This question already has answers here:
What's the difference between next() and nextLine() methods from Scanner class?
(15 answers)
Closed 3 years ago.
im asked to write a program that removes duplicate letters from a string
**note: uppercase and lowercase letters are considered duplicates.
I wrote the code and it's working for all inputs without spacebars, when an string is given with spaces, it show errors.
i have to use loops and arrays only, no extra functions or hashs,
this is my code that ALMOST works:
case 2:
System.out.println("Give the string input");
String original=reader.next();
char[] charts=original.toCharArray();
int length=charts.length;
for (int i=0; i<length; i++){
for (int j=i+1; j<length; j++){
if(charts[i]==charts[j]||charts[i]+32==charts[j] ||charts[i]-32==charts[j]){
int temp=j; //duplicate element index
for (int k=temp; k<length-1; k++){ //delete shifting elements to left.
charts[k]=charts[k+1];
}//inner inner for
j--;
length--; // reduce char array length because we removed a character
}//if
}//inner for
}//for
String CleanString= new String(charts); //new string without repeated chars
CleanString=CleanString.substring(0,length); //set its length
System.out.println("New str = "+CleanString);
break;
I recommend you to use Scanner's method nextLine() to read string with spaces and process it with your algorithm
Scanner scanner = new Scanner(System.in);
String original = scanner.nextLine();
By the way, if you cannot use regular expressions, you maybe want to use count sort-based approach. Create an array of size equal to maximum size of char. Iterate over string and increment an array element of index X when you meet character value 'X'. Add X to your array of chars. When you meet array[X] >= 1, do not add X to array.
Your code will work fine. Just use this code at third line:
String original="";
original+=reader.nextLine();
Related
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Using charAt method, won't add them as an Int, and wont print as string. Will explain better
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(5 answers)
Why does this code print the ASCII value instead of the character
(2 answers)
How to use java.util.Scanner to correctly read user input from System.in and act on it?
(1 answer)
Closed 5 years ago.
I'm getting the user to enter a string of numbers, then a for loop should pick out each number from the string and add it to an ArrayList. I'm sure someone can help me out fairly quickly
My problem is as follows. When I print out all the values in the ArrayList, It is printing out much higher numbers e.g. 1234 = 49 50 51 52.
I think what is happening is that it is printing out the ASCII values rather than the numbers themselves. Can anyone spot where and why this is happening?
I have tried changing the int variable barcodeNumberAtI to a char, which yields the same result.
Apologies for lack of comments but this was only supposed to be a quick program
int tempNewDigit;
String barCode, ans;
int barcodeNumberAtI;
ArrayList <Integer> numbers = new ArrayList <Integer>();
public void addNumbers(){
Scanner s = new Scanner(System.in);
do{
System.out.println("Please enter a 12 digit barcode\n");
barCode = s.nextLine();
for(int i = 0; i < barCode.length(); i++){
barcodeNumberAtI = barCode.charAt(i);
System.out.println(barcodeNumberAtI);
numbers.add(barcodeNumberAtI);
}
System.out.print("Would you like to add another? y/n\n");
ans = s.nextLine();
} while (!ans.equals("n"));
}
public void displayNumbers(){
for(int i = 0; i < numbers.size(); i++){
System.out.print(numbers.get(i));
}
}
Happens at this line: barcodeNumberAtI = barCode.charAt(i);
barCode.charAt(i) returns a char which is converted to a int by using its ASCII value.
Use this instead:
barcodeNumberAtI = Character.digit(barCode.charAt(i), 10);
What Character.digit does is converting its first argument from the type char to the corresponding int in the radix specified by the second argument.
Here's a link to the documentation
This question already has answers here:
Java calculator not executing if-statement [duplicate]
(3 answers)
Closed 9 years ago.
In the code below, in the first iteration of the first for loop, boxes[a] is automatically assigned a null value.
The remainder of the iterations are fine (user input is accepted). Only the first has the issue where a null value is automatically assigned.
Does anyone know why this may be? Thank you.
package testing;
import java.util.Scanner;
public class Testing {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
Scanner in2 = new Scanner(System.in);
int boxNumber;
boxNumber = in.nextInt();
String[] boxes = new String[boxNumber];
System.out.println(boxNumber);
for(int a=0; a <= boxes.length - 1; a++){
boxes[a] = in.nextLine();
System.out.println(boxes[a]);
}
int packageNumber;
packageNumber = in2.nextInt();
String[] packages = new String[packageNumber];
System.out.println(packageNumber);
for(int n=0; n <= packageNumber - 1; n++){
packages[n] = in.nextLine();
System.out.println(packages[n]);
}
}
}
The scenario fitting the description of what occurs is when you type in a number on the first line, then the rest of the lines are strings for the boxes.
But the nextInt() method doesn't advance past the first newline character, so the first time you call nextLine(), it matches on the rest of the line until the first newline character, "" ( not null).
After the call to nextInt(), insert a call to newLine() before the for loop to bypass the first newline character.
String firstNewLine = in.nextLine();
for(int a=0; a <= boxes.length - 1; a++){
when you did hit enter after entring the first number you also have and empty line that's why nextLine() return empty string, you can use this boxNumber = in2.nextInt(); instead but I would suggest to think of another way, normally you don't need two Scanner instances
I am having an extremely difficult time splitting each line from the text file into an array of strings and using it like I need to. The split() seems to work okay. I end up having an array of strings, where the first slot of the strings array contains a number that I need to parse as an int, to continue my code. For some reason, I keep getting the error shown below that I can't seem to figure out.
My goal is it to simply store every line of the text file that contains letters, in an array, and parse the number which is going to be the first value of the line, as an integer. Once I accomplish this, I need to be able to use every preceding group of letters independently, so I am trying to get those in an array as well.
I appreciate any help with this.
Many thanks in advance!
NOTE: numGrammars is the first number shown on the first line of the text file.
My Code
numGrammars = Integer.parseInt(fin.next());
System.out.println("Num Grammars:" + numGrammars);
for(int v=0; v < numGrammars; v++){
int numVariables = Integer.parseInt(fin.next());
System.out.printf("numVariables: %s", numVariables);
for(int z=0; z < numVariables; z++){
//reads in variable line
String line = fin.nextLine();
String[] strings = line.split(" ");
for(int m=0; m < strings.length; m++){
int numRules = Integer.parseInt(strings[0]);
//All other array slots in strings array should be groups of letters on group per slot...
}
}
}
Console Output
Num Grammars:2
numVariables: 3Exception in thread "main" java.lang.NumberFormatException: For input string: ""
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at java.lang.Integer.parseInt(Unknown Source)
at Methods.readFile(Methods.java:34)
at Main.main(Main.java:12)
Text file I am reading from:
1
3
2 S AB BB
3 A BB a b
2 B b c
Only use fin.nextLine(). After the call to next(), the cursor is right after the numVariables value 3, but before the newline. When you call nextLine() after that, it returns everything between the cursor and the newline, which is an empty string! Using nextLine() each time always places the cursor after the newline, and everything is OK.
numGrammars = Integer.parseInt(fin.nextLine());
System.out.println("Num Grammars:" + numGrammars);
for(int v=0; v < numGrammars; v++){
int numVariables = Integer.parseInt(fin.nextLine());
System.out.printf("numVariables: %s", numVariables);
for(int z=0; z < numVariables; z++){
//reads in variable line
String line = fin.nextLine();
String[] strings = line.split(" ");
for(int m=0; m < strings.length; m++){
int numRules = Integer.parseInt(strings[0]);
//All other array slots in strings array should be groups of letters on group per slot...
}
}
}
You don't say what fin is, so I can't say what it does for next() versus nextLine(), but perhaps you are picking up the newline character in your string.
Instructions:
Write a program that will read a line of text that ends
with a period, which serves as a sentinel value. Display all the
letters that occur in the text, one per line and in alphabetical
order, along with the number of times each letter occurs in the text.
Use an array of base type int of length 26 so that the element at
index 0 contains the number of as. and index 1 contain number of bs etc.
package alphabetize;
import java.util.*;
public class Alphabetize
{
private static void number(String s)
{
int[] array = new int[26];
s = s.toUpperCase();
System.out.println(s);
for (int i = 0; i < s.length(); ++i)
{
if (s.charAt(i) >= 'A' && s.charAt(i) <= 'Z')
{
++array[s.charAt(i) - 'A'];
}
}
for (int i = 0; i < 26; ++i)
{
System.out.println("|" + (char) ('A' + i) + "|" + array[i] + "|");
}
}
public static void main(String[] args)
{
Scanner keyboard = new Scanner(System.in);
String aString = ".";
while (true)
{
System.out.println("Please enter sentence with a period to end");
aString = keyboard.nextLine();
if (".".equals(aString))
{
System.exit(0);
}
number(aString);
}
}
}
Still having problem with the period thing.. it does not seem to work the way i did it.
Considering this is a homework and instructions are very specific, you should read the text character by character instead of using built-in functions
If your text file was something like
abcabca.
The output should be something a appears three times, b appears two times etc etc.
So your algo should be something like
Read next character
If char is period goto 5
If char is space goto 1.
If char is between a <-> z. update the counter in arr[0..25] and goto 1
output arr[0..25] one per line
Was it mandated that this assignment is done in Java? The whole idea of a "sentinal character" rather than just using a line terminator is pretty bizarre.
Anyway, you can achieve the behaviour you want by setting the delimiter of Scanner:
keyboard.useDelimiter("\\.");
As for the looping, a big hint is this:
int[] counts;
counts[chars[0] - 'a'] = counts[chars[0] - 'a'] + 1;
or simply
counts[chars[0] - 'a']++;
I'll leave it up to you to include that in a loop.
Edit
If you are looking for character-at-a-time input, I would suggest you use an InputStreamReader instead of Scanner for your input. Here's a basic skeleton of what that looks like:
Reader reader = new InputStreamReader(System.in);
while (true) {
int nextInput = reader.read();
if (nextInput == -1) {
System.out.println("End of input reached without sentinal character");
break;
}
char nextChar = (char) nextInput;
//deal with next character
}
Still, read() will typically block until either the end of input is reached (CTRL-D or CTRL-Z from most consoles) or a new line is sent. Thus the sentinal character is of limited use since you still have to do something after typing ".".
You have to check whether period is there at the end or not. So the last character should be '.'.
Then take the length of string before last '.'.
For the counting part create an array like u are doing :
int [] name = new int[26]
where each index starting from 0, 25 corresponds to 'a' till 'z'.
Now you put the string characters in a loop and have to check what that character is like :
if its a 'a' : increase the value at index 0 by 1.
if its a 'd' : increase the value at index 3 by 1.
like wise.
later you display the whole array with a, z along with indexes from 0 till 25.
Suggestion: If its not required to use an array, and you can use any other data-structure you can implement the same in a HashMap very easily. by keeping 'a', 'z' as the keys and count as the corresponding values. and then retrieving and showing the values will also be easier.
You need an int array (e.g., int[] counts = new int[26];) After you read the input line, examine it character by character in a loop. If the character is a not period, then increment the appropriate element of the counts array. (If the character is a, then increment counts[0]; if it is b, increment counts[1]; etc. Hint: you can subtract a from the character to get the appropriate index.) When you find a period, exit the loop and print the results (probably using a second loop).
Hey guys, I'm new to Java (well, 3/4 of a year spent on it).
So I don't know much about it, I can do basic things, but the advanced concepts have not been explained to me, and there is so much to learn! So please go a little but easy on me...
Ok, so I have this project where I need to read lines of text from a file into an array but only those which meet specific conditions. Now, I read the lines into the array, and then skip out on all of those which don't meet the criteria. I use a for loop for this. This is fine, but then when I print out my array (required) null values crop up all over the place where I skipped out on the words.
How would I remove the null elements specifically? I have tried looking everywhere, but the explanations have gone way over my head!
Here is the code that I have to deal with the arrays specifically: (scanf is the scanner, created a few lines ago):
//create string array and re-open file
scanf = new Scanner(new File ("3letterWords.txt"));//re-open file
String words [] = new String [countLines];//word array
String read = "";//to read file
int consonant=0;//count consonants
int vowel=0;//count vowels
//scan words into array
for (int i=0; i<countLines; i++)
{
read=scanf.nextLine();
if (read.length()!=0)//skip blank lines
{
//add vowels
if (read.charAt(0)=='a'||read.charAt(0)=='e'||read.charAt(0)=='i'||read.charAt(0)=='o'||read.charAt(0)=='u')
{
if (read.charAt(2)=='a'||read.charAt(2)=='e'||read.charAt(2)=='i'||read.charAt(2)=='o'||read.charAt(2)=='u')
{
words[i]=read;
vowel++;
}
}
//add consonants
if (read.charAt(0)!='a'&&read.charAt(0)!='e'&&read.charAt(0)!='i'&&read.charAt(0)!='o'&&read.charAt(0)!='u')
{
if (read.charAt(2)!='a'&&read.charAt(2)!='e'&&read.charAt(2)!='i'&&read.charAt(2)!='o'&&read.charAt(2)!='u')
{
words[i]=read;
consonant++;
}
}
}//end if
//break out of loop when reached EOF
if (scanf.hasNext()==false)
break;
}//end for
//print data
System.out.println("There are "+vowel+" vowel words\nThere are "+consonant+" consonant words\nList of words: ");
for (int i=0; i<words.length; i++)
System.out.println(words[i]);
Thanks so much for any help received!
Just have a different counter for the words array and increment it only when you add a word:
int count = 0;
for (int i=0; i<countLines; i++) {
...
// in place of: words[i] = read;
words[count++] = read;
...
}
When printing the words, just loop from 0 to count.
Also, here's a simpler way of checking for a vowel/consonant. Instead of:
if (read.charAt(0)=='a'||read.charAt(0)=='e'||read.charAt(0)=='i'||read.charAt(0)=='o'||read.charAt(0)=='u')
you can do:
if ("aeiou".indexOf(read.charAt(0)) > -1)
Update: Say read.charAt(0) is some character x. The above line says look for that character in the string "aeiou". indexOf returns the position of the character if found or -1 otherwise. So anything > -1 means that x was one of the characters in "aeiou", in other words, x is a vowel.
public static String[] removeElements(String[] allElements) {
String[] _localAllElements = new String[allElements.length];
for(int i = 0; i < allElements.length; i++)
if(allElements[i] != null)
_localAllElements[i] = allElements[i];
return _localAllElements;
}