I need to write code that asks you to guess a number between 1 and 10 and uses a loop. It has to use the System.in.read() method to take user input. The correct number is 7, and when you guess that it ends. If you guess wrong it tells you to try again. I don't know why my code isn't working right, so I could use some help. The output I get is weird, no matter what number I enter it just says:
Hello! Enter a number between 1 and 10:
(entered number ex. 4)
Your guess is too high
Hello! Enter a number between 1 and 10:
Your guess is too high
Hello! Enter a number between 1 and 10:
I am new to programming so sorry if it isn't indented right or the solution is obvious.
public static void main(String[] args) throws java.io.IOException {
int input;
boolean play = true;
while (play == true) {
System.out.println("Hello! Enter a number between 1 and 10: ");
input = System.in.read();
if (input > 7) {
System.out.println("Your guess is too high");
} else if (input < 7) {
System.out.println("Your guess is too low");
} else if (input == 7) {
System.out.println("Correct! the correct number was: 7");
}
}
}
It should give you a specific result depending on the number, like if it is too high or low, then you can try again and enter a new number until you get the correct answer of 7. If the number isn't 1-10 you should get an error message. Thanks.
You're not changing the play variable, so there is no goin out of the while loop. You would have to change it like this:
else if (input == 7) {
System.out.println("Correct! the correct number was: 7");
play = false;
}
Also you might want to move this line: System.out.println("Hello! Enter a number between 1 and 10: "); before while loop.
This might solve your problem.
public static void main(String[] args) {
int input;
boolean play = true;
Scanner inputNumber = new Scanner(System.in);
while (play) {
System.out.println("Hello! Enter a number between 1 and 10: ");
input = inputNumber.nextInt();
if (input > 7) {
System.out.println("Your guess is too high");
} else if (input < 7) {
System.out.println("Your guess is too low");
} else if (input == 7) {
System.out.println("Correct! the correct number was: 7");
play = false;
}
}
}
Related
I am fully aware this question has been asked many times, it is a classic first year problem in CSC. I am not looking for the solution to the problem itself. I think I have it basically done however I am missing something that I cannot find how to do.
Here is my code:
import java.util.Scanner;
import java.util.Random;
public class HiLow
{
public static void main (String[] args)
{
Random generator = new Random();
Scanner scan = new Scanner(System.in);
int num1,guess;
int count = 0;
num1 = generator.nextInt(100) + 1;
while(true) {
System.out.print("Enter an integer between 1 or 100 or enter 0 at anytime to quit: ");
guess = scan.nextInt();
count++;
if(guess == num1 || guess == 0) {
if(guess == 0) {
System.out.println("Thanks for playing");
break;
}
System.out.println("Congrats you've guessed correct and your total guesses is " + count );
break;
}
else if (guess > 100 || guess < 1) {
System.out.print("I see you cannot follow instructions. I said ");
count--;
}
else if (guess > num1) {
System.out.println("You have guessed too high. ");
}
else {
System.out.println("You have guessed too low.");
}
}
}
}
My problem is i am required to prompt the user at the point of "if the user quits or successfully guesses the correct number, prompt the user to see if they wish to play again". I am lost and not sure how to continue my while loop from the beginning after my breaks. Is there a way to end the break condition i have from (guess == num1 || guess ==0) and direct my program to start again at the while(true) statement?
Thanks
I will say search up continue;
Tips to help further:
The continue statement is used to bring the loop back to the start, try it instead of a break where you want the user to continue.
You need some sort of check if the user wants to continue, (try asking them to type in some specific int you check, p.s negative numbers are integers as well)
#Ahmed thinks you should continue, I would rather not break, or conditionally break.
Well there are multiple ways you could accomplish this, One would be to just to prompt the user with a "press q to quit" dialogue using the Scanner class where .next() returns the String when the user hits enter:
if(guess == num1 || guess == 0) {
if(guess == 0) {
System.out.println("Thanks for playing");
}else{
System.out.println("Congrats you've guessed correct and your total guesses is " + count );
}
System.out.println("would you like to play again [y/n]?");
if(scan.next().equals("y")){
num1 = generator.nextInt(100) + 1;
count=0;
}else{
break;
}
}
If thats what you mean. Hopefully I helped.
or maybe you can have it only quit at zero, if so just remove that second break and replace it with num1 = generator.nextInt(100) + 1; to set the new value to guess.
I am still new to Java and as such I am still figuring some things out. I have been having issues with including code asking the user if they want to play again. I have attempted putting it in the main class in a print statement which gave me an error. After that, I attempted putting it in the Guess.java class in multpile places but I just recieved errors. I have read up on the issue and some sites have suggested a while loop but I am unsure how to implement it into my current code. I have included both the main class which is called GuessingGame.java and the Guess.java class below. Thank you for any assistance that can be provided.
GuessingGame.java
public class GuessingGame {
public static void main(String[] args) {
new Guess().doGuess();
}
}
Guess.java
class Guess {
private int answer = 0;
int tries = 0;
Scanner input = new Scanner(System.in);
int guess, i;
boolean win = false;
int amount = 10;
public Guess() {
answer = generateRandomNumber();
}
//Generate a private number between 1 and a thousand
private int generateRandomNumber() {
Random rand = new Random();
return rand.nextInt(1000) + 1;
}
public void doGuess() {
while (!win) {
System.out.println("You are limited to ten attempts."
+ " Guess a number between 1 and 1000: ");
guess = input.nextInt();
if (tries > 9) {
System.out.println("You should be able to do better!"
+ " You have hit your ten guess limit. The number"
+ " was: " + answer);
System.out.println("Do you want to play again?: ");
return;
}
if (guess > 1000) {
System.out.println("Your guess is out of the range!");
} else if (guess < 1) {
System.out.println("Your guess is out of the range!");
} else if (guess == answer) {
win = true;
tries++;
} else if (guess < answer && i != amount - 1) {
System.out.println("Your guess is too low!");
tries++;
} else if (guess > answer && i != amount - 1) {
System.out.println("Your guess is too high!");
tries++;
}
}
System.out.println("Congragulations! You guessed the number!"
+ "The number was: " + answer);
System.out.println("It took you " + tries + " tries");
}
}
You already found a good position for adding this functionality:
System.out.println("Do you want to play again?: ");
The first step now is to also tell the user what he/she should enter after that question:
System.out.println("Do you want to play again? (enter 0 for yes and 1 for no): ");
After that we need to get the user input of course:
int number;
//If the user enters e.g. a string instead of a number, the InputMismatchException
//will be thrown and the catch-block will be executed
try {
number = input.nextInt();
//If number < 0 OR number > 1
if(number < 0 || number > 1) {
//The rest of the try-block will not be executed.
//Instead, the following catch-block will be executed.
throw new InputMismatchException();
}
break;
}
catch(InputMismatchException e) {
System.out.println("Enter 0=yes or 1=no");
//Clears the scanner to wait for the next number
//This is needed if the user enters a string instead of a number
input.nextLine();
}
If you don't know about try-catch-statements yet, I suggest to read this explanation. For details about the InputMismatchException, please see the documentation.
The problem now is that the user only has one chance to enter 0 or 1. If the user makes a wrong input the program will just stop. One solution to this problem is to just put the code in a while-loop:
int number;
while(true) {
try {
number = input.nextInt();
if(number < 0 || number > 1) {
throw new InputMismatchException();
}
break;
}
catch(InputMismatchException e) {
System.out.println("Enter 0=yes or 1=no");
input.nextLine();
}
}
After this block, we can be sure that number is either 0 or 1. So now we can add a simple if-statement to check the value:
if(number == 0) {
new Guess().doGuess();
}
return;
So all in all the code looks like this:
System.out.println("Do you want to play again? (enter 0 for yes and 1 for no): ");
int number;
while(true) {
try {
number = input.nextInt();
if(number < 0 || number > 1) {
throw new InputMismatchException();
}
break;
}
catch(InputMismatchException e) {
System.out.println("Enter 0=yes or 1=no");
input.nextLine();
}
}
if(number == 0) {
new Guess().doGuess();
}
return;
Don't forget to add the following import-statements:
import java.util.Scanner;
import java.util.InputMismatchException;
import java.util.Random;
Try this. Basically, if the user responds with "yes" , we will call the function again.
if (tries > 9) {
System.out.println("You should be able to do better!"
+ " You have hit your ten guess limit. The number" + " was: " + answer);
System.out.println("Do you want to play again? (yes/no): "); // modified line
if("yes".equalsIgnoreCase(input.next())){ // newly added if block
answer = generateRandomNumber();
tries=0;
i=0;
win = false;
doGuess();
}
return;
}
I am struggling to correctly loop the code I have written to convert integers to roman numerals.
I have tried implementing a do while loop to run the code starting at "please enter an integer" and ending after my switch statement with the while part being: while(case "y" || "Y" == true )
Any help would be greatly appreciated. I have been searching through previous posts on stack overflow for a couple hours now and haven't been able to find anything that helps.
public class project8
{
/**
* Constructor for objects of class Project4
*/
public static void main(String[] args) {
System.out.println("Welcome to my integer Roman numeral conversion program");
System.out.println("------------------------------------------------------");
System.out.println(" ");
Scanner in = new Scanner (System.in);
System.out.print("Enter an integer in the range 1-3999 (both inclusive): ");
int input = in.nextInt();
if (input < 0 || input > 3999){
System.out.println("Sorry, this number is outside the range.");
System.out.println("Do you want to try again? Press Y for yes and N for no: ");
String userInput = in.next();
switch (userInput) {
case "N":
case "n":
System.exit(0);
break;
case "Y":
case "y":
break;
}
}
else if (input > 0 && input < 3999);
{ System.out.println(Conversion.Convert(input));
}
}
}
1) Your if - else if conditions are redundant. You can use a simple if - else as input can only be in that range or not. else if makes only sence if you had two or more ranges to check, e.g.
if(input > 0 && input < 3999){
...
}
else if (input > 4000 && input < 8000){
...
}
else {
...
}
2) You don't need a switch block instead use the user input in your while condition as you want to continue looping when user input is Y/y, i.e while(userChoice.equals("Y"))
3) Use a do - while loop as you want that your application to run at least on time
public static void main(String[] args) {
System.out.println("Welcome to my integer Roman numeral conversion program");
System.out.println("------------------------------------------------------");
System.out.println(" ");
Scanner in = new Scanner (System.in);
String choice;
do{
System.out.print("Enter an integer in the range 1-3999 (both inclusive): ");
int input = in.nextInt();
if(input > 0 && input < 3999){
System.out.println(Conversion.Convert(input));
}
else{
System.out.println("Sorry, this number is outside the range.");
}
System.out.println("Do you want to try again? Press Y for yes and N for no: ");
choice = in.next();
}while(choice.equals("Y") || choice.equals("y"));
}
new to programming.
I have a class in java and i'm trying to write this program but it's printing none-stop and it's even bugging my browser! (Im using an online ide)
my instructions:
Q: how much do you love me?
Below 10 : wrong answer
equal to 10 and more = good answer
I know how to do it but I dont want the program to stop every time i write an answer. I want the program to keep running until i have a 10 +. So i can always input until it's 10+ out of 10.
this is my lines :
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner input = new Scanner (System.in);
System.out.println ("how much do you love me out of 10");
int num1 = input.nextInt();
while (true)
if (num1 <= 9) {
System.out.println("Wrong answer");
}
else {
System.out.println ("Good answer");
}
}
}
This should work:
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner (System.in);
System.out.println ("Out of 10, how much do you love me?");
int input = 0
while (input <= 9) {
input = scanner.nextInt();
if (input <= 9) {
System.out.println("Wrong answer");
} else {
System.out.println("Good answer");
}
}
}
}
Explanation: It loops until input is less not less than or equal to 9 (while (input <= 9)). Each time through the loop, it gets input and acts on it.
Hope this helps!
First off, you need to move the int num1 = input.nextInt(); statement inside your while loop, this will allow for a new input every time the while loop loops (iterates).
Second, if you are looking to run the program until num1 >= 10, then you could implement it in two ways.
while(num1 < 10) {
num1 = input.nextInt();
if(num1 >= 10) {
System.out.println("Good answer");
} else {
System.out.println("Wrong answer");
}
}
or using the keyword break,
while(true) {
num1 = input.nextInt();
if(num1 >= 10) {
System.out.println("Good answer");
break;
} else {
System.out.println("Wrong answer");
}
}
break simply escapes the loop it resides in when called
Hoped this helped
I have two questions regarding my code.
Why does is the output "Oops please enter a number between 1 and 6" when I enter a number between 1 and 6. When I try to be more specific and make an else if statement, nothing happens when I enter a number NOT between 1 and 6.
How do I restart my program? In my code, there is an if statement
when the user inputs "play again" My commented out line reads
Mastermind.main() to re run the program, but that didn't work.
Here is the code:
import java.util.Scanner;
public class Mastermind {
public static void main (String [] args) {
// boolean variable to signal when the game is over.
boolean done = false;
// Scanner object
Scanner scanner = new Scanner(System.in);
// sets the value to twelve outside the loop so it doesn't set back each time.
int guesses = 12;
System.out.println("Please enter a number between 1-6 to begin (or \"quit\") to exit.");
// while loop for the game
while (!done) {
//System.out.println("Please enter a number between 1-6 (or \"quit\") to exit the game:");
// user input
String input = scanner.nextLine();
int number = 0; //Just initialized to some number
// checks to see if the user wants to quit the game.
if (input.equalsIgnoreCase("quit")) {
System.out.println("Goodbye!");
done = true;
scanner.close();
}
else{
try{
//Trying to see if the input was a number
number = Integer.parseInt(input);
}
catch(Exception e){
//The input wasn't an integer, it's invalid the starts loop again.
System.out.println("Invalid input.");
continue;
}
}
// defines necessary int variables
int random1 = (int) (Math.random() * 7);
int random2 = (int) (Math.random() * 7);
int random3 = (int) (Math.random() * 7);
int random4 = (int) (Math.random() * 7);
// If the user doesn't and decides to play, it runs this code.
// checks to see if the user enters a number between 1-6
if (number >= 1 && number <= 6) {
if (number == random1) {
System.out.println("You guessed a correct number!");
guesses--;
System.out.println("guesses = " + guesses);
}
else if (number == random2) {
System.out.println("You guessed a correct number!");
guesses--;
System.out.println("guesses = " + guesses);
}
else if (number == random3) {
System.out.println("You guessed a correct number!");
guesses--;
System.out.println("guesses = " + guesses);
}
else if (number == random4) {
System.out.println("You guessed a correct number!");
guesses--;
System.out.println("guesses = " + guesses);
}
else {
System.out.println("Sorry that's not one of the numbers! Try again.");
guesses--;
System.out.println("guesses = " + guesses);
}
}
if (guesses == 0){
System.out.println("You've run out of guesses. To play again, enter \"play again\". Otherwise, enter or \"quit\")");
if (input.equalsIgnoreCase("play again")){
// how do I restart the program?
//Mastermind.main(); // QUESTION 2
}
else if (input.equalsIgnoreCase("quit")){
System.out.println("Goodbye!");
done = true;
scanner.close();
}
else {
System.out.println("Goodbye!");
done = true;
scanner.close();
}
}
else { //QUESTION 1
System.out.println("Oops! Please choose a number between 1 and 6");
}
}
}
}
You're printing that message every time through the loop whenever guesses == 0 evaluates to false. You probably just need to switch the order of the two blocks. Instead of this:
if (number >= 1 && number <= 6) {
...
}
if (guesses == 0) {
...
}
else { //QUESTION 1
System.out.println("Oops! Please choose a number between 1 and 6");
}
Use this:
if (number >= 1 && number <= 6) {
...
}
else { //QUESTION 1
System.out.println("Oops! Please choose a number between 1 and 6");
}
if (guesses == 0) {
...
}
Regarding restarting your program: if I'm reading the logic correctly, all you need to do is keep done set to false and reset guesses to 12.
Two other logic points. First, you should probably either continue or break after detecting that the user has entered "quit". Second, it seems like you are generating four new random integers for every user guess. I don't know if that's what you intended, but you might want to change the logic a bit. That might also affect the restart logic.