This question already has an answer here:
FIXT1.1 ERROR_MISSING_EXECUTINGTRADER PartyRole
(1 answer)
Closed 3 years ago.
How can you send the new order single request on test PSE.
I made my request according to FIX official documents but still, error is coming-
Request-
8=FIXT.1.19=15335=D34=349=13552=20191226-04:40:18.78856=PSE11=157733521842938=10040=144=9.8154=155=2GO59=060=20191226-12:40:18.772447=D448=0452=36453=010=062
Response-
8=FIXT.1.19=21335=834=349=PSE52=20191226-04:40:18.86056=13511=157733521842914=017=TE536337=NONE38=10039=840=144=9.8154=155=2GO58=ERROR.MISSING_EXECUTINGTRADER
PartyRole60=20191226-04:40:18.856103=99150=8151=010=209
Please help and suggest me how can I send my request on test PSE and get a proper response.
Your issue is not a generic FIX protocol issue, but a logical error that stems from you not following your counterparty's proper procedure.
Do you see this field? 58=ERROR.MISSING_EXECUTINGTRADER
You have sent them New Order Single message that is clearly missing information that they want.
You need to get ahold of your counterparty's documentation for this FIX interface and read it thoroughly.
Related
This question already has answers here:
HTTP POST using JSON in Java
(12 answers)
Closed 1 year ago.
I want to make an HTTP request with Java,
but I'm new to Java and have no clue how.
I've had a look at a few tutorials,
but I was unable to understand anything.
I want to send JSON data and also receive JSON data.
In Python it would look like this:
response = json.load(urllib.request.urlopen(urllib.request.Request('http://localhost:8765', requestJson)))
Any help would be much appreciated.
Use the below link for reference
https://www.baeldung.com/java-http-request
You can use rest template also if you're using external library.
ResponseEntity<> response = restTemplate.exchange(
UriComponentsBuilder.fromHttpUrl(baseurl + "jobs").toString(),
HttpMethod.POST,
new HttpEntity<>(body,headers),
<someClass>.class);
I am trying to fetch Facebook user access token as in the question title.
I configured my application, I am sending request to:
redirect:https://www.facebook.com/dialog/oauth?client_id="+appId+"&redirect_uri="+REDIRECT_URI+"&response_type=token
and I always got response where there is a hashtag before first parameter:
/auth/fb/callback/?#access_token=blablabla
Does anyone know why Fb is keep adding the # before access_token??
I have hard time to parse this from HTTP request, as Spring shows me 0 GET parameters.
Is it possible to avoid this situation or parse with #???
Does anyone know why Fb is keep adding the # before access_token?
Because you asked for it, by using response_type=token. You actually want to ask for a code instead.
https://developers.facebook.com/docs/facebook-login/manually-build-a-login-flow#logindialog
This question already has answers here:
Can I read the hash portion of the URL on my server-side application (PHP, Ruby, Python, etc.)?
(12 answers)
Closed 6 years ago.
I am trying to get the entire url in filters but it doesn't give me after #
Browser url :
/en_US/web/guest/regulatory/disclosures#esma_endorsement
Below is code to get the url in my filters:
String reqUrl = httpReq.getRequestURL().toString();
It always gives:
/en_US/web/guest/regulatory/disclosures
I also tried with queryString but no luck.
I want to get the url along with #symbol
Can any one help me out?
Thanks,
Naresh.
That's how it works. The # part is interpreted client side, by the browser. There's no need to ever let the server know this part. If you definitely want it, you can access it with javascript on the browser and explicitly send it to the server, using parameters. But it won't be part of the URL if you don't explicitly handle it. And when it will be, it won't be separated by #
The part that you would like to receive is not actually belong to URI. Hash character called 'fragment identifier' and it is not send to server. That part is used on some extra actions on browser.
So basically you cant retrieve that part on server side. But you can do some tricks like retrieving related part on front end and sending back to server as a part of your url like:
/en_US/web/guest/regulatory/disclosures?name=esma_endorsement
This question already has answers here:
Why do you have to call URLConnection#getInputStream to be able to write out to URLConnection#getOutputStream?
(6 answers)
Closed 7 years ago.
So, I am kinda new to android development and Yesterday I had a problem.
My problem was that when I was trying to post something to a servlet using standard OutputStream only, and it was not making the request then I put InputSteam with my HttpURLConection then the request went through.
The OutputStream is what you (as the client) are going to write your HTTP POST data to. The InputStream, in this case, will be the response from the server. Presumably, the server doesn't commit the transaction until the response completes.
This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
How to use java.net.URLConnection to fire and handle HTTP requests?
I have to send an http post message to a server.
This message must have an header and a body and to send it i must use a Stream.
Both the header and the body must be an array of Byte.
How can I do this?
Thank you
From the server you can get header information separately from HttpServletRequest.getHeaders(). Data should be read in the form of parts (multipart/form-data) using input stream that can be opened from Request object. Hope this help.
Ref:
http://www.servlets.com/cos/javadoc/com/oreilly/servlet/MultipartRequest.html
http://www.jguru.com/faq/view.jsp?EID=1045507