Java bubble sort help needed - java

Good evening,
My and my bud tried to figure out why the program won't bubble sort the names that we input, maybe someone could hint about it.
public static void sortDatPlane(String Ref[]){
int n = Ref.length;
int k = 1;
int j = n - 2;
int i;
while(k < n){
i = 0;
while (i <= j) {
if(notInOrder(Ref, i, i+1)){
swap(Ref, i, i+1);
}
i++;
}
k++;
}
for (String Ref1 : Ref) {
System.out.println(Ref1);
}
}
public static void swap(String Ref[], int i, int j){
String temp = Ref[i];
Ref[i] = Ref[j];
Ref[j] = temp;
}
public static boolean notInOrder(String Ref[],int i, int j){
return Ref[i].substring(0,1).compareTo(Ref[j].substring(0,1)) == 1;
}

As stated by Ken Y-N in the comments, you are only comparing the first characters of the strings (substring(0, 1) does this). Remove that part and it will probably work.

Related

Quicksort - Java

I'm implementing Quicksort but the answer does not display correctly. I have been finding the errors but don't know where I get wrong. The answer is still 3,5,1,8,6,7,9,2. Can someone tell me what is wrong in my code?
public class quicksortJava {
public static void main (String args[]) {
int A [] = {3,5,1,8,6,7,9,2};
quicksort(A,0,A.length-1);
for(int i = 0; i < A.length; i++ ){
System.out.print(A[i]+" ");
}
}
public static void quicksort(int[]A,int start,int end){
if (start < end){
int pIndex = partition(A,start,end);
quicksort(A,start,pIndex-1);
quicksort(A,pIndex+1,end);
}
}
public static int partition(int[]A,int start,int end){
int pivot = A[end];
int pIndex = start;
for (int i = start;i < end; i++){
if (A[i] <= pivot){
swap(A[i],A[pIndex]);
pIndex++;
}
}
swap(A[pIndex],A[end]);
return pIndex;
}
public static void swap(int A,int B){
int temp = A;
A = B;
B = temp;
}
Your swap method does not work, because you are only changing the local variables "A" and "B" within the method "swap". You are not actually changing anything in the list.
Try this:
public static void swap(int a, int b) {
int tmp = list[a];
list[a] = list[b];
list[b] = tmp;
}
You'll need to change all the calls to "swap", too, so they pass an index rather than a value.
(Also, Java variables are lowercase / camelCase, not uppercase. You have multiple variables called "A", which makes everything confusing.)
Here is the correct answer
public static int partition(int[]A,int start,int end){
int pivot = A[end];
int pIndex = start;
for (int i = start;i < end; i++){
if (A[i] <= pivot){
//swap(i,pIndex);
int temp = A[i];
A[i] = A[pIndex];
A[pIndex] = temp;
pIndex++;
}
}
//swap(A[pIndex],A[end]);
int temp = A[pIndex];
A[pIndex] = A[end];
A[end] = temp;
return pIndex;
}

StackOverFlow error for QuickSort Algorithm

I am getting a StackOverflowError for this code. It says lines 184/185, which is where I initialize the split position (see below) and call the first recursive quickSort method. I can see that the code is having trouble exiting from the recursion, but I'm not sure where that is happening. Each time I call quickSort, it is on a smaller partition.
import java.util.*;
public class java2{
public static int MAXINT = 10000;
public static int[] intArray = new int[MAXINT];
public static int index;
public static long comparisons;
public static void main(String[] args)
{
System.out.println("SORTING ALGORITHM: Quicksort");
// Create a random array of integers and sort using the CombSort algorithm
// Print the number of items and comparisions
for(index = 10; index <= 10000; index = index * 10)
{
if (index == 10)
for(int i = 0; i < index; i++)
System.out.print(intArray[i] + " ");
comparisons = 0;
generate(intArray, index);
quickSort(intArray, 0, index - 1);
output(comparisons);
}
}
// Generate an array of random values between 0 and 10000
public static void generate(int[] valueArray, int count)
{
Random generator = new Random();
for(int temp = 0; temp < count; temp++)
{
valueArray[temp] = generator.nextInt(MAXINT) + 1;
}
}
// Print the number of values in the array and the number of comparisons
public static void output(long count)
{
System.out.println("Number of values in array: " + index);
System.out.println("Number of comparisons required: " + count);
System.out.println();
}
//Swap the given values and then assign them to the correct place in the array
public static void swap(int[] value, int i, int j)
{
int temp = value[i];
value[i] = value[j];
value[j] = temp;
}
//Implement Quicksort algorithm
public static void quickSort(int[] value, int startIndex, int endIndex)
{
int r = endIndex;
int l = startIndex;
int s;
if (l < r)
{
s = partition(intArray, l, r);
quickSort(intArray, l, s - 1); // StackOverflowError here
quickSort(intArray, s + 1, r);
}
}
//Partition an array into two parts
public static int partition(int[] value, int startIndex, int endIndex)
{
int r = endIndex;
int l = startIndex;
int p = value[l];
int i = l;
int j = r + 1;
while(i < j)
{
while(value[i] < p)
{
i++;
comparisons++;
}
while(value[j] > p)
{
j--;
comparisons++;
}
swap(value, i, j);
}
swap(value, i, j);
swap(value, l, j);
return j;
}
} // end main
Here are a few things to get you started with debugging.
You haven't posted your swap, but it's almost certainly incorrect. The way you're using it, its prototype would be void swap(int, int, int, int) which means it cannot have any effect on the value array. Try something like this:
public static void swap(int[] value, int i, int j) {
int temp = value[i];
value[i] = value[j];
value[j] = temp;
}
and use it like this:
swap(value, i, j);
Next, get the length=10 case correct. Print out the full array before and after sort, verify that the output is correct. When I run your code on an all zero array I get an infinite loop.
Next, if you're still having problems, add print statements!
By restructuring the partition method, the problem has been fixed:
public static int partition(int[] value, int p, int r)
{
int x = value[p];
int i = p - 1;
int j = r + 1 ;
while (true)
{
do
{
j--;
comparisons++;
}
while (value[j] > x);
do
{
i++;
comparisons++;
}
while (value[i] < x);
if (i < j)
{
swap(value, i, j);
}
else
return j;
}
}

Iterative Quicksort steps?

I have to implement an iterative quicksort in java for homework.
i've search a lot about it but i couldn't find a website with a clear explanation about how to implement an iterative quicksort.
i have found this code in java, and it sorts very well, but i can't tell how does it work, i know how the recursive quicksort works though.
i've commented the code with my questions
public static void iterativeQsort(int[] arr) {
Stack<Integer> stack = new Stack<Integer>();
stack.push(0);
stack.push(arr.length);
while (!stack.isEmpty()) {
int end = stack.pop();
int start = stack.pop();
if (end - start < 2) continue;
int p = start + ((end-start)/2);
p = partition(arr,p,start,end);
stack.push(p+1);
stack.push(end);
stack.push(start);
stack.push(p);
}
}
private static int partition(int[] arr, int p, int start, int end) {
int l = start;
int h = end - 2; //what is h and l variables for and why h has to be end -2?
int piv = arr[p];
swap(arr,p,end-1);
while (l < h) {
if (arr[l] < piv) {
l++;
} else if (arr[h] >= piv) {
h--;
} else {
swap(arr,l,h);
}
}
int idx = h; // what is idx exactly?
if (arr[h] < piv) idx++;
swap(arr,end-1,idx);
return idx; //why return idx.
}
private static void swap(int[] arr, int i, int j) {
int temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
i'm mostly confused by the partition method, i don't know what it does.
if someone could explain me the main steps to make an iterative quicksort i'll be very happy.
Thanks for your help.

Sorting an array of strings in reverse alphabetical order in Java

I've been tasked with turning this code into a reverse sort, but for the life of me cannot figure out how to do it. These are my sort, findlargest and swap methods. I have a feeling I am missing something glaringly obvious here, any help would be really appreciated.
public static void sort(String[] arr)
{
for (int pass = 1; pass < arr.length; pass++)
{
int largestPos = findLargest(arr, arr.length - pass);
if (largestPos != arr.length - pass)
{
swap(arr, largestPos, arr.length - pass);
}
}
}
public static int findLargest(String[] arr, int num)
{
int largestPos = 0;
for (int i = 1; i <= num; i++)
{
if (arr[i].compareToIgnoreCase(arr[largestPos]) > 0)
{
largestPos = i;
}
}
return largestPos;
}
public static void swap(String[] arr, int first, int second)
{
String temp = arr[first];
arr[first] = arr[second];
arr[second] = temp;
}
}
Don't reinvent the wheel -
String[] strs = {"a", "b", "d", "c", "e"};
Arrays.sort(strs, Collections.reverseOrder(String.CASE_INSENSITIVE_ORDER));
System.out.println(Arrays.toString(strs));
[e, d, c, b, a]
Follow up from A. R. S.'s answer:
You could use a custom comparator if you are allowed to use the Arrays.Sort method...
Arrays.sort(stringArray, new Comparator<String>() {
#Override
public int compare(String t, String t1) {
return -t.compareToIgnoreCase(t1); //reverse the comparison, while ignoring case
}
});
Can you just turn findLargest to findSmallest, like this:
public static void sort(String[] arr) {
for (int pass = 1; pass < arr.length; pass++) {
int largestPos = findSmallest(arr, arr.length - pass);
if (largestPos != arr.length - pass) {
swap(arr, largestPos, arr.length - pass);
}
}
}
public static int findSmallest(String[] arr, int num) {
int largestPos = 0;
for (int i = 1; i <= num; i++) {
if (arr[i].compareToIgnoreCase(arr[largestPos]) < 0) {
largestPos = i;
}
}
return largestPos;
}
public static void swap(String[] arr, int first, int second) {
String temp = arr[first];
arr[first] = arr[second];
arr[second] = temp;
}
I think This is the one you need (if you don't think about collection framework).
public static void main(String args[]) {
String [] arr ={"abc","bac","cbc"};
String temp="";
for(int i=0;i<arr.length;i++){
for(int j=i+1;j<arr.length;j++){
if(arr[j].compareTo(arr[i]) > 0){
temp = arr[i] ;
arr[i] = arr[j];
arr[j] = temp;
}
}
}
for(String val:arr){
System.out.println(val);
}
}
Output is
cbc
bac
abc
you can use Arrays.sort(arr) to sort in alphabetical order.
and then reverse it.
public static void sort(String[] arr) {
Arrays.sort(arr);
for (int i=0; i<arr.length/2; i++) {
swap(arr,i,arr.length-1-i);
}
}
Try this one if you want. In your version you are moving the largest towards the end of the array, resulting in alphabetical order.
Just in case you insist on your original approach, I have made some minor changes to your code:
public static void sort(String[] arr)
{
for (int pass = 1; pass < arr.length; pass++)
{
int largestPos = findLargest(arr, pass-1);
if (largestPos != pass - 1)
{
swap(arr, largestPos, pass - 1);
}
}
}
public static int findLargest(String[] arr, int num)
{
int largestPos = num;
for (int i = num+1; i < arr.length; i++)
{
if (arr[i].compareToIgnoreCase(arr[largestPos]) > 0)
{
largestPos = i;
}
}
return largestPos;
}
The most trivial one though, as suggested by Ian Roberts, is simply Arrays.sort(arr, Collections.reverseOrder());.
So, first we need to create String array, then use Arrays.sort(String[]);, then use for to reverse sort array to reverse order.
import java.util.Arrays;
public class SortClass {
public static void main(String[] args) {
String[] arrayString = new String[5];
arrayString[0] = "Cat";
arrayString[1] = "Apple";
arrayString[2] = "Dog";
arrayString[3] = "Mouse";
arrayString[4] = "kitchen";
Arrays.sort(arrayString);
String[] arrReverse = new String[arrayString.length];
for (int i = arrayString.length - 1; i >= 0; i--) {
arrReverse[arrayString.length - 1 - i] = arrayString[i];
}
}
}
String arr[]= new String[];
String s; //input string
int count=0;
for(int i=0;i<=s.length()-k;i++){
arr[i]=s.substring(i,i+k); //using substring method
count++;
}
int i=0;
int b=count;
while(count>0){
int j=0;
while(j<b){
if((arr[i].compareTo(arr[j])>0)){
String temp= arr[i];
arr[i]=arr[j];
arr[j]=temp;
}
j++;
}
i++;
count--;
}
for(i=0;i<b;i++)
System.out.println(arr[i]);

Array Out Of Bounds

The purpose of this program is to find the kth smallest element in an array without sorting the array using a recursive and nonrecursive decrease and conquer type method.
I was hoping someone could look over my code and try to help me with my array out of bounds error(s).
The method that is throwing these errors is the recursive selection the non recursive selection works fine.
My driver is also attached and everything should compile if you want to test my code.
public class KthSmallest
{
private int counter;
private int term;
private int[] A;
int SelectionNonRecursive(int A[], int kthSmallest, int sizeOfA)
{
this.A = A;
if(kthSmallest == 1 || kthSmallest == sizeOfA)
{
return (LinearSearch(kthSmallest, sizeOfA));
}
else
{
for(int i = 0; i<sizeOfA; i++)
{
counter = 0;
for(int j = 0; j<sizeOfA; j++)
{
if(A[i] < A[j])
{
counter++;
}
}
if((sizeOfA - counter) == kthSmallest)
{
return A[i];
}
}
}
return 0;
}
int SelectionRecursive(int A[], int kthSmallest, int sizeOfA)
{
this.A = A;
return Selection_R(0, sizeOfA - 1, kthSmallest);
}
int Selection_R(int l, int r, int kthSmallest)
{
if(l<r)
{
if(kthSmallest == 1 || kthSmallest == A.length)
{
return (LinearSearch(kthSmallest, A.length));
}
else
{
int s = LomutoPartition(l, r);
if(s == kthSmallest - 1)
{
return A[s];
}
else if(s > (A[0] + kthSmallest - 1))
{
Selection_R(l, s-1, kthSmallest);
}
else
{
Selection_R(s+1, r, kthSmallest);
}
}
}
return 0;
}
int LomutoPartition(int l, int r)
{
int pivot = A[l];
int s = l;
for(int i = l+1; i<r; i++)
{
if(A[i] < pivot)
{
s += 1;
swap(A[s], A[i]);
}
}
swap(A[l], A[s]);
return s;
}
public void swap(int i, int j)
{
int holder = A[i];
A[i] = A[j];
A[j] = holder;
}
int LinearSearch(int kthSmallest, int sizeOfA)
{
term = A[0];
for(int i=1; i<sizeOfA; i++)
{
if(kthSmallest == 1)
{
if(term > A[i])
{
term = A[i];
}
}
else
{
if(term < A[i])
{
term = A[i];
}
}
}
return term;
}
}
public class KthDriver
{
public static void main(String[] args)
{
KthSmallest k1 = new KthSmallest();
int[] array = {7,1,5,9,3};
System.out.print(k1.SelectionRecursive(array, 3, array.length));
}
}
Inside your LomutoPartition method, you are passing the array elements in your swap method: -
swap(A[s], A[i]); // Inside for loop
and
swap(A[l], A[s]); // Outside for loop
And your swap method considers them as indices: -
public void swap(int i, int j) <-- // `i` and `j` are elements A[s] and A[i]
{
int holder = A[i]; <-- // You are accessing them as indices(A[i] -> A[A[s]])
A[i] = A[j];
A[j] = holder;
}
That is why you are getting that exception. Because, if any element in array is greater than size, it will blast out.
You should change your invocation to: -
swap(s, i); // Inside for loop
and
swap(l, s); // Outside for loop
respectively. And leave your method as it is.
Note that, you should pass array indices, and not array elements. If you pass array elements, then the swapping in the method will not be reflected in your array. Because, your method will have its own copy of your elements.

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