Consider a String "2022-03-23 21:06:29.4933333 +00:00".
How do I parse the above DateTimeOffset String to LocalDateTime in Java?
I tried with the following DateTimeFormatter but the format seems to be incorrect:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss\[.nnnnnnn\] \[+|-\]hh:mm\]");
LocalDateTime dateTime = LocalDateTime.parse(timestamp, formatter)
First, start by having the JavDocs for DateTimeFormatter at hand, this is going to really help determine which specifiers you need
The first thing to do is parse the text into a ZonedDateTime, LocalDateTime won't parse a input value with a time zone (AFAIK), you "might" be able to force it, but what's the point?
String text = "2022-03-23 21:06:29.4933333 +00:00";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("uuuu-MM-dd HH:mm:ss.SSSSSSS z");
ZonedDateTime zdt = ZonedDateTime.parse(text, formatter);
System.out.println(zdt);
This prints...
2022-03-23T21:06:29.493333300Z
Now you could use ZonedDateTime#toLocalDateTime, but this won't take into account the current time zone of the user/computer.
If you need to convert the ZonedDateTime to LocalDateTime, it's best to do so in away which will translate the time (and date if required) to best represent the time within the current time zone (okay, I was confused typing it)
For example, converting the input value into my current time zone (+11 hours) would look like this...
ZoneId currentZone = ZoneId.systemDefault();
ZonedDateTime currentZDT = zdt.withZoneSameInstant(currentZone);
System.out.println(currentZDT);
LocalDateTime ldt = currentZDT.toLocalDateTime();
System.out.println(ldt);
which will print...
2022-03-24T08:06:29.493333300+11:00[Australia/Melbourne]
2022-03-24T08:06:29.493333300
This means that at 9:06pm on the 23rd March in Grinch (GMT), it was 8:06am on the 24th March where I live.
Now you can use different ZoneIds to convert to a TimeZone which is not the current computers TimeZone, but I'll leave that up to you to experiment with (for example, I used Convert ZonedDateTime to LocalDateTime at time zone to base my example on)
You need create custom DateTimeFormatter:
import java.time.*;
import java.time.format.DateTimeFormatter;
import java.time.format.DateTimeFormatterBuilder;
public class Main {
public static void main(String args[]){
String dateString = "2022-03-23 21:06:29.4933333 +00:00";
DateTimeFormatter formatter = new DateTimeFormatterBuilder()
.append(java.time.format.DateTimeFormatter.ISO_LOCAL_DATE)
.appendLiteral(' ')
.append(java.time.format.DateTimeFormatter.ISO_LOCAL_TIME)
.appendLiteral(' ')
.appendOffsetId()
.toFormatter();
//In case of OffSet matter, retaining the instant
LocalDateTime localDateTimeSavePointOfTime = OffsetDateTime.parse(dateString, formatter).withOffsetSameInstant(OffsetDateTime.now().getOffset()).toLocalDateTime();
//In case OffSet does not matter we can skip it
LocalDateTime localDateTimeSkipOffSet = LocalDateTime.parse(dateString, formatter);
}
}
final Timestamp rawDateTime = Timestamp.valueOf("2031-04-25 18:30:00");
final ZoneId zoneId = ZoneId.of("Asia/Calcutta");
final ZonedDateTime zonedDateTime = ZonedDateTime.ofInstant(
Instant.ofEpochMilli(rawDateTime.getTime()), zoneId);
// here we are getting output as 2031-04-25T18:30+05:30[Asia/Calcutta]
final ZonedDateTime zonedDateTime1 =
ZonedDateTime.of(rawDateTime.toLocalDateTime(), zoneId);
// here we are getting output as 2031-04-25T18:30+05:30[Asia/Calcutta]
But I want to get the converted date time as 2031-04-26 00:00:00+5:30 as my timestamp value is in the UTC Timezone.
Please help.
First, you should not use Timestamp. You can use DateTimeFormatter to parse into a LocalDateTime.
You then zone that LocalDateTime to UTC before converting to the Calcutta zone with ZonedDateTime.withZoneSameInstant.
DateTimeFormatter formatter = new DateTimeFormatterBuilder()
.append(DateTimeFormatter.ISO_LOCAL_DATE)
.appendLiteral(' ')
.append(DateTimeFormatter.ISO_LOCAL_TIME)
.toFormatter();
LocalDateTime localDateTime = LocalDateTime.parse("2031-04-25 18:30:00", formatter);
ZoneId calcuttaZone = ZoneId.of("Asia/Calcutta");
ZonedDateTime calcuttaZonedDateTime = localDateTime.atZone(ZoneOffset.UTC)
.withZoneSameInstant(calcuttaZone);
Using DateTimeFormatter to format ZonedDateTime:
final Timestamp rawDateTime = Timestamp.valueOf("2031-04-25 18:30:00");
final ZoneId zoneId = ZoneId.of("Asia/Calcutta");
final ZonedDateTime zonedDateTime = ZonedDateTime.ofInstant(
Instant.ofEpochMilli(rawDateTime.getTime()), zoneId);
// here we are getting output as 2031-04-25T18:30+05:30[Asia/Calcutta]
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss[XXX]");
System.out.println(formatter.format(zonedDateTime));
final ZonedDateTime zonedDateTime1 =
ZonedDateTime.of(rawDateTime.toLocalDateTime(), zoneId);
// here we are getting output as 2031-04-25T18:30+05:30[Asia/Calcutta]
System.out.println(formatter.format(zonedDateTime1));
The output:
2031-04-25 23:00:00+05:30
2031-04-25 18:30:00+05:30
Edited: according to the comment from #Ole V.V. - The local date time has to be converted to the zonedatetime , before applying the format :
final Timestamp rawDateTime = Timestamp.valueOf("2031-04-25 18:30:00");
LocalDateTime ldt = rawDateTime.toLocalDateTime();
final ZoneId zoneId = ZoneId.of("Asia/Calcutta");
ZonedDateTime zdt = ldt.atZone(ZoneId.of("UTC"))
.withZoneSameInstant(zoneId);
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm:ss[XXX]");
System.out.println(formatter.format(zdt));
This will give the output:
2031-04-26 00:00:00+5:30
Instead of ZonedDateTime with named zones having (supra-)national standards like day-time-savings, use OffsetDateTime.
OffsetDateTime utc = OffsetDateTime.parse("2031-04-25T18:30:00Z");
OffsetDateTime asia = utc.withOffsetSameInstant(ZoneOffset.ofHoursMinutes(5, 30));
The default parsing is for the ISO format.
Z means zero, UTC, +0:00.
The resulting default formatting is 2031-04-26T00:00+05:30.
After comment of Ole V.V.
The above is especially error prone if summer time is involved, like in Central European Time with varying offsets +1:00 and +2:00.
Instant raw = Instant.parse("2031-04-25T18:30:00Z");
ZonedDateTime zoned = raw.atZone(ZoneId.of("Asia/Calcutta"));
OffsetDateTime offset = OffsetDateTime.from(zoned);
I have a datetime-string WITHOUT a specified timezone.
But I want to parse it with ZonedDateTime to give it a timezone-meaning in the act of parsing.
This code is working but uses LocalDateTime for parsing - and then convert it to ZonedDateTime with giving it a timezone-meaning.
DateTimeFormatter dtf = DateTimeFormatter.ofPattern ("yyyyMMddHHmm");
String tmstr = "201810110907";
LocalDateTime tmp = LocalDateTime.parse (tnstr,dtf);
ZonedDateTime mytime = ZonedDateTime.of (tmp, ZoneId.of ("UTC"));
Is there a way I can parse it directly with ZonedDateTime?
I have tried this, but it was not working.
mytime = mytime.withZoneSameInstant(ZoneId.of("UTC")).parse(str,dtf);
You may specify a default time zone on the formatter:
DateTimeFormatter dtf = DateTimeFormatter.ofPattern("yyyyMMddHHmm")
.withZone(ZoneId.of("UTC"));
String tmstr = "201810110907";
ZonedDateTime mytime = ZonedDateTime.parse(tmstr, dtf);
System.out.println(mytime);
Output:
2018-10-11T09:07Z[UTC]
Bonus tip: Rather than ZoneId.of("UTC") it’s usually nicer to use ZoneOffset.UTC. If you accept the output being printed as 2018-10-11T09:07Z instead (Z meaning UTC).
I have a time with string type like: "2015-01-05 17:00" and ZoneId is "Australia/Sydney".
How can I convert this time information to the corresponding to UTC time using Java 8 datetime API?
Also need to considering DST stuff.
You are looking for ZonedDateTime class in Java8 - a complete date-time with time-zone and resolved offset from UTC/Greenwich. In terms of design, this class should be viewed primarily as the combination of a LocalDateTime and a ZoneId. The ZoneOffset is a vital, but secondary, piece of information, used to ensure that the class represents an instant, especially during a daylight savings overlap.
For example:
ZoneId australia = ZoneId.of("Australia/Sydney");
String str = "2015-01-05 17:00";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm");
LocalDateTime localtDateAndTime = LocalDateTime.parse(str, formatter);
ZonedDateTime dateAndTimeInSydney = ZonedDateTime.of(localtDateAndTime, australia );
System.out.println("Current date and time in a particular timezone : " + dateAndTimeInSydney);
ZonedDateTime utcDate = dateAndTimeInSydney.withZoneSameInstant(ZoneOffset.UTC);
System.out.println("Current date and time in UTC : " + utcDate);
An alternative to the existing answer is to setup the formatter with the appropriate time zone:
String input = "2015-01-05 17:00";
ZoneId zone = ZoneId.of("Australia/Sydney");
DateTimeFormatter fmt = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm").withZone(zone);
ZonedDateTime utc = ZonedDateTime.parse(input, fmt).withZoneSameInstant(UTC);
Since you want to interact with a database, you may need a java.sql.Timestamp, in which case you don't need to explicitly convert to a UTC time but can use an Instant instead:
ZonedDateTime zdt = ZonedDateTime.parse(input, fmt);
Timestamp sqlTs = Timestamp.from(zdt.toInstant());
**// Refactored Logic**
ZoneId australia = ZoneId.of("Australia/Sydney");
ZoneId utcZoneID= ZoneId.of("Etc/UTC");
String ausTime = "2015-01-05 17:00";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd HH:mm");
//converting in datetime of java8
LocalDateTime ausDateAndTime = LocalDateTime.parse(ausTime, formatter);
// DateTime With Zone
ZonedDateTime utcDateAndTime = ausDateAndTime.atZone(utcZoneID);
// output - 2015-01-05T17:00Z[Etc/UTC]
// With Formating DateTime
String utcDateTime = utcDateAndTime.format(formatter);
// output - 2015-01-05 17:00
I am simply trying to convert a date string into a DateTime object in Java 8. Upon running the following lines:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDateTime dt = LocalDateTime.parse("20140218", formatter);
I get the following error:
Exception in thread "main" java.time.format.DateTimeParseException:
Text '20140218' could not be parsed:
Unable to obtain LocalDateTime from TemporalAccessor:
{},ISO resolved to 2014-02-18 of type java.time.format.Parsed
at java.time.format.DateTimeFormatter.createError(DateTimeFormatter.java:1918)
at java.time.format.DateTimeFormatter.parse(DateTimeFormatter.java:1853)
at java.time.LocalDateTime.parse(LocalDateTime.java:492)
The syntax is identical to what has been suggested here, yet I am served with an exception. I am using JDK-8u25.
It turns out Java does not accept a bare Date value as DateTime. Using LocalDate instead of LocalDateTime solves the issue:
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDate dt = LocalDate.parse("20140218", formatter);
If you really need to transform a date to a LocalDateTime object, you could use the LocalDate.atStartOfDay(). This will give you a LocalDateTime object at the specified date, having the hour, minute and second fields set to 0:
final DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDateTime time = LocalDate.parse("20140218", formatter).atStartOfDay();
For what is worth if anyone should read again this topic(like me) the correct answer would be in DateTimeFormatter definition, e.g.:
private static DateTimeFormatter DATE_FORMAT =
new DateTimeFormatterBuilder().appendPattern("dd/MM/yyyy[ [HH][:mm][:ss][.SSS]]")
.parseDefaulting(ChronoField.HOUR_OF_DAY, 0)
.parseDefaulting(ChronoField.MINUTE_OF_HOUR, 0)
.parseDefaulting(ChronoField.SECOND_OF_MINUTE, 0)
.toFormatter();
One should set the optional fields if they will appear. And the rest of code should be exactly the same.
Edit : usefull thing from wittyameta comment :
Remember to add the parseDefaulting AFTER you have called appendPattern. Otherwise it'll give DateTimeParseException
For anyone who landed here with this error, like I did:
Unable to obtain LocalDateTime from TemporalAccessor: {HourOfAmPm=0, MinuteOfHour=0}
It came from a the following line:
LocalDateTime.parse(date, DateTimeFormatter.ofPattern("M/d/yy h:mm"));
It turned out that it was because I was using a 12hr Hour pattern on a 0 hour, instead of a 24hr pattern.
Changing the hour to 24hr pattern by using a capital H fixes it:
LocalDateTime.parse(date, DateTimeFormatter.ofPattern("M/d/yy H:mm"));
This is a really unclear and unhelpful error message. After much trial and error I found that LocalDateTime will give the above error if you do not attempt to parse a time. By using LocalDate instead, it works without erroring.
This is poorly documented and the related exception is very unhelpful.
Expanding on retrography's answer..: I had this same problem even when using LocalDate and not LocalDateTime. The issue was that I had created my DateTimeFormatter using .withResolverStyle(ResolverStyle.STRICT);, so I had to use date pattern uuuuMMdd instead of yyyyMMdd (i.e. "year" instead of "year-of-era")!
DateTimeFormatter formatter = new DateTimeFormatterBuilder()
.parseStrict()
.appendPattern("uuuuMMdd")
.toFormatter()
.withResolverStyle(ResolverStyle.STRICT);
LocalDate dt = LocalDate.parse("20140218", formatter);
(This solution was originally a comment to retrography's answer, but I was encouraged to post it as a stand-alone answer because it apparently works really well for many people.)
If the date String does not include any value for hours, minutes and etc you cannot directly convert this to a LocalDateTime. You can only convert it to a LocalDate, because the string only represent the year,month and date components it would be the correct thing to do.
DateTimeFormatter dtf = DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDate ld = LocalDate.parse("20180306", dtf); // 2018-03-06
Anyway you can convert this to LocalDateTime.
DateTimeFormatter dtf = DateTimeFormatter.ofPattern("yyyyMMdd");
LocalDate ld = LocalDate.parse("20180306", dtf);
LocalDateTime ldt = LocalDateTime.of(ld, LocalTime.of(0,0)); // 2018-03-06T00:00
You do not need to define a DateTimeFormatter
You do not need to define a DateTimeFormatter to parse the given date string. You can use the OOTB (Out-Of-The-Box), DateTimeFormatter.BASIC_ISO_DATE to parse it.
Demo:
import java.time.LocalDate;
import java.time.LocalDateTime;
import java.time.LocalTime;
import java.time.format.DateTimeFormatter;
public class Main {
public static void main(String[] args) {
LocalDate date = LocalDate.parse("20140218", DateTimeFormatter.BASIC_ISO_DATE);
System.out.println(date);
// In case you need an instance of LocalDateTime
LocalDateTime ldt = date.atTime(LocalTime.MIN);
System.out.println(ldt);
}
}
Output:
2014-02-18
2014-02-18T00:00
ONLINE DEMO
Learn more about the modern Date-Time API* from Trail: Date Time.
* If you are working for an Android project and your Android API level is still not compliant with Java-8, check Java 8+ APIs available through desugaring. Note that Android 8.0 Oreo already provides support for java.time. Check this answer and this answer to learn how to use java.time API with JDBC.
DateTimeFormatter format = new DateTimeFormatterBuilder()
.appendPattern("yyyy-MM-dd")
.parseDefaulting(ChronoField.HOUR_OF_DAY, 0)
.parseDefaulting(ChronoField.MINUTE_OF_HOUR, 0)
.parseDefaulting(ChronoField.SECOND_OF_MINUTE, 0)
.parseDefaulting(ChronoField.MILLI_OF_SECOND, 0)
.toFormatter();
Works for me
In cases where you simply want to take a format (whether or not it has time) and want to parse to a LocalDateTime, you can do the following.
LocalDateTime parseDateTime(String dateTime, DateTimeFormatter fmt) {
return fmt.parse(dateTime, t -> {
LocalDate date = t.query(TemporalQueries.localDate());
LocalTime time = t.query(TemporalQueries.localTime());
return LocalDateTime.of(date, time != null ? time : LocalTime.MIDNIGHT);
});
}
I needed this because I was getting the date/time pattern as a parameter for a custom Spark UDF.
This works fine
public class DateDemo {
public static void main(String[] args) {
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("dd-MM-yyyy hh:mm");
String date = "16-08-2018 12:10";
LocalDate localDate = LocalDate.parse(date, formatter);
System.out.println("VALUE="+localDate);
DateTimeFormatter formatter1 = DateTimeFormatter.ofPattern("dd-MM-yyyy HH:mm");
LocalDateTime parse = LocalDateTime.parse(date, formatter1);
System.out.println("VALUE1="+parse);
}
}
output:
VALUE=2018-08-16
VALUE1=2018-08-16T12:10
Try this one:
DateTimeFormatter dateTimeFormatter = DateTimeFormatter.ofPattern("MM-dd-yyyy");
LocalDate fromLocalDate = LocalDate.parse(fromdstrong textate, dateTimeFormatter);
You can add any format you want. That works for me!
I arrived at this problem because my input string didn't have a year in it:
input string: Tuesday, June 8 at 10:00 PM
formatter: DateTimeFormatter.ofPattern("EEEE, MMMM d 'at' h:mm a", Locale.US);
I knew the year so I just appended it to get:
input string: Tuesday, June 8 at 6:30 PM 2021
formatter: DateTimeFormatter.ofPattern("EEEE, MMMM d 'at' h:mm a uuuu", Locale.US);