This question already has answers here:
How to find out the number of CPUs using python
(15 answers)
Closed 3 years ago.
In Java, this will return the number of available processors:
Runtime.getRuntime().availableProcessors()
This is handy when deciding how many long running threads to create.
Is there an equivalent function to call in Python?
Here you go, there are definitely duplicate answers out there
import os
os.cpu_count()
With python 2.6 or greater ,
multiprocessing.cpu_count()
Related
This question already has answers here:
Large Numbers Requiring More than 64 bit Representation
(5 answers)
Closed 2 years ago.
In a project that is related to security,
it is required to deal with very huge prime numbers such as:
3136666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666313
I am using java, and as it is know that maximum number that could be declared is 64-bits (type long)
So is there any approach to deal with these numbers?
You can use BigDecimal from java.math package:
BigDecimal longerThanLong = new BigDecimal("9223372036854775808");
This question already has answers here:
How can I represent a range in Java?
(9 answers)
Closed 4 years ago.
I am looking for a Range API in JDK8 which also exports some static utilities , but no luck uptill now. I am working on a interval scheduling algorithm which needs one.If not I will work to create a custom interface .
I not sure, perhaps Google Guava has what you need:
https://github.com/google/guava/wiki/RangesExplained
or perhaps Google can help ;)
This question already has answers here:
Pseudorandom Number Generator - Exponential Distribution
(9 answers)
Java exponential distribution
(1 answer)
Closed 5 years ago.
I am given a mean of 5. I need to generate a random number (exponentially distributed) in Java.
I know for Python, you can just run something like random.expovariate(5), but I'm not sure how to solve this for Java. Can anyone help me out?
see here. What you are looking for is something like this:
public double getNext() {
return Math.log(1-rand.nextDouble())/(-lambda);
}
(code taken from here)
This question already has answers here:
Different behaviour of java bytecode
(6 answers)
Closed 7 years ago.
Why do we have the iconst_* instructions?
Why would I ever want to use these instead of bipush?
I found this StackOverflow question when searching but it does not properly answer my question.
Because a bipush instruction takes two bytes in the bytecode, and an iconst_* instruction takes one byte.
This question already has answers here:
Raising a number to a power in Java
(10 answers)
Closed 8 years ago.
Could anyone explain to me why
System.out.println(100*(1-10^(-10/10)));
results in the number "800" being printed out? The correct answer is 90 when you use a calculator. How would I go about doing this calculation in Java?
Thanks!
The ^ operator does not do what you think it does. It is bitwise-xor
You need to look into the Math.pow() method.