I know that the method would be protected not private if what I want to do was intended, however I want to make my own PriorityQueue that will need to call siftUp a few more times. I can't edit the declaration of the field as PriorityQueue is a part of the java library, so I'm looking for another way to call it. Is the only thing I can do copy the whole class from the library and change it to my needs?
There is no way to override the superclass's private method, unfortunately.
According to Oracle's documentation on Controlling Access to Members of a Class, the private method is only for the class itself to access.
Here's the table of the Superclass's visibility to Subclass:
I believe they offer the developers to implement the "least privilege" principle by offering the private visibility so there would be no way for it to be accessible anywhere outside the class it was created in.
If you wanted to be able to override it, you should make it protected or don't give it any modifier (considered "Package access" level).
Here is an example:
package this.silly.package;
public class Foo() {
void thisAction() {
// do stuff...
}
private void somethingElse() {
// Do secret stuff.
}
}
package this.silly.package;
public class Bar extends Foo() {
// This will work
// because this class is in the same package as Foo.
#Override
void thisAction() {
// Do something else
}
// This will not work
// because Foo made this method private,
// so it is only accessible by Foo.
#Override
private void somethingElse() {
// Please don't do secret stuff. You might drive me crazy!
}
}
Related
In an abstract class I have a Predicate field, that is meant to be a combination of an unknown number of other Predicates. Joining the predicates works just fine but I am trying to have some way to know when the predicate has been initialized (or rather, just a way to know if it has or hasn't been initted).
Here is a short example of what I'm talking about:
public abstract class LimitedSystem implements Moveable {
private Predicate<Double> limits;
private final boolean initialized;
public void setLimits(SingleLimit... limits) {
List<Predicate<Double>> limitsList = Arrays.asList(limits);
this.limits = limitsList.stream().reduce(Predicate::and).orElse(x -> true);
}
public void setLimits(TwoLimits limits) {
this.limits = limits;
}
...
I am looking for ways to set initialized to true once (and once only, hence the final. I think I used it right) any of the setLimits have been called (they're overloaded).
I have other setLimits methods, but for the sake of generic code, I don't want to put a initialized at the end of each of the overloaded methods.
So my question is how can I, in a generic way, set the value of initialized after any of the setLimits methods has been called.
My first idea was to try to wrap the setLimits in some generic method which would call the correct overload by the parameter it gets, and then change initialized in that method. But I am not sure if that's a good idea.
Some other idea I got from another question1 was to put the setLimits in some interface or something similar. But I'm not sure how useful that might prove.
So how might this be accomplished?
(Also, if you happen to notice any design problems in this, please tell me because I'm trying to improve in that matter)
There's no need for separate fields:
private Predicate<Double> limits;
private final boolean initialized;
is basically
private Optional<Predicate<Double>> limits = Optional.empty();
if you want initialized to be set to true once limits is set,
provided you can guarantee that none of the setLimits methods can set it to Optional.empty() again. initialized == limits.isPresent().
You can't guarantee that a method is called in the body of an overridden method; in any case, this is a variant of the Call super antipattern.
You can do it like this:
abstract class Base {
final void setFoo(Object param) { // final, so can't be overridden.
setFooImpl(param);
thingThatMustBeCalled();
}
protected abstract void setFooImpl(Object param);
final void thingThatMustBeCalled() { ... }
}
class Derived extends Base {
#Override protected void setFooImpl(Object param) { ... }
}
But it's pretty ugly.
Say, I have a package Pack containing classes A and B. A is self-contained and no one (even in the Pack) should see A's insides, so most of the fields and methods are private.
Now I want to extend A to change one of its private methods keeping the rest - let it be class AMod. Doing it requires most of A's fields and the method to override to be protected, but protected gives access to the package.
So how do I create AMod inside Pack so that AMod has an access to A's fields and methods while no one else does? Make a nested/separate package?
UPD:
UPD2:
UPD3:
As Jacob G. suggested, my code needed redesigning, and I managed to remove the derived class from the architecture. Thanks for help!
The one answer I find missing: don't be so focused on using inheritance in order to avoid code duplication.
If you only need a subtle variation of behavior of A then you should first consider to "wrap" around A (for example via decorator) instead of extending A - the good old FCoI!
If that isn't possible: have a very close look at the common behavior of A and Amod and extract those parts in a common base class.
Finally: don't get too energetic about java access modifiers in the first place. In the end, they help you to communicate a certain thought or idea. "Evil-willing" people will always find a way to work around your intentions. What I am saying is: if you are concerned that your team members use your class in the wrong way ... that is a social problem; and you will never be able to solve that on the technical layer. You have to solve it on the social layer, too (by educating people to ensure that they understand what to do; instead of hoping that private here or protected there will prevent them from doing the wrong thing).
In other words: establish a simple policy such as "only what is marked public is meant to be public; anything else is not" might be able to table such discussions for all times. Versus spending hours and hours to find a perfect private-protected solution within source code.
Thanks for posting code.
My advice would be to first move B#stepBMod into A.java. Then, you can pass a boolean parameter to A#build; with this, you can rewrite A#build:
public Result build(boolean mod) {
stepA();
if (mod) {
stepBMod();
} else {
stepB();
}
stepC();
return result;
}
Now, B.java isn't needed anymore.
Your question is two parts. 1)Accessing fields and 2)Accessing methods.
Case1), you should make class A's fields protected. This means no one can access it by name, except derived classes.
Case2), you cannot access a protected method by name, unless in a derived class. But still you can access a protected method by name using an object of A. In order to prevent other classes making objects, your A class should be abstract.
Here is an example
public abstract class A{
protected int n;
protected void display(){
System.out.println(n);
}
}
public class B extends A{
public void demo(){
B object = new B();
object.display();
}
public void modify(){
n = 0;
}
}
Update
class A
{
public A(Args args){...}
public Result build() {
stepA();
stepB();
stepC();
return result;
}
protected void stepA() {...}
private void stepB() {...}
protected void stepC() {...}
protected T field;
}
class AMod extends A
{
public AMod(Args args){
super(args);
...
}
public Result build() {
stepA();
stepBMod();
stepC();
return result;
}
private void stepBMod() {...}
}
i have my DTO class that is :
public class EmailResponse {
// Make public to avoid getters and setters
public Email email;
public RequestData reqData;
public EmailResponse() {
super();
}
}
and i want to implement to it this interface:
public interface IAssertionErrorDo {
public void onErrorDo();
}
but i want to do it during execution, i don't want to touch "EmailResponse" because it would not be ok to make it implements that interface due they don't belong to the same layer, i mean, EmailResponse would belong to service layer and IAssertionError would belong to test layer. I am using TestNG.
Do you know how i could do this? Regards
EDIT:
My implementation is this:
EmailResponse emailResponse = emailService.getUserEmail(userId);
And the reason i want to do this "injection" is because i have
public class LoggingAssert
extends Assertion {
private static final Logger LOGGER = LoggerFactory.getLogger(LoggingAssert.class);
private IAssertionErrorDo dataE;
#Override
public void onAssertFailure(IAssert a, AssertionError ex) {
LOGGER.info("[ERROR] " + a.getMessage());
if (this.dataE != null) {
this.dataE.onErrorDo();
}
}
public LoggingAssert setOnErrorDo(IAssertionErrorDo object) {
this.object = object;
return this;
}
}
loggingAssert.setOnErrorDo(emailResponse).assertNotNull(emailResponse.getEmail().getId(),
"Checking created email doesn't exists");
So i want to if assert fails execute method onErrorDo() from emailResponse
You could do
public class MyEmailResponse extends EmailResponse implements IAssertionErrorDo {
...
}
implementation calls in interfaces, you can call more than 1 interface if you want by adding commas to separate them..
to call interface methods you simply just use the method's name.
like this:
public class MyEmailResponse implements IAssertionErrorDo
{
public void onErrorDo() {//define it's behavior}
}
if you extend a class you use:
super.MyMethod()
to call the a method inside the extended class, but if you already have an extended class and want a method from another class you have to create an object for that class first then call it, thus:
MyClass mc = new MyClass();
if it is in a different package then
myPackage.MyClass mc = new myPackage.MyClass();
then you call your method from that class using the object you created, which is in this case mc.. so:
mc.MyMethod();
if you want it to return a variable then you will need to add a return statement in that method with the variable you want it to return.
interfaces are usually used for global an changing environments (dynamics), for example if you developed a program and it needs a driver to connect to databases then you will make an interface and send it to the database developers, and each one will fill the codes in that interface and send it back... this guarantees consistency.
when you implement an interface you have to define every method inside it (even if you leave it empty) and you cannot change the interface's methods names nor add... it is used in other areas as well, i don't think you need to use it in your case.
In Java: What is the best way to pass a method from one object to another so that it can be called at a later time by the second object?
I come from an ActionScript background where it is as easy to pass around references to methods as it is to pass around references to variables but this seems to be much more difficult in Java. The first few links I found flat out say it is not possible (and it may have been at the time of their posting), but then I found http://www.javacamp.org/javavscsharp/delegate.html which details how this can be accomplished.
My issue with using Javacamp's example is the string based reference to the method. Methods get renamed all the time and a string reference will only complain once you actually run that function runtime as opposed to compile time for a proper explicit link.
Is there no way to do this with proper explicit links to the method you want the other class to execute?
Model of what I am hoping to accomplish:
Player clicks an upgrade button on Activity1 > Activity1 passes upgrade method to a new confirmation activity
Player clicks "Yes" > Confirmation activity calls upgrade method passed in from Activity1
OR: Player clicks "No" > Confirmation Activity closes
EDIT:
To be clear I am not looking for a static method solution as that would require my Confirmation activity to hold many lines of logic for which static method to call. The Confirmation activity will be used all over my application: a simple "Are you sure you want to X?" -Yes -No, if yes execute X
I am currently looking at implementing onActivityResult to avoid this issue but that will be more logic than I like for this kind of issue.
you can use interfaces like this:
public interface MyMethod {
public void method();
}
public class FirtObject{
private SecondObject ob;
public void tellSecondObjectExecuteLater(){
ob.executeLater( new MyMethod() {
public void method(){System.out.println("duh Method");} });
}
}
public class SecondObject {
private MyMethod myMth;
public void executeLater(MyMethod mth){
myMth = mth;
}
public void executeNow(){
myMth.method();
}
}
does this solve your problem?
The typical way to pass methods is to use an Interface and Anonymous Inner Classes. In order to maintain static typing an Interface is used to declare the method signature and typing information. The caller can use either a concrete implementation of that interface as a normal class or using Anonymous Inner Classes for quick class creation. I'll use standard Java SDK classes to illustrate:
interface Comparator<T> {
public int compare( T a, T b);
}
class SpecialCollection<T> {
public void sort( Comparator<T> comparator ) {...}
}
public class SomeClient {
public void doSomething( SpecialCollection<SpecialObj> collection ) {
collection.sort( new Comparator<SpecialObj>() {
public int compare( SpecialObject a, SpecialObject b ) {
// some implementation
}
} );
}
}
The above is an example of a strategy pattern. The thing about the strategy pattern (and passing callback methods like in Javascript). The author has to plan for those types of extensions. The author has to predict up front where he/she wants you to extend. And it just happens it's cleanest if you use Interfaces.
However, pure delegation doesn't have to have always involve Interfaces. You can pass concrete classes, since Java can always pass a subclass that overrides various methods of that class to change what method or code will be invoked. For example in Java InputStream/OutputStream are abstract classes and you typically pass subclass instances to the methods.
If you need the method to act differently depending on the context (AKA, it is different depending on how it is created), you'll want to pass along the instance of the class that the method is in.
If it is a static method, you can just referenced the method itself if you import that class at the top of your new class.
For example, lets say you have a method that will tell you stuff about a certain string. IF the class looks like this:
class stringChecker {
private String stringToCheck;
public class stringChecker(String s) {
stringToCheck = s;
}
public int getStringLength() {
return stringToCheck.length();
}
public boolean stringStartsWith(String startsWith) {
return (stringToCheck.indexOf(startsWith) == 0);
}
}
Then you'll want to pass along the instance, since it is non-static. Different instances have different strings that they were created with, so you will get a different return if you use a different instance.
However, if your class looks more like this:
class stringChecker {
public static int getStringLength(String s) {
return s.length();
}
public static boolean stringStartsWith(String s, String startsWith) {
return (s.indexOf(startsWith) == 0);
}
}
Then you can just reference those methods with stringChecker.getStringLength("test");, because the methods are static. It doesn't matter what instance they are in. The returned result depends ONLY on what is being passed in. You just have to make sure to add import stringChecker; at the top or whatever your class will be called. For you, it'll probably be something like com.example.blah.otherthing.stringChecker, since you're working with android.
Good luck! I hope this helps :)
EDIT: Looks like I may have read the problem too quickly...if this isn't what you were asking about, just let me know with a comment and I'll delete this answer so as to not confuse anybody else.
You said that you are using it in a project to open a Confirmation activity.
Activities should not contain references to each other to avoid memory leaks. To pass data between activities should be used Intent class. To receive a result, call StartActivityForResult() and get result in the onActivityResult() method.
But in general for your task is more suitable AlertDialog or PopupWindow.
Given that I have a class Base that has a single argument constructor with a TextBox object as it's argument. If I have a class Simple of the following form:
public class Simple extends Base {
public Simple(){
TextBox t = new TextBox();
super(t);
//wouldn't it be nice if I could do things with t down here?
}
}
I will get a error telling me that the call to super must be the first call in a constructor. However, oddly enough, I can do this.
public class Simple extends Base {
public Simple(){
super(new TextBox());
}
}
Why is it that this is permited, but the first example is not? I can understand needing to setup the subclass first, and perhaps not allowing object variables to be instantiated before the super-constructor is called. But t is clearly a method (local) variable, so why not allow it?
Is there a way to get around this limitation? Is there a good and safe way to hold variables to things you might construct BEFORE calling super but AFTER you have entered the constructor? Or, more generically, allowing for computation to be done before super is actually called, but within the constructor?
Thank you.
Yes, there is a workaround for your simple case. You can create a private constructor that takes TextBox as an argument and call that from your public constructor.
public class Simple extends Base {
private Simple(TextBox t) {
super(t);
// continue doing stuff with t here
}
public Simple() {
this(new TextBox());
}
}
For more complicated stuff, you need to use a factory or a static factory method.
I had the same problem with computation before super call. Sometimes you want to check some conditions before calling super(). For example, you have a class that uses a lot of resources when created. the sub-class wants some extra data and might want to check them first, before calling the super-constructor. There is a simple way around this problem. might look a bit strange, but it works well:
Use a private static method inside your class that returns the argument of the super-constructor and make your checks inside:
public class Simple extends Base {
public Simple(){
super(createTextBox());
}
private static TextBox createTextBox() {
TextBox t = new TextBox();
t.doSomething();
// ... or more
return t;
}
}
It is required by the language in order to ensure that the superclass is reliably constructed first. In particular, "If a constructor does not explicitly invoke a superclass constructor, the Java compiler automatically inserts a call to the no-argument constructor of the superclass."
In your example, the superclass may rely on the state of t at construction time. You can always ask for a copy later.
There's an extensive discussion here and here.
You can define a static supplier lambda which can contain more complicated logic.
public class MyClass {
private static Supplier<MyType> myTypeSupplier = () -> {
return new MyType();
};
public MyClass() {
super(clientConfig, myTypeSupplier.get());
}
}
The reason why the second example is allowed but not the first is most likely to keep the language tidy and not introduce strange rules.
Allowing any code to run before super has been called would be dangerous since you might mess with things that should have been initialized but still haven't been. Basically, I guess you can do quite a lot of things in the call to super itself (e.g. call a static method for calculating some stuff that needs to go to the constructor), but you'll never be able to use anything from the not-yet-completely-constructed object which is a good thing.
This is my solution that allows to create additional object, modify it without creating extra classes, fields, methods etc.
class TextBox {
}
class Base {
public Base(TextBox textBox) {
}
}
public class Simple extends Base {
public Simple() {
super(((Supplier<TextBox>) () -> {
var textBox = new TextBox();
//some logic with text box
return textBox;
}).get());
}
}
That's how Java works :-) There are technical reasons why it was chosen this way. It might indeed be odd that you can not do computations on locals before calling super, but in Java the object must first be allocated and thus it needs to go all the way up to Object so that all fields are correctly initialized before you can modify them.
In your case there is most of the time a getter that allows you to access the parameter you gave to super(). So you would use this:
super( new TextBox() );
final TextBox box = getWidget();
... do your thing...