Develop Reference

Objects and getting parents methods

Here is the best way I could summarise my situation:
Class1 makes new Thread(new Class2)
Is there a way from inside objects 2 code I can access non-static public methods from object 1?
Not sure if I have explained myself enough but I can answer any questions that could help describe it better
Edit: To elaborate Class1 is a multithreaded server and Class2 is the WorkerClass and i want to access Class1.stop() to stop the server from inside the workerClass

There are at least 3 ways to do this:
(1) Use an anonymous inner class:
public class Class1 {
public void foo() {}
public void bar() {
Thread t = new Thread(new Runnable() {
#Override
public void run() {
foo();
}
});
}
}
(2) Use a named inner class:
public class Class1 {
public void foo() {}
public void bar() {
Thread t = new Thread(new MyRunnable());
}
private class MyRunnable implements Runnable {
#Override
public void run() {
foo();
}
}
}
(3) Pass this to the constructor of another top-level class:
public class Class1 {
public void foo() {}
public void bar() {
Thread t = new Thread(new MyRunnable(this));
}
}
class MyRunnable implements Runnable {
private Class1 class1;
public MyRunnable(Class1 class1) {
this.class1 = class1;
}
#Override
public void run() {
class1.foo();
}
}

Passing a Runnable object to a class extending Thread class and then starting it prints unexpected result

I heard about an interview question from one of my friend.
What happens when we pass a Runnable object to an object of a class extending Thread class and start the class.
public class A extends Thread {
Runnable obj;
public A(Runnable obj) {
this.obj=obj;
}
public void run() {
System.out.println("Printing A")
}
}
public class B implements Runnable {
public void run() {
System.out.println("Printing B");
}
}
public class MainApp {
public static void main() {
B b = new B();
A a = new A(b);
a.start();
}
}
Now it outputs Printing A
I was expecting Printing B as it is a perfect analogy to
Thread obj = new Thread(Runnable runnableObj)
Can someone please explain me this weird output??

Thread has a run method which essentially calls runnable.run(). Except that in your class A you have overriden that method to do something else.
So runnable.run() is not called any longer...

You are creating an instance of class A (Now it is a Thread).
Then you are calling start() of that Thread using instance a.
You are just passing a Runnable object as a normal instance variable to class A.
There is nothing complicated in that.
The result is normal.

With a tiny adjustment your code runs as expected.
public class A extends Thread {
Runnable obj;
public A(Runnable obj) {
this.obj = obj;
}
public void run() {
System.out.println("Printing A");
obj.run();// <---- I added this.
}
}
public class B implements Runnable {
public void run() {
System.out.println("Printing B");
}
}
public void test() {
B b = new B();
A a = new A(b);
a.start();
}

The problem is that you are overriding the run() method on Thread and never pass the Runnable obj to super(). Try this:
public class A extends Thread {
public A(Runnable obj) {
super(obj);
}
public class B implements Runnable {
public void run() {
System.out.println("Printing B");
}
}
public void test() {
B b = new B();
A a = new A(b);
a.start();
}
}

Passing an argument to a method defined inside a method in Java

So the situation is something like this:
private void myMethod()
{
System.out.println("Hello World"); //some code
System.out.println("Some Other Stuff");
System.out.println("Hello World"); //the same code.
}
We don't want to be repeating our code.
The technique described here works pretty well:
private void myMethod()
{
final Runnable innerMethod = new Runnable()
{
public void run()
{
System.out.println("Hello World");
}
};
innerMethod.run();
System.out.println("Some other stuff");
innerMethod.run();
}
But what if I want to pass in a parameter to that inner method?
eg.
private void myMethod()
{
final Runnable innerMethod = new Runnable()
{
public void run(int value)
{
System.out.println("Hello World" + Integer.toString(value));
}
};
innerMethod.run(1);
System.out.println("Some other stuff");
innerMethod.run(2);
}
gives me: The type new Runnable(){} must implement the inherited abstract method Runnable.run()
While
private void myMethod()
{
final Runnable innerMethod = new Runnable()
{
public void run()
{
//do nothing
}
public void run(int value)
{
System.out.println("Hello World" + Integer.toString(value));
}
};
innerMethod.run(1);
System.out.println("Some other stuff");
innerMethod.run(2);
}
gives me The method run() in the type Runnable is not applicable for the arguments (int).

Nope, that isn't a method but an anonymous object. You can create an extra method to use for the object.
Thread thread = new Thread( new Runnable()
{
int i,j;
public void init(int i, int j)
{
this.i = i;
this.j=j;
}
});
thread.init(2,3);
thread.start();
And wrap runnable in a Thread, and call start! Not run().
Because you can't call the constructor of an anonymous class, as pointed out by #HoverCraft you could extend a named class that implements Runnable.
public class SomeClass implements Runnable
{
public SomeClass(int i){ }
}

Looks like you just want inner methods. Java does't let you have them, so the Runnable hack you describe lets you sort-of declare an inner method.
But since you want more control over it, why not define your own:
interface Inner<A, B> {
public B apply(A a);
}
Then you can say:
private void myMethod(..){
final Inner<Integer, Integer> inner = new Inner<Integer, Integer>() {
public Integer apply(Integer i) {
// whatever you want
}
};
// then go:
inner.apply(1);
inner.apply(2);
}
Or use some library that provides functor objects. There should be many. Apache Commons has a Functor that you can use.

Accesing an instance of Class from another class

Im writing a project using an API .
So overall my program looks like so .
public class Programm extends bridge {
Client Eclient = new Client() ;
public static void main(String[] args) {
Programm MyProgramm = new Programm();
MyProgramm.MyMethod();
public void MyMethod(){
Runnable countdown = new flipper();
Thread worker = new Thread(countdown);
worker.start();
}
}
abstract bridge implements API{}
class flipper implements runnable {
public void run(){MyProgramm.Eclient.ApiMethod()}
}
Basiclly i need to access the EClient class instance as it would be accesed by MyProgramm instance from class flipper

Option 2: Make Flipper an inner class
public class Program extends bridge {
Client eClient = new Client() ;
public void main(String[] args) {...}
public void myMethod(){...}
class Flipper implements Runnable {
public void run(){Program.eClient.apiMethod()}
}
}

class flipper implements Runnable {
private ESocket lEClient;
public flipper (Object pEClient) {
lEClient = pEClient;
}
And then you call use the constructor like this:
public void MyMethod()
{
Runnable countdown = new flipper(Eclient);
Thread worker = new Thread(countdown);
worker.start();
}
public void run() {lEClient .Apimethod()}

Access anonymous outer class without storing in variable?

Is there a way to access an anonymous outer class? A normal class can be accessed by ClassName.this. This doesn't work, as an anonymous class obviously doesn't have a name. I also tried using the extended class/interface (like Runnable.this) but it doesn't seem like it would work this way.
I'm sure this may be not the best coding style, I'm just curious if it's possible without storing this of the outer in a variable.
Example, watch out for outer.this:
public class A
{
public static void main(String[] args) {
new Thread(new Runnable() {
#Override
public void run() {
new Thread(new Runnable() {
#Override
public void run() {
synchronized (outher.this) {
outher.this.notify();
}
}
}).start();
try {
synchronized (this) {
wait();
}
} catch (final InterruptedException ex) {}
}
}).start();
}
}

No, there is no way to access anonymous classes from anywhere, except from inside them (i.e. otherwise than by this reference). Or by an explicitly declared variable.
final Runnable r1 = new Runnable() {...};
Runnable r2 = new Runnable() {
public void run() {
synchronized(r1) {...}
}
};

You could add a method to return this middle this. It would be in scope but not hidden (is that the right term? Shadowed? I forget.).
public static void main(String[] args) {
new Thread(new Runnable() {
Runnable middleThis() { return this; } // <-- this
#Override
public void run() {
new Thread(new Runnable() {
#Override
public void run() {
synchronized (middleThis()) {
middleThis().notify();
Note, although anonymous inner classes have no name, they still are types. So adding members is visible to the immediate expression (new X() { Y z; }.z) and inside. You can't do middleThis().middleThis().