I coded up a method which reads a text file, when I run it it works, but when I execute the jar, I get the NoSuchFileException error.
Here is my code:
private static final String textFile = "textFile.txt";
public readText() {
try {
regex = new String(Files.readAllBytes(Paths
.get(textFile)))
.replaceAll("\\r", "").split("\n");
} catch (final IOException e) {
e.printStackTrace();
}
}
Could someone point out where am I going wrong or what changes I'm supposed to make?
I figured out a way:
try {
InputStream in = getClass().getResourceAsStream(textFile);
StringBuilder content = new StringBuilder();
BufferedReader reader = new BufferedReader(new InputStreamReader(in));
String line = reader.readLine();
while(line!=null){
content.append(line).append(System.lineSeparator());
line = reader.readLine();
}
regex = content.toString()
.replaceAll("\\r", "").split("\n");
} catch (final IOException e) {
e.printStackTrace();
}
Related
After reading a file, I'm trying to delete it, but the following error appears:
java.io.IOException: Unable to delete file test.zip at
org.apache.commons.io.FileUtils.forceDelete (FileUtils.java:1390) at
org.apache.commons.io.FileUtils.cleanDirectory (FileUtils.java:1044)
at org.apache.commons.io.FileUtils.deleteDirectory
(FileUtils.java:977)
Here is my code. I've been careful to close the InputStream in the finally clause and only then call the method that deletes the file, but even then I can only delete it when I stop the program.
InputStream is = null;
try {
is = new URL(filePath).openStream(); // filePath is a string containing the path to the file like http://test.com/file.zip
BufferedReader reader = new BufferedReader(new InputStreamReader(is, "utf-8"));
String line;
StringBuilder sb = new StringBuilder();
while ((line = reader.readLine()) != null) {
sb.append(line.trim());
}
String xml = sb.toString(); // this code is working, the result of the "xml" variable is as expected
} catch (Exception e) {
e.printStackTrace();
} finally {
try {
if (is != null) {
is.close();
}
} catch (Exception e) {
e.printStackTrace();
}
removeFileAndFolder(absolutePath);
}
private void removeFileAndFolder(String absolutePath) {
new Thread(new Runnable() {
#Override
public void run() {
try {
String folder = getFolder(absolutePath); // this method just get the path to the folder, because I want to delete the entire folder, but the error occurs when deleting the file
FileUtils.deleteDirectory(new File(folder));
} catch (Exception e) {
e.printStackTrace();
}
}
}).start();
}
After some tests I discovered that I can manually delete the file just before the line "is = new URL (filePath) .openStream ();". After it, and even after the line "is.close ();" I can not delete the file manually unless I stop the program.
I got it. I was opening the file by the url (is = new URL(filePath).openStream();), and trying to delete it by absolute path. I changed it to "is = new FileInputStream(absoluteFilePath);" and it works!
i use eclipse
and my structure looks like this:
TSG-jar
->src
->myBean.java (here i need a path)
and another one web application
TSG-war
->WebContent
->js
->boot.js
so they are both in the same workspace
I call the boot.js file from TSG-war in my TSG-jar (from myBean.java), and i need a path...but i have no idea how to do it...
In myBean.java i got this code:
private String getSrc(String path) {
try {
BufferedReader in = new BufferedReader(new FileReader(path));
StringBuilder sb = new StringBuilder();
String line = "";
while ((line = in.readLine()) != null) {
sb.append(line);
}
in.close();
return sb.toString();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
I need the path of the javaScript.js file to send it to the function...
can u help me?
i tried:
String s = "..\\..\\..\\TSG-war\\WebContent\\js\\boot.js"
String s = "\\..\\..\\..\\TSG-war\\WebContent\\js\\boot.js"
String s = "\\..\\..\\..\\..\\TSG-war\\WebContent\\js\\boot.js"
System.out.println(getSrc(s));
its always null...
where is the error?
Below I have the following code to read in a file and go through it line by line.. This is using java's BufferedReader class. That I am fine with.
String filename = "C:\\test.txt"
String line = null;
FileReader fileReader = new FileReader(filename);
BufferedReader bufferedReader = new BufferedReader(fileReader);
try {
while (((line = bufferedReader.readLine()) != null)) {
//do the following....
}
} catch (IOException) {
e.printStackTrace();
}
However I want to now start using InputStreamReader in Spring / Java. I have the below code written but I am unsure how I can step through my file line by line. Really confused over this part. Anyone have any ideas or know how this can be done?
String filepath= "C:\\test.txt"
File filename= new File(filepath);
try {
InputStream fileInputStream = new BOMInputStream(new fileInputStream(filename));
// now want to step through the file, line by line..
} catch (IOException) {
e.printStackTrace();
}
Thanks
This is how you can read your input file byte by byte using InputStreamReader.
char[] chars = new char[100];
try {
InputStream inputStream = new FileInputStream("C:\\test.txt");
InputStreamReader inputStreamReader = new InputStreamReader(inputStream,"UTF-8");
inputStreamReader.read(chars);
System.out.println(new String(chars).trim());
} catch (IOException e) {
e.printStackTrace();
}
Check this out -
String filename = "C:\\test.txt"
String line = null;
FileInputStream fileInputStream = new FileInputStream(filename);
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(fileInputStream));
try {
while (((line = bufferedReader.readLine()) != null)) {
//do the following....
}
} catch (IOException) {
e.printStackTrace();
}
public static void main(String[] args) {
try (BufferedReader reader = new BufferedReader(new InputStreamReader(new FileInputStream("c:\\test.txt")))) {
reader.lines().forEach(line -> {
// do what you want with the line
});
} catch (IOException e) {
throw new RuntimeException(e);
}
}
I am trying to read values from CSV file which is present in package com.example.
But when i run code with the following syntax:
DataModel model = new FileDataModel(new File("Dataset.csv"));
It says:
java.io.FileNotFoundException:Dataset.csv
I have also tried using:
DataModel model = new FileDataModel(new File("/com/example/Dataset.csv"));
Still not working.
Any help would be helpful.
Thanks.
If this is the FileDataModel from org.apache.mahout.cf.taste.impl.model.file then it can't take an input stream and needs just a file. The problem is you can't assume the file is available to you that easily (see answer to this question).
It might be better to read the contents of the file and save it to a temp file, then pass that temp file to FileDataModel.
InputStream initStream = getClass().getClasLoader().getResourceAsStream("Dataset.csv");
//simplistic approach is to put all the contents of the file stream into memory at once
// but it would be smarter to buffer and do it in chunks
byte[] buffer = new byte[initStream.available()];
initStream.read(buffer);
//now save the file contents in memory to a temporary file on the disk
//choose your own temporary location - this one is typical for linux
String tempFilePath = "/tmp/Dataset.csv";
File tempFile = new File(tempFilePath);
OutputStream outStream = new FileOutputStream(tempFile);
outStream.write(buffer);
DataModel model = new FileDataModel(new File(tempFilePath));
...
public class ReadCVS {
public static void main(String[] args) {
ReadCVS obj = new ReadCVS();
obj.run();
}
public void run() {
String csvFile = "file path of csv";
BufferedReader br = null;
String line = "";
String cvsSplitBy = ",";
try {
br = new BufferedReader(new FileReader(csvFile));
while ((line = br.readLine()) != null) {
// Do stuff here
}
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} finally {
if (br != null) {
try {
br.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
System.out.println("Done");
}
}
CSV file which is present in package com.example
You can use getResource() or getResourceAsStream() to access the resource from within the package. For example
InputStream is = getClass().getResourceAsStream("/com/example/Dataset.csv");//uses absolute (package root) path
BufferedReader br = new BufferedReader(new InputStreamReader(is));
//read from BufferedReader
(note exception handling and file closing are omitted above for brevity)
public static void main(String[] args) throws IOException {
String filename = "C:\\audiofile.wav";
InputStream in = null;
try{
in = new FileInputStream(filename);
}
catch(FileNotFoundException ex){
System.out.println("File not found");
}
AudioStream s = null;
s = new AudioStream(in);
AudioPlayer.player.start(s);
}
i have written this code in netbeans. Name of my audio file is audiofile.wav. But it is all time showing the exception "file not found". Can anyone help me ???
root folders in C drive of Windows Vista and above are protected by UAC. This requires you to run the java executable in Administrative mode.
However, you can shift the wav file elsewhere, where UAC will not interfere(like Documents folder of your currently logged in user) or the root of a different drive(Eg. D:\ and E:)
Also, make sure that the audiofile.wav is indeed in the said location(C:\audiofile.wav)
I think first, you should paste your exception code!
then, I think java I/O support the both two way:
"C:/audiofile.wav"
"C:\audiofile.wav"
import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.InputStreamReader;
public class Main {
public static void main(String[] args) {
// write your code here
String fileLocation = "C:\\1.diff";
String fileLocation1 = "C:/1.diff";
try {
FileInputStream f = new FileInputStream(fileLocation);
BufferedReader reader = new BufferedReader(new InputStreamReader(f));
String line = reader.readLine();
System.out.println("11111111111111111111111111");
while (line != null) {
// Process line
line = reader.readLine();
System.out.println(line);
}
System.out.println("11111111111111111111111111");
} catch (Exception ex) {
System.out.println(ex);
}
try {
FileInputStream ff = new FileInputStream(fileLocation1);
BufferedReader reader1 = new BufferedReader(new InputStreamReader(ff));
String line1 = reader1.readLine();
System.out.println("2222222222222222222222222");
while (line1 != null) {
// Process line
line1 = reader1.readLine();
System.out.println(line1);
}
System.out.println("2222222222222222222222222");
} catch (Exception ex) {
System.out.println(ex);
}
}
}
it works. I don't know what you did, anyway paste your error msg!
====
```
private static void B() {
String filename = "C:\\test.wav";
InputStream in = null;
try {
in = new FileInputStream(filename);
} catch (FileNotFoundException ex) {
System.out.println("File not found");
}
try {
AudioStream s = new AudioStream(in);
AudioPlayer.player.start(s);
} catch (IOException ex) {
System.out.println(ex.getMessage());
}
}
```
it works!
Try just placing your file in a different location and see what happens
ProjectRootDir
audiofile.wav
src
And running this String
String filename = "audiofile.wav";