Moving a file in processing - java

I'm trying to move a file with processing.
import java.util.Base64;
import java.io.*;
import java.nio.file.Files;
import java.nio.file.Paths;
String source = "C:\test\1.jpeg";
String newdir = "C:\test123\1.jpeg";
void setup() {
Files.move(source, newdir.resolve(source.getFileName()));
}
I took a look at this and tried to make it work, however I get an error that The function getFileName() does not exist. I looked for this also, but didn't find much. Could someone point me into the right direction for moving a file from one dir to another?

Take a look at this:
import java.nio.file.*;
String source = "C:\\test\\1.jpeg";
String newdir = "C:\\test123\\1.jpeg";
void setup() {
try {
Path temp = Files.move(Paths.get(source), Paths.get(newdir));
} catch (IOException e) {
print(e);
}
}
Couple of points - use \\ instead of a single \ when specifying the paths. Secondly, getFileName() can only be applied to a Path object, not a String, and that caused your error in the question. Same, by the way, with the resolve(String s) method, it can only be applied to a Path, not String.
Using Paths:
import java.nio.file.*;
Path source = Paths.get("...");
Path newdir = Paths.get("...");
void setup() {
try {
Files.move(source, newdir);
} catch (IOException e) {
print(e);
}
}

Related

How can I convert a xml file to a xml written with javascript file with java?

I have got two XML files from two different databases, but they has got the same infos. One of them has got VSReports and the other Jasperreports(JavaScript). I has to convert the XML file from VSReports into the Jasperreports. The only programming language I am allowed to use is java.
I am already stucked when I try to read in a xml file with my code.
import javax.swing.*;
import java.io.IOException;
import java.nio.charset.Charset;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
public class InputBox {
public static void main(String[] args) {
Pfad();
}
//opens JFileChooser
public static void Pfad() {
JFileChooser chooser = new JFileChooser();
int rueckgabeWert = chooser.showOpenDialog(null);
if (rueckgabeWert == JFileChooser.APPROVE_OPTION) {
System.out.println("Die zu öffnende Datei ist: "
+ chooser.getSelectedFile().getName());
}
Path path = Paths.get(chooser.getSelectedFile().getName());
String content = null;
try {
content = Files.readString(path, Charset.defaultCharset());
} catch (IOException e) {
e.printStackTrace();
}
//System.out.println the content of the file
System.out.println(content);
}
}
It works really fine with a txt file, but when I try a XML file it comes to a error:
java.nio.file.NoSuchFileException: 123.xml
at java.base/sun.nio.fs.WindowsException.translateToIOException(WindowsException.java:85)
at java.base/sun.nio.fs.WindowsException.rethrowAsIOException(WindowsException.java:103)
at java.base/sun.nio.fs.WindowsException.rethrowAsIOException(WindowsException.java:108)
at java.base/sun.nio.fs.WindowsFileSystemProvider.newByteChannel(WindowsFileSystemProvider.java:231)
at java.base/java.nio.file.Files.newByteChannel(Files.java:370)
at java.base/java.nio.file.Files.newByteChannel(Files.java:421)
at java.base/java.nio.file.Files.readAllBytes(Files.java:3205)
at java.base/java.nio.file.Files.readString(Files.java:3283)
at InputBox.Pfad(InputBox.java:26)
at InputBox.main(InputBox.java:10)
null
you are trying to open a file without giving it an absolute path, it will only work if the file is in the current working directory
Based on your description, it seems you didn't pass the full name of the xml file to your function.
So try
File f = chooser.getSelectedFile();
String path = f.getAbsolutePath + f.getName();
try {
content = Files.readString(path, Charset.defaultCharset());
} catch (IOException e) {
e.printStackTrace();
}
Hope this help.
As said, File#getName() loses the directory part of the path, so it will only find a file if it is in the current directory. To convert a File object to a Path, just use its toPath() method:
Path path = chooser.getSelectedFile().toPath();

create .gitignore with java

I'm aware this question might be a duplicate in some sense but first hear me out.
I tried to create a code where i can create gitignore file with contents and for some reason i always end up having a file with txt extension and without name. Can someone explain this behavior and why?
Example Code:
System.out.println(fileDir+"\\"+".gitignore");
FileOutputStream outputStream = new FileOutputStream(fileDir+"\\"+".gitignore",false);
byte[] strToBytes = fileContent.getBytes();
outputStream.write(strToBytes);
outputStream.close();
You can use java.nio for it. See the following example:
import java.io.IOException;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.Paths;
import java.util.ArrayList;
import java.util.List;
public class StackoverflowMain {
public static void main(String[] args) {
// create the values for a folder and the file name as Strings
String folder = "Y:\\our\\destination\\folder"; // <-- CHANGE THIS ONE TO YOUR FOLDER
String gitignore = ".gitignore";
// create Paths from the Strings, the gitignorePath is the full path for the file
Path folderPath = Paths.get(folder);
Path gitignorPath = folderPath.resolve(gitignore);
// create some content to be written to .gitignore
List<String> lines = new ArrayList<>();
lines.add("# folders to be ignored");
lines.add("**/logs");
lines.add("**/classpath");
try {
// write the file along with its content
Files.write(gitignorPath, lines);
} catch (IOException e) {
e.printStackTrace();
}
}
}
It creates the file on my Windows 10 machine without any problems. You need Java 7 or higher for it.

Copying file using Apache Commons FileUtils

On the first run, I want to copy the given File to a new location with a new file name.
Every subsequent run should overwrite the same destination file created during first run.
During first run, the destination file does not exist. Only the directory exists.
I wrote the following program:
package myTest;
import java.io.File;
import java.io.IOException;
import java.net.URISyntaxException;
import java.net.URL;
import java.nio.file.Paths;
import org.apache.commons.io.FileUtils;
public class FileCopy {
public static void main(String[] args) {
TestFileCopy fileCopy = new TestFileCopy();
File sourceFile = new File("myFile.txt");
fileCopy.saveFile(sourceFile);
File newSourceFile = new File("myFile_Another.txt");
fileCopy.saveFile(newSourceFile);
}
}
class TestFileCopy {
private static final String DEST_FILE_PATH = "someDir/";
private static final String DEST_FILE_NAME = "myFileCopied.txt";
public void saveFile(File sourceFile) {
URL destFileUrl = getClass().getClassLoader().getResource(DEST_FILE_PATH
+ DEST_FILE_NAME);
try {
File destFile = Paths.get(destFileUrl.toURI()).toFile();
FileUtils.copyFile(sourceFile, destFile);
} catch (IOException | URISyntaxException e) {
e.printStackTrace();
}
}
}
However, this throws null pointer exception on the following line:
File destFile = Paths.get(destFileUrl.toURI()).toFile();
What am I missing?
Directory someDir is directly under my project's root directory in eclipse.
Both source files myFile.txt and myFile_Another.txt exists directly under my project's root directory in eclipse.
I used this and it works as I am expecting:
public void saveFile1(File sourceFile) throws IOException {
Path from = sourceFile.toPath();
Path to = Paths.get(DEST_FILE_PATH + DEST_FILE_NAME);
Files.copy(from, to, StandardCopyOption.REPLACE_EXISTING);
}
Using Java nio.

Reading multiple files in directory and printing specific content

What I am trying to achieve is basically a Java file which looks through a specific directory on the users computer, search all the files in the directory for specific word (in this case an email) and then at the end print them out.
The current script of which I have now, looks for all the files in a certain directory, prints out those file names. As well as that I have also figured out how to have that script search through one file for a specific word and then print it out. The only problem is that although it searches through that one file and gets that word/phrase it has to be given the full directory and file to work. I just want it to have a specific directory and then search all the files in it. I have tried doing this using the directory variable of which I have created to find all files, but it does not work when using that as the directory for the files to search through to find the word(s).
Here underneath is the part of my code which is used for the function I want. The actual function is called in my real script so don't worry about that as it is working. I have also just commented in the script what variable I want to work where.
package aProject;
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
public class aScanner {
static String usernameMac = System.getProperty("user.name");
final static File foldersMac = new File("/Users/" + usernameMac + "/Library/Mail/V2"); // this is the right directory I want to look through
public static void listFilesForFolder(final File foldersMac) {
for (final File fileEntry : foldersMac.listFiles()) {
if (fileEntry.isDirectory()) {
listFilesForFolder(fileEntry);
try {
BufferedReader bReaderM = new BufferedReader(new FileReader("/Users/username/Library/Mail/V2/AosIMAP-/INBOX.mbox/longnumber-folder/Data/Messages/1.emlx")); //this is where I would like the foldersMac variable to work in, instead of this full directory
String lineMe;
while((lineMe = bReaderM.readLine()) != null)
{
if(lineMe.contains(".com"))
System.out.println(lineMe);
}
bReaderM.close();
}
catch (IOException e) {
}
} else {
System.out.println(fileEntry.getName());
}
}
}
}
I think this is what you're trying to achieve:
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.ArrayList;
public class aScanner {
static String usernameMac = System.getProperty("user.name");
final static File foldersMac = new File("/Users/" + usernameMac + "/Library/Mail/V2");
public static void main(String[] args) throws IOException {
listFilesForFolder(foldersMac);
}
public static void listFilesForFolder(final File foldersMac) throws IOException {
for (final File fileEntry : foldersMac.listFiles()) {
if (fileEntry.isDirectory()) {
listFilesForFolder(fileEntry);
} else {
ArrayList<String> lines = new ArrayList<>();
try (BufferedReader bReaderM = new BufferedReader(new FileReader(fileEntry))) {
String lineMe;
while ((lineMe = bReaderM.readLine()) != null) {
if (lineMe.contains(".com")) {
lines.add(lineMe);
}
}
}
if (!lines.isEmpty()) {
System.out.println(fileEntry.getAbsolutePath() + ":");
for (String line : lines) {
System.out.println(" " + line.trim());
}
}
}
}
}
}
I think your problem lies around your recursion logic,
You go down recursively in the directory structure, you walk through you tree, but write out nothing cause of this if statement:
if (fileEntry.isDirectory()) {
listFilesForFolder(fileEntry);
...
}
Close that If statement earlier, then it should work.

getClassLoader().getResourceAsStream method returns null for a file with ".LIB" extension

I'm trying to load a file from resources/ path using
getClassLoader().getResourceAsStream("file.LIB")
but the method always returns null, unless I rename the file into another extension, say ".dll".
I've looked into the official Java documentation, but to no avail.
Why does the method acts strange on that file type?
Note: I'm using JDK 1.8.0_111 x86 (due to constraints on that lib file, which only works well with a 32-bit JVM)
It does works for me, you need to be sure what exactly you are doing with lib file.
import java.io.IOException;
import java.io.InputStream;
import java.util.Properties;
public class FileHelper {
public String getFilePathToSave() {
Properties prop = new Properties();
String filePath = "";
try {
InputStream inputStream =
getClass().getClassLoader().getResourceAsStream("abc.lib");
prop.load(inputStream);
filePath = prop.getProperty("json.filepath");
} catch (IOException e) {
e.printStackTrace();
}
return filePath;
}
public static void main(String args[]) {
FileHelper fh = new FileHelper();
System.out.println(fh.getFilePathToSave());
}
}

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