Develop Reference

How to translate words in android studio app?

I have used geocoder to get the address through the location. However, the city name is in English and I want to show it in Arabic.
This is the code to get the address :
public String getAddress(double LATITUDE, double LONGITUDE) {
String city = "";
try {
Geocoder geocoder = new Geocoder(this, Locale.getDefault());
List<Address> addresses = geocoder.getFromLocation(LATITUDE, LONGITUDE, 1);
if (addresses != null && addresses.size() > 0) {
String address = addresses.get(0).getAddressLine(0);
city = addresses.get(0).getLocality();
String state = addresses.get(0).getAdminArea();
String country = addresses.get(0).getCountryName();
String postalCode = addresses.get(0).getPostalCode();
String knownName = addresses.get(0).getFeatureName();
}
} catch (IOException e) {
e.printStackTrace();
}
return city;
}
And then this is where I show the city name in a TextView :
String country_and_city = getAddress(latitude, longitude);
TextView city_name = findViewById(R.id.city);
city_name.setText(country_and_city);
Here, the city name will be displayed in English, how can I translate it or use other methods to show it in Arabic? For example, maybe using google-translate api or something if that is even possible

In order to use the Google Cloud Translation API, you need to have a project which has this API enabled, so you can make authenticated calls. You can set it up here.
Google provide a lot of sample codes, here, which you can use. The code below is used to translate a string Spanish(es) to German(de),
Translation translation =
translate.translate(
"Hola Mundo!",
Translate.TranslateOption.sourceLanguage("es"),
Translate.TranslateOption.targetLanguage("de"),
// Use "base" for standard edition, "nmt" for the premium model.
Translate.TranslateOption.model("nmt"));
System.out.printf("TranslatedText:\nText: %s\n", translation.getTranslatedText());
This article explains in details how to integrate the API within your Android Studio project, it can give you a better overview of the whole process.
Lastly, I should point out that according to the documentation,
Prices are pro rata (proportional and incremental). Charges are scaled to the number of characters actually provided to Cloud Translation. For example, if you send 575,000 characters for processing within a month, you are charged $1.50. The first 500,000 characters are free, and then you are charged for the additional 75,000 characters sent for detection, translation, or both.
As another alternative you can also check the googletrans library, which according to the documentation:
Googletrans is a free and unlimited python library that implemented Google Translate API. This uses the Google Translate Ajax API to make calls to such methods as detect and translate.

Java have Alexa Custom Skill ask for missing slots

I am currently building a custom skill for Alexa in Java.
I want Alexa to set an appointment using an existing Exchange Server.
For the appointment I want Alexa to check wether a name, a date and a time are given by the user. I do so using if-statements like:
if(date.getValue() == null) {
return askResponse("Please give a date in order to create an appointment")
What happens is Alexa asks for the missing slot but when I answer the skill just quits. I don't know how to have Alexa recognize my response.
Code is as follows:
public SpeechletResponse getTerminResponse(Slot name, Slot date, Slot time, Session session, IntentRequest request) throws Exception {
if(time.getValue() == null) {
return askResponse("Please insert time");
} else if (date.getValue() == null) {
return askResponse("Please insert date");
} else if (name.getValue() == null) {
return askResponse("Please insert name");
} else {
try {
String[] datumArray = date.getValue().split("-");
String[] zeitArray = time.getValue().split(":");
Date startDate = new Date((Integer.parseInt(datumArray[0])-1900), (Integer.parseInt(datumArray[1])-1), (Integer.parseInt(datumArray[2])), (Integer.parseInt(zeitArray[0])), (Integer.parseInt(zeitArray[1])), 0);
Date endDate = new Date((Integer.parseInt(datumArray[0])-1900), (Integer.parseInt(datumArray[1])-1), (Integer.parseInt(datumArray[2])), (Integer.parseInt(zeitArray[0]))+1, (Integer.parseInt(zeitArray[1])), 0);
System.out.println(startDatum.toString());
System.out.println(endDatum.toString());
ExchangeHelper eh = new ExchangeHelper();
eh.createMeeting(name.getValue(), "Test", startDate, endDate);
return getTellSpeechletResponse("Appointment created successfully");
} catch (Exception e) {
System.out.println(e);
return askResponse("Failed to create appointment");
}
}
}
Here is my Interaction Model
Any help would be highly appreciated since I have been researching documentations and examples for days and I just can not get it to work.
Best regards

Can you give the code for getTellSpeechletResponse?
According to the picture you attached you are using the "new" Dialog model so that Amazon collect all the slots for you intent.
https://developer.amazon.com/public/solutions/alexa/alexa-skills-kit/docs/dialog-interface-reference#directives
Most probably you forgot to send back the DelegateDirective (via speechletResponse.setDirectives(...)) to amazon to tell Alexa to take care for collecting the slot values. But this only can be answered if you send the code. I would also like to see an Dialog Java example by amazon but haven't found yet.
If you are using this dialog model you also don't need the if elses as alexa recognize itself which slots are missing. You have to mark this "Is this slot required to fulfill the intent" with yes in the interaction model. Than you also don't need to create own ask responses but just to give utterances in interaction model for your 4 slots.

How to make google maps coordinates works on specific country. - Android

I am android developer, and i am working on application such as Uber, Careem, etc.
I have a functionality using the google map, to let the user to set his own marker on particular confidantes.
The problem here is my application is just works on Saudi Arabia only and Jeddah city to be exact. and i am not support any other countries or city expect the above.
I need a solution when the user drop down his marker to display a pop up or something telling him that we are not support this area yet.
Is there any solution.
Thanks,

/**
* Get ISO 3166-1 alpha-2 country code for this device (or null if not available)
* #param context Context reference to get the TelephonyManager instance from
* #return country code or null
*/
public static String getUserCountry(Context context) {
try {
final TelephonyManager mTelephonyManager= (TelephonyManager) context.getSystemService(Context.TELEPHONY_SERVICE);
final String simCountry = mTelephonyManager.getSimCountryIso();
if (simCountry != null && simCountry.length() == 2) { // SIM country code is available
return simCountry.toLowerCase(Locale.US);
}
else if (mTelephonyManager.getPhoneType() != TelephonyManager.PHONE_TYPE_CDMA) { // device is not 3G (would be unreliable)
String networkCountry = mTelephonyManager.getNetworkCountryIso();
if (networkCountry != null && networkCountry.length() == 2) { // network country code is available
return networkCountry.toLowerCase(Locale.US);
}
}
}
catch (Exception e) { }
return null;
}

Get Android Device Name

How to get Android device name? I am using HTC desire. When I connected it via HTC Sync the software is displaying the Name 'HTC Smith' . I would like to fetch this name via code.
How is this possible in Android?

In order to get Android device name you have to add only a single line of code:
android.os.Build.MODEL;
Found here: getting-android-device-name

You can see answers at here Get Android Phone Model Programmatically
public String getDeviceName() {
String manufacturer = Build.MANUFACTURER;
String model = Build.MODEL;
if (model.startsWith(manufacturer)) {
return capitalize(model);
} else {
return capitalize(manufacturer) + " " + model;
}
}
private String capitalize(String s) {
if (s == null || s.length() == 0) {
return "";
}
char first = s.charAt(0);
if (Character.isUpperCase(first)) {
return s;
} else {
return Character.toUpperCase(first) + s.substring(1);
}
}

I solved this by getting the Bluetooth name, but not from the BluetoothAdapter (that needs Bluetooth permission).
Here's the code:
Settings.Secure.getString(getContentResolver(), "bluetooth_name");
No extra permissions needed.

On many popular devices the market name of the device is not available. For example, on the Samsung Galaxy S6 the value of Build.MODEL could be "SM-G920F", "SM-G920I", or "SM-G920W8".
I created a small library that gets the market (consumer friendly) name of a device. It gets the correct name for over 10,000 devices and is constantly updated. If you wish to use my library click the link below:
AndroidDeviceNames Library on Github
If you do not want to use the library above, then this is the best solution for getting a consumer friendly device name:
/** Returns the consumer friendly device name */
public static String getDeviceName() {
String manufacturer = Build.MANUFACTURER;
String model = Build.MODEL;
if (model.startsWith(manufacturer)) {
return capitalize(model);
}
return capitalize(manufacturer) + " " + model;
}
private static String capitalize(String str) {
if (TextUtils.isEmpty(str)) {
return str;
}
char[] arr = str.toCharArray();
boolean capitalizeNext = true;
String phrase = "";
for (char c : arr) {
if (capitalizeNext && Character.isLetter(c)) {
phrase += Character.toUpperCase(c);
capitalizeNext = false;
continue;
} else if (Character.isWhitespace(c)) {
capitalizeNext = true;
}
phrase += c;
}
return phrase;
}
Example from my Verizon HTC One M8:
// using method from above
System.out.println(getDeviceName());
// Using https://github.com/jaredrummler/AndroidDeviceNames
System.out.println(DeviceName.getDeviceName());
Result:
HTC6525LVW
HTC One (M8)

Try it. You can get Device Name through Bluetooth.
Hope it will help you
public String getPhoneName() {
BluetoothAdapter myDevice = BluetoothAdapter.getDefaultAdapter();
String deviceName = myDevice.getName();
return deviceName;
}

You can use:
From android doc:
MANUFACTURER:
String MANUFACTURER
The manufacturer of the product/hardware.
MODEL:
String MODEL
The end-user-visible name for the end product.
DEVICE:
String DEVICE
The name of the industrial design.
As a example:
String deviceName = android.os.Build.MANUFACTURER + " " + android.os.Build.MODEL;
//to add to textview
TextView textView = (TextView) findViewById(R.id.text_view);
textView.setText(deviceName);
Furthermore, their is lot of attribute in Build class that you can use, like:
os.android.Build.BOARD
os.android.Build.BRAND
os.android.Build.BOOTLOADER
os.android.Build.DISPLAY
os.android.Build.CPU_ABI
os.android.Build.PRODUCT
os.android.Build.HARDWARE
os.android.Build.ID
Also their is other ways you can get device name without using Build class(through the bluetooth).

Following works for me.
String deviceName = Settings.Global.getString(.getContentResolver(), Settings.Global.DEVICE_NAME);
I don't think so its duplicate answer. The above ppl are talking about Setting Secure, for me setting secure is giving null, if i use setting global it works. Thanks anyways.

universal way to get user defined DeviceName working for almost all devices and not requiring any permissions
String userDeviceName = Settings.Global.getString(getContentResolver(), Settings.Global.DEVICE_NAME);
if(userDeviceName == null)
userDeviceName = Settings.Secure.getString(getContentResolver(), "bluetooth_name");

Try this code. You get android device name.
public static String getDeviceName() {
String manufacturer = Build.MANUFACTURER;
String model = Build.MODEL;
if (model.startsWith(manufacturer)) {
return model;
}
return manufacturer + " " + model;
}

#hbhakhra's answer will do.
If you're interested in detailed explanation, it is useful to look into Android Compatibility Definition Document. (3.2.2 Build Parameters)
You will find:
DEVICE - A value chosen by the device implementer containing the
development name or code name identifying the configuration of the
hardware features and industrial design of the device. The value of
this field MUST be encodable as 7-bit ASCII and match the regular
expression “^[a-zA-Z0-9_-]+$”.
MODEL - A value chosen by the device implementer containing the name
of the device as known to the end user. This SHOULD be the same name
under which the device is marketed and sold to end users. There are no
requirements on the specific format of this field, except that it MUST
NOT be null or the empty string ("").
MANUFACTURER - The trade name of the Original Equipment Manufacturer
(OEM) of the product. There are no requirements on the specific format
of this field, except that it MUST NOT be null or the empty string
("").

UPDATE
You could retrieve the device from buildprop easitly.
static String GetDeviceName() {
Process p;
String propvalue = "";
try {
p = new ProcessBuilder("/system/bin/getprop", "ro.semc.product.name").redirectErrorStream(true).start();
BufferedReader br = new BufferedReader(new InputStreamReader(p.getInputStream()));
String line;
while ((line = br.readLine()) != null) {
propvalue = line;
}
p.destroy();
} catch (IOException e) {
e.printStackTrace();
}
return propvalue;
}
But keep in mind, this doesn't work on some devices.

Simply use
BluetoothAdapter.getDefaultAdapter().getName()

static String getDeviceName() {
try {
Class systemPropertiesClass = Class.forName("android.os.SystemProperties");
Method getMethod = systemPropertiesClass.getMethod("get", String.class);
Object object = new Object();
Object obj = getMethod.invoke(object, "ro.product.device");
return (obj == null ? "" : (String) obj);
} catch (Exception e) {
e.printStackTrace();
return "";
}
}
you can get 'idol3' by this way.

Tried These libraries but nothing worked according to my expectation and was giving absolutely wrong names.
So i created this library myself using the same data.
Here is the link
AndroidPhoneNamesFinder
To use this library just add this for implementation
implementation 'com.github.aishik212:AndroidPhoneNamesFinder:v1.0.2'
Then use the following kotlin code
DeviceNameFinder.getPhoneValues(this, object : DeviceDetailsListener
{
override fun details(doQuery: DeviceDetailsModel?)
{
super.details(doQuery)
Log.d(TAG, "details: "+doQuery?.calculatedName)
}
})
These are the values you will get from DeviceDetailsModel
val brand: String? #This is the brandName of the Device
val commonName: String?, #This is the most common Name of the Device
val codeName: String?, #This is the codeName of the Device
val modelName: String?, #This is the another uncommon Name of the Device
val calculatedName: String?, #This is the special name that this library tries to create from the above data.
Example of Android Emulator -
brand=Google
commonName=Google Android Emulator
codeName=generic_x86_arm
modelName=sdk_gphone_x86
calculatedName=Google Android Emulator

Within the GNU/Linux environment of Android, e.g., via Termux UNIX shell on a non-root device, it's available through the /system/bin/getprop command, whereas the meaning of each value is explained in Build.java within Android (also at googlesource):
% /system/bin/getprop | fgrep ro.product | tail -3
[ro.product.manufacturer]: [Google]
[ro.product.model]: [Pixel 2 XL]
[ro.product.name]: [taimen]
% /system/bin/getprop ro.product.model
Pixel 2 XL
% /system/bin/getprop ro.product.model | tr ' ' _
Pixel_2_XL
For example, it can be set as the pane_title for the status-right within tmux like so:
tmux select-pane -T "$(getprop ro.product.model)"

Gets an Android system property, or lists them all
adb shell getprop >prop_list.txt
Find your device name in prop_list.txt to get the prop name
e.g. my device name is ro.oppo.market.name
Get oppo.market Operator
adb shell getprop ro.oppo.market.name
My case on windows as follows
D:\winusr\adbl
λ *adb shell getprop ro.oppo.market.name*
OPPO R17

Getting device/driver information related to a COM port?

I have a Serial-to-USB device with a similarly named device driver in the Windows device manager. The devices do not always grab the same COM port on system boot, so my program needs to identify it on start up.
I've tried using RXTX to enumerate the COM ports on the system, but this didn't work because CommPortIdentifier.getName() simply returns the COM name (eg. COM1, COM2, etc.) I need to acquire either the driver manufacturer name, or the driver name as it appears in the device manager, and associate it with the COM name.
Can this easily be done in Java? (I'd be interested in any 3rd party Java libraries that support this.) Otherwise, how I could begin to accomplish this via the win32 API?

I achieved what I wanted by using the WinRegistry class provided by David in this SO question to obtain the FriendlyName from registry key associated with my USB device. I then parse out the COM number from the friendly name.
Some things to consider:
USB devices are located at HKEY_LOCAL_MACHINE\SYSTEM\CurrentControlSet\Enum\USB\ in the registry (tested on WinXP, Win7.)
I required the device VID + PID to identify the correct device key (eg. VID_xxxx&PID_xxxx.) Since VID and PID are device specific, this key should be reliable across multiple systems.
The VID_xxxx&PID_xxxx key contains another sub-key with device values. I had some trouble enumerating the sub-keys with WinRegistry, so I hard-coded the sub-key name as a quick hack during development. A much safer solution would search sub-keys to find the correct name.
The device keys exist in the registry regardless of whether the device is currently connected. This code makes the assumption that Windows will update FriendlyName if the device is reconnected to a different COM port. I haven't verified this, but things looked good during use-testing.
Example
String keyPath = "SYSTEM\\CurrentControlSet\\Enum\\USB\\Vid_067b&Pid_2303\\";
String device1 = "5&75451e6&0&1";
System.out.println("First COM device: " + getComNumber(keyPath + device1));
Code
import java.util.regex.Pattern;
import java.util.regex.Matcher;
// Given a registry key, attempts to get the 'FriendlyName' value
// Returns null on failure.
//
public static String getFriendlyName(String registryKey) {
if (registryKey == null || registryKey.isEmpty()) {
throw new IllegalArgumentException("'registryKey' null or empty");
}
try {
int hkey = WinRegistry.HKEY_LOCAL_MACHINE;
return WinRegistry.readString(hkey, registryKey, "FriendlyName");
} catch (Exception ex) { // catch-all:
// readString() throws IllegalArg, IllegalAccess, InvocationTarget
System.err.println(ex.getMessage());
return null;
}
}
// Given a registry key, attempts to parse out the integer after
// substring "COM" in the 'FriendlyName' value; returns -1 on failure.
//
public static int getComNumber(String registryKey) {
String friendlyName = getFriendlyName(registryKey);
if (friendlyName != null && friendlyName.indexOf("COM") >= 0) {
String substr = friendlyName.substring(friendlyName.indexOf("COM"));
Matcher matchInt = Pattern.compile("\\d+").matcher(substr);
if (matchInt.find()) {
return Integer.parseInt(matchInt.group());
}
}
return -1;
}

#robjb Your code does not allow for more than one device to be connected. How will the user know the device name? I added to your code thus to return a list of com ports:
ArrayList<String> subKeys = WinRegistry.readStringSubKeys(WinRegistry.HKEY_LOCAL_MACHINE, keyPath);
ArrayList<Integer> comPorts = new ArrayList<Integer>();
for (String subKey : subKeys) {
String friendlyName = getFriendlyName(keyPath + subKey);
if (friendlyName != null && friendlyName.contains("MyDriverName") && friendlyName.contains("COM")) {
int beginIndex = friendlyName.indexOf("COM") + 3 /*length of 'COM'*/;
int endIndex = friendlyName.indexOf(")");
comPorts.add(Integer.parseInt(friendlyName.substring(beginIndex, endIndex)));
}
}
Update: I don't think these are solutions. Why? This information is statically stored in the registry - even when the device is not connected.

Great example, using JNA, here.
The author (Geir Arne Ruud) has released it under Public Domain License.
My example code
public static String getFriendlyName(GoGPSModel model, String name)
{
if(model.getSystem().getOSType() != OSType.Windows32
&& model.getSystem().getOSType() != OSType.Windows64) {
return name;
}
for (DeviceInformation devInfo : infoObjects) {
System.out.println(devInfo.toString());
String friendlyName = devInfo.getFriendlyName();
if(friendlyName != null && !friendlyName.equals("") && friendlyName.contains(name)) {
return devInfo.getManufacturer() + ": " + friendlyName;
}
}
return name;
}