Develop Reference

how to read a value in CSV with the value left to it

I have searched in stack and web a lot, for parsing a CSV file.
But I won't get what I want.
I have this table in CSV format,
what I want is, if I give the "ID"(which is 0,1,2,3... ) it should return me the value right to it i.e., if i give
"2" it should return me "hello how are you ?".
"4" it should return me "What do you prefer over tea ?"
How to achieve this?
Right now I kept my CSV file in the raw folder.
Any help will be apppreciated

You can save data in CSV as:-
ArrayList<TableData> arrayList=new ArrayList<>();
arrayList.add(new TableData(1,"Hello"));
arrayList.add(new TableData(2,"How are u"));
arrayList.add(new TableData(3,"I am fine"));
arrayList.add(new TableData(4,"Thank You"));
File file;
File root = Environment.getExternalStorageDirectory();
if (root.canWrite()){
File dir = new File (root.getAbsolutePath() + "/PersonData");
dir.mkdirs();
file = new File(dir, "Data.csv");
FileOutputStream out = null;
try {
// write to byte array
ByteArrayOutputStream baos = new ByteArrayOutputStream();
DataOutputStream dos = new DataOutputStream(baos);
for (TableData element : arrayList) {
dos.writeUTF(String.valueOf(element.id));
dos.writeUTF(String.valueOf(element.name));
}
byte[] bytes = baos.toByteArray();
out = new FileOutputStream(file);
out.write(bytes);
out.close();
}catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
And Retrive it as:-
File file;
File root = Environment.getExternalStorageDirectory();
File dir = new File (root.getAbsolutePath() + "/PersonData");
dir.mkdirs();
file = new File(dir, "Data.csv");
Uri u1 = null;
u1 = Uri.fromFile(file);
try {
FileInputStream inputStream=new FileInputStream(file);
String input="2";
String previousValue="";
ByteArrayInputStream bais = new ByteArrayInputStream(readFully(inputStream));
DataInputStream in = new DataInputStream(bais);
while (in.available() > 0) {
String element = in.readUTF();
if(previousValue.equalsIgnoreCase(input)){
textView.setText(element);
}
previousValue=element;
}
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
Method to convert inputStream to byte[]:-
public static byte[] readFully(InputStream input) throws IOException
{
byte[] buffer = new byte[8192];
int bytesRead;
ByteArrayOutputStream output = new ByteArrayOutputStream();
while ((bytesRead = input.read(buffer)) != -1)
{
output.write(buffer, 0, bytesRead);
}
return output.toByteArray();
}

Create a separate class for reading CSV file as:-
public class CSVFile {
InputStream inputStream;
public CSVFile(InputStream inputStream){
this.inputStream = inputStream;
}
public List read(){
List resultList = new ArrayList();
BufferedReader reader = new BufferedReader(new InputStreamReader(inputStream));
try {
String csvLine;
while ((csvLine = reader.readLine()) != null) {
String[] row = csvLine.split(",");
resultList.add(row);
}
}
catch (IOException ex) {
throw new RuntimeException("Error in reading CSV file: "+ex);
}
finally {
try {
inputStream.close();
}
catch (IOException e) {
throw new RuntimeException("Error while closing input stream: "+e);
}
}
return resultList;
}
}
Now call this in your activity:-
String input="2";
InputStream inputStream = getResources().openRawResource(R.raw.sample);
CSVFile csvFile = new CSVFile(inputStream);
List scoreList = csvFile.read();
for(int i=0;i<scoreList.size();i++){
Object data_list=scoreList.get(i);
String a[]= (String[]) data_list;
String id=a[0];
String value=a[1];
if(input.equalsIgnoreCase(id)){
Log.d("TAG", "Value Found "+value);
}
}

Unzip to folder in internal storage

I'm trying to create a folder in internal storage called "unzip" and then unzip a file into the internal storage "unzip folder". Not sure what i'm doing wrong? If you could please explain what's wrong it'd be great! Thanks
Edit: The issues is that I don't think the folder is being created and the file is also not being unzipped.
public void send(View view) {
try {
File mydir = this.getDir("unzip", Context.MODE_PRIVATE);//create folder in internal storage
unzip(getFilesDir().getAbsolutePath(), job_no, getFilesDir() + "/unzip/");
} catch (IOException e) {
}
}
public void unzip(String filepath, String filename, String unzip_path) throws IOException {
InputStream is = new FileInputStream(filepath + filename);
ZipInputStream zis = new ZipInputStream(new BufferedInputStream(is));
try {
ZipEntry ze;
while ((ze = zis.getNextEntry()) != null) {
ByteArrayOutputStream baos = new ByteArrayOutputStream();
byte[] buffer = new byte[1024];
int count;
String filename_temp = ze.getName();
File fmd = new File(filepath + filename_temp);
if (!fmd.getParentFile().exists()) {
fmd.getParentFile().mkdirs();
}
FileOutputStream fout = new FileOutputStream(unzip_path + filename_temp);
while ((count = zis.read(buffer)) != -1) {
baos.write(buffer, 0, count);
byte[] bytes = baos.toByteArray();
fout.write(bytes);
baos.reset();
}
fout.close();
//}
}
} finally {
zis.close();
}
}

This will get absolute storage device.
final static String MEDIA_PATH = Environment.getExternalStorageDirectory().getPath() + "/";

Android - Copy assets to internal storage

Good day!
I have just started developing for android. In my app, I need to copy the items in my assets folder to the internal storage.
I have searched a lot on SO including this which copies it to the external storage.
How to copy files from 'assets' folder to sdcard?
This is what I want to achieve:
I have a directory already present in the internal storage as X>Y>Z. I need a file to be copied to Y and another to Z.
Can anyone help me out with a code snippet? I really don't have any idea how to go on about this.
Sorry for my bad English.
Thanks a lot.

Use
String out= Environment.getExternalStorageDirectory().getAbsolutePath() + "/X/Y/Z/" ;
File outFile = new File(out, Filename);
After Editing in your ref. Link Answer.
private void copyAssets() {
AssetManager assetManager = getAssets();
String[] files = null;
try {
files = assetManager.list("");
} catch (IOException e) {
Log.e("tag", "Failed to get asset file list.", e);
}
for(String filename : files) {
InputStream in = null;
OutputStream out = null;
try {
in = assetManager.open(filename);
String outDir = Environment.getExternalStorageDirectory().getAbsolutePath() + "/X/Y/Z/" ;
File outFile = new File(outDir, filename);
out = new FileOutputStream(outFile);
copyFile(in, out);
in.close();
in = null;
out.flush();
out.close();
out = null;
} catch(IOException e) {
Log.e("tag", "Failed to copy asset file: " + filename, e);
}
}
}
private void copyFile(InputStream in, OutputStream out) throws IOException {
byte[] buffer = new byte[1024];
int read;
while((read = in.read(buffer)) != -1){
out.write(buffer, 0, read);
}
}

I did something like this. This allows you to copy all the directory structure to copy from Android AssetManager.
public String copyDirorfileFromAssetManager(String arg_assetDir, String arg_destinationDir) throws IOException
{
File sd_path = Environment.getExternalStorageDirectory();
String dest_dir_path = sd_path + addLeadingSlash(arg_destinationDir);
File dest_dir = new File(dest_dir_path);
createDir(dest_dir);
AssetManager asset_manager = getApplicationContext().getAssets();
String[] files = asset_manager.list(arg_assetDir);
for (int i = 0; i < files.length; i++)
{
String abs_asset_file_path = addTrailingSlash(arg_assetDir) + files[i];
String sub_files[] = asset_manager.list(abs_asset_file_path);
if (sub_files.length == 0)
{
// It is a file
String dest_file_path = addTrailingSlash(dest_dir_path) + files[i];
copyAssetFile(abs_asset_file_path, dest_file_path);
} else
{
// It is a sub directory
copyDirorfileFromAssetManager(abs_asset_file_path, addTrailingSlash(arg_destinationDir) + files[i]);
}
}
return dest_dir_path;
}
public void copyAssetFile(String assetFilePath, String destinationFilePath) throws IOException
{
InputStream in = getApplicationContext().getAssets().open(assetFilePath);
OutputStream out = new FileOutputStream(destinationFilePath);
byte[] buf = new byte[1024];
int len;
while ((len = in.read(buf)) > 0)
out.write(buf, 0, len);
in.close();
out.close();
}
public String addTrailingSlash(String path)
{
if (path.charAt(path.length() - 1) != '/')
{
path += "/";
}
return path;
}
public String addLeadingSlash(String path)
{
if (path.charAt(0) != '/')
{
path = "/" + path;
}
return path;
}
public void createDir(File dir) throws IOException
{
if (dir.exists())
{
if (!dir.isDirectory())
{
throw new IOException("Can't create directory, a file is in the way");
}
} else
{
dir.mkdirs();
if (!dir.isDirectory())
{
throw new IOException("Unable to create directory");
}
}
}

try this below code
private void copyAssets() {
AssetManager assetManager = getAssets();
String[] files = null;
try {
files = assetManager.list("");
} catch (IOException e) {
Log.e("tag", "Failed to get asset file list.", e);
}
for(String filename : files) {
InputStream in = null;
OutputStream out = null;
try {
in = assetManager.open(filename);
File outFile = new File(getExternalFilesDir(null), filename);
out = new FileOutputStream(outFile);
copyFile(in, out);
in.close();
in = null;
out.flush();
out.close();
out = null;
} catch(IOException e) {
Log.e("tag", "Failed to copy asset file: " + filename, e);
}
}
}
private void copyFile(InputStream in, OutputStream out) throws IOException {
byte[] buffer = new byte[1024];
int read;
while((read = in.read(buffer)) != -1){
out.write(buffer, 0, read);
}
}

This is my Kotlin solution with auto-closable streams to copy in internal app storage:
val copiedFile = File(context.filesDir, "copied_file.txt")
context.assets.open("original_file.txt").use { input ->
copiedFile.outputStream().use { output ->
input.copyTo(output, 1024)
}
}

My small solution on Kotlin, for copy data from assets to INTERNAL STORAGE
fun copy() {
val bufferSize = 1024
val assetManager = context.assets
val assetFiles = assetManager.list("")
assetFiles.forEach {
val inputStream = assetManager.open(it)
val outputStream = FileOutputStream(File(context.filesDir, it))
try {
inputStream.copyTo(outputStream, bufferSize)
} finally {
inputStream.close()
outputStream.flush()
outputStream.close()
}
}
}

public void addFilesToSystem(String sysName, String intFil, Context c){
//sysName is the name of the file we have in the android os
//intFil is the name of the internal file
file = new File(path, sysName + ".txt");
if(!file.exists()){
path.mkdirs();
try {
AssetManager am = c.getAssets();
InputStream is = am.open(intFil);
OutputStream os = new FileOutputStream(file);
byte[] data = new byte[is.available()];
is.read(data);
os.write(data);
is.close();
os.close();
Toast t = Toast.makeText(c, "Making file: " + file.getName() + ". One time action", Toast.LENGTH_LONG);
t.show();
//Update files for the user to use
MediaScannerConnection.scanFile(c,
new String[] {file.toString()},
null,
new MediaScannerConnection.OnScanCompletedListener() {
public void onScanCompleted(String path, Uri uri) {
// TODO Auto-generated method stub
}
});
} catch (IOException e) {
Toast t = Toast.makeText(c, "Error: " + e.toString() + ". One time action", Toast.LENGTH_LONG);
t.show();
e.printStackTrace();
}
}
}
To add a file, call the addFilesToSystem("this_file_is_in_the_public_system", "this_file_is_in_the_assets_folder", context/this context is if you do not have the method in the Activity/
Hope it helps

You can use the Envrionment#getDataDirectory method for that. It'll give the path of the data directory of the internal storage memory. This is generally where all the app related data is stored.
Alternately, if you want to store in the root directory, you can use the Environment#getRootDirectory method for that.

If you need to copy any file from assets to the internal storage and do it only once:
public void writeFileToStorage() {
Logger.d(TAG, ">> writeFileToStorage");
AssetManager assetManager = mContext.getAssets();
if (new File(getFilePath()).exists()) {
Logger.d(TAG, "File exists, do nothing");
Logger.d(TAG, "<< writeFileToStorage");
return;
}
try (InputStream input = assetManager.open(FILE_NAME);
OutputStream output = new FileOutputStream(getFilePath())) {
Logger.d(TAG, "File does not exist, write it");
byte[] buffer = new byte[input.available()];
int length;
while ((length = input.read(buffer)) != -1) {
output.write(buffer, 0, length);
}
} catch (FileNotFoundException e) {
e.printStackTrace();
Logger.e(TAG, "File is not found");
} catch (IOException e) {
e.printStackTrace();
Logger.d(TAG, "Error while writing the file");
}
Logger.d(TAG, "<< writeFileToStorage");
}
public String getFilePath() {
String filePath = mContext.getFilesDir() + "/" + FILE_NAME;
Logger.d(TAG, "File path: " + filePath);
return filePath;
}

How to create binary file of specific size?

How can I create one binary file of size 250KB and another one of 1MB using Java?
Is it possible?

new RandomAccessFile("file.file", "rw").setLength(1048576);

FileOutputStream s = new FileOutputStream("a.bin");
byte[] buf = new byte[250*1024];
s.write(buf);
s.flush();
s.close();

public voidwriteFile(String path, int bytes) throws Exception {
OutputStream outputStream = null;
File f=null;
try {
f = new File(path + "/tmp.txt");
f.createNewFile();
byte[] buf = new byte[bytes];
outputStream = new BufferedOutputStream(new FileOutputStream(f));
outputStream.write(buf);
outputStream.flush();
} catch (Exception e) {
throw new Exception();
} finally {
try {
if(f!=null){
f.delete();
}
outputStream.close();
} catch (IOException e) {
}
}
}

How to create a zip file in Java

I have a dynamic text file that picks content from a database according to the user's query. I have to write this content into a text file and zip it in a folder in a servlet. How should I do this?

Look at this example:
StringBuilder sb = new StringBuilder();
sb.append("Test String");
File f = new File("d:\\test.zip");
ZipOutputStream out = new ZipOutputStream(new FileOutputStream(f));
ZipEntry e = new ZipEntry("mytext.txt");
out.putNextEntry(e);
byte[] data = sb.toString().getBytes();
out.write(data, 0, data.length);
out.closeEntry();
out.close();
This will create a zip in the root of D: named test.zip which will contain one single file called mytext.txt. Of course you can add more zip entries and also specify a subdirectory like this:
ZipEntry e = new ZipEntry("folderName/mytext.txt");
You can find more information about compression with Java here.

Java 7 has ZipFileSystem built in, that can be used to create, write and read file from zip file.
Java Doc: ZipFileSystem Provider
Map<String, String> env = new HashMap<>();
// Create the zip file if it doesn't exist
env.put("create", "true");
URI uri = URI.create("jar:file:/codeSamples/zipfs/zipfstest.zip");
try (FileSystem zipfs = FileSystems.newFileSystem(uri, env)) {
Path externalTxtFile = Paths.get("/codeSamples/zipfs/SomeTextFile.txt");
Path pathInZipfile = zipfs.getPath("/SomeTextFile.txt");
// Copy a file into the zip file
Files.copy(externalTxtFile, pathInZipfile, StandardCopyOption.REPLACE_EXISTING);
}

To write a ZIP file, you use a ZipOutputStream. For each entry that you want to place into the ZIP file, you create a ZipEntry object. You pass the file name to the ZipEntry constructor; it sets the other parameters such as file date and decompression method. You can override these settings if you like. Then, you call the putNextEntry method of the ZipOutputStream to begin writing a new file. Send the file data to the ZIP stream. When you are done, call closeEntry. Repeat for all the files you want to store. Here is a code skeleton:
FileOutputStream fout = new FileOutputStream("test.zip");
ZipOutputStream zout = new ZipOutputStream(fout);
for all files
{
ZipEntry ze = new ZipEntry(filename);
zout.putNextEntry(ze);
send data to zout;
zout.closeEntry();
}
zout.close();

Here is an example code to compress a Whole Directory(including sub files and sub directories), it's using the walk file tree feature of Java NIO.
import java.io.FileOutputStream;
import java.io.IOException;
import java.nio.file.*;
import java.nio.file.attribute.BasicFileAttributes;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;
public class ZipCompress {
public static void compress(String dirPath) {
final Path sourceDir = Paths.get(dirPath);
String zipFileName = dirPath.concat(".zip");
try {
final ZipOutputStream outputStream = new ZipOutputStream(new FileOutputStream(zipFileName));
Files.walkFileTree(sourceDir, new SimpleFileVisitor<Path>() {
#Override
public FileVisitResult visitFile(Path file, BasicFileAttributes attributes) {
try {
Path targetFile = sourceDir.relativize(file);
outputStream.putNextEntry(new ZipEntry(targetFile.toString()));
byte[] bytes = Files.readAllBytes(file);
outputStream.write(bytes, 0, bytes.length);
outputStream.closeEntry();
} catch (IOException e) {
e.printStackTrace();
}
return FileVisitResult.CONTINUE;
}
});
outputStream.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
To use this, just call
ZipCompress.compress("target/directoryToCompress");
and you'll get a zip file directoryToCompress.zip

Single file:
String filePath = "/absolute/path/file1.txt";
String zipPath = "/absolute/path/output.zip";
try (ZipOutputStream zipOut = new ZipOutputStream(new FileOutputStream(zipPath))) {
File fileToZip = new File(filePath);
zipOut.putNextEntry(new ZipEntry(fileToZip.getName()));
Files.copy(fileToZip.toPath(), zipOut);
}
Multiple files:
List<String> filePaths = Arrays.asList("/absolute/path/file1.txt", "/absolute/path/file2.txt");
String zipPath = "/absolute/path/output.zip";
try (ZipOutputStream zipOut = new ZipOutputStream(new FileOutputStream(zipPath))) {
for (String filePath : filePaths) {
File fileToZip = new File(filePath);
zipOut.putNextEntry(new ZipEntry(fileToZip.getName()));
Files.copy(fileToZip.toPath(), zipOut);
}
}

Spring boot controller, zip the files in a directory, and can be downloaded.
#RequestMapping(value = "/files.zip")
#ResponseBody
byte[] filesZip() throws IOException {
File dir = new File("./");
File[] filesArray = dir.listFiles();
if (filesArray == null || filesArray.length == 0)
System.out.println(dir.getAbsolutePath() + " have no file!");
ByteArrayOutputStream bo = new ByteArrayOutputStream();
ZipOutputStream zipOut= new ZipOutputStream(bo);
for(File xlsFile:filesArray){
if(!xlsFile.isFile())continue;
ZipEntry zipEntry = new ZipEntry(xlsFile.getName());
zipOut.putNextEntry(zipEntry);
zipOut.write(IOUtils.toByteArray(new FileInputStream(xlsFile)));
zipOut.closeEntry();
}
zipOut.close();
return bo.toByteArray();
}

This is how you create a zip file from a source file:
String srcFilename = "C:/myfile.txt";
String zipFile = "C:/myfile.zip";
try {
byte[] buffer = new byte[1024];
FileOutputStream fos = new FileOutputStream(zipFile);
ZipOutputStream zos = new ZipOutputStream(fos);
File srcFile = new File(srcFilename);
FileInputStream fis = new FileInputStream(srcFile);
zos.putNextEntry(new ZipEntry(srcFile.getName()));
int length;
while ((length = fis.read(buffer)) > 0) {
zos.write(buffer, 0, length);
}
zos.closeEntry();
fis.close();
zos.close();
}
catch (IOException ioe) {
System.out.println("Error creating zip file" + ioe);
}

public static void main(String args[])
{
omtZip("res/", "omt.zip");
}
public static void omtZip(String path,String outputFile)
{
final int BUFFER = 2048;
boolean isEntry = false;
ArrayList<String> directoryList = new ArrayList<String>();
File f = new File(path);
if(f.exists())
{
try {
FileOutputStream fos = new FileOutputStream(outputFile);
ZipOutputStream zos = new ZipOutputStream(new BufferedOutputStream(fos));
byte data[] = new byte[BUFFER];
if(f.isDirectory())
{
//This is Directory
do{
String directoryName = "";
if(directoryList.size() > 0)
{
directoryName = directoryList.get(0);
System.out.println("Directory Name At 0 :"+directoryName);
}
String fullPath = path+directoryName;
File fileList = null;
if(directoryList.size() == 0)
{
//Main path (Root Directory)
fileList = f;
}else
{
//Child Directory
fileList = new File(fullPath);
}
String[] filesName = fileList.list();
int totalFiles = filesName.length;
for(int i = 0 ; i < totalFiles ; i++)
{
String name = filesName[i];
File filesOrDir = new File(fullPath+name);
if(filesOrDir.isDirectory())
{
System.out.println("New Directory Entry :"+directoryName+name+"/");
ZipEntry entry = new ZipEntry(directoryName+name+"/");
zos.putNextEntry(entry);
isEntry = true;
directoryList.add(directoryName+name+"/");
}else
{
System.out.println("New File Entry :"+directoryName+name);
ZipEntry entry = new ZipEntry(directoryName+name);
zos.putNextEntry(entry);
isEntry = true;
FileInputStream fileInputStream = new FileInputStream(filesOrDir);
BufferedInputStream bufferedInputStream = new BufferedInputStream(fileInputStream, BUFFER);
int size = -1;
while( (size = bufferedInputStream.read(data, 0, BUFFER)) != -1 )
{
zos.write(data, 0, size);
}
bufferedInputStream.close();
}
}
if(directoryList.size() > 0 && directoryName.trim().length() > 0)
{
System.out.println("Directory removed :"+directoryName);
directoryList.remove(0);
}
}while(directoryList.size() > 0);
}else
{
//This is File
//Zip this file
System.out.println("Zip this file :"+f.getPath());
FileInputStream fis = new FileInputStream(f);
BufferedInputStream bis = new BufferedInputStream(fis,BUFFER);
ZipEntry entry = new ZipEntry(f.getName());
zos.putNextEntry(entry);
isEntry = true;
int size = -1 ;
while(( size = bis.read(data,0,BUFFER)) != -1)
{
zos.write(data, 0, size);
}
}
//CHECK IS THERE ANY ENTRY IN ZIP ? ----START
if(isEntry)
{
zos.close();
}else
{
zos = null;
System.out.println("No Entry Found in Zip");
}
//CHECK IS THERE ANY ENTRY IN ZIP ? ----START
}catch(Exception e)
{
e.printStackTrace();
}
}else
{
System.out.println("File or Directory not found");
}
}
}

Given exportPath and queryResults as String variables, the following block creates a results.zip file under exportPath and writes the content of queryResults to a results.txt file inside the zip.
URI uri = URI.create("jar:file:" + exportPath + "/results.zip");
Map<String, String> env = Collections.singletonMap("create", "true");
try (FileSystem zipfs = FileSystems.newFileSystem(uri, env)) {
Path filePath = zipfs.getPath("/results.txt");
byte[] fileContent = queryResults.getBytes();
Files.write(filePath, fileContent, StandardOpenOption.CREATE);
}

You have mainly to create two functions. First is writeToZipFile() and second is createZipfileForOutPut .... and then call the createZipfileForOutPut('file name of .zip')` …
public static void writeToZipFile(String path, ZipOutputStream zipStream)
throws FileNotFoundException, IOException {
System.out.println("Writing file : '" + path + "' to zip file");
File aFile = new File(path);
FileInputStream fis = new FileInputStream(aFile);
ZipEntry zipEntry = new ZipEntry(path);
zipStream.putNextEntry(zipEntry);
byte[] bytes = new byte[1024];
int length;
while ((length = fis.read(bytes)) >= 0) {
zipStream.write(bytes, 0, length);
}
zipStream.closeEntry();
fis.close();
}
public static void createZipfileForOutPut(String filename) {
String home = System.getProperty("user.home");
// File directory = new File(home + "/Documents/" + "AutomationReport");
File directory = new File("AutomationReport");
if (!directory.exists()) {
directory.mkdir();
}
try {
FileOutputStream fos = new FileOutputStream("Path to your destination" + filename + ".zip");
ZipOutputStream zos = new ZipOutputStream(fos);
writeToZipFile("Path to file which you want to compress / zip", zos);
zos.close();
fos.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}

There is another option by using zip4j at https://github.com/srikanth-lingala/zip4j
Creating a zip file with single file in it / Adding single file to an existing zip
new ZipFile("filename.zip").addFile("filename.ext");
Or
new ZipFile("filename.zip").addFile(new File("filename.ext"));
Creating a zip file with multiple files / Adding multiple files to an existing zip
new ZipFile("filename.zip").addFiles(Arrays.asList(new File("first_file"), new File("second_file")));
Creating a zip file by adding a folder to it / Adding a folder to an existing zip
new ZipFile("filename.zip").addFolder(new File("/user/myuser/folder_to_add"));
Creating a zip file from stream / Adding a stream to an existing zip
new ZipFile("filename.zip").addStream(inputStream, new ZipParameters());

I know this question is answered but if you have a list of strings and you want to create a separate file for each string in the archive, you can use the snippet below.
public void zipFileTest() throws IOException {
Map<String, String> map = Map.ofEntries(
new AbstractMap.SimpleEntry<String, String>("File1.txt", "File1 Content"),
new AbstractMap.SimpleEntry<String, String>("File2.txt", "File2 Content"),
new AbstractMap.SimpleEntry<String, String>("File3.txt", "File3 Content")
);
createZipFileFromStringContents(map, "archive.zip");
}
public void createZipFileFromStringContents(Map<String, String> map, String zipfilePath) throws IOException {
FileOutputStream fout = new FileOutputStream(zipfilePath);
ZipOutputStream zout = new ZipOutputStream(fout);
for (Map.Entry<String, String> entry : map.entrySet()) {
String fileName = entry.getKey();
ZipEntry zipFile = new ZipEntry(fileName);
zout.putNextEntry(zipFile);
String fileContent = entry.getValue();
zout.write(fileContent.getBytes(), 0, fileContent.getBytes().length);
zout.closeEntry();
}
zout.close();
}
It will create a zip file with the structure as in the below image:

Here is my working solution:
public static byte[] createZipFile(Map<String, FileData> files) throws IOException {
try(ByteArrayOutputStream tZipFile = new ByteArrayOutputStream()) {
try (ZipOutputStream tZipFileOut = new ZipOutputStream(tZipFile)) {
for (Map.Entry<String, FileData> file : files.entrySet()) {
ZipEntry zipEntry = new ZipEntry(file.getValue().getFileName());
tZipFileOut.putNextEntry(zipEntry);
tZipFileOut.write(file.getValue().getBytes());
}
}
return tZipFile.toByteArray();
}
}
public class FileData {
private String fileName;
private byte[] bytes;
public String getFileName() {
return this.fileName;
}
public byte[] getBytes() {
return this.bytes;
}
}
This will create byte[] of ZIP file which contains one or more compressed files. I've used this method inside controller method and write bytes[] of ZIP file into response to download ZIP file(s) from server.

Since it took me a while to figure it out, I thought it would be helpful to post my solution using Java 7+ ZipFileSystem
openZip(runFile);
addToZip(filepath); //loop construct;
zipfs.close();
private void openZip(File runFile) throws IOException {
Map<String, String> env = new HashMap<>();
env.put("create", "true");
env.put("encoding", "UTF-8");
Files.deleteIfExists(runFile.toPath());
zipfs = FileSystems.newFileSystem(URI.create("jar:" + runFile.toURI().toString()), env);
}
private void addToZip(String filename) throws IOException {
Path externalTxtFile = Paths.get(filename).toAbsolutePath();
Path pathInZipfile = zipfs.getPath(filename.substring(filename.lastIndexOf("results"))); //all files to be stored have a common base folder, results/ in my case
if (Files.isDirectory(externalTxtFile)) {
Files.createDirectories(pathInZipfile);
try (DirectoryStream<Path> ds = Files.newDirectoryStream(externalTxtFile)) {
for (Path child : ds) {
addToZip(child.normalize().toString()); //recursive call
}
}
} else {
// copy file to zip file
Files.copy(externalTxtFile, pathInZipfile, StandardCopyOption.REPLACE_EXISTING);
}
}

public static void zipFromTxt(String zipFilePath, String txtFilePath) {
Assert.notNull(zipFilePath, "Zip file path is required");
Assert.notNull(txtFilePath, "Txt file path is required");
zipFromTxt(new File(zipFilePath), new File(txtFilePath));
}
public static void zipFromTxt(File zipFile, File txtFile) {
ZipOutputStream out = null;
FileInputStream in = null;
try {
Assert.notNull(zipFile, "Zip file is required");
Assert.notNull(txtFile, "Txt file is required");
out = new ZipOutputStream(new FileOutputStream(zipFile));
in = new FileInputStream(txtFile);
out.putNextEntry(new ZipEntry(txtFile.getName()));
int len;
byte[] buffer = new byte[1024];
while ((len = in.read(buffer)) > 0) {
out.write(buffer, 0, len);
out.flush();
}
} catch (Exception e) {
log.info("Zip from txt occur error,Detail message:{}", e.toString());
} finally {
try {
if (in != null) in.close();
if (out != null) {
out.closeEntry();
out.close();
}
} catch (Exception e) {
log.info("Zip from txt close error,Detail message:{}", e.toString());
}
}
}

Using Jeka https://jeka.dev JkPathTree, it's quite straightforward.
Path wholeDirToZip = Paths.get("dir/to/zip");
Path zipFile = Paths.get("file.zip");
JkPathTree.of(wholeDirToZip).zipTo(zipFile);

If you want decompress without software better use this code. Other code with pdf files sends error on manually decompress
byte[] buffer = new byte[1024];
try {
FileOutputStream fos = new FileOutputStream("123.zip");
ZipOutputStream zos = new ZipOutputStream(fos);
ZipEntry ze= new ZipEntry("file.pdf");
zos.putNextEntry(ze);
FileInputStream in = new FileInputStream("file.pdf");
int len;
while ((len = in.read(buffer)) > 0) {
zos.write(buffer, 0, len);
}
in.close();
zos.closeEntry();
zos.close();
} catch(IOException ex) {
ex.printStackTrace();
}