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How can I not repeat the same case after I use it

So, I made a burger class with a method for extra stuff, my question is how can I use case 0,1,2 only 1 time, like if I use case 0, I can't use it anymore, I can use only 1 and 2, If I use case 1 after 0 , then I can use only case 2 since I used case 0 and 1 before , It's possible to do something like that ? If yes how ?
The code:
boolean flag=true;
while(flag){
System.out.println("Enter your choice for extra toppings ");
int choice=scanner.nextInt();
scanner.nextLine();
switch(choice) {
case 0:
double salad = 0.35;
setAdditional(getAdditional() + salad);
System.out.println("salad added\n");
break;
case 1:
double bacon=1.05;
setAdditional(getAdditional()+bacon);
System.out.println("Bacon added \n");
break;
case 2:
double fries=0.79;
setAdditional(getAdditional()+fries);
System.out.println("fries added \n");
break;
case 3:
System.out.println("Done");
flag=false;
}
}
} ```

boolean flag = true;
Set<Integer> set = new HashSet<>();
while (flag) {
System.out.println("Enter your choice for extra toppings ");
int choice = scanner.nextInt();
scanner.nextLine();
switch (choice) {
case 0:
if (!set.contains(choice)) {
double salad = 0.35;
setAdditional(getAdditional() + salad);
System.out.println("salad added\n");
break;
}
else {
System.out.println("Added already");
}
continue;
case 1:
double bacon = 1.05;
setAdditional(getAdditional() + bacon);
System.out.println("Bacon added \n");
break;
case 2:
double fries = 0.79;
setAdditional(getAdditional() + fries);
System.out.println("fries added \n");
break;
case 3:
System.out.println("Done");
flag = false;
}
set.add(choice);
}
}
so I did it with Set in the end, only for salad, but it's the same for the rest, if someone else needs it.

your cases go by integer numbers, so an array of boolean with 1 element for every option.
boolean[] allowed = new boolean[options]; (faster than hasMap of string to boolean).
add a check just before the "switch" statement:
if(allowed[choice] && choice != 3) {...}
you should also create an integer constant STOP_OPTION or something like that and use it in the above if-statement and in the final "case" of your switch statement. in your example, set it to 3. then later you can change it without replacing all instances of "3" in your code. but that's more of a styling suggestion.
the "flag" boolean is also redundant, the while loop can just check if choice != 3. be careful of NumberFormatExceptions!
good luck!

Figure out Odd Even or Zero by entering the value

My teacher asked me a question and I was really confused how to write it out as a code. I understood what I had to do, but just couldn't write in Java. So the question was that: Design and implement an application that determines and prints the number of odd even and zero digits. Input could be anything from the user/keyboard. I just don't know how to start. So can someone help me here with an answer and an explanation with that?(without using string)
Thank you so much for your time.

Application? It's three lines:
int odds = str.replaceAll("[^13579]", "").length();
int evens = str.replaceAll("[^2468]", "").length();
int zeroes = str.replaceAll("[^0]", "").length();
If the input is not a string, make it one:
long number;
String str = number + "";

I would use a for loop to traverse the input string. Within the for loop would be a switch statement that increments either the 'odd' variable, the 'even' variable,' the 'zero' variable, or does nothing.
This way the string is only traversed once instead of three times.
The code would look something like:
int numOdds = 0;
int numEvens = 0;
int numZeroes = 0;
for(int i = 0; i < inputString.length(); i++) {
switch(inputString.charAt(i)) {
case '1':
case '3':
case '5':
case '7':
case '9': numOdds++;
break;
case '2':
case '4':
case '6':
case '8': numEvens++;
break;
case '0': numZeroes++;
default: break;
}
}

Looks like you have a couple answers. Here is another you may like more because you probably can understand it:
int odds, evens, zeroes;
public void setOddsEvensZereos(String str) {
for(char c:str) {
try {
int i = Integer.parseInt(c + "");
if(i == 0)
zereos++;
else if(i % 2 == 0)
evens++;
else
odds++;
} catch (Exception e){/*the character isn't a number*/}
}
}

How to put characters beyond 9 in superscript in java?

So I am making a program in Java on a BlueJ environment that computes Binary expansion. However, I can't seem to figure out how to add powers more than 9 in the output.
If I have an input power of anything more than 9 the program goes haywire, presumably because there are no cases after 9.
Also, I personally feel my program in general is extremely inefficient but I just did it this morning and this was the first approach I saw, so if you see a way to make it more efficient than using switch case, that'd be great too.
This is my code so far. It's not all mine, but I'm not sure if intellectual property and stuff applies on here, so just putting it out there.
import java.util.*;
class Binomial_Theorem_Expansion
{
public static void main(String args[])
{
Scanner s=new Scanner(System.in);
System.out.println("Enter the value of x in (x+a)^n");
int x=s.nextInt();
System.out.println("Enter the value of a in (x+a)^n");
int a=s.nextInt();
System.out.println("Enter the value of n in (x+a)^n");
int n=s.nextInt();
System.out.println ("The expanded answer is");
int r=0;
int powx=n;
while (r<=n)
{
long nCr=calculatenCr(n,r);
if(nCr!=-1)
{
double y=Math.pow((double)x,(double)n-r);
double z=Math.pow((double)a,(double)r);
switch (powx)
{
case 0: System.out.print ("("+nCr*y*z);
break;
case 1: System.out.print ("("+nCr*y*z+"x");
break;
case 2: System.out.print ("("+nCr*y*z+"x\u00B2");
break;
case 3: System.out.print ("("+nCr*y*z+"x\u00B3");
break;
case 4: System.out.print ("("+nCr*y*z+"x\u2074");
break;
case 5: System.out.print ("("+nCr*y*z+"x\u2075");
break;
case 6: System.out.print ("("+nCr*y*z+"x\u2076");
break;
case 7: System.out.print ("("+nCr*y*z+"x\u2077");
break;
case 8: System.out.print ("("+nCr*y*z+"x\u2078");
break;
case 9: System.out.print ("("+nCr*y*z+"x\u2079");
break;
case 10: System.out.print ("("+nCr*y*z+"x\u2071\u00B2");
break;
}
switch (r) {
case 0: System.out.print (")");
break;
case 1: System.out.print ("y"+")");
break;
case 2: System.out.print ("y\u00B2"+")");
break;
case 3: System.out.print ("y\u00B3"+")");
break;
case 4: System.out.print ("y\u2074"+")");
break;
case 5: System.out.print ("y\u2075"+")");
break;
case 6: System.out.print ("y\u2076"+")");
break;
case 7: System.out.print ("y\u2077"+")");
break;
case 8: System.out.print ("y\u2078"+")");
break;
case 9: System.out.print ("y\u2079"+")");
break;
}
r++;
if (r<=n)
{
System.out.print ("+");
}
powx--;
}
}
}
public static long calculatenCr(int n,int r)
{
long res=1;
if(n>=r)
{
res=getFact(n)/(getFact(n-r)*getFact(r));
return res;
}
else return -1;
}
public static long getFact(int n)
{
long f=1;
for(int i=n;i>=1;i--)
{
f*=i;
}
return f;
}
}
Thanks for any constructive input. :)

presumably because there are no cases after 9.
Your code is using UNICODE superscript characters, and the cases that you have cover only numbers zero through ten for x and zero through nine for y.
You can fix this by defining a method that produces a superscript UNICODE conversion of a multidigit number, and calling it from both places where you need to produce such representation:
switch (powx) {
case 0: System.out.print ("("+nCr*y*z);
break;
case 1: System.out.print ("("+nCr*y*z+"x");
break;
default: System.out.print ("("+nCr*y*z+"x"+toSuperscript(powx));
break;
}
The other switch (i.e. switch (r)) should be converted in a similar way.
You can implement String toSuperscript(int n) by producing a decimal representation of n, and then replacing '0' with '\u2070', '1' with '\u00B9', and so on.

Switch statement + user input

Thanks for taking your time to help me. I need this switch statement to only accept ints 1-4. Any others entered will ask for input again. Entering 5 will quit the system.
System.out.println("A random numbers list has been generated for you:\n ");
System.out.println("Choose an option:\n1)Form list to be heapified.\n2)Enqueue the integer 10" +
"\n3)Dequeue the integer 10.\n4)Print the updated heap.\n5)Quit the system \n>>");
Scanner scanner = new Scanner( System.in );
int var = 0;
String input = scanner.next();
int answer = Integer.parseInt(input);
do{
input = scanner.next();
answer = Integer.parseInt(input);
var = answer;
switch(var){
case 1:
for (int i = 0; i < 20; i++) {
h.insert(new Integer((int)(100 * Math.random())), i);
}
break;
case 2:
System.out.println("\nEnqueue-ing 10...\n");
pushFoward(10, 20);//priority 20
break;
case 3:
System.out.println("\nDequeue-ing 10...\n");
dequeue;//priority highest deleted
break;
case 4:
while (h.heapsize() > 0) {
System.out.print(h.pop() + " ");
}
break;
}
}while(var ==1 || var==2 || var==3
|| var==4);
I cant seem to get it right. Keep making it worse.
Edited:
do{
String input = scanner.next();
int answer = Integer.parseInt(input);
switch(var){
case 1:
for (int i = 0; i < 20; i++) {
h.insert(new Integer((int)(100 * Math.random())), i);
}
break;
case 2:
System.out.println("\nEnqueue-ing 10...\n");
h.pushFoward(10, 20);//priority 20
break;
case 3:
System.out.println("\nDequeue-ing 10...\n");
h.dequeue();//priority highest deleted
break;
case 4:
while (h.heapsize() > 0) {
System.out.print(h.pop() + " ");
}
break;
default: input = scanner.next();
break;
}
}while(var!=5)
;

Try adding a "default:" statement, like this:
switch(var){
case 1:
for (int i = 0; i < 20; i++) {
h.insert(new Integer((int)(100 * Math.random())), i);
}
break;
case 2:
System.out.println("\nEnqueue-ing 10...\n");
pushFoward(10, 20);//priority 20
break;
case 3:
System.out.println("\nDequeue-ing 10...\n");
dequeue;//priority highest deleted
break;
case 4:
while (h.heapsize() > 0) {
System.out.print(h.pop() + " ");
}
break;
default:
*Add whatever code you want to execute if its greater then or equal to 5 here!*
}while(var ==1 || var==2 || var==3
|| var==4);

You can set a 'default' case.
default: doSomething();
break;
This will be invoked when a user enters a value that isn't one of your cases.
} while (answer != 5);
This should make the loop break when 5 is entered.
EDIT:
Also, you need to switch on the answer variable instead of 'var'
switch(answer) {

You don't need to put it in a loop. The use case is simple:
For 1-4 : do something and then return
For 5: quit/return Everything
else: ask for input again
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int answer = Integer.parseInt(scanner.next());
switch(answer) {
case 1:
System.out.println(1);
break;
case 2:
System.out.println(2);
break;
case 3:
System.out.println(3);
break;
case 4:
System.out.println(4);
break;
case 5:
return; // System.exit(0) or quit however you want to
default:
answer = Integer.parseInt(scanner.next());
}
}

Switch statement for some reason does not like case 8. Compiler is acting real weird

Here is the code:
public static void main(String args[])
{
int i=0;
int m=0;
double scale;
boolean exit;
Shape[] s = new Shape[10];
while(exit !=true)
{
System.out.print("\nChoose an option:\n"+
"1-Add a new circle\n"+
"2-Add a new rectangle\n"+
"3-Delete all shapes\n"+
"4-Scale all shapes\n"+
"5-Display perimeter of all shapes\n"+
"6-Display the area of all shapes\n"+
"7-Enter scale factor\n"+
"8-Exit program\n");
Scanner input = new Scanner(System.in);
m=input.nextInt();
if(i<=9)
{
switch (m)
{
case 1: Circle c = new Circle(0);
s[i]=c;
i++;
break;
case 2: Rectangle r = new Rectangle(1,1);
s[i]=r;
i++;
break;
case 3: s=null;
i=0;
break;
case 4: for(i=0; i<s.length; i++)
{
s[i].scaleShape();
}
break;
case 5: for(i=0; i<s.length; i++)
{
if(s[i] != null)
{
System.out.println(s[i].getPerimeter());
}
}
break;
case 6: for(i=0; i<s.length; i++)
{
if(s[i] != null)
{
System.out.println(s[i].getArea());
}
}
break;
case 7: do
{
System.out.println("\nEnter scale factor");
scale=input.nextDouble();
}
while(scale<0);
Shape.setScaleFactor(scale);
}
break;
case 8: System.out.println("Do you want to quit?");
break; //Nothing here since loop should terminate it.
//default: System.out.println("Number must be 1-8");
// break;
}
}
}
}
Oddly the compiler is giving me an error on case 8 saying:
Type mismatch can't convert from int to boolean.
But Im not converting anything to boolean
-syntax error on token "case" assert expected
-syntax error on token :, ; expected
But all the commands there have semi-colons
expression must return a value
Why is the compiler acting so funny? Normally errors like that are easy to find. What is going on?

Your problem is in the case for 7:
case 7: do
{
System.out.println("\nEnter scale factor");
scale=input.nextDouble();
}
while(scale<0);
Shape.setScaleFactor(scale);
}
Notice the extra close brace: that's closing your switch statement, orphaning your case 8.

} // <-- Why is this here?
break;
case 8: System.out.println("Do you want to quit?");
You're ending the switch statement with an extra }. Remove it and things may work.

Every one has pointed out that you have an extra parenthesis in your code, what we've failed to point out is where it's coming from...
while(scale<0); // <-- This isn't going to work....
Shape.setScaleFactor(scale);
}
It should be...
while(scale<0) {
Shape.setScaleFactor(scale);
}
The next question is, how is scale decremented? Cause this could cause an infinite loop if you're not careful.

while(scale<0);
Shape.setScaleFactor(scale);
} // Remove this parenthesis.
break;