Develop Reference

Method that corrects the text, inserting spaces after the comma in Java

I want to create a refactorSeparators method that takes an object of the String type as an argument. Method returns the text from the input object corrected so that if there is any
a comma or a period and there is no space after it, it will insert this space.I'm stuck, don't know what to do next, below is my code. How can I finish it? I wonder how to write this part: if (s.equals(".") && i.next().equals())
public class Separator {
public static void main(String[] args) {
String text = "Periods,hyphens, the last two characters cannot be a period. The rest of them don't. And there you go.";
ArrayList<String> stringArr = new ArrayList<>();
String[] arrOfStr = text.split("");
Iterator i = stringArr.iterator();
for (String s : arrOfStr) {
stringArr.add(s);
System.out.println("{" +s + "}");
}
for (String s : arrOfStr) {
if (s.equals(".") && i.next().equals()) {
String space = " ";
stringArr.add(i.next(, " ");
} else {
System.out.println("error");
}
}
}}

You're over-thinking it:
String refactorSeparators(String str) {
return str.replaceAll("([,.]) ?", "$1 ").trim();
}
The regex ([,.]) ? matches a comma or dot optionally followed by a space, which is replaced with the dot/comma and a space. The trim() removes the space that would be added if there's a dot at the end of the input.

Your main problem is here:
Iterator i = stringArr.iterator();
// ...
for (String s : arrOfStr) {
if (s.equals(".") && i.next().equals()) {
You are iterating both with an iterator and a for-loop, that makes life complicated. I'd suggest using a for-loop over the index.
Also your second equals expression is missing an argument.
Since Bohemian already posted the regex one liner, I might as well post my solution too:
public class PunctuationFixer {
private String text;
private int index;
public static String addMissingWhitespaceAfterPunctuation(String input) {
return new PunctuationFixer(input).fix();
}
private PunctuationFixer(String input) {
this.text = input;
this.index = 0;
}
private String fix() {
while (index < this.text.length() - 1) {
fix(this.text.charAt(index));
index++;
}
return this.text;
}
private void fix(char current) {
if (current == '.' || current == ',') {
addSpaceIfNeeded();
}
}
private void addSpaceIfNeeded() {
if (' ' != (text.charAt(index + 1))) {
text = text.substring(0, index + 1) + " " + text.substring(index + 1);
index++;
}
}
public static void main(String[] args) {
String text = "Periods,hyphens, the last two characters cannot be a period. The rest of them don't. And there you go.";
System.out.println(addMissingWhitespaceAfterPunctuation(text));
}
}

That's an typical parse issue. You have to remember the last char you've read and deppendend on your current char, you know what to do.
public static void main(String[] args) {
String text = "Periods,hyphens, the last two characters cannot be a period.The rest of them don't. And there you go.";
StringBuilder fixedString = new StringBuilder();
String[] arrOfStr = text.split("");
String lastChar = null;
for(String currentChar : arrOfStr) {
if(lastChar != null && (lastChar.equals(",") || lastChar.equals(".")) && !currentChar.equals(" "))
fixedString.append(" ");
fixedString.append(currentChar);
lastChar = currentChar;
}
System.out.println(fixedString);
}
Side note: The shortest and most elegant solution is, of course, #bohemian's. But I suspect it is not in the sense of the homework! ;-)

Reverse a string using recursion in java

I want to reverse a whole String. For example, "Cat is running" should give output "running is cat".
I have tried a lot but I am unable to do it. It shows "gninnur si taC". Kindly help me that it should take "cat" as a single character instead of taking 'c' as a single character.
Here is the code:
public static void main(String[] args) {
String str = "Cat is running";
System.out.println("Before recursion: " + str);
System.out.println("After recursion: " + reverse(str));
}
public static String reverse(String str) {
if(str.isEmpty())
return str;
String s = "";
for(int i = 0; i < str.length(); i++) {
s = s + str.charAt(i);
}
return reverse(s.substring(1)) + s.charAt(0);
}

You have to find the first word in the String, pass the rest of the String to the recursive call, and append the first word at the end:
public static String reverse(String str) {
if(str.isEmpty() || !str.contains(" "))
return str;
int sep = str.indexOf(' ');
return reverse(str.substring(sep+1)) + " " + str.substring(0,sep);
}
Output:
Before recursion: Cat is running
After recursion: running is Cat
BTW, the loop is your original code is pointless. You can simply use str directly instead of creating a copy of it.
You can make it even shorter with:
public static String reverse(String str) {
int sep = str.indexOf(' ');
return sep >= 0 ? reverse(str.substring(sep+1)) + " " + str.substring(0,sep) : str;
}

I think I made it a little less good than #Eran but I already wrote:
private static String reverse(String str) {
if (str.isEmpty() || !str.contains(" "))
return str;
StringBuilder sb = new StringBuilder(" ");
int i = 0;
while (i < str.length() && str.charAt(i) != ' ') {
sb.append(str.charAt(i));
i++;
}
return reverse(str.substring(i + 1)) + sb.toString();
}

Reverse string printing method

I am trying to solve the following problem but how do write the method that accepts String as an argument?
Write a method named printReverse that accepts a String as an
argument and prints the characters in the opposite order. If the empty
string is passed as an argument, the method should produce no output.
Be sure to write a main method that convincingly demonstrates your
program in action. Do not use the reverse method of the
StringBuilder or StringBuffer class!
So far I have solved it in a easier manner:
import java.util.Scanner;
class ReverseString {
public static void main(String args[]) {
String original, reverse = "";
Scanner in = new Scanner(System.in);
System.out.println("Enter a string to reverse");
original = in.nextLine();
int length = original.length();
for (int i = length - 1; i >= 0; i--)
reverse = reverse + original.charAt(i);
System.out.println("Reverse of entered string is: " + reverse);
}
}

I highly recommend you to go through a basic tutorial.
You can simply do:
private static String myReverse(String str) {
String reverse = "";
int length = str.length();
for( int i = length - 1 ; i >= 0 ; i-- ) {
reverse = reverse + str.charAt(i);
}
return reverse;
}
And in your main, you simply:
String reversed = myReverse(in.nextLine());
Note that the method is static because you're referring to it from a static manner (main method). If you don't want it to be static, you'll have to access it via an object.
Also note that it's a good practice to always have curly brackets for for loops, even if it contains a single line.

how do write the method that accepts String as an argument?
public static String reverse(String forward) {
char[] strChar = forward.toCharArray();
String reverse = "";
for( int i = strChar.length - 1 ; i >= 0 ; i-- )
reverse = reverse + strChar[i];
return reverse;
}
But for large string appending character with + operator can be inefficient. And reversing string with above approach will result in wrong for uni-code mismatches. As it reverse the code units but not character. There is actually a built-in support available to reverse a string using StringBuilder which works correctly:
public static String reverse(String forward) {
StringBuilder builder = new StringBuilder(forward);
String reverse = builder.reverse().toString();
return reverse;
}

Something like this:
public class StringUtils {
public static String reverse(String forward) {
String result = "";
// Put your code here
return result;
}
}

Using Java 9 you can implement something like this. This code works with both regular characters and surrogate pairs:
public static void printReverse(String str) {
// character code points
str.codePoints()
// character as string
.mapToObj(Character::toString)
// concatenate in reverse order
.reduce((a, b) -> b + a)
// output
.ifPresent(System.out::println);
}
public static void main(String[] args) {
// regular characters
printReverse("lorem ipsum");
// surrogate pairs
printReverse("\uD835\uDD43\uD835\uDD46R\uD835\uDD3C\uD835\uDD44" +
" \uD835\uDD40P\uD835\uDD4A\uD835\uDD4C\uD835\uDD44");
}
Output:
muspi merol
𝕄𝕌𝕊P𝕀 𝕄𝔼R𝕆𝕃
See also: Is there any other way to remove all whitespaces in a string?

Try this:
private static String reverseString(String str) {
String revString = "";
for (int i = str.length() - 1; i >= 0; i--) {
revString = revString + str.charAt(i);
}
return revString;
}

package dowhile;
public class Dowhile {
public static void main(String[] args) {
// TODO code application logic here
String message = "i love java programming";
int msglength = message.length();
int index = msglength - 1;
while (index >= 0) {
System.out.print(message.charAt(index));
index--;
}
}
}
Output:
gnimmargorp avaj evol i

private static void printReverse(String org) {
StringBuffer buffer = new StringBuffer(org);
String reversedStr = buffer.reverse().toString();
System.out.println("The reverse of the string \""
+ str + "\" is \"" + reversedStr + "\".");
}
in the main call the function
printReverse(original);

How to separate each word from a string in java?

One of my AP projects includes separating each word from a string, I have tried accomplishing numerous times yet with no success! My class has not yet learned about arrays, regex, or split yet so if you could help please avoid any of those. However we did learn substring, charAt, indexOf, length, trim ...
This is one of my attempts:
(notice that in order for me to actually notice I've split them I try adding N to the string I am re-creating, which is newWord)
public class Functions {
public static String stringReversal(String word){
if (word.length() <= 1){
return word;
}else{
char c = word.charAt(0);
return stringReversal(word.substring(1)) + c;
}
}
public static Boolean palindrome(String word){
Boolean palindrome;
if (word.equalsIgnoreCase(stringReversal(word))){
return palindrome = true;
} else{
return palindrome = false;
}
}
public static String pigLatin(String sentence){
if(sentence.length() <= 1){
return sentence;
} else {
String newWord = "";
return newWord += pigLatin(sentence.substring(0, sentence.indexOf(" "))) + " N ";
}
}
}
Main:
public class Main {
public static void main (String [] args){
Scanner in = new Scanner(System.in);
String word = in.nextLine();
System.out.println(Functions.test(word));
}
}
However the output only print N! Can anyone please help and show a way that I can accomplish this, I've tried many ideas yet none worked.

Since this seems to be highly homework-related, I will only post some hints and suggestions, you will have to combine my hints and suggestions to come up with the/a solution yourself.
I believe this:
sentence.indexOf("")
should be this: sentence.indexOf(" ")
Checking indexOf an empty string makes not much sense (it always returns zero, since the empty string can be found everywhere within a String).
public static void main(String[] args) {
String word = "a bit of words";
System.out.println(test(word));
}
public static String test(String sentence){
if(sentence.length() <= 1){
return sentence;
} else {
String newWord = "";
return newWord += test(sentence.substring(0, sentence.indexOf(" "))) + " N ";
}
}
The above prints: a N
However, if your input is only one word then sentence.indexOf(" ") will return -1. You will need to check this. Suggestion: Modify your if-statement to instead check if string contains a space character or not.
To solve the assignment, you will need some kind of loop (recursion can also be a kind of loop) to repeat a slightly modified process for each word. Hint: Fetch the first word, then fetch the original String except for the extracted word.

public static void main( String[] args )
{
Scanner in = new Scanner( System.in );
try
{
while( true )
{
String word = in.nextLine();
System.out.println( splitWords( word ) );
}
}
finally
{
in.close();
}
}
private static String splitWords( String s )
{
int splitIndex = s.indexOf( ' ' );
if( splitIndex >= 0 )
return s.substring( 0, splitIndex ) + " N " + splitWords( s.substring( splitIndex + 1 ) );
return s;
}

you can use standard method String#split()
String[] words = sentence.split(' ');
note than words is an array

How to capitalize the first character of each word in a string

Is there a function built into Java that capitalizes the first character of each word in a String, and does not affect the others?
Examples:
jon skeet -> Jon Skeet
miles o'Brien -> Miles O'Brien (B remains capital, this rules out Title Case)
old mcdonald -> Old Mcdonald*
*(Old McDonald would be find too, but I don't expect it to be THAT smart.)
A quick look at the Java String Documentation reveals only toUpperCase() and toLowerCase(), which of course do not provide the desired behavior. Naturally, Google results are dominated by those two functions. It seems like a wheel that must have been invented already, so it couldn't hurt to ask so I can use it in the future.

WordUtils.capitalize(str) (from apache commons-text)
(Note: if you need "fOO BAr" to become "Foo Bar", then use capitalizeFully(..) instead)

If you're only worried about the first letter of the first word being capitalized:
private String capitalize(final String line) {
return Character.toUpperCase(line.charAt(0)) + line.substring(1);
}

The following method converts all the letters into upper/lower case, depending on their position near a space or other special chars.
public static String capitalizeString(String string) {
char[] chars = string.toLowerCase().toCharArray();
boolean found = false;
for (int i = 0; i < chars.length; i++) {
if (!found && Character.isLetter(chars[i])) {
chars[i] = Character.toUpperCase(chars[i]);
found = true;
} else if (Character.isWhitespace(chars[i]) || chars[i]=='.' || chars[i]=='\'') { // You can add other chars here
found = false;
}
}
return String.valueOf(chars);
}

Try this very simple way
example givenString="ram is good boy"
public static String toTitleCase(String givenString) {
String[] arr = givenString.split(" ");
StringBuffer sb = new StringBuffer();
for (int i = 0; i < arr.length; i++) {
sb.append(Character.toUpperCase(arr[i].charAt(0)))
.append(arr[i].substring(1)).append(" ");
}
return sb.toString().trim();
}
Output will be: Ram Is Good Boy

I made a solution in Java 8 that is IMHO more readable.
public String firstLetterCapitalWithSingleSpace(final String words) {
return Stream.of(words.trim().split("\\s"))
.filter(word -> word.length() > 0)
.map(word -> word.substring(0, 1).toUpperCase() + word.substring(1))
.collect(Collectors.joining(" "));
}
The Gist for this solution can be found here: https://gist.github.com/Hylke1982/166a792313c5e2df9d31

String toBeCapped = "i want this sentence capitalized";
String[] tokens = toBeCapped.split("\\s");
toBeCapped = "";
for(int i = 0; i < tokens.length; i++){
char capLetter = Character.toUpperCase(tokens[i].charAt(0));
toBeCapped += " " + capLetter + tokens[i].substring(1);
}
toBeCapped = toBeCapped.trim();

I've written a small Class to capitalize all the words in a String.
Optional multiple delimiters, each one with its behavior (capitalize before, after, or both, to handle cases like O'Brian);
Optional Locale;
Don't breaks with Surrogate Pairs.
LIVE DEMO
Output:
====================================
SIMPLE USAGE
====================================
Source: cApItAlIzE this string after WHITE SPACES
Output: Capitalize This String After White Spaces
====================================
SINGLE CUSTOM-DELIMITER USAGE
====================================
Source: capitalize this string ONLY before'and''after'''APEX
Output: Capitalize this string only beforE'AnD''AfteR'''Apex
====================================
MULTIPLE CUSTOM-DELIMITER USAGE
====================================
Source: capitalize this string AFTER SPACES, BEFORE'APEX, and #AFTER AND BEFORE# NUMBER SIGN (#)
Output: Capitalize This String After Spaces, BeforE'apex, And #After And BeforE# Number Sign (#)
====================================
SIMPLE USAGE WITH CUSTOM LOCALE
====================================
Source: Uniforming the first and last vowels (different kind of 'i's) of the Turkish word D[İ]YARBAK[I]R (DİYARBAKIR)
Output: Uniforming The First And Last Vowels (different Kind Of 'i's) Of The Turkish Word D[i]yarbak[i]r (diyarbakir)
====================================
SIMPLE USAGE WITH A SURROGATE PAIR
====================================
Source: ab 𐐂c de à
Output: Ab 𐐪c De À
Note: first letter will always be capitalized (edit the source if you don't want that).
Please share your comments and help me to found bugs or to improve the code...
Code:
import java.util.ArrayList;
import java.util.Date;
import java.util.List;
import java.util.Locale;
public class WordsCapitalizer {
public static String capitalizeEveryWord(String source) {
return capitalizeEveryWord(source,null,null);
}
public static String capitalizeEveryWord(String source, Locale locale) {
return capitalizeEveryWord(source,null,locale);
}
public static String capitalizeEveryWord(String source, List<Delimiter> delimiters, Locale locale) {
char[] chars;
if (delimiters == null || delimiters.size() == 0)
delimiters = getDefaultDelimiters();
// If Locale specified, i18n toLowerCase is executed, to handle specific behaviors (eg. Turkish dotted and dotless 'i')
if (locale!=null)
chars = source.toLowerCase(locale).toCharArray();
else
chars = source.toLowerCase().toCharArray();
// First charachter ALWAYS capitalized, if it is a Letter.
if (chars.length>0 && Character.isLetter(chars[0]) && !isSurrogate(chars[0])){
chars[0] = Character.toUpperCase(chars[0]);
}
for (int i = 0; i < chars.length; i++) {
if (!isSurrogate(chars[i]) && !Character.isLetter(chars[i])) {
// Current char is not a Letter; gonna check if it is a delimitrer.
for (Delimiter delimiter : delimiters){
if (delimiter.getDelimiter()==chars[i]){
// Delimiter found, applying rules...
if (delimiter.capitalizeBefore() && i>0
&& Character.isLetter(chars[i-1]) && !isSurrogate(chars[i-1]))
{ // previous character is a Letter and I have to capitalize it
chars[i-1] = Character.toUpperCase(chars[i-1]);
}
if (delimiter.capitalizeAfter() && i<chars.length-1
&& Character.isLetter(chars[i+1]) && !isSurrogate(chars[i+1]))
{ // next character is a Letter and I have to capitalize it
chars[i+1] = Character.toUpperCase(chars[i+1]);
}
break;
}
}
}
}
return String.valueOf(chars);
}
private static boolean isSurrogate(char chr){
// Check if the current character is part of an UTF-16 Surrogate Pair.
// Note: not validating the pair, just used to bypass (any found part of) it.
return (Character.isHighSurrogate(chr) || Character.isLowSurrogate(chr));
}
private static List<Delimiter> getDefaultDelimiters(){
// If no delimiter specified, "Capitalize after space" rule is set by default.
List<Delimiter> delimiters = new ArrayList<Delimiter>();
delimiters.add(new Delimiter(Behavior.CAPITALIZE_AFTER_MARKER, ' '));
return delimiters;
}
public static class Delimiter {
private Behavior behavior;
private char delimiter;
public Delimiter(Behavior behavior, char delimiter) {
super();
this.behavior = behavior;
this.delimiter = delimiter;
}
public boolean capitalizeBefore(){
return (behavior.equals(Behavior.CAPITALIZE_BEFORE_MARKER)
|| behavior.equals(Behavior.CAPITALIZE_BEFORE_AND_AFTER_MARKER));
}
public boolean capitalizeAfter(){
return (behavior.equals(Behavior.CAPITALIZE_AFTER_MARKER)
|| behavior.equals(Behavior.CAPITALIZE_BEFORE_AND_AFTER_MARKER));
}
public char getDelimiter() {
return delimiter;
}
}
public static enum Behavior {
CAPITALIZE_AFTER_MARKER(0),
CAPITALIZE_BEFORE_MARKER(1),
CAPITALIZE_BEFORE_AND_AFTER_MARKER(2);
private int value;
private Behavior(int value) {
this.value = value;
}
public int getValue() {
return value;
}
}

Using org.apache.commons.lang.StringUtils makes it very simple.
capitalizeStr = StringUtils.capitalize(str);

From Java 9+
you can use String::replaceAll like this :
public static void upperCaseAllFirstCharacter(String text) {
String regex = "\\b(.)(.*?)\\b";
String result = Pattern.compile(regex).matcher(text).replaceAll(
matche -> matche.group(1).toUpperCase() + matche.group(2)
);
System.out.println(result);
}
Example :
upperCaseAllFirstCharacter("hello this is Just a test");
Outputs
Hello This Is Just A Test

With this simple code:
String example="hello";
example=example.substring(0,1).toUpperCase()+example.substring(1, example.length());
System.out.println(example);
Result: Hello

I'm using the following function. I think it is faster in performance.
public static String capitalize(String text){
String c = (text != null)? text.trim() : "";
String[] words = c.split(" ");
String result = "";
for(String w : words){
result += (w.length() > 1? w.substring(0, 1).toUpperCase(Locale.US) + w.substring(1, w.length()).toLowerCase(Locale.US) : w) + " ";
}
return result.trim();
}

Use the Split method to split your string into words, then use the built in string functions to capitalize each word, then append together.
Pseudo-code (ish)
string = "the sentence you want to apply caps to";
words = string.split(" ")
string = ""
for(String w: words)
//This line is an easy way to capitalize a word
word = word.toUpperCase().replace(word.substring(1), word.substring(1).toLowerCase())
string += word
In the end string looks something like
"The Sentence You Want To Apply Caps To"

This might be useful if you need to capitalize titles. It capitalizes each substring delimited by " ", except for specified strings such as "a" or "the". I haven't ran it yet because it's late, should be fine though. Uses Apache Commons StringUtils.join() at one point. You can substitute it with a simple loop if you wish.
private static String capitalize(String string) {
if (string == null) return null;
String[] wordArray = string.split(" "); // Split string to analyze word by word.
int i = 0;
lowercase:
for (String word : wordArray) {
if (word != wordArray[0]) { // First word always in capital
String [] lowercaseWords = {"a", "an", "as", "and", "although", "at", "because", "but", "by", "for", "in", "nor", "of", "on", "or", "so", "the", "to", "up", "yet"};
for (String word2 : lowercaseWords) {
if (word.equals(word2)) {
wordArray[i] = word;
i++;
continue lowercase;
}
}
}
char[] characterArray = word.toCharArray();
characterArray[0] = Character.toTitleCase(characterArray[0]);
wordArray[i] = new String(characterArray);
i++;
}
return StringUtils.join(wordArray, " "); // Re-join string
}

public static String toTitleCase(String word){
return Character.toUpperCase(word.charAt(0)) + word.substring(1);
}
public static void main(String[] args){
String phrase = "this is to be title cased";
String[] splitPhrase = phrase.split(" ");
String result = "";
for(String word: splitPhrase){
result += toTitleCase(word) + " ";
}
System.out.println(result.trim());
}

1. Java 8 Streams
public static String capitalizeAll(String str) {
if (str == null || str.isEmpty()) {
return str;
}
return Arrays.stream(str.split("\\s+"))
.map(t -> t.substring(0, 1).toUpperCase() + t.substring(1))
.collect(Collectors.joining(" "));
}
Examples:
System.out.println(capitalizeAll("jon skeet")); // Jon Skeet
System.out.println(capitalizeAll("miles o'Brien")); // Miles O'Brien
System.out.println(capitalizeAll("old mcdonald")); // Old Mcdonald
System.out.println(capitalizeAll(null)); // null
For foo bAR to Foo Bar, replace the map() method with the following:
.map(t -> t.substring(0, 1).toUpperCase() + t.substring(1).toLowerCase())
2. String.replaceAll() (Java 9+)
ublic static String capitalizeAll(String str) {
if (str == null || str.isEmpty()) {
return str;
}
return Pattern.compile("\\b(.)(.*?)\\b")
.matcher(str)
.replaceAll(match -> match.group(1).toUpperCase() + match.group(2));
}
Examples:
System.out.println(capitalizeAll("12 ways to learn java")); // 12 Ways To Learn Java
System.out.println(capitalizeAll("i am atta")); // I Am Atta
System.out.println(capitalizeAll(null)); // null
3. Apache Commons Text
System.out.println(WordUtils.capitalize("love is everywhere")); // Love Is Everywhere
System.out.println(WordUtils.capitalize("sky, sky, blue sky!")); // Sky, Sky, Blue Sky!
System.out.println(WordUtils.capitalize(null)); // null
For titlecase:
System.out.println(WordUtils.capitalizeFully("fOO bAR")); // Foo Bar
System.out.println(WordUtils.capitalizeFully("sKy is BLUE!")); // Sky Is Blue!
For details, checkout this tutorial.

BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
System.out.println("Enter the sentence : ");
try
{
String str = br.readLine();
char[] str1 = new char[str.length()];
for(int i=0; i<str.length(); i++)
{
str1[i] = Character.toLowerCase(str.charAt(i));
}
str1[0] = Character.toUpperCase(str1[0]);
for(int i=0;i<str.length();i++)
{
if(str1[i] == ' ')
{
str1[i+1] = Character.toUpperCase(str1[i+1]);
}
System.out.print(str1[i]);
}
}
catch(Exception e)
{
System.err.println("Error: " + e.getMessage());
}

I decided to add one more solution for capitalizing words in a string:
words are defined here as adjacent letter-or-digit characters;
surrogate pairs are provided as well;
the code has been optimized for performance; and
it is still compact.
Function:
public static String capitalize(String string) {
final int sl = string.length();
final StringBuilder sb = new StringBuilder(sl);
boolean lod = false;
for(int s = 0; s < sl; s++) {
final int cp = string.codePointAt(s);
sb.appendCodePoint(lod ? Character.toLowerCase(cp) : Character.toUpperCase(cp));
lod = Character.isLetterOrDigit(cp);
if(!Character.isBmpCodePoint(cp)) s++;
}
return sb.toString();
}
Example call:
System.out.println(capitalize("An à la carte StRiNg. Surrogate pairs: 𐐪𐐪."));
Result:
An À La Carte String. Surrogate Pairs: 𐐂𐐪.

Use:
String text = "jon skeet, miles o'brien, old mcdonald";
Pattern pattern = Pattern.compile("\\b([a-z])([\\w]*)");
Matcher matcher = pattern.matcher(text);
StringBuffer buffer = new StringBuffer();
while (matcher.find()) {
matcher.appendReplacement(buffer, matcher.group(1).toUpperCase() + matcher.group(2));
}
String capitalized = matcher.appendTail(buffer).toString();
System.out.println(capitalized);

There are many way to convert the first letter of the first word being capitalized. I have an idea. It's very simple:
public String capitalize(String str){
/* The first thing we do is remove whitespace from string */
String c = str.replaceAll("\\s+", " ");
String s = c.trim();
String l = "";
for(int i = 0; i < s.length(); i++){
if(i == 0){ /* Uppercase the first letter in strings */
l += s.toUpperCase().charAt(i);
i++; /* To i = i + 1 because we don't need to add
value i = 0 into string l */
}
l += s.charAt(i);
if(s.charAt(i) == 32){ /* If we meet whitespace (32 in ASCII Code is whitespace) */
l += s.toUpperCase().charAt(i+1); /* Uppercase the letter after whitespace */
i++; /* Yo i = i + 1 because we don't need to add
value whitespace into string l */
}
}
return l;
}

package com.test;
/**
* #author Prasanth Pillai
* #date 01-Feb-2012
* #description : Below is the test class details
*
* inputs a String from a user. Expect the String to contain spaces and alphanumeric characters only.
* capitalizes all first letters of the words in the given String.
* preserves all other characters (including spaces) in the String.
* displays the result to the user.
*
* Approach : I have followed a simple approach. However there are many string utilities available
* for the same purpose. Example : WordUtils.capitalize(str) (from apache commons-lang)
*
*/
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Test {
public static void main(String[] args) throws IOException{
System.out.println("Input String :\n");
InputStreamReader converter = new InputStreamReader(System.in);
BufferedReader in = new BufferedReader(converter);
String inputString = in.readLine();
int length = inputString.length();
StringBuffer newStr = new StringBuffer(0);
int i = 0;
int k = 0;
/* This is a simple approach
* step 1: scan through the input string
* step 2: capitalize the first letter of each word in string
* The integer k, is used as a value to determine whether the
* letter is the first letter in each word in the string.
*/
while( i < length){
if (Character.isLetter(inputString.charAt(i))){
if ( k == 0){
newStr = newStr.append(Character.toUpperCase(inputString.charAt(i)));
k = 2;
}//this else loop is to avoid repeatation of the first letter in output string
else {
newStr = newStr.append(inputString.charAt(i));
}
} // for the letters which are not first letter, simply append to the output string.
else {
newStr = newStr.append(inputString.charAt(i));
k=0;
}
i+=1;
}
System.out.println("new String ->"+newStr);
}
}

Here is a simple function
public static String capEachWord(String source){
String result = "";
String[] splitString = source.split(" ");
for(String target : splitString){
result += Character.toUpperCase(target.charAt(0))
+ target.substring(1) + " ";
}
return result.trim();
}

This is just another way of doing it:
private String capitalize(String line)
{
StringTokenizer token =new StringTokenizer(line);
String CapLine="";
while(token.hasMoreTokens())
{
String tok = token.nextToken().toString();
CapLine += Character.toUpperCase(tok.charAt(0))+ tok.substring(1)+" ";
}
return CapLine.substring(0,CapLine.length()-1);
}

Reusable method for intiCap:
public class YarlagaddaSireeshTest{
public static void main(String[] args) {
String FinalStringIs = "";
String testNames = "sireesh yarlagadda test";
String[] name = testNames.split("\\s");
for(String nameIs :name){
FinalStringIs += getIntiCapString(nameIs) + ",";
}
System.out.println("Final Result "+ FinalStringIs);
}
public static String getIntiCapString(String param) {
if(param != null && param.length()>0){
char[] charArray = param.toCharArray();
charArray[0] = Character.toUpperCase(charArray[0]);
return new String(charArray);
}
else {
return "";
}
}
}

Here is my solution.
I ran across this problem tonight and decided to search it. I found an answer by Neelam Singh that was almost there, so I decided to fix the issue (broke on empty strings) and caused a system crash.
The method you are looking for is named capString(String s) below.
It turns "It's only 5am here" into "It's Only 5am Here".
The code is pretty well commented, so enjoy.
package com.lincolnwdaniel.interactivestory.model;
public class StringS {
/**
* #param s is a string of any length, ideally only one word
* #return a capitalized string.
* only the first letter of the string is made to uppercase
*/
public static String capSingleWord(String s) {
if(s.isEmpty() || s.length()<2) {
return Character.toUpperCase(s.charAt(0))+"";
}
else {
return Character.toUpperCase(s.charAt(0)) + s.substring(1);
}
}
/**
*
* #param s is a string of any length
* #return a title cased string.
* All first letter of each word is made to uppercase
*/
public static String capString(String s) {
// Check if the string is empty, if it is, return it immediately
if(s.isEmpty()){
return s;
}
// Split string on space and create array of words
String[] arr = s.split(" ");
// Create a string buffer to hold the new capitalized string
StringBuffer sb = new StringBuffer();
// Check if the array is empty (would be caused by the passage of s as an empty string [i.g "" or " "],
// If it is, return the original string immediately
if( arr.length < 1 ){
return s;
}
for (int i = 0; i < arr.length; i++) {
sb.append(Character.toUpperCase(arr[i].charAt(0)))
.append(arr[i].substring(1)).append(" ");
}
return sb.toString().trim();
}
}

Here we go for perfect first char capitalization of word
public static void main(String[] args) {
String input ="my name is ranjan";
String[] inputArr = input.split(" ");
for(String word : inputArr) {
System.out.println(word.substring(0, 1).toUpperCase()+word.substring(1,word.length()));
}
}
}
//Output : My Name Is Ranjan

For those of you using Velocity in your MVC, you can use the capitalizeFirstLetter() method from the StringUtils class.

String s="hi dude i want apple";
s = s.replaceAll("\\s+"," ");
String[] split = s.split(" ");
s="";
for (int i = 0; i < split.length; i++) {
split[i]=Character.toUpperCase(split[i].charAt(0))+split[i].substring(1);
s+=split[i]+" ";
System.out.println(split[i]);
}
System.out.println(s);

package corejava.string.intern;
import java.io.DataInputStream;
import java.util.ArrayList;
/*
* wap to accept only 3 sentences and convert first character of each word into upper case
*/
public class Accept3Lines_FirstCharUppercase {
static String line;
static String words[];
static ArrayList<String> list=new ArrayList<String>();
/**
* #param args
*/
public static void main(String[] args) throws java.lang.Exception{
DataInputStream read=new DataInputStream(System.in);
System.out.println("Enter only three sentences");
int i=0;
while((line=read.readLine())!=null){
method(line); //main logic of the code
if((i++)==2){
break;
}
}
display();
System.out.println("\n End of the program");
}
/*
* this will display all the elements in an array
*/
public static void display(){
for(String display:list){
System.out.println(display);
}
}
/*
* this divide the line of string into words
* and first char of the each word is converted to upper case
* and to an array list
*/
public static void method(String lineParam){
words=line.split("\\s");
for(String s:words){
String result=s.substring(0,1).toUpperCase()+s.substring(1);
list.add(result);
}
}
}

If you prefer Guava...
String myString = ...;
String capWords = Joiner.on(' ').join(Iterables.transform(Splitter.on(' ').omitEmptyStrings().split(myString), new Function<String, String>() {
public String apply(String input) {
return Character.toUpperCase(input.charAt(0)) + input.substring(1);
}
}));

String toUpperCaseFirstLetterOnly(String str) {
String[] words = str.split(" ");
StringBuilder ret = new StringBuilder();
for(int i = 0; i < words.length; i++) {
ret.append(Character.toUpperCase(words[i].charAt(0)));
ret.append(words[i].substring(1));
if(i < words.length - 1) {
ret.append(' ');
}
}
return ret.toString();
}