Develop Reference

Convert String with special characters

String descriptionEscaped = "Domnul Florin Cîţu afirmă"
=>
String descriptionEscaped = "Domnul Florin Cîţu afirmă, sâmbătă"
Is there a way to do this ?
(Sorry for the confusing title of question)

following is helping you to convert special characters
public static void main(String[] args) {
String descriptionEscaped = "Domnul Florin Cîţu afirmă";
descriptionEscaped =
StringEscapeUtils.unescapeHtml4(descriptionEscaped);
System.out.println(descriptionEscaped);
}

Extract a specific word from a text in java

I want to extract a particular word from a text using Java. Is it possible
e.g. :
String str = "this is 009876 birthday of mine";
I want to get '009876' from above text in Java. Is this possible ?

You can do it easily by regex. Below is an example:
import java.util.regex.*;
class Test {
public static void main(String[] args) {
String hello = "this is 009876 birthday of mine";
Pattern pattern = Pattern.compile("009876");
Matcher matcher = pattern.matcher(hello);
int count = 0;
while (matcher.find())
count++;
System.out.println(count); // prints 1
}
}
If you want to check if the text contains the source string (e.g. "009876") you can do it simply by contains method of String as shown in below example:
public static String search() {
// TODO Auto-generated method stub
String text = "this is 009876 birthday of mine";
String source = "009876";
if(text.contains(source))
return text;
else
return text;
}
Let me know if any issue.

You can do it like this:
class ExtractDesiredString{
static String extractedString;
public static void main(String[] args) {
String hello = "this is 009876 birthday of mine";
Pattern pattern = Pattern.compile("009876");
if (hello.contains(pattern.toString())) {
extractedString = pattern.toString();
}else{
Assert.fail("Given string doesn't contain desired text")
}
}
}

Replacing german umlauts generated by latex or bibtex tool in java?

I want to replace the german umlauts generated by a Citavi-Bibtex-Export-Tool. For example one reference string input is J{\"o}rgand I want Jörg as a result. After inspecting my JUnit-Test the result of my method was J{"o}rg - what went wrong?
public String replaceBibtexMutatedVowels(String str){
CharSequence target = "{\\\"o}";
CharSequence replacement = "ö";
str.replace(target, replacement);
return str;
}
UPDATE: Thanks guys - I was able to master german umlauts - unfortunately Bibtex escapes quotation marks with {\dg} - I was not able to create the corresponding java code.
String afterDg = "";
CharSequence targetDg = "{\\dg}";
CharSequence replacementDg = "\"";
afterDg = afterAe.replace(targetDg, replacementDg);
newStringInstance = afterDg;
return newStringInstance;

Basically, you are doing all right, but:
str.replace(target, replacement);
must be replaced with
str = str.replace(target, replacement);
because replace doesn't change the string itself, but returns a "replaced string".
P.S.: German has more special characters than "ö"; you're missing "ä", "ü" (and their corresponding capital letters), "ß" etc.
And here's my test code:
package test;
public class Test {
public static void main(String[] args) throws Exception {
String latexText = "J{\\\"o}rg";
String normalText = replaceBibtexMutatedVowels(latexText);
System.out.println(latexText);
System.out.println(normalText);
}
public static String replaceBibtexMutatedVowels(String str) {
CharSequence target = "{\\\"o}";
CharSequence replacement = "ö";
str = str.replace(target, replacement);
return str;
}
}

How to remove everything from HTML except special tag in java?

I want to parse HTML String by extracting only <form> ... </form>. All other stuff don't needed and I can remove it.
Today I have some helpers to remove through replaceAll special tag content like:
/** remove form */
String newString = string.replaceAll("(?s)<form.*?</form>", "");
(?s)<form.*?</form>
removes form tags. But I need vice versa, remove everything except form.
How can I fix it?
See my Gskinner example

Try below code.
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class Client {
private static final String PATTERN = "<form>(.+?)</form>";
private static final Pattern REGEX = Pattern.compile(PATTERN);
private static final boolean ONLY_TAG = true;
public static void main(String[] args) {
String text = "Hello <form><span><table>Hello Rais</table></span></form> end";
System.out.println(getValues(text, ONLY_TAG));
System.out.println(getValues(text, !ONLY_TAG));
}
private static String getValues(final String text, boolean flag) {
final Matcher matcher = REGEX.matcher(text);
String tagValues = null;
if (flag) {
if (matcher.find()) {
tagValues = "<form>" + matcher.group(1) + "</form>";
}
} else {
tagValues = text.replaceAll(PATTERN, "");
}
return tagValues;
}
}
You will get below output
<form><span><table>Hello Rais</table></span></form>
Hello end

The below code will give you a direction in what you are looking for:
String str = "<html><form>test form</form></html>";
String newString = str.replaceAll("[^<form</form>]+|((?s)<form.*?</form>)", "$1");
System.out.println(newString);

Android equivalent of vb.net StringValue.ToString("0000")

Is there an equivilent of vb.nets StringValue.ToString("0000") so that it returns the string as four numbers. I'm trying to work it on :
public static String getNextID(int stationID, String tablename) {
String rtnID;
rtnID = Integer.toString(stationID) + "-" + getNextID(tablename);
return rtnID;
}
So that the value of rtnID is 4 characters long and it's added 0's in the right place if needed
Tom
Edit: heres what I now have that isn't working:
public static String getNextID(int stationID, String tablename) {
String rtnID;
NumberFormat formatter = new DecimalFormat("0000");
String s = formatter.format(String.valueOf(stationID));
rtnID = s + "-" + getNextID(tablename);
return rtnID;
}
With this error: http://pastebin.com/XpvzkC5D

You can use this:
NumberFormat formatter = new DecimalFormat("0000");
String s = formatter.format(stationID);