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How would I add two int that are in the same array to each other and convert them into an int. In the Luhn Algorithm

I am trying to add two parts of an array together to go into an int value. I am using Luhn algorithm to figure out of a credit card is a valid credit card. We are only using 6 digit credit card's just to make sure no one enter's a real credit card number. The part I am confused on is when I go to split a number that is above 10 and add it together. Example if the algorithm was to give me 12 I would need to separate it into 1 and 2 and then add them together to equal 3. I believe I am splitting it currently in the code but when I go to add them together I get some number that makes no since. here is a section of the code with some notes about it.
I have printed out numbers in certain places to show myself what is going on in certain places. I have also added in some comments that say that either the number that is printed out is what is expected, and some comments for when there isn't something I expected
int[] cardNumber = new int[]{ 1,2,3,4,5,5};
int doubleVariablesum = 0;
int singleVariablesum = 0;
int totalSum = 0;
int cutOffVar = 0;
String temp2;
for (int i = cardNumber.length - 1; i >= 0;) {
int tempSum = 0;
int temp = cardNumber[i];
temp = temp * 2;
System.out.println("This is the temp at temp * 2: " + temp);
temp2 = Integer.toString(temp);
if (temp2.length() == 1) {
System.out.println("Temp2 char 0: "+ temp2.charAt(0));
// this prints out the correct number
// Example: if there number should be 4 it will print 4
tempSum = temp2.charAt(0);
System.out.println("This is tempSum == 1: " + tempSum);
// when this goes to add temp2.charAt(0) which should be 4 it prints out //something like 56
} else {
System.out.println("TEMP2 char 0 and char 1: " + temp2.charAt(0) + " " + temp2.charAt(1));
// this prints out the correct number successfully spited
tempSum = temp2.charAt(0) + temp2.charAt(1);
System.out.println("This is tempSum != 1: " + tempSum);
// but here it when I try to add them together it is giving me something
// like 97 which doesn't make since for the numbers I am giving it
}
doubleVariablesum = tempSum + doubleVariablesum;
System.out.println("This is the Double variable: " + doubleVariablesum);
System.out.println();
i = i - 2;
}

Since you are converting the number to a string to split the integer, and then trying to add them back together. You're essentially adding the two characters numerical values together which is giving you that odd number. You would need to convert it back to an integer, which you can do by using
Integer.parseInt(String.valueOf(temp2.charAt(0)))

When adding char symbols '0' and '1' their ASCII values are added - not numbers 0 and 1.
It is possible to use method Character::getNumericValue or just subtract '0' when converting digit symbol to int.
However, it is also possible to calculate sum of digits in a 2-digit number without any conversion to String and char manipulation like this:
int sum2digits = sum / 10 + sum % 10; // sum / 10 always returns 1 if sum is a total of 2 digits

Seems like charAt() type casts into integer value, but the ascii one. Hence for the characters '0' and '1', the numbers 48 and 49 are returned resulting in a sum of 97. To fix this, you could just assign temp2 to (temp / 10) + (temp % 10). Which actually splits a two digit integer and adds their sum.

You need to be aware of the following when dealing with char and String
Assigning the result of charAt(index) to an int will assign the ASCII value and not the actual integer value. To get the actual value you need to String.valueOf(temp2.charAt(0)).
The result of concatenating chars is the sum of the ASCII values.
eg if char c = '1'; System.out.println(c + c); will print "98" not "11".
However System.out.println("" + c + c); will print "11". Note the "" will force String concatenation.

Java, converting from hexadecimal to decimal using casting

I found an exercise to convert from hex to decimal using casting, but I did not understand how that decimal + 'A' - 10 worked. Can anybody explain me?
code is here:
import java.util.Scanner;
public class Test {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("Please enter a decimal value (0-15):");
int decimal = input.nextInt();
if (decimal <= 9 && decimal >= 0) {
System.out.println("The hex value is: " + decimal);
}
else if (decimal >= 10 && decimal <= 15) {
System.out.println("The hex value is " + (char)(decimal + 'A' - 10));
}
else {
System.out.println("It's an invalid input.");
}
}
}
Thanks.

The alphabetical characters in Unicode have sequential codes:
A = 65
B = 66
C = 67
D = 68
...
So, the value of (char)('A'+1) is the same as 'B', as the char value 'A' is interpreted as 65 when used in an arithmetic expression, and then the +1 makes it 66, and then you cast it as char again, it's 'B'.
So what you have there is the value of 'A' plus the difference between the decimal and 10 (which is 0 through 5). This will give you the values 'A' + 0, 'A' + 1, 'A' + 2 etc, which means 'A', 'B', 'C' respectively when you calculate it.

Each char has integer value associated with it. Hence casting int to (char) will yield to char value.

Specific digit detector issue

I have written a small piece of code where you enter a 3 digit number via the command line, and then it detects how many 5's are in the code.
public class fivedet {
public static void main (String[] args) {
String input = args[0];
int[] a = {0,0,0};
int x = 0;
int y = 0;
int z = 0;
for(int i = 0; i<input.length();i++) {
a[i] = input.charAt(i) - 48;
}
if(a[0]==5) {
x=5;
}
if(a[1]==5) {
y=5;
}
if(a[2]==5) {
z=5;
}
System.out.println("5 digits here:" + x + y + z);
}
}
My main question is why I require the -48 term after the input.charAt(i) method in order for each value in a[] to be equal to the actual number I input.
For example I enter
java fivedet 505
and without the -48 the array a[]={53,48,53} instead of a[]={5,0,5} and I unfortunately am not experienced enough with coding java (began learning 3 months ago) to understand why this is happening.
I also do want to develop it to be able to detect different digits and for different lengths of input numbers.
I would appreciate any insight as to why this happens.

Subtracting 48 is a quick but slightly confusing way of converting from a character to an integer. It so happens that the character code for each digit is 48 away from its numeric value.
See this table of ASCII values. (Java uses unicode, not ascii - strings are UTF-16 internally - but the values are valid in this specific case). So the character '0' has the value 48; the character '9' has the value 57.
Another way of doing this would be to take 1-character substrings of input, then call Integer.parseInt() on that string, converting "1" to 1, "2" to 2, etc.

You don’t need to convert to int in order to detect character 5. Just count them as chars.
for (char i : args[0].toCharArray()) {
System.out.print(i == '5' ? i : '0');
}
Also this question has good answers to count occurrences of a char in string

Why is myArrayList.size(); producing incorrect/gigantic numbers?

Basically, I'm trying to write a program that converts a number from base 2 to base 10. What I tried doing was translating the process listed on this website under the "Doubling method" into a for loop, but for some reason the numbers I'm getting are way to big.
The basic formula is (2 * previousTotal) + (currentDigit of the ArrayList that holds the user's inputted binary number) = previousTotal.
So for 1011001 in binary, the math would be:
(0 x 2) + 1 = 1
(1 x 2) + 0 = 2
(2 x 2) + 1 = 5
(5 x 2) + 1 = 11
(11x 2) + 0 = 22
(22 x 2) + 0 = 44
(44 x 2) + 1 = 89
The console however, prints out 6185 as the result. I'm thinking it might have something to do with me using an ArrayList of characters, but the charWhole.size() returns 7, which is how many digits are in the user's binary number. As soon as I do charsWhole.get(w); however, I start getting big numbers such as 49. I'd really appreciate some help!
I wrote out this loop, and according to some print statements that I placed throughout the code and my variable addThis seems to be where the problem is. The console prints out a final total of 6185, when 1011001 in base 10 is actually 89.
public static void backto2(){
System.out.println("What base are you coming from?");
Scanner backToB10 = new Scanner(System.in);
int bringMeBack = backToB10.nextInt();
//whole
System.out.println("Please enter the whole number part of your number.");
Scanner eachDigit = new Scanner(System.in);
String theirNumber = eachDigit.nextLine();
String str = theirNumber;
ArrayList<Character> charsWhole = new ArrayList<Character>();
for (char testt : str.toCharArray()) {
charsWhole.add(testt);
}
System.out.println(theirNumber); // User's number
System.out.println(charsWhole); // User's number separated into elements of an ArrayList
System.out.println(charsWhole.size()); // Gets size of arrayList, comes out as 7 which seems fine.
int previousTotal = 0, addThis = 0, q =0;
for( int w = 0; w < charsWhole.size(); w ++) {
addThis = charsWhole.get(w); //current digit of arraylist PROBLEM
q = previousTotal *2;
previousTotal = q + addThis; // previous total gets updated
System.out.println(q);
System.out.println(addThis);
System.out.println(q + " and " + addThis + "equals " + previousTotal);
}
System.out.println(previousTotal);

You are attempting to add a character to an integer. The implicit conversion uses the ASCII value of the character, so that '1' gets converted to 49, not 1, because 49 is the code for the character '1'. Subtract '0' to get the actual integer value.
addThis = charsWhole.get(w) - '0';
This works because the digits 0-9 are represented in ASCII as the codes 48-57, so in effect you will, for '1', subtract 49 - 48 to get 1.
You'll still have to handle cases when the character is outside the range of allowable characters.
EDIT
Java uses Unicode, but for the purposes of the codes for the digits 0-9, the codes are the same (48 thru 57, or 0x30 thru 0x39) in both ASCII and Unicode.

The problem is that you're using the chars rather than the number value they represent. In the line
addThis = charsWhole.get(w);
the value of addThis is the ascii value of the character. For '0', this is 48. Use this instead:
addThis = Integer.parseInt(charsWhole.get(w));

Another suggestion to solve the same problem:
addThis = charsWhole.getNumericValue(w);
See here for more information.

Conversion from ASCII values to Char

String source = "WEDGEZ"
char letter = source.charAt(i);
shift=5;
for (int i=0;i<source.length();i++){
if (source.charAt(i) >=65 && source.charAt(i) <=90 )
letterMix =(char)(('D' + (letter - 'D' + shift) % 26));
}
Ok what I'm trying to do is take the string WEDGEZ, and shift each letter by 5, so W becomes B and E becomes J, etc. However I feel like there is some inconsistency with the numbers I'm using.
For the if statement, I'm using ASCII values, and for the
letterMix= statement, I'm using the numbers from 1-26 (I think). Well actually, the question is about that too:
What does
(char)(('D' + (letter - 'D' + shift) % 26)); return anyway? It returns a char right, but converted from an int. I found that statement online somewhere I didn't compose it entirely myself so what exactly does that statement return.
The general problem with this code is that for W it returns '/' and for Z it returns _, which I'm guessing means it's using the ASCII values. I really dont know how to approach this.
Edit: New code
for (int i=0;i<source.length();i++)
{
char letter = source.charAt(i);
letterMix=source.charAt(i);
if (source.charAt(i) >=65 && source.charAt(i) <=90 ){
letterMix=(char)('A' + ( ( (letter - 'A') + input ) % 26));
}
}

Well I'm not sure if this homework, so i'll be stingy with the Code.
You're Writing a Caesar Cipher with a shift of 5.
To address your Z -> _ problem...I'm Assuming you want all the letters to be changed into encoded letters (and not weird Symbols). The problem is ASCII values of A-Z lie between 65 and 90.
When coding Z (for eg), you end up adding 5 to it, which gives u the value 95 (_).
What you need to do is Wrap around the available alphabets. First isolate, the relative position of the character in the alphabets (ie A = 0, B = 1 ...) You Need to subtract 65 (which is ASCII of A. Add your Shift and then apply modulus 26. This will cause your value to wrap around.
eg, it your encoding Z, (ASCII=90), so relative position is 25 (= 90 - 65).
now, 25 + 5 = 30, but you need the value to be within 26. so you take modulus 26
so 30 % 26 is 4 which is E.
So here it is
char letter = message(i);
int relativePosition = letter - 'A'; // 0-25
int encode = (relativePosition + shift) % 26
char encodedChar = encode + 'A' // convert it back to ASCII.
So in one line,
char encodedChar = 'A' + ( ( (letter - 'A') + shift ) % 26)
Note, This will work only for upper case, if your planning to use lower case, you'll need some extra processing.
You can use Character.isUpperCase() to check for upper case.

You can try this code for convert ASCII values to Char
class Ascii {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
char ch=sc.next().charAt(0);
if(ch==' ') {
int in=ch;
System.out.println(in);
}
}
}