I make a post request to my rest controller and as a result I want to get information about the error in case of incorrect data. Error information is generated in #RestControllerAdvice.
Here is my advice class:
#RestControllerAdvice
public class RestControllerErrorHandler {
#ExceptionHandler(MethodArgumentNotValidException.class)
#ResponseStatus(HttpStatus.BAD_REQUEST)
public Map<String, Object> handleCustomerException(MethodArgumentNotValidException exception) {
Map<String, Object> body = new LinkedHashMap<>();
body.put("timestamp", new Date());
body.put("exception", "MethodArgumentNotValidException");
List<String> errors = exception
.getBindingResult()
.getFieldErrors()
.stream()
.map(DefaultMessageSourceResolvable::getDefaultMessage)
.collect(Collectors.toList());
body.put("errors", errors);
return body;
}
}
Here is the result of the error that I get.
{
"timestamp": "2020-07-07T20:20:44.778+00:00",
"exception": "MethodArgumentNotValidException",
"errors": [
"Login length: 6 - min and 10 - max",
"Password length: 6 - min and 10 - max"
]
}
This is how I call method POST from ajax:
$(document).ready(function () {
$("#sendForm").click(function () {
const login = $('input[name=login]').val();
const password = $('input[name=password]').val();
$.ajax({
type: "POST",
url: "/api/users",
contentType: 'application/json',
data: JSON.stringify({"login": login, "password": password}),
dataType: "json",
success: function (data) {
alert('success: ' + data.id + " " + data.login + " " + data.password)
},
error: function (requestObject, error, errorThrown) {
alert(error);//this field return "error" string
alert(errorThrown);//for some reason this is empty when I get an error
}
});
});
});
How can I read it to get exactly the error information? I want to display this: "Login length: 6 - min and 10 - max", "Password length: 6 - min and 10 - max" in alert().
so, what you should note - the response is an object (array-like) which has a subkey named errors which itself contains the data (non-keyed array). So, you should change the Ajax success part to this:
success: function (data) {
var parsed_response = JSON.parse(data);
alert(parsed_response.errors[0]+ " " + parsed_response.errors[1]);
},
as you see, with parsed response, you get the access to the members of the object.
update:
if you want to get the error response, that it means the "response object" (which contained timespamp, exception, errors... members) you had prepared for your response, doesnt matter, as it will not be returned in that (erroneus) situation. So, in that case, as you already mentioned, you are getting alert of the error message, and depending on that (i.e. 404, 410, ...) it will tell you what happens on backend. you will not get any response in that case, because "error" function itself says that server didn't return the readable (outputed) answer, and you have to fix that error (i.e. 410, 503 or whatever, search for them in google).
I might also suggest to save debug file in backend language when receiving the ajax request, so you will find out in which line the backend code breaks.
i.e.
save_to_file("a1");
your codes
save_to_file("a2");
your another codes
save_to_file("a3");
and so on...
so, some of the backend code has error.
found a solution:
error: function (requestObject, error, errorThrown) {
const result = JSON.parse(requestObject.responseText);
alert('error: ' + result.errors[0]);//"Login length: 6 - min and 10 - max"
}
In the code below, the AngularJS $http method calls the URL, and submits the xsrf object as a "Request Payload" (as described in the Chrome debugger network tab). The jQuery $.ajax method does the same call, but submits xsrf as "Form Data".
How can I make AngularJS submit xsrf as form data instead of a request payload?
var url = 'http://somewhere.com/';
var xsrf = {fkey: 'xsrf key'};
$http({
method: 'POST',
url: url,
data: xsrf
}).success(function () {});
$.ajax({
type: 'POST',
url: url,
data: xsrf,
dataType: 'json',
success: function() {}
});
The following line needs to be added to the $http object that is passed:
headers: {'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8'}
And the data passed should be converted to a URL-encoded string:
> $.param({fkey: "key"})
'fkey=key'
So you have something like:
$http({
method: 'POST',
url: url,
data: $.param({fkey: "key"}),
headers: {'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8'}
})
From: https://groups.google.com/forum/#!msg/angular/5nAedJ1LyO0/4Vj_72EZcDsJ
UPDATE
To use new services added with AngularJS V1.4, see
URL-encoding variables using only AngularJS services
If you do not want to use jQuery in the solution you could try this. Solution nabbed from here https://stackoverflow.com/a/1714899/1784301
$http({
method: 'POST',
url: url,
headers: {'Content-Type': 'application/x-www-form-urlencoded'},
transformRequest: function(obj) {
var str = [];
for(var p in obj)
str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]));
return str.join("&");
},
data: xsrf
}).success(function () {});
I took a few of the other answers and made something a bit cleaner, put this .config() call on the end of your angular.module in your app.js:
.config(['$httpProvider', function ($httpProvider) {
// Intercept POST requests, convert to standard form encoding
$httpProvider.defaults.headers.post["Content-Type"] = "application/x-www-form-urlencoded";
$httpProvider.defaults.transformRequest.unshift(function (data, headersGetter) {
var key, result = [];
if (typeof data === "string")
return data;
for (key in data) {
if (data.hasOwnProperty(key))
result.push(encodeURIComponent(key) + "=" + encodeURIComponent(data[key]));
}
return result.join("&");
});
}]);
As of AngularJS v1.4.0, there is a built-in $httpParamSerializer service that converts any object to a part of a HTTP request according to the rules that are listed on the docs page.
It can be used like this:
$http.post('http://example.com', $httpParamSerializer(formDataObj)).
success(function(data){/* response status 200-299 */}).
error(function(data){/* response status 400-999 */});
Remember that for a correct form post, the Content-Type header must be changed. To do this globally for all POST requests, this code (taken from Albireo's half-answer) can be used:
$http.defaults.headers.post["Content-Type"] = "application/x-www-form-urlencoded";
To do this only for the current post, the headers property of the request-object needs to be modified:
var req = {
method: 'POST',
url: 'http://example.com',
headers: {
'Content-Type': 'application/x-www-form-urlencoded'
},
data: $httpParamSerializer(formDataObj)
};
$http(req);
You can define the behavior globally:
$http.defaults.headers.post["Content-Type"] = "application/x-www-form-urlencoded";
So you don't have to redefine it every time:
$http.post("/handle/post", {
foo: "FOO",
bar: "BAR"
}).success(function (data, status, headers, config) {
// TODO
}).error(function (data, status, headers, config) {
// TODO
});
As a workaround you can simply make the code receiving the POST respond to application/json data. For PHP I added the code below, allowing me to POST to it in either form-encoded or JSON.
//handles JSON posted arguments and stuffs them into $_POST
//angular's $http makes JSON posts (not normal "form encoded")
$content_type_args = explode(';', $_SERVER['CONTENT_TYPE']); //parse content_type string
if ($content_type_args[0] == 'application/json')
$_POST = json_decode(file_get_contents('php://input'),true);
//now continue to reference $_POST vars as usual
These answers look like insane overkill, sometimes, simple is just better:
$http.post(loginUrl, "userName=" + encodeURIComponent(email) +
"&password=" + encodeURIComponent(password) +
"&grant_type=password"
).success(function (data) {
//...
You can try with below solution
$http({
method: 'POST',
url: url-post,
data: data-post-object-json,
headers: {'Content-Type': 'application/x-www-form-urlencoded'},
transformRequest: function(obj) {
var str = [];
for (var key in obj) {
if (obj[key] instanceof Array) {
for(var idx in obj[key]){
var subObj = obj[key][idx];
for(var subKey in subObj){
str.push(encodeURIComponent(key) + "[" + idx + "][" + encodeURIComponent(subKey) + "]=" + encodeURIComponent(subObj[subKey]));
}
}
}
else {
str.push(encodeURIComponent(key) + "=" + encodeURIComponent(obj[key]));
}
}
return str.join("&");
}
}).success(function(response) {
/* Do something */
});
Create an adapter service for post:
services.service('Http', function ($http) {
var self = this
this.post = function (url, data) {
return $http({
method: 'POST',
url: url,
data: $.param(data),
headers: {'Content-Type': 'application/x-www-form-urlencoded'}
})
}
})
Use it in your controllers or whatever:
ctrls.controller('PersonCtrl', function (Http /* our service */) {
var self = this
self.user = {name: "Ozgur", eMail: null}
self.register = function () {
Http.post('/user/register', self.user).then(function (r) {
//response
console.log(r)
})
}
})
There is a really nice tutorial that goes over this and other related stuff - Submitting AJAX Forms: The AngularJS Way.
Basically, you need to set the header of the POST request to indicate that you are sending form data as a URL encoded string, and set the data to be sent the same format
$http({
method : 'POST',
url : 'url',
data : $.param(xsrf), // pass in data as strings
headers : { 'Content-Type': 'application/x-www-form-urlencoded' } // set the headers so angular passing info as form data (not request payload)
});
Note that jQuery's param() helper function is used here for serialising the data into a string, but you can do this manually as well if not using jQuery.
var fd = new FormData();
fd.append('file', file);
$http.post(uploadUrl, fd, {
transformRequest: angular.identity,
headers: {'Content-Type': undefined}
})
.success(function(){
})
.error(function(){
});
Please checkout!
https://uncorkedstudios.com/blog/multipartformdata-file-upload-with-angularjs
For Symfony2 users:
If you don't want to change anything in your javascript for this to work you can do these modifications in you symfony app:
Create a class that extends Symfony\Component\HttpFoundation\Request class:
<?php
namespace Acme\Test\MyRequest;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\ParameterBag;
class MyRequest extends Request{
/**
* Override and extend the createFromGlobals function.
*
*
*
* #return Request A new request
*
* #api
*/
public static function createFromGlobals()
{
// Get what we would get from the parent
$request = parent::createFromGlobals();
// Add the handling for 'application/json' content type.
if(0 === strpos($request->headers->get('CONTENT_TYPE'), 'application/json')){
// The json is in the content
$cont = $request->getContent();
$json = json_decode($cont);
// ParameterBag must be an Array.
if(is_object($json)) {
$json = (array) $json;
}
$request->request = new ParameterBag($json);
}
return $request;
}
}
Now use you class in app_dev.php (or any index file that you use)
// web/app_dev.php
$kernel = new AppKernel('dev', true);
// $kernel->loadClassCache();
$request = ForumBundleRequest::createFromGlobals();
// use your class instead
// $request = Request::createFromGlobals();
$response = $kernel->handle($request);
$response->send();
$kernel->terminate($request, $response);
Just set Content-Type is not enough, url encode form data before send.
$http.post(url, jQuery.param(data))
I'm currently using the following solution I found in the AngularJS google group.
$http
.post('/echo/json/', 'json=' + encodeURIComponent(angular.toJson(data)), {
headers: {
'Content-Type': 'application/x-www-form-urlencoded; charset=UTF-8'
}
}).success(function(data) {
$scope.data = data;
});
Note that if you're using PHP, you'll need to use something like Symfony 2 HTTP component's Request::createFromGlobals() to read this, as $_POST won't automatically loaded with it.
AngularJS is doing it right as it doing the following content-type inside the http-request header:
Content-Type: application/json
If you are going with php like me, or even with Symfony2 you can simply extend your server compatibility for the json standard like described here: http://silex.sensiolabs.org/doc/cookbook/json_request_body.html
The Symfony2 way (e.g. inside your DefaultController):
$request = $this->getRequest();
if (0 === strpos($request->headers->get('Content-Type'), 'application/json')) {
$data = json_decode($request->getContent(), true);
$request->request->replace(is_array($data) ? $data : array());
}
var_dump($request->request->all());
The advantage would be, that you dont need to use jQuery param and you could use AngularJS its native way of doing such requests.
Complete answer (since angular 1.4). You need to include de dependency $httpParamSerializer
var res = $resource(serverUrl + 'Token', { }, {
save: { method: 'POST', headers: { 'Content-Type': 'application/x-www-form-urlencoded' } }
});
res.save({ }, $httpParamSerializer({ param1: 'sdsd', param2: 'sdsd' }), function (response) {
}, function (error) {
});
In your app config -
$httpProvider.defaults.transformRequest = function (data) {
if (data === undefined)
return data;
var clonedData = $.extend(true, {}, data);
for (var property in clonedData)
if (property.substr(0, 1) == '$')
delete clonedData[property];
return $.param(clonedData);
};
With your resource request -
headers: {
'Content-Type': 'application/x-www-form-urlencoded'
}
This isn't a direct answer, but rather a slightly different design direction:
Do not post the data as a form, but as a JSON object to be directly mapped to server-side object, or use REST style path variable
Now I know neither option might be suitable in your case since you're trying to pass a XSRF key. Mapping it into a path variable like this is a terrible design:
http://www.someexample.com/xsrf/{xsrfKey}
Because by nature you would want to pass xsrf key to other path too, /login, /book-appointment etc. and you don't want to mess your pretty URL
Interestingly adding it as an object field isn't appropriate either, because now on each of json object you pass to server you have to add the field
{
appointmentId : 23,
name : 'Joe Citizen',
xsrf : '...'
}
You certainly don't want to add another field on your server-side class which does not have a direct semantic association with the domain object.
In my opinion the best way to pass your xsrf key is via a HTTP header. Many xsrf protection server-side web framework library support this. For example in Java Spring, you can pass it using X-CSRF-TOKEN header.
Angular's excellent capability of binding JS object to UI object means we can get rid of the practice of posting form all together, and post JSON instead. JSON can be easily de-serialized into server-side object and support complex data structures such as map, arrays, nested objects, etc.
How do you post array in a form payload? Maybe like this:
shopLocation=downtown&daysOpen=Monday&daysOpen=Tuesday&daysOpen=Wednesday
or this:
shopLocation=downtwon&daysOpen=Monday,Tuesday,Wednesday
Both are poor design..
This is what I am doing for my need, Where I need to send the login data to API as form data and the Javascript Object(userData) is getting converted automatically to URL encoded data
var deferred = $q.defer();
$http({
method: 'POST',
url: apiserver + '/authenticate',
headers: { 'Content-Type': 'application/x-www-form-urlencoded' },
transformRequest: function (obj) {
var str = [];
for (var p in obj)
str.push(encodeURIComponent(p) + "=" + encodeURIComponent(obj[p]));
return str.join("&");
},
data: userData
}).success(function (response) {
//logics
deferred.resolve(response);
}).error(function (err, status) {
deferred.reject(err);
});
This how my Userdata is
var userData = {
grant_type: 'password',
username: loginData.userName,
password: loginData.password
}
The only thin you have to change is to use property "params" rather than "data" when you create your $http object:
$http({
method: 'POST',
url: serviceUrl + '/ClientUpdate',
params: { LangUserId: userId, clientJSON: clients[i] },
})
In the example above clients[i] is just JSON object (not serialized in any way). If you use "params" rather than "data" angular will serialize the object for you using $httpParamSerializer: https://docs.angularjs.org/api/ng/service/$httpParamSerializer
Use AngularJS $http service and use its post method or configure $http function.
I am sending the the value from my jsp to my servlet in url parsing.
The value contains the special character (), but when I am receiving the value it is ( and ).
How to decode this back to ()?
jsp code
var devicename=document.getElementById('s_loc_1').value;
var param=devicename;
param=encodeURIComponent(devicename);
var updatedevsaturl="http://"+window.location.host+"/services/PCEquipmentDevice?productid={}&action=updatePCDeviceStatus&reqby={}¶m="+param;
var productId=document.getElementById('pid').value;
updatedevsaturl=sustituteParameter(updatedevsaturl,productId);
updatedevsaturl=sustituteParameter(updatedevsaturl,userUpi);
alert(updatedevsaturl);
$.ajax({
type : "GET",
timeout:20000,
url : updatedevsaturl,
async: false,
dataType : "xml",
success: function(data) { }, error: function (xhr, ajaxOptions, thrownError) {
alert('Service Unavailable - VPU List');
}
});
java code to decode
if(action.equals("updatePCDeviceStatus")){
System.out.println("param: "+param);
//String decodeparam3 = new String(param.getBytes("UTF-8"),"ASCII");
//String decodeparam3 =URLDecoder.decode(param, "UTF-8");
String decodeparam3= URLDecoder.decode(param, "ISO-8859-1");
System.out.println("decodeparam132 "+ decodeparam3);
I tried all the ways give on net but didnt workenter code here
input at jsp 2-in-1 Laptop (12.5 inches)
output at servlet 2-in-1 Laptop ྫྷ.5 inches)
This is ASCII code for "(". Look at this answer Java: How to unescape HTML character entities in Java? . You have to create a char from that html entity.
I have a Datatable created, and I'm using jeditable plugin to edit cells to push back data. I can edit the cells but when I hit enter and it sends back to my URL Rest endpoint (which I just have a System.out.println to see the data) I get this error from firebug
"NetworkError: 415 Unsupported Media Type - my rest endpoint url"
My endpoint is expecting an Object in JSON, jeditable is only sending some string parameters. So I need to wrap it up.
Let me post my datatable initialization along with jeditable init.
var computerTable = $("#table_computerTable ").dataTable({
"bProcessing": true,
"bServerSide": true,
"bInfo":false,
"bAutoWidth":false,
"bScrollInfinite":true,
"sAjaxSource": ApiUrl(),
"aoColumns":[ // Maps <th> elements in html to JSON data
{"mData": "id"},
{"mData": "description","sClass" : "read_only"},
{"mData": "serial"},
{"mData": "daily"}
],
"aoColumnDefs":[
{"sName":"id","bVisible":false, "aTargets": [0]},
{"sWidth": "55%","aTargets": [1]},
{"sName":"serial","bVisible":false, "aTargets": [2]},
{"sName":"daily","aTargets":[3]}
],
"fnServerData": function ( sSource, aoData, fnCallback ) {
$.getJSON( sSource, aoData, function (json) {
map = {};
map["aaData"] = json;
fnCallback(map);
});
},
"fnRowCallback": function(nRow, aData, iDisplayIndex ){
$(nRow).attr("id",aData["id"]); // Change row ID attribute to match database row id
return nRow;
}
}).makeEditable({
sUpdateURL: getApiUrl() + "cpu/save",
sReadOnlyCellClass: "read_only",
ajaxoptions:{
dataType: "json",
type: 'POST'
}
});
This is the data I get back when I send the POST (read from firebug)
columnId 3
columnName daily
columnPosition 2
id 24
rowId 0
value 50
What I would like to do is initialize an object and send back all the data I want in that. The ID / Serial / Hourly(the new value)
I don't know enough jquery, javascript to know where to begin with that modification.
Any suggestions?
Edit your makeEditable like this:
makeEditable(
{
sUpdateURL: function(value, settings)
{
var sentObject = {}
var rowId = oTable.fnGetPosition(this)[0];
var columnPosition = oTable.fnGetPosition(this)[1];
var columnId = oTable.fnGetPosition(this)[2];
var sColumnTitle = oTable.fnSettings().aoColumns[columnId].sTitle;
sentObject["rowid"]= rowId
sentObject["columnpos"]= columnPosition
sentObject["columnId"]= columnId
sentObject["sColumnName"]= sColumnTitle
sentObject["valueOfCell"]=value
sentObject["Serial"]="serialnumber"
sentObject["Hourly"]="somevalue"
$.ajax({
type: "POST",
url: "url",
data: "sentObj="+JSON.stringify(sentObject)
})
return value;
},
sSuccessResponse: "IGNORE"
}
);
It's like an own customization of ajax request for updating a cell.