I have the below code that is not reading or infinitely looping when a user inputs text using System.in. If I hard code the text into the Scanner variable it works fine so I am not sure what is wrong with the System.in portion of this code. Any help is appreciated.
import java.util.Scanner; // needed to use the Scanner class
public class HW2 {
static Scanner in = new Scanner(System.in);
public static void main(String [] args) {
System.out.println("Enter your line here");
int the =0;
int and =0;
int is = 0;
int was =0;
int noword =0;
while (in.hasNext()){
String word = in.next();
if (word.equals("the")){
the++;
}
else if( word.equals("and")){
and ++;
}
else if (word.equals("is")){
is++;
}
else if (word.equals("was")){
was++;
}
else noword++;
}
System.out.println("The number of occurrences of the was"+ the);
System.out.println("The number of occurrences of and was"+ and);
System.out.println("The number of occurrences of is was"+ is);
System.out.println("The number of occurrences of was was"+ was);
}
}
As has been mentioned, a Scanner attached to System.in will block while looking for more input. One way to approach this would be to read a single line in from the scanner, tokenize it, and then loop through the words that way. That would look something like this:
//...
String line = in.nextLine(); // Scanner will block waiting for user to hit enter
for (String word : line.split(" ")){
if (word.equals("the")) {
the++;
}
//...
You can always substitute one loop structure (for, while, do-while) for another. They all do the same thing, just with different syntax to make one a bit simpler to use than others depending on the circumstances. So if you want to use a while loop, you can do something like this:
// ...
String line = in.nextLine();
String[] tokens = line.split(" ");
int i = 0;
while (i < tokens.length){
String word = tokens[i];
if (word.equals("the")) {
the++;
}
// ...
i++;
} // end of the while loop
However, I'm of the opinion that a for loop is cleaner in the case of looping over a known set of data. While loops are better when you have an unknown dataset, but a known exit condition.
As System.in is always available while the program is running unless you close it. It will never exit the while loop. So you could add else if (word.equals("exit")) { break; }. This way, whenever you type 'exit' it will close the while loop and execute the code AFTER the while loop.
Depends, do you want to just read 1 line of text and then count the words individually?
Because is you want only one line you could take the input string using the Scanner library and split the string into individual words and apply the if-statement then. Something like:
public static void main(String [] args) {
System.out.println("Enter your line here");
int the =0;
int and =0;
int is = 0;
int was =0;
int noword =0;
String input = in.nextLine();
String words[] = input.split(" ");
for (String s : words) {
if (s.equals("the")){
the++;
} else if( s.equals("and")){
and++;
} else if (s.equals("is")){
is++;
} else if (s.equals("was")){
was++;
} else {
noword++;
}
}
System.out.println("The number of occurrences of the was: "+ the);
System.out.println("The number of occurrences of and was: "+ and);
System.out.println("The number of occurrences of is was: "+ is);
System.out.println("The number of occurrences of was was: "+ was);
}
This way you won't need a while loop at all. So it's more processor and memory efficient.
Related
Write a method called countWords that accepts an ArrayList of String as argument and
prints out the number of words (i.e. Strings) that start with ―A‖ or ―a‖ and prints all words longer than 5 characters on one line.
My solution is like
int count=0;
String[] st=null;
Scanner input=new Scanner(System.in);
ArrayList<String> array = new ArrayList<String>();
System.out.println("please input something");
while(input.hasNext()) {
String st1=input.next();
array.add(st1);
}
for(int i=0; i<array.size();i++) {
if(array.get(i).startsWith("a")||array.get(i).startsWith("A")) {
count++;
}
}
for(int j=0; j<array.size(); j++) {
if(array.get(j).length()>5)
st[j]=array.get(j);
}
System.out.println(count);
System.out.println(st);
}
but there will be no end for typing in Strings
As the last line of your question said
but there will be no end for typing in Strings
Well That is because you did not provided any way to end the while loop.
while(input.hasNext())
Will run forever and ever waiting for next user input. You have to break the while loop once the inputting is done.
AFTERWARDS
As the question said "prints out the number of words that start with A or a and prints all words longer than 5 characters on one line."
For this you can loop through the ArrayList and check for
if(array.get(i).startsWith("A") || array.get(i).startsWith("a")) count++;
if(array.get(i).length()>5) System.out.print(array.get(i)+" ");
and print the number of A or a Occurrence after the loop
System.out.println("\n Number of word with A or a:"+count);
Here is a working implementation of your code
public static void main(String[] args) {
int count=0;
String[] st=null;
Scanner input=new Scanner(System.in);
ArrayList<String> array = new ArrayList<String>();
System.out.println("please input something");
//System.out.println(input.hasNext());
while(input.hasNext()) {
String st1=input.next();
//System.out.println((int) st1.charAt(0));
if(st1.equals("exit")) break;
array.add(st1);
}
for(int i=0; i<array.size();i++) {
if(array.get(i).startsWith("A") || array.get(i).startsWith("a")){
count++;
}
if(array.get(i).length()>5) {
System.out.print(array.get(i)+" ");
}
}
System.out.println("\nNumber of word with A or a:"+count);
}
to end the loop you have to type exit.
Here is a solution to your problem..
import java.util.Arrays;
import java.util.List;
public class Test {
public static void main(String... args){
// Sample String sentence
String sentence = "This is the sentence with 5 words starting with
all like allwords alltogether also Allnotout allother and allofus.";
// Splitting above sentence to get each word separately and storing them into List
List<String> strings = Arrays.asList(sentence.split("\\s+"));
// calling a method named countWord() as per your assignment question.
Test.countWords(strings);
}
// implementing that method
static void countWords(List<String> input){
long count = input.stream().filter(word -> word.startsWith("all") || word.startsWith("All")).count();
System.out.print("Total words starting with all/All are : "+ count +"\t");
input.stream().filter(word -> word.length() > 5).forEach( word -> System.out.print(word + "\t"));
}
}
So I am trying to read a file using a scanner. This file contains data where there are two towns, and the distance between them follows them on each line. So like this:
Ebor,Guyra,90
I am trying to get each town individual, allowing for duplicates. This is what I have so far:
// Create scanner for file for data
Scanner scanner = new Scanner(new File(file)).useDelimiter("(\\p{javaWhitespace}|\\.|,)+");
// First, count total number of elements in data set
int dataCount = 0;
while(scanner.hasNext())
{
System.out.print(scanner.next());
System.out.println();
dataCount++;
}
Right now, the program prints out each piece of information, whether it is a town name, or an integer value. Like so:
Ebor
Guyra
90
How can I make it so I have an output like this for each line:
Ebor
Guyra
Thank you!
Assuming well-formed input, just modify the loop as:
while(scanner.hasNext())
{
System.out.print(scanner.next());
System.out.print(scanner.next());
System.out.println();
scanner.next();
dataCount += 3;
}
Otherwise, if the input is not well-formed, check with hasNext() before each next() call if you need to break the loop there.
Try it that way:
Scanner scanner = new Scanner(new File(file));
int dataCount = 0;
while(scanner.hasNext())
{
String[] line = scanner.nextLine().split(",");
for(String e : line) {
if (!e.matches("-?\\d+")) System.out.println(e);;
}
System.out.println();
dataCount++;
}
}
We will go line by line, split it to array and check with regular expression if it is integer.
-? stays for negative sign, could have none or one
\\d+ stays for one or more digits
Example input:
Ebor,Guyra,90
Warsaw,Paris,1000
Output:
Ebor
Guyra
Warsaw
Paris
I wrote a method called intParsable:
public static boolean intParsable(String str)
{
int n = -1;
try
{
n = Integer.parseInt(str);
}
catch(Exception e) {}
return n != -1;
}
Then in your while loop I would have:
String input = scanner.next();
if(!intParsable(input))
{
System.out.print(input);
System.out.println();
dataCount++;
}
I have a program that reads a file. The file will be split into lines with the nextLine() method of scanner.
My file looks like this:
*#* lalala lalala lalaa lalala lalal la
x,v,m,k
221312, stringgg, pwd
...
*#* baba bababaa babababa
I want to go into a while loop when reading *#*, then the while should break when reaching the next *#*.
How can this be done?
Are you sure while should break? This will cause while to stop entirely. I think continue is better option, since it will just skip to next while iteration, i.e. it will skip current line.
while(...) {
String line = scanner.nextLine();
if(line.startsWith("#")) {
continue; // or break, if you're sure it's what you want
}
// your code
}
I hope this will help you
/* If I see the string first time I increase the variable n by one.
* If I see the string second time again I increase n by one, now
* n will be 2, If n is 2 I break the for loop ABC
*/
public static void main(String []args){
int n = 0;
String str;
Scanner scanner = new Scanner(System.in);
System.out.print("Enter a sentence: ");
String line = scanner.nextLine();
// System.out.println(line);
int count = line.length();
// System.out.print(count);
ABC:
for(int i=0; i<line.length()-2;i++){
str =line.substring(i, i+3);
if(str.equals("*#*")){
n++;
System.out.println(n);
while(n==2){
break ABC;
}
}
System.out.println(str);
}
}
What I am trying to do is read from a file (in this case the file contains over 100,000+ lines) and store the values in an array, then print out the first 10 lines. However when I run the program I get the first line, and then followed by 9 lines of "null" which is obviously not what I want! This is the code and any tips would be appreciated.
import java.io.*;
import java.util.Scanner;
public class DawsonZachA5Q2{
public static void main(String[] args){
Scanner keyboard = new Scanner(System.in);
System.out.println("Enter a size for the number of letters for words: ");
int size = keyboard.nextInt();//prompts user for input
String[] array = new String[27000];
try {
File file = new File("big-word-list.txt");
Scanner scanner = new Scanner(file);
// Start a line count and declare a string to hold our current line.
int linecount=0;
// Tells user what we're doing
System.out.println("Searching for words with " + size + " letters in file...");
int wordCount=0;
while (scanner.hasNext()){
int i = 0;
String word = scanner.next();
if(size == word.length()){
wordCount++;
array[i]=word;
i++;
//add word to array
// increase the count and find the place of the word
}
}
linecount++;
System.out.println(wordCount);
System.out.println(wordCount+" words were found that have "+size+ " letters.");//final output
for(int o = 0; o<10; o++){
System.out.println(array[o]);
}
scanner.close();
}// our catch just in case of error
catch (IOException e) {
System.out.println("Sorry! File not found!");
}
} // main
} // class
Define int i = 0; outside of the while loop. It gets set to zero each time the loop runs. That is the problem here.
You have mistaken in the while loop. You must define 'int i = 0' before the while loop. In your case, what happen is that whenever the while loop execute, i is initialized to 0. i.e. every time, the word with required length found, that word will be stored in array[0] (Since i is initialized to 0 every iteration of while loop) replacing the previous stored value. As a result, you only get the first value and remaining displayed as null since nothing is stored after array[1].
Therefore, the actual flow should be like this.
// i is initialized outside of loop.
int i = 0;
while (scanner.hasNext()){
//int i = 0; this is your error
String word = scanner.next();
if(size == word.length()){
wordCount++;
array[i]=word;
i++;
//add word to array
// increase the count and find the place of the word
}
}
I am trying to search the File for characters in Java language. For that I am using Scanner to scan the file.
Well to check the Heirarchy work, I am using System.out.print("Worked till here!"); so that I can check whether it is executed or not. I was able to execute the code till the last stage, but then I found that the essential boolean variable wasn't altered, which was under the condition to check whether there is a character match or not.
The file contents are as
Ok, here is some text!
Actually this file is created to test the validity of the java application
Java is my favourite programming language.
And I think I can score even more :)
Wish me luck!
However, no matter what I search it always prompts me to be false.
Here is the code I am using
public static void main (String[] args) throws IOException {
// Only write the output here!!!
System.out.print("Write the character to be found in the File: ");
Scanner sc = new Scanner(System.in);
String character = sc.next();
// Find the character
System.out.println("Searching now...");
getCharacterLocation(character);
// Close the resource!
sc.close();
}
The method call executed and the method is as
public static void getCharacterLocation (String character) throws IOException {
System.out.println("File found...");
File file = new File("res/File.txt");
Scanner sc = new Scanner(file);
int lineNumber = 0;
int totalLines = 0;
boolean found = false;
// First get the total number of lines
while(sc.hasNextLine()) {
totalLines++;
sc.nextLine();
System.out.println("Line looping! For Total Lines variable.");
}
int[] lineNumbers = new int[totalLines];
int lineIndex = 0;
System.out.println("Searching in each line...");
while(sc.hasNextLine()) {
// Until the end
/* Get each of the character, I mean string from
* each of the line... */
while(sc.hasNext()) {
// Until the end of line
String characterInLine = sc.next();
if(sc.findInLine(character) != null) {
found = true;
}
}
System.out.print(sc.nextLine() + "\n");
lineNumber++;
sc.nextLine();
}
System.out.println("Searching complete, showing results...");
// All done! Now post that.
if(found) {
// Something found! :D
System.out.print("Something was found!");
} else {
// Nope didn't found a fuck!
System.out.println("Sorry, '" + character +
"' didn't match any character in file.");
}
sc.close();
}
Never mind the extra usage of variables, and arrays. I would use it in further coding if I can get the character and set the value to true.
Here is the output of this program.
Initial Stage
This is the initial stage for that. I wrote Ok in the input field, you can see Ok is the very first character in the File too.
Final Stage
This is the result after the execution.
Any help in this?
You count lines and don't restart the scanner.
boolean found = false;
// First get the total number of lines
while(sc.hasNextLine()) {
totalLines++;
sc.nextLine();
System.out.println("Line looping! For Total Lines variable.");
}
int[] lineNumbers = new int[totalLines];
int lineIndex = 0;
System.out.println("Searching in each line..."); // <------
while(sc.hasNextLine()) {
add e.g.
UPDATED from the comment
sc.close();
sc = new Scanner(file);
before the next while(sc.hasNextLine())
You need to implement a way to string your characters together and check them against your input. It appears that you don't currently have a way to do this in your code.
Try building an array of characters with your scanner, and moving through and doing a check of your input vs the indexes. Or maybe there is a way to implement the tonkenizer class achieve this.
Put remember, what you are looking for is not a character, it is a string, and you need to keep this in mind when writing your code.
When you count your lines you use while(sc.hasNextLine()).
After this loop, your scanner is behind the last line, so when you go to your next loop while(sc.hasNextLine()) { it is never executed.
There are multiple problems with your code:
You Iterated through your scanner here:
while(sc.hasNextLine()) {
totalLines++;
sc.nextLine();
System.out.println("Line looping! For Total Lines variable.");
}
So after this you have to reset it again to read for further processing.
While searching for character you are having two loops:
while(sc.hasNextLine()) {
// Until the end
/* Get each of the character, I mean string from
* each of the line... */
while(sc.hasNext()) {
// Until the end of line
String characterInLine = sc.next();
if(sc.findInLine(character) != null) {
found = true;
}
}
Here you just need a single loop like:
while(sc.hasNextLine()) {
String characterInLine = sc.nextLine();
if(characterInLine.indexOf(character) != -1) {
found = true;
break;
}
}