {
outputList.add(fixJsonTimestamps(item));
}
val = outputList;
}
outMap.put(key, val);
}
return outMap;
}
Not the most ideal solution but it works for what I am doing, I think I saw someone recommend using a different timestamp class.

You can convert json string to Proto using builder and json String
Example :
YourProto.Builder protoBuilder = YourProto.newBuilder();
JsonFormat.parser().merge(JsonString, protoBuilder);
If you want to ignore unknown json field then
YourProto.Builder protoBuilder = YourProto.newBuilder();
JsonFormat.parser()..ignoringUnknownFields().merge(JsonString, protoBuilder);
Another way is, to use mergeFrom method from ProtocolBuffer
Example :
YourProto.Builder protoBuilder = YourProto.newBuilder();
protoBuilder.mergeFrom(JsonString.getBytes());
Once it execute, you will get all the data in protoBuilder from json String

online service:
https://json-to-proto.github.io/
This tool instantly converts JSON into a Protobuf. Paste a JSON structure on the left and the equivalent Protobuf will be generated to the right, which you can paste into your program. The script has to make some assumptions, so double-check the output!

nameValuePair key added in new JSONObject

When I am building a json object from string it is appended with a root key "nameValuePairs".
String curStr = "{\"e\": \"{}\", \"f\": \"{}\", \"g\": \"{}\"}";
JSONObject oldObj = new JSONObject(curStr);
results to
{"nameValuePairs":{"b":"{}","c":"{}","a":"{}"}}
Why?
Any way to prevent that?
Btw, I am using the string json to represent the actual json which I will use later.

First of all your json is syntactically correct but I guess you wished to represent objects as values, in your case the curly brackets are evaluated as simple strings:
String curStr = "{\"e\": \"{}\", \"f\": \"{}\", \"g\": \"{}\"}";
JSONObject oldObj = new JSONObject(curStr);
using a json like this instead will produce values as objects:
String curStr = "{\"e\": {}, \"f\": {}, \"g\": {}}";
JSONObject oldObj = new JSONObject(curStr);
Anyway, I've tried to create that JSONObject and then print a toString of it, and it will simply print the json, without any accessory name.
As you find out in the comment the problem was given by Gson, that will evaluate the JSONObject as a map. I've tried a little example and I've got "map" as field. Probably I've tried a different version of Gson.
Gson gson = new Gson();
String jsonStr = gson.toJson(oldObj);
result: {"map":{"f":"{}","g":"{}","e":"{}"}}
If you want to create a custom object and deserialize a json with Gson create a class with those properties and use the fromJson(String json, Class clazz) method
public class Test {
private String e;
private String f;
private String g;
}
and
Gson gson = new Gson();
Test myTestObj = gson.fromJson(curStr, Test.class);
Hope this will help you. :)

You can try jsonStringer instead.
Something like below code:
JSONStringer jObject = new JSONStringer()
.object()
.key("UserName").value(userNameValue)
.key("Name").value(nameValue)
.key("EmailId").value(emailIdValue)
.key("CountryId").value(contryIdValue)
.key("CountryName").value("") // It should be blank As Spanish Name is not set if User have App in Spanish
.key("State").value(stateValue)
.key("City").value(cityValue)
.key("ImageByteArray").value(imageBytes)
.endObject();
UPDATE
I have just use your code in my App and check it.
Its showing me the result as we have formed.
Result i am getting is:
{
"f": "{}",
"g": "{}",
"e": "{}"
}
Please check your packages you are importing.
For your reference i am importing below class to represent json object.
import org.json.JSONException;
import org.json.JSONObject;
Just import above class and see the result.
Let me know if you still have any query.

Getting a value from deep inside JSON

I am connecting to a third party API and getting back a long JSON string. I only need one value from it, but it is located pretty deep inside the hierarchy. Is there a simple way to get it, without going through the whole thing? I looked all over but nothing seems easy.
Here's my example:
"response":{"status":1,"httpStatus":200,"data":{"myDesiredInfo":"someInfo"},"errors":[],"errorMessage":null}}
I've been trying to use Gson so I can get this blob as a JsonObject. I was sure there's something simple, like this:
jsonObject.get("myDesiredInfo")
or at the minimum something like this:
jsonObject.get("response.data.myDesiredInfo")
But it doesn't seem to exist.
So is there any parser out there that will allow me to do this?

This is my json string
String s="{"age":0,"name":"name","email":"emailk","address":{"housename":"villa"}}";
I use following code to get housename
JsonElement je = new JsonParser().parse(s);
JsonObject asJsonObject = je.getAsJsonObject();
JsonElement get = asJsonObject.get("address");
System.out.println(s + "\n" + get);
JsonObject asJsonObject1 = get.getAsJsonObject();
JsonElement get1 = asJsonObject1.get("housename");
System.out.println(get1);
The Following is my output :
{"age":0,"name":"name","email":"emailk","address":{"housename":"villa"}}
{"housename":"villa"}
"villa"
I don't think there is another way to do this. I also tried to do in other ways but i didn't get any output.

The following way you can retrieve from your jsonObject.
JSONObject jObject = new JSONObject(yourresponse);
Log.i("Desired Info is ",jObject.getJSONObject("response").getJSONObject("data").getString("myDesiredInfo"));

I wrote a little utility method that uses Gson's API to get a value as String from a JSON object, based on a java.util.List of values. So for my original question the list objects will be "response", "data", "myDesiredInfo."
Surely this can be improved on, but it's a start.
/*
* Takes a JsonObject and parses it for a primitive value, going level by level
* according to the values in #infos
*/
public static String parseJson(JsonObject json, List<String> infos) {
try {
if(infos.size() == 0) {
return json.toString();
}
JsonElement je = json.get((String)infos.get(0));
infos.remove(0);
if(je instanceof JsonObject) {
return parseJson(je.getAsJsonObject(), infos);
} else {
return je.getAsString();
}
} catch (Exception e) {
e.printStackTrace();
return null;
}
}

Most languages have a JSON decoding library, a lot of them native. No idea what language you're using so here's PHP as an example:
$jsonObj = json_decode($json);
$json->response->data->myDesiredInfo;
Ruby, Python, Java - all these languages have good libraries.

How to maintain the order of a JSONObject

I am using a JSONObject in order to remove a certin attribute I don't need in a JSON String:
JSONObject jsonObject = new JSONObject(jsonString);
jsonObject.remove("owner");
jsonString = jsonObject.toString();
It works ok however the problem is that the JSONObject is "an unordered collection of name/value pairs" and I want to maintain the original order the String had before it went through the JSONObject manipulation.
Any idea how to do this?

try this
JSONObject jsonObject = new JSONObject(jsonString) {
/**
* changes the value of JSONObject.map to a LinkedHashMap in order to maintain
* order of keys.
*/
#Override
public JSONObject put(String key, Object value) throws JSONException {
try {
Field map = JSONObject.class.getDeclaredField("map");
map.setAccessible(true);
Object mapValue = map.get(this);
if (!(mapValue instanceof LinkedHashMap)) {
map.set(this, new LinkedHashMap<>());
}
} catch (NoSuchFieldException | IllegalAccessException e) {
throw new RuntimeException(e);
}
return super.put(key, value);
}
};
jsonObject.remove("owner");
jsonString=jsonObject.toString();

You can't.
That is why we call it an unordered collection of name/value pairs.
Why you would need to do this, I'm not sure. But if you want ordering, you'll have to use a json array.

I have faced the same problem recently and just transitioned all our tests (which expect JSON attributes to be in the same order) to another JSON library:
<dependency>
<groupId>org.codehaus.jettison</groupId>
<artifactId>jettison</artifactId>
<version>1.3.5</version>
</dependency>
Internally it uses a LinkedHashMap, which maintains the order of attributes. This library is functionally equivalent to the json.org library, so I don't see any reason why not use it instead, at least for tests.

You can go for the JsonObject provided by the com.google.gson it is nearly the same with the JSONObject by org.json but some different functions.
For converting String to Json object and also maintains the order you can use:
Gson gson = new Gson();
JsonObject jsonObject = gson.fromJson(<Json String>, JsonObject.class);
For eg:-
String jsonString = "your json String";
JsonObject jsonObject = gson.fromJson(jsonString, JsonObject.class);
It just maintains the order of the JsonObject from the String.

If you can edit the server repose then change it to array of JSON objects.
JSON:
[
{PropertyName:"Date of Issue:",PropertyValue:"3/21/2011"},
PropertyName:"Report No:",PropertyValue:"2131196186"},{PropertyName:"Weight:",PropertyValue:"1.00"},
{PropertyName:"Report Type:",PropertyValue:"DG"}
]
And I handled it with JSONArray in client side (Android):
String tempresult="[{PropertyName:"Date of Issue:",PropertyValue:"3/21/2011"},PropertyName:"Report No:",PropertyValue:"2131196186"},PropertyName:"Weight:",PropertyValue:"1.00"},{PropertyName:"Report Type:",PropertyValue:"DG"}]"
JSONArray array = new JSONArray(tempresult);
for (int i = 0; i < array.length(); i++)
{
String key = array.getJSONObject(i).getString("PropertyName");
String value = array.getJSONObject(i).getString("PropertyValue");
rtnObject.put(key.trim(),value.trim()); //rtnObject is LinkedHashMap but can be any other object which can keep order.
}

You can use Jsckson library in case to maintain the order of Json keys.
It internally uses LinkedHashMap ( ordered ).
import com.fasterxml.jackson.core.JsonToken;
import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;
import com.fasterxml.jackson.databind.node.ObjectNode;
The code to remove a field, the removed JsonToken could itself be read if required.
String jsonString = "{\"name\":\"abc\",\"address\":\"add\",\"data\":[\"some 1\",\"some 2\",\"some3 3\"],\"age\":12,\"position\":8810.21}";
ObjectMapper mapper = new ObjectMapper();
JsonNode node = mapper.readTree(jsonString);
System.out.println("In original order:"+node.toString());
JsonToken removedToken = ((ObjectNode) node).remove("address").asToken();
System.out.println("Aft removal order:"+node.toString());
ObjectNode implementation uses a LinkedHashMap, which maintains the insertion order:
public ObjectNode(JsonNodeFactory nc) {
super(nc);
_children = new LinkedHashMap<String, JsonNode>();
}

Go on JSONObject class
Change from HashMap() to LinkedHashMap()
/**
* Construct an empty JSONObject.
*/
public JSONObject() {
this.map = new LinkedHashMap();
}
The LinkedHashMap class extends the Hashmap class. This class uses a doubly linked list containing all the entries of the hashed table, in the order in which the keys were inserted in the table: this allows the keys to be "ordered".

This is not easy, the main idea is to use LinkedHashMap, either pass in to the constructor (JSONObject(Map map)), or modify bytecode to handle the String parameter (JSONObject(String source)), which is the main use case. I got a solution in oson:
public static JSONObject getJSONObject(String source) {
try {
int lineNumberToReplace = 157;
ClassPool classPool = ClassPool.getDefault();
CtClass ctClass = classPool.get("org.json.JSONObject");
if (ctClass.isFrozen() || ctClass.isModified()) {
if (source == null) {
return new JSONObject();
} else {
return new JSONObject(source);
}
}
ctClass.stopPruning(true);
CtConstructor declaredConstructor = ctClass.getDeclaredConstructor(new CtClass[] {});
CodeAttribute codeAttribute = declaredConstructor.getMethodInfo().getCodeAttribute();
LineNumberAttribute lineNumberAttribute = (LineNumberAttribute)codeAttribute.getAttribute(LineNumberAttribute.tag);
// Index in bytecode array where the instruction starts
int startPc = lineNumberAttribute.toStartPc(lineNumberToReplace);
// Index in the bytecode array where the following instruction starts
int endPc = lineNumberAttribute.toStartPc(lineNumberToReplace+1);
// Let's now get the bytecode array
byte[] code = codeAttribute.getCode();
for (int i = startPc; i < endPc; i++) {
// change byte to a no operation code
code[i] = CodeAttribute.NOP;
}
declaredConstructor.insertAt(lineNumberToReplace, true, "$0.map = new java.util.LinkedHashMap();");
ctClass.writeFile();
if (source == null) {
return (JSONObject) ctClass.toClass().getConstructor().newInstance();
} else {
return (JSONObject) ctClass.toClass().getConstructor(String.class).newInstance(source);
}
} catch (Exception e) {
//e.printStackTrace();
}
if (source == null) {
return new JSONObject();
} else {
return new JSONObject(source);
}
}
need to include jar file from using mvn
<dependency>
<groupId>javassist</groupId>
<artifactId>javassist</artifactId>
<version>3.12.1.GA</version>
</dependency>

From Android 20, JSONObject preserves the order as it uses LinkedHashMap to store namevaluepairs. Android 19 and below uses HashMap to store namevaluepairs. So, Android 19 and below doesn't preserve the order. If you are using 20 or above, don't worry, JSONObject will preserve the order. Or else, use JSONArray instead.

In JDK 8 and above, We can do it by using nashorn engine, supported in JDK 8.
Java 8 support to use js engine to evaluate:
String content = ..json content...
String name = "test";
String result = (String) engine.eval("var json = JSON.stringify("+content+");"
+ "var jsResult = JSON.parse(json);"
+ "jsResult.name = \"" + name + "\";"
+ "jsResult.version = \"1.0\";"
+ "JSON.stringify( jsResult );"
);

I was able to do this with help of classpath overriding.
created package package org.json.simple which is same as in jar and class named as JSONObject.
Took existing code from jar and updated the class by extending LinkedHashmap instead of Hashmap
by doing these 2 steps it will maintain the order, because preference of picking `JSONObject will be higher to pick from the new package created in step 1 than the jar.

I accomplished it by doing a:
JSONObject(json).put(key, ObjectMapper().writeValueAsString(ObjectMapper().readValue(string, whatever::class)))
So essentially I deserialize a string to an ordered class, then I serialize it again. But then I also had to format that string afterwards to remove escapes.
.replace("\\\"", "\"").replace("\"{", "{").replace("}\"", "}")
You may also have to replace null items as well if you don't want nulls.