According to third party API spec, I need to send null value in JSON using ObjectMapper if no value exists,
Expected results : "optional": null
If optional value exists, then send "optional": "value"
I didn't find such option in Jackson – Working with Maps and nulls
Code:
requestVO = new RequestVO(optional);
ObjectMapper mapper = new ObjectMapper();
String requestString = mapper.writeValueAsString(requestVO);
Class:
public class RequestVO {
String optional;
public RequestVO(String optional) {
this.optional = optional;
}
public String getOptional() {
return optional;
}
public void setOptional(String optional) {
this.optional= optional;
}
Add #JsonInclude(JsonInclude.Include.USE_DEFAULTS) annotation to your class.
#JsonInclude(JsonInclude.Include.USE_DEFAULTS)
class RequestVO {
String optional;
public RequestVO(String optional) {
this.optional = optional;
}
public String getOptional() {
return optional;
}
public void setOptional(String optional) {
this.optional = optional;
}
}
Example :
RequestVO requestVO = new RequestVO(null);
ObjectMapper mapper = new ObjectMapper();
try {
String requestString = mapper.writeValueAsString(requestVO);
System.out.println(requestString);
} catch (JsonProcessingException e) {
e.printStackTrace();
}
Output :
{"optional":null}
With value:
RequestVO requestVO = new RequestVO("test");
ObjectMapper mapper = new ObjectMapper();
try {
String requestString = mapper.writeValueAsString(requestVO);
System.out.println(requestString);
} catch (JsonProcessingException e) {
e.printStackTrace();
}
Output:
{"optional":"test"}
You can use #JsonInclude annotation on even properties. So, this way you can either serialize as null or ignore some of the properties while serializing.
You can configure your ObjectMapper this way:
ObjectMapper mapper = new ObjectMapper();
mapper.setSerializationInclusion(JsonInclude.Include.NON_NULL);
If no value is present on the JSON request your processed will have a null as you expected.
You can even configure a Spring bean for the ObjectMapper if you need.
EDIT:
I misunderstood the question, he was interested on the JSON response and not on the object parsed. The correct property is this case is JsonInclude.Include.USE_DEFAULTS.
Apologies for the confusion.
Related
I was trying to filter out certain fields from serialization via SimpleBeanPropertyFilter using the following (simplified) code:
public static void main(String[] args) {
ObjectMapper mapper = new ObjectMapper();
SimpleFilterProvider filterProvider = new SimpleFilterProvider().addFilter("test",
SimpleBeanPropertyFilter.filterOutAllExcept("data1"));
try {
String json = mapper.writer(filterProvider).writeValueAsString(new Data());
System.out.println(json); // output: {"data1":"value1","data2":"value2"}
} catch (JsonProcessingException e) {
e.printStackTrace();
}
}
private static class Data {
public String data1 = "value1";
public String data2 = "value2";
}
Us I use SimpleBeanPropertyFilter.filterOutAllExcept("data1")); I was expecting that the created serialized Json string contains only {"data1":"value1"}, however I get {"data1":"value1","data2":"value2"}.
How to create a temporary writer that respects the specified filter (the ObjectMapper can not be re-configured in my case).
Note: Because of the usage scenario in my application I can only accept answers that do not use Jackson annotations.
If for some reason MixIns does not suit you. You can try this approach:
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.setAnnotationIntrospector(new JacksonAnnotationIntrospector(){
#Override
public boolean hasIgnoreMarker(final AnnotatedMember m) {
List<String> exclusions = Arrays.asList("field1", "field2");
return exclusions.contains(m.getName())|| super.hasIgnoreMarker(m);
}
});
You would normally annotate your Data class to have the filter applied:
#JsonFilter("test")
class Data {
You have specified that you can't use annotations on the class. You could use mix-ins to avoid annotating Data class.
#JsonFilter("test")
class DataMixIn {}
Mixins have to be specified on an ObjectMapper and you specify you don't want to reconfigure that. In such a case, you can always copy the ObjectMapper with its configuration and then modify the configuration of the copy. That will not affect the original ObjectMapper used elsewhere in your code. E.g.
ObjectMapper myMapper = mapper.copy();
myMapper.addMixIn(Data.class, DataMixIn.class);
And then write with the new ObjectMapper
String json = myMapper.writer(filterProvider).writeValueAsString(new Data());
System.out.println(json); // output: {"data1":"value1"}
The example of excluding properties by name:
public Class User {
private String name = "abc";
private Integer age = 1;
//getters
}
#JsonFilter("dynamicFilter")
public class DynamicMixIn {
}
User user = new User();
String[] propertiesToExclude = {"name"};
ObjectMapper mapper = new ObjectMapper()
.addMixIn(Object.class, DynamicMixIn.class);
FilterProvider filterProvider = new SimpleFilterProvider()
.addFilter("dynamicFilter", SimpleBeanPropertyFilter.filterOutAllExcept(propertiesToExclude));
mapper.setFilterProvider(filterProvider);
mapper.writeValueAsString(user); // {"name":"abc"}
You can instead of DynamicMixIn create MixInByPropName
#JsonIgnoreProperties(value = {"age"})
public class MixInByPropName {
}
ObjectMapper mapper = new ObjectMapper()
.addMixIn(Object.class, MixInByPropName.class);
mapper.writeValueAsString(user); // {"name":"abc"}
Note: If you want exclude property only for User you can change parameter Object.class of method addMixIn to User.class
Excluding properties by type you can create MixInByType
#JsonIgnoreType
public class MixInByType {
}
ObjectMapper mapper = new ObjectMapper()
.addMixIn(Integer.class, MixInByType.class);
mapper.writeValueAsString(user); // {"name":"abc"}
It seems you have to add an annotation which indicts which filter to use when doing the serialization to the bean class if you want the filter to work:
#JsonFilter("test")
public class Data {
public String data1 = "value1";
public String data2 = "value2";
}
EDIT
The OP has just added a note that just take the answer that not using a bean animation, then if the field you want to export is very less amount, you can just retrieve that data and build a Map of List yourself, there seems no other way to do that.
Map<String, Object> map = new HashMap<String, Object>();
map.put("data1", obj.getData1());
...
// do the serilization on the map object just created.
If you want to exclude specific field and kept the most field, maybe you could do that with reflect. Following is a method I have written to transfer a bean to a map you could change the code to meet your own needs:
protected Map<String, Object> transBean2Map(Object beanObj){
if(beanObj == null){
return null;
}
Map<String, Object> map = new HashMap<String, Object>();
try {
BeanInfo beanInfo = Introspector.getBeanInfo(beanObj.getClass());
PropertyDescriptor[] propertyDescriptors = beanInfo.getPropertyDescriptors();
for (PropertyDescriptor property : propertyDescriptors) {
String key = property.getName();
if (!key.equals("class")
&& !key.endsWith("Entity")
&& !key.endsWith("Entities")
&& !key.endsWith("LazyInitializer")
&& !key.equals("handler")) {
Method getter = property.getReadMethod();
if(key.endsWith("List")){
Annotation[] annotations = getter.getAnnotations();
for(Annotation annotation : annotations){
if(annotation instanceof javax.persistence.OneToMany){
if(((javax.persistence.OneToMany)annotation).fetch().equals(FetchType.EAGER)){
List entityList = (List) getter.invoke(beanObj);
List<Map<String, Object>> dataList = new ArrayList<>();
for(Object childEntity: entityList){
dataList.add(transBean2Map(childEntity));
}
map.put(key,dataList);
}
}
}
continue;
}
Object value = getter.invoke(beanObj);
map.put(key, value);
}
}
} catch (Exception e) {
Logger.getAnonymousLogger().log(Level.SEVERE,"transBean2Map Error " + e);
}
return map;
}
But I recommend you to use Google Gson as the JSON deserializer/serializer And the main reason is I hate dealing with exception stuff, it just messed up with the coding style.
And it's pretty easy to satisfy your need with taking advantage of the version control annotation on the bean class like this:
#Since(GifMiaoMacro.GSON_SENSITIVE) //mark the field as sensitive data and will not export to JSON
private boolean firstFrameStored; // won't export this field to JSON.
You can define the Macro whether to export or hide the field like this:
public static final double GSON_SENSITIVE = 2.0f;
public static final double GSON_INSENSITIVE = 1.0f;
By default, Gson will export all field that not annotated by #Since So you don't have to do anything if you do not care about the field and it just exports the field.
And if some field you are not want to export to json, ie sensitive info just add an annotation to the field. And generate json string with this:
private static Gson gsonInsensitive = new GsonBuilder()
.registerTypeAdapter(ObjectId.class,new ObjectIdSerializer()) // you can omit this line and the following line if you are not using mongodb
.registerTypeAdapter(ObjectId.class, new ObjectIdDeserializer()) //you can omit this
.setVersion(GifMiaoMacro.GSON_INSENSITIVE)
.disableHtmlEscaping()
.create();
public static String toInsensitiveJson(Object o){
return gsonInsensitive.toJson(o);
}
Then just use this:
String jsonStr = StringUtils.toInsensitiveJson(yourObj);
Since Gson is stateless, it's fine to use a static method to do your job, I have tried a lot of JSON serialize/deserialize framework with Java, but found Gson to be the sharp one both performance and handily.
I'm using #JSONCreator and #JsonCreator to convert a response bean to JSON in Lagom Framework. But, the JSON is not formatted. How can I pretty print the JSON using the annotations (not ObjectMapper)? Here's my sample response bean:
#Immutable
#JsonDeserialize
public class foo {
private final List<Result> _result;
private final MetadataBean _meta;
#JsonCreator
public foo (List<Result> _result, MetadataBean _meta) {
this._result= _result;
this._meta = _meta;
}
}
It seems that pretty printing is controlled by the ObjectMapper and cannot be influenced by annotations. The Lagom documentation for negotiated serializers has this example:
public class JsonTextSerializer implements MessageSerializer.NegotiatedSerializer<String, ByteString> {
private final ObjectMapper mapper = new ObjectMapper();
#Override
public MessageProtocol protocol() {
return new MessageProtocol(Optional.of("application/json"), Optional.empty(), Optional.empty());
}
#Override
public ByteString serialize(String s) throws SerializationException {
try {
return ByteString.fromArray(mapper.writeValueAsBytes(s));
} catch (JsonProcessingException e) {
throw new SerializationException(e);
}
}
}
Pretty printing can then be enabled on the mapper (probably in a constructor):
mapper.enable(SerializationFeature.INDENT_OUTPUT);
I am trying a simple JSON to de-serialize in to java object. I am however, getting empty String values for java.lang.String property values. In rest of the properties, blank values are converting to null values(which is what I want).
My JSON and related Java class are listed below.
JSON string:
{
"eventId" : 1,
"title" : "sample event",
"location" : ""
}
EventBean class POJO:
public class EventBean {
public Long eventId;
public String title;
public String location;
}
My main class code:
ObjectMapper mapper = new ObjectMapper();
mapper.disable(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES);
mapper.enable(DeserializationFeature.ACCEPT_EMPTY_STRING_AS_NULL_OBJECT);
try {
File file = new File(JsonTest.class.getClassLoader().getResource("event.txt").getFile());
JsonNode root = mapper.readTree(file);
// find out the applicationId
EventBean e = mapper.treeToValue(root, EventBean.class);
System.out.println("It is " + e.location);
}
I was expecting print "It is null". Instead, I am getting "It is ". Obviously, Jackson is not treating blank String values as NULL while converting to my String object type.
I read somewhere that it is expected. However, this is something I want to avoid for java.lang.String too. Is there a simple way?
Jackson will give you null for other objects, but for String it will give empty String.
But you can use a Custom JsonDeserializer to do this:
class CustomDeserializer extends JsonDeserializer<String> {
#Override
public String deserialize(JsonParser jsonParser, DeserializationContext context) throws IOException, JsonProcessingException {
JsonNode node = jsonParser.readValueAsTree();
if (node.asText().isEmpty()) {
return null;
}
return node.toString();
}
}
In class you have to use it for location field:
class EventBean {
public Long eventId;
public String title;
#JsonDeserialize(using = CustomDeserializer.class)
public String location;
}
It is possible to define a custom deserializer for the String type, overriding the standard String deserializer:
this.mapper = new ObjectMapper();
SimpleModule module = new SimpleModule();
module.addDeserializer(String.class, new StdDeserializer<String>(String.class) {
#Override
public String deserialize(JsonParser p, DeserializationContext ctxt) throws IOException, JsonProcessingException {
String result = StringDeserializer.instance.deserialize(p, ctxt);
if (StringUtils.isEmpty(result)) {
return null;
}
return result;
}
});
mapper.registerModule(module);
This way all String fields will behave the same way.
You might first like to see if there has been any progress on the Github issue requesting this exact feature.
For those using Spring Boot: The answer from jgesser was the most helpful to me, but I spent a while trying to work out the best way to configure it in Spring Boot.
Actually, the documentation says:
Any beans of type com.fasterxml.jackson.databind.Module are
automatically registered with the auto-configured
Jackson2ObjectMapperBuilder and are applied to any ObjectMapper
instances that it creates.
So here's jgesser's answer expanded into something you can copy-paste into a new class in a Spring Boot application
#Configuration
public class EmptyStringAsNullJacksonConfiguration {
#Bean
SimpleModule emptyStringAsNullModule() {
SimpleModule module = new SimpleModule();
module.addDeserializer(
String.class,
new StdDeserializer<String>(String.class) {
#Override
public String deserialize(JsonParser parser, DeserializationContext context)
throws IOException {
String result = StringDeserializer.instance.deserialize(parser, context);
if (StringUtils.isEmpty(result)) {
return null;
}
return result;
}
});
return module;
}
}
I could get this by following configuration.
final ObjectMapper mapper = new ObjectMapper();
mapper.configure(DeserializationFeature.ACCEPT_EMPTY_STRING_AS_NULL_OBJECT, true);
it is possible to use JsonCreator annotation. It worked for me
public class Foo {
private String field;
#JsonCreator
public Foo(
#JsonProrerty("field") String field) {
this.field = StringUtils.EMPTY.equals(field) ? null : field ;
}
}
I am trying to return {"status": its value}´in the case of routeD!=0 currently I am getting {"status":201,"routes":null} I would get the response in this form {"status":201} without "routes":null at the same time I dont want to lost the response of routeD==0 which is for example {"status":230,"routes":[1,9,3]}
I appeciate any help.
Receiver class:
#Path("/data")
public class Receiver {
#POST
#Consumes(MediaType.APPLICATION_JSON)
public Response storeData(Data data) {
Database db = new Database();
String macD = data.getMac();
int routeD = data.getRoute();
double latD = data.getLatitude();
double longD = data.getLongitude();
double speedD = data.getSpeed();
// Jackson class to wrapper the data in JSON string.
SDBean bean = new SDBean();
if (routeD != 0) {
bean.status = db.insertData(macD, routeD, latD, longD);
return Response.status(bean.status).entity(bean.toJson()).build();
} else {
bean.routes = db.detectRoute(latD, longD);
return Response.status(230).entity(bean.toJson()).build();
}
}
}
SDBean class:
public class SDBean {
public int status;
public ArrayList<Integer> routes;
public SDBean(){
status = 230;
}
public String toJson() {
ObjectMapper mapper = new ObjectMapper();
String json = null;
try {
json = mapper.writeValueAsString(this);
} catch (JsonProcessingException e) {
e.printStackTrace();
}
System.out.println(json);
return json;
}
}
Just use #JsonInclude(JsonInclude.Include.NON_NULL)
Annotation used to indicate when value of the annotated property (when used for a field, method or constructor parameter), or all properties of the annotated class, is to be serialized. Without annotation property values are always included, but by using this annotation one can specify simple exclusion rules to reduce amount of properties to write out.
import com.fasterxml.jackson.annotation.JsonInclude;
[...]
#JsonInclude(JsonInclude.Include.NON_NULL)
public class SDBean {
When I use object mapper, it inluces \r\n in the responses.Help me how to resolve it.
I am having train POJO and it has String name and String Value.
I set name as "Sydney" and Value as "SYD".It reruns
{\ \ \"name \" : \"Sydney\",\ \ \"Value \" : \"SYD\",\ \ \"isEnable\" : false,\ \ \"isCurrent\" : false\ \ }"
raw value in browser
"{\r\n \"name\" : \"Sydney\",\r\n \"name\" : \"SYD\",\r\n \"isEnable\" : false,\r\n \"isCurrent\" : false\r\n}"
below is my code
Train
public class Train {
public Train() {
}
private String name;
private String value;
private String Code;
private String countryName;
private String state;
private String stateName;
private boolean isEnable;
private boolean isCurrent;
//*getters and setters/*/
}
Controller calss
public ResponseEntity<String> getDetails( )
throws IOException {
ResponseEntity<String> responseEntity = null;
try(StringWriter writer = new StringWriter()) {
ObjectMapper mapper = new ObjectMapper();
Train train = new Train();
// set name and value to the train object//
if(train != null)
{
mapper.setSerializationInclusion(Inclusion.NON_NULL);
mapper.setSerializationInclusion(Inclusion.NON_EMPTY);
mapper.writerWithDefaultPrettyPrinter().writeValue(writer,
train);
responseEntity = new ResponseEntity<>(writer.toString(),
HttpStatus.OK);
}
}
catch()
{}
return responseEntity;
}
Configuration:
#Override
public void configureMessageConverters(
List<HttpMessageConverter<?>> converters) {
converters.add(extendedJsonConvertor());
super.configureMessageConverters(converters);
}
#Bean
public MappingJackson2HttpMessageConverter extendedJsonConvertor() {
MappingJackson2HttpMessageConverter mappingJackson2HttpMessageConverter = new MappingJackson2HttpMessageConverter();
mappingJackson2HttpMessageConverter
.setObjectMapper(getNullAndEmptyFilteredObjectMapper());
return mappingJackson2HttpMessageConverter;
}
#Bean
public ObjectMapper getNullAndEmptyFilteredObjectMapper() {
ObjectMapper objectMapper = new ObjectMapper();
objectMapper.setSerializationInclusion(JsonInclude.Include.NON_EMPTY);
objectMapper.configure(
DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);
return objectMapper;
}
When I debug the above code I came to know mapper include those \r\n in the response.Help me how to remove those slashes.
The problem is the line below.
mapper.writerWithDefaultPrettyPrinter().writeValue(writer,train);
Try replacing it with
mapper.writeValue(writer,train);
Why do you create a new object mapper when you are configuring, MappingJackson2HttpMessageConverter?
You can autowire the object mapper or return the actual object and let spring convert it to json
That's a "simple" double encoding issue i believe. You set a string in the response entity which is again writen as a json response.
If you want to rely on the spring view rendering (mappingjackson2httpmessageconverter) you have to create a response entity for "Train". (Or return a train instance directly from your controller method)
Or you use the way you implemented it and you have to ensure that rendering a string for a json response will not use the jackson message converter, but is left untouched by spring.