I am trying to get the file path of a file from a file picker.
My problem is, that when I output the file path in text form, I get the following output:
file:/storage/emulated/~rest_of_path~
I assume, to access the file, the path should begin something like this:
file:///storage/emulated/~rest_of_path~
or at least file://
Why do I only get file:/ i.e a single slash.
The code in charge for getting the file path:
...
File fileToImport = new File(actualfilepath);
String tempPath = uri.getPath();
if (tempPath.contains("//")){
tempPath = tempPath.substring(tempPath.indexOf("//")+1);
}
if ( actualfilepath.equals("") || actualfilepath.equals(" ")) {
fileToImport = new File(tempPath);
}else {
fileToImport = new File("file://"+actualfilepath);
}
// TODO: 2019-06-04
functionforfile(fileToImport)
filePath.setText(fileToImport.toString());
The text view for the code filePath.setText(fileToImport.toString());
shows me the file path for debug purpose only
if fileToImport = new File("file://"+actualfilepath); has File("file://"actualfilepath) instead, it outputs the file path without file:// which I understand, but why do the two // get removed when I add "file://" + actualfilepath
How could I add the correct file:///
Thanks in advance
Related
I'm trying to get the directory path to a file. The issue I am having is getting the last \ or / of the directory. As this code is supposed to work on all operating systems, I can't seem to find any solution for this. Any help is appreciated.
My code so far:
System.out.print("Enter dir: ");
String path = kb.nextLine();
File pathes = new File(path);
String path2 = pathes.getParent();
path = path.substring(0, path.lastIndexOf("\\")+1);
System.out.println("PATH: " + path);
System.out.println("PATH2: "+path2);
My output is:
PATH: C:\Users\User\Desktop\test\
PATH2: C:\Users\User\Desktop\test
This is just test code and not the real code I'm working on.
EDIT
What I'm trying to get is
C:\Users\User\Desktop\test\
from
C:\Users\User\Desktop\test\test.txt
To get the absolute path to the parent directory you can do:
File f = new File("C:\\Users\\User\\Desktop\\test\\test.txt");
String path = f.getParentFile().getAbsolutePath();
System.out.println(path);
Output:
C:\Users\User\Desktop\test
If you really want the trailing slash, then you can just append File.separator:
File f = new File("C:\\Users\\User\\Desktop\\test\\test.txt ");
String path = f.getParentFile().getAbsolutePath() + File.separator;
System.out.println(path);
Output:
C:\Users\User\Desktop\test\
I want to upload files and save them into specific directory.And i am new to files concept.When i uploading files from my page they are saved in another directory(C:\Users\ROOTCP~1\AppData\Local\Temp\multipartBody989135345617811478asTemporaryFile) and not in specified directory.I am unable to set it.Please help me in finding a solution.For all help thanks in advance.
public static Result uploadHoFormsByHeadOffice() throws Exception {
Logger.info("#C HoForms -->> uploadHoFormsByHeadOffice() -->> ");
final String basePath = System.getenv("INVOICE_HOME");
play.mvc.Http.MultipartFormData body = request().body()
.asMultipartFormData(); // get Form Body
StringBuffer fileNameString = new StringBuffer(); // to save file path
// in DB
String formType = body.asFormUrlEncoded().get("formType")[0];// get formType from select Box
FilePart upFile = body.getFile("hoFiles");//get the file details
String fileName = upFile.getFilename();//get the file name
String contentType = upFile.getContentType();
File file = upFile.getFile();
//fileName = StringUtils.substringAfterLast(fileName, ".");
// path to Upload Files
File ftemp= new File(basePath +"HeadOfficeForms\\"+formType+"");
//File ftemp = new File(basePath + "//HeadOfficeForms//" + formType);
File f1 = new File(ftemp.getAbsolutePath());// play
ftemp.mkdirs();
file.setWritable(true);
file.setReadable(true);
f1.setWritable(true);
f1.setReadable(true);
//HoForm.create(fileName, new Date(), formType);
Logger.info("#C HoForms -->> uploadHoFormsByHeadOffice() <<-- Redirecting to Upload Page for Head Office");
return redirect(routes.HoForms.showHoFormUploadPage());
}
}
I really confused why the uploaded file is saved in this(C:\Users\ROOTCP~1\AppData\Local\Temp\multipartBody989135345617811478asTemporaryFile) path.
You're almost there.
File file = upFile.getFile(); is the temporary File you're getting through the form input. All you've got to do is move this file to your desired location by doing something like this: file.renameTo(ftemp).
Your problem in your code is that you're creating a bunch of files in memory ftemp and f1, but you never do anything with them (like writing them to the disk).
Also, I recommend you to clean up your code. A lot of it does nothing (aforementioned f1, also the block where you're doing the setWritable's). This will make debugging a lot easier.
I believe when the file is uploaded, it is stored in the system temporary folder as the name you've provided. It's up to you to copy that file to a name and location that you prefer. In your code you are creating the File object f1 which appears to be the location you want the file to end up in.
You need to do a file copy to copy the file from the temporary folder to the folder you want. Probably the easiest way is using the apache commons FileUtils class.
File fileDest = new File(f1, "myDestFileName.txt");
try {
FileUtils.copyFile(ftemp, fileDest);
}
catch(Exception ex) {
...
}
I have a few PDF files in the assets folder of a Grails 3 application. I want to load them when the user clicks some button. i.e User clicks button "Get first book", and a grails controller looks for all files in the assets folder until it finds a match, and then returns the correct one.
Currently, I am loading the files by directly accessing the path. i.e. I am using an explicit aboslute path. According to this post, this is one of the advisable approaches. However, I want to load a file in grails by asking my application to get all assets in the asset folder, instead of using any paths.
My question then is, is it possible to get all files from the assets folder in a simple manner like we can get properties in the yml file (grailsApplication.config.someProperty)
Found the solution here: Grails : getting assets local storage path inside the controller
The following sample:
def assetResourceLocator
assetResourceLocator.findAssetForURI('file.jpg')?.getInputStream()?.bytes
worked fine for me.
this code makes something similar for me (however, my files are located outside of my project directory). Its a controller method, that receives the file name (id) and the filetype (filetype) and looks in a predefined directory. I think you just have to adapt your "serverLocation" and "contentLocation".
To get a list of the files, which you can pass to the view:
List listOfNewsletters = []
String contentLocation = grailsApplication.config.managedNewsletter.contentLocation;
File rootDirectory = new File(servletContext.getRealPath("/"));
File webappsDirectory = rootDirectory.getParentFile();
String serverLocation = webappsDirectory.getAbsolutePath();
serverLocation = serverLocation + contentLocation + "/";
File f = new File(serverLocation);
if (f.exists()) {
f.eachFile() { File file ->
listOfNewsletters.push([
path: file.path,
filename: file.name,
filetype: "pdf"
])
}
}
To deliver the file:
def openNewsletter() {
if (params.id != null && params.filetype != null) {
String pdf = (String) params.id + "." + (String) params.filetype;
String contentLocation = grailsApplication.config.managedNewsletter.contentLocation;
File rootDirectory = new File(servletContext.getRealPath("/"));
File webappsDirectory = rootDirectory.getParentFile();
String serverLocation = webappsDirectory.getAbsolutePath();
serverLocation = serverLocation + contentLocation + "/";
File pdfFile =new File(serverLocation + pdf);
response.contentType = 'application/pdf' // or whatever content type your resources are
response.outputStream << pdfFile.getBytes()
response.outputStream.flush()
}
}
I created a desktop project in netbeans, in the project folder I have three files : file.txt, file2.txt and file3.txt, in the load of the program I want to call these three files, and this is the code I tried :
public void run() {
Path path = Paths.get("file.txt");
Path path2 = Paths.get("file2.txt");
Path path3 = Paths.get("file3.txt");
if(Files.exists(path) && Files.exists(path2) && Files.exists(path3)) {
lireFichiers();
}else{
JOptionPane.showConfirmDialog(null, "Files didn't found !");
}
}
but when I run my program I get the message : "Files didn't found !" which means he didn't found those files.
those files are created by this code :
File file = new File("Id.txt");
File file2 = new File("Pass.txt");
File file3 = new File("Remember.txt");
The following three lines will only create file handlers for your program to use. This will not create a file by itself. If you are using the handler to write it will also create a file for you provided you close correctly after writing.
File file = new File("Id.txt");
File file2 = new File("Pass.txt");
File file3 = new File("Remember.txt");
So, a sample code will look like:
File file = new File("Id.txt");
FileWriter fw = new FileWriter(file);
try
{
// write to file
}
finally
{
fw.close();
}
If the file is in the root of your project, this should work:
Path path = Paths.get("foo.txt");
System.out.println(Files.exists(path)); // true
Where exatlcy are the files you want to open in your project?
Please specify the language you use.
Generally you could search the file to see whether the files are in the program bootup folder. For webapps you should pay attention to the "absolute path and the relative path".
=========Edit============
If you are using Jave, then the file should be write out using FileWriter.close() before you can find them in your hard disk.
Ref
Thank you all for your help, I just tried this :
File file = new File("Id.txt");
File file2 = new File("Pass.txt");
File file3 = new File("Remember.txt");
if(file.exists() && file2.exists() && file3.exists()){
// manipulation
}
and it works
This is probably a very basic question but I tried various options and it didn't work out and hence requesting help. I want to create a file inside a specified directory. If the file already exists, I want to append data to it. Below is what I tried:
var DirectoryName: String = "LogFiles"
var dir: File = new File(DirectoryName);
dir.mkdir();
var ActorID: String = "1"
var FileName: String = DirectoryName + File.separator + "Actor_" + ActorID + ".log"
val FileObj: File = new File(FileName)
// FileObj.getParentFile().mkdirs();
// FileObj.createNewFile();
var FileWriterObj: FileWriter = null
var FileExistsFlag = 0
if (!FileObj.exists())
{
FileWriterObj = new FileWriter(FileObj.getName())
}
else
{
FileWriterObj = new FileWriter(FileObj.getName(), true)
FileExistsFlag = 1
}
var writer = new PrintWriter(FileWriterObj)
if(FileExistsFlag == 0)
writer.write("new file")
else
writer.append("appending to old file")
Internet search asks to use the below:
FileObj.getParentFile().mkdirs();
FileObj.createNewFile();
But it creates empty files inside the directory and creates new files outside the directory and appends to it. And also few posts suggests that there is no need to use createNewFile() to create a file.
I tried giving various path formats like below:
var DirectoryName: String = "../LogFiles"
var DirectoryName: String = "/home/ms/Desktop/Project/LogFiles"
But still it does not create the files inside the directory.
Can you please point me what I'm missing?
OS: Ubuntu 12.04
You should be using FileObj.getAbsolutePath, rather than FileObj.getName. getName just returns the name of the file, which explains why it was always being placed in the current directory.
The empty files issue could be solved by calling writer.close() at the end of your function. I don't think it's necessary to use createNewFile