I have a model class like below:
#Entity
#Table(name = "User")
public class UserModel implements Serializable{
private static final long serialVersionUID = 204096185700135310L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "user_id", unique = true, nullable = false)
private Integer userId;
#Column(name = "user_login_name")
private String userLoginName;
#Column(name = "user_email_id")
private String userEmailId;
#Column(name = "user_password")
private String userPassword;
}
and I am writting a criteria with projection to get the userLoginName based on userId, like SELECT user_login_name from USER where user_id=1 :
public UserModel getUserByUserName(Integer userId) {
return (UserModel) HibernateService.getSession(sessionFactory)
.createCriteria(UserModel.class)
.setProjection(Projections.projectionList()
.add(Projections.property("userLoginName"), "userLoginName"))
.add(Restrictions.eq(AppConstant.USER_Id, userId))
.uniqueResult();
}
But it's throwing java.lang.String cannot be cast to com.app.aus.model.UserModel excetion. can someone help me here
Related
I have 2 entities User and Venue. One user can have multiple venues. The table looks like this:
user_id is the foreign key in the Venue table.
I am trying to create a query for retrieving all Venues by user_id. This is what I have:
#Override
public List<Venue> findVenueByOwnerId(Long userId) {
return em.createQuery("select v from Venue v where v.user.id = :ownerId", Venue.class)
.setParameter("ownerId", userId)
.getResultList();
}
What am I doing wrong?
EDIT:
These are my mappings:
For User class:
#Entity
public class User {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id", updatable = false, nullable = false)
private Long id;
private String email;
private String username;
private String password;
private String firstName;
private String lastName;
#OneToMany
#JoinColumn(name = "user_id")
private List<Venue> venues;
For Venue class:
#Entity
public class Venue {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "id", updatable = false, nullable = false)
private Long id;
private String name;
private String location;
private int capacity;
#ManyToOne
#Column(name = "user_id", updatable = false, nullable = false)
private User user;
And if I am trying to add getters and setters for the User in the Venue class, it throws me this error:
Caused by: org.hibernate.MappingException: Could not determine type for: razvan.sem3.project.model.User, at table: Venue, for columns: [org.hibernate.mapping.Column(user)]
Here are my entity classes.
JobPost.java
#Entity
#Table(name = "job_post")
public class JobPost {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "job_post_id")
private Long jobPostId;
#Column(name = "job_title")
private String jobTitle;
#Column(name = "job_description")
private String jobDescription;
#Column(name = "vacancy")
private int vacancy;
#Column(name = "posted_date")
#JsonFormat(pattern = "yyyy-MM-dd")
private Date postedDate;
#Column(name = "total_applicants")
private int totalApplicants;
}
JobApplication.java
#Entity
#Table(name = "job_application")
public class JobApplication {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "job_application_id")
private Long jobApplicationId;
#Column(name = "job_post_id")
private Long jobPostId;
#Column(name = "applicant_id")
private Long applicantId;
}
Applicant.java
#Entity
#Table(name = "applicant")
public class Applicant {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "applicant_id")
private Long applicantId;
#Column(name = "applicant_name")
private String applicantName;
#Column(name = "applicant_mobile_no")
private String applicantMobileNo;
#Column(name = "applicant_email")
private String applicantEmail;
}
My main goal is to listing the ApplicantList on JobPostId. I am totally new in Spring data JPA. Is JPA mappings are correct?. I don't know which query I should fire in order to fetch the applicantList based on jobPostId.
I would recommend to use JpaMappings and use SpringData instead of using native query.
Steps to follow:
Many-To-Many:
Use JoinTable to directly map JobPost and Applicant instead of creating a separate class.
Link for help:
https://attacomsian.com/blog/spring-data-jpa-many-to-many-mapping
Use SpringData JPA findOne or findById method (depends on spring version). If you use EAGER fetch then it will give you all Applicants associated with the JobPost Id.
One-To-Many
Keep JobApplication class and use OneToMany annotation.
Link for help:
https://attacomsian.com/blog/spring-data-jpa-one-to-many-mapping
Query:
#Query("select a from JobPost j inner join j.jobApplicantList ja inner join ja.applicant a where j.jobPostId=:jobPostId")
List<String> findAllJobApplicants(#Param("jobPostId") Long jobPostId);
I think that you should configure the mappings in such a way.To do this, you only need two entities
JobPost.java
#Entity
#Table(name = "job_post")
public class JobPost {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(name = "job_title")
private String jobTitle;
#Column(name = "job_description")
private String jobDescription;
#Column(name = "vacancy")
private int vacancy;
#Column(name = "posted_date")
#JsonFormat(pattern = "yyyy-MM-dd")
private Date postedDate;
#Column(name = "total_applicants")
private int totalApplicants;
#ManyToMany
#JoinTable(name = "applicant_job_post",
joinColumns = {
#JoinColumn(name = "job_post_id", referencedColumnName = "id")
}, inverseJoinColumns = {
#JoinColumn(name = "applicant_id", referencedColumnName = "id")
})
private Set<Applicant> applicants;
public JobPost() {
}
public void addApplicant(Applicant applicant) {
applicants.add(applicant);
applicant.getJobPosts().add(this);
}
public void removeApplicant(Applicant applicant) {
applicants.remove(applicant);
applicant.getJobPosts().remove(this);
}
}
Applicant.java
#Entity
#Table(name = "applicant")
public class Applicant {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(name = "applicant_name")
private String applicantName;
#Column(name = "applicant_mobile_no")
private String applicantMobileNo;
#Column(name = "applicant_email")
private String applicantEmail;
#ManyToMany(mappedBy = "applicants")
private Set<JobPost> jobPosts;
public Applicant() {
}
public void addJobPost(JobPost jobPost) {
jobPosts.add(jobPost);
jobPost.getApplicants().add(this);
}
public void removeJobPost(JobPost jobPost) {
jobPosts.remove(jobPost);
jobPost.getApplicants().remove(this);
}
}
I'm just learning Spring Data. I want to map a database view Entity with a simple Entity and pass to DTO which will contain columns both entities. I understand that I can use a special database view but I need to map precisely entities of Spring Data.
I have a database view Entity "MentorStudents":
#Entity
#Table(name = "mentor_students")
#Immutable
public class MentorStudents implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#Column(name = "mentor_id", updatable = false, nullable = false)
private Long mentorId;
//This entity I need to map
private Mentor mentor;
#Column(name = "active_students")
private Integer activeStudents;
public MentorStudents() {
}
//getters, setters, equals, hashCode
}
A database view sql of an above entity is:
SELECT id AS mentor_id, active_students
FROM mentor
LEFT JOIN ( SELECT mentor_id, count(mentor_id) AS active_students
FROM contract
WHERE close_type IS NULL
GROUP BY mentor_id) active ON mentor.id = active.mentor_id
ORDER BY mentor.id;
And I have a simple Entity "Mentor":
#Entity
#Table(name = "mentor")
#Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
public class Mentor implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE, generator = "sequenceGenerator")
#SequenceGenerator(name = "sequenceGenerator")
private Long id;
#NotNull
#Column(name = "first_name", nullable = false)
private String firstName;
#NotNull
#Column(name = "last_name", nullable = false)
private String lastName;
#Column(name = "patronymic")
private String patronymic;
#Column(name = "phone")
private String phone;
#NotNull
#Column(name = "email", nullable = false)
private String email;
#Column(name = "skype")
private String skype;
#Column(name = "country")
private String country;
#Column(name = "city")
private String city;
#Column(name = "max_students")
private Long maxStudents;
//getters, setters, equals, hashCode
I have to get a DTO which contains all Mentor fields and an "activeStudents" MentorStudents field without a "mentorId" field. How do it?
Use spring data projection:
public interface YourDto {
// all Mentor get fields
String getFirstName();
...
// activeStudents get field
Integer getActiveStudents();
}
public interface YourRepository extends JpaRepository<YourEntity, Integer> {
#Query(value = "select ...(all fields match YourDto) from Mentor m, MentorStudents s where m.id = s.mentorId and m.id = ?1")
Optional<YourDto> findMyDto(Integer mentorId);
}
I have a SQL query like this:
"Select UIProfileID from UserTable where UPPER(UserID) = UPPER('?1')".
I want to convert it to Spring JPA.
I want to write getUIProfileId() and return Integer. But I don't know how to implement. Because User table doesn't have UIProfileId column that it was joined from UIProfileTable table. Please help me solve it.
Currently, I have tables:
User.java
#Entity
#Getter
#Setter
#NoArgsConstructor
#AllArgsConstructor
#Builder
#Table(name = "UserTable")
public class User {
#Column(name = "UserID", length = 32, nullable = false)
#Id
private String name;
#ManyToOne
#JoinColumn(name = "DomainID", nullable = false)
private Domain domain;
#Column(name = "Password", length = 32, nullable = false)
private String password;
#ManyToOne
#JoinColumn(name = "UIProfileID", nullable = false)
private UIProfile uiProfile;
#Column(name = "ResPerpage", nullable = false)
private Integer resperpage;
#Column(name = "DefaultTab")
private Integer defaulttab;
#ManyToOne
#JoinColumn(name = "AdminProfile")
private AdminProfiles adminProfile;
#Column(name = "LanguageId")
private Integer languageId;
}
UIProfile.java
#Entity
#Getter
#Setter
#Table(name = "UIProfileTable")
public class UIProfile implements Serializable {
#Id
#Column(name = "UIProfileID", length = 11, nullable = false)
private Integer id;
#Column(name = "UIProfileName", length = 32, nullable = false)
private String name;
#OneToMany(mappedBy = "id.uiProfile")
private List<UIProfileTopLevel> topLevels;
}
UserRepository.java
public interface UserRepository extends Repository<User, String> {
Optional<User> findOne(String name);
#Query("Select UIProfileID from User where UPPER(UserID) = UPPER('admin')")
Integer getUIProfileId();
}
You can try this:
#Query("SELECT u.uiProfile.id from User u where UPPER(u.name)=UPPER('admin')")
Integer getUIProfileId();
Here User is the domain class name and u is the reference of User. with u we will access User's field NOT the column name which are specified with #Column or #JoinColumn Ex : #JoinColumn(name = "UIProfileID", nullable = false).
I'm trying to achieve something like sql command below by using HQL and JPA.
Instead of "SELECT user_id..." I need SELECT OBJECT(o).
SELECT user_id FROM posix_user o INNER JOIN postgre_user n ON n.id=o.user_id WHERE n.name='USERNAME2'
I have some problems with this part of the code in JPA DAO:
public List<PosixUserEntity> listPosixUsers(final String uid_number) {
final StringBuilder queryString = new StringBuilder("SELECT OBJECT(o) FROM ");
queryString.append(this.entityClass.getSimpleName());
queryString.append(" o JOIN com.services.dao.user.jpa.UserEntity n ON (n.id=o.user_id) WHERE n.name LIKE :uid_number");
final Query findByNameQuery = entityManager.createQuery(queryString.toString()).setParameter("uid_number", uid_number);
return findByNameQuery.getResultList();
}
JOIN ON is not allowet here and I did not know how to replace it.
Also how can I replace com.services.dao.user.jpa.UserEntity by something cleaner.
There is my Entites, they may need to be improved:
#Entity
#Table(name = "posix_user")
public class PosixUserEntity implements Serializable {
private static final long serialVersionUID = 1L;
#Id
//#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "user_id")
private String user_id;
#Column(name = "uid_number")
private String uid_number;
#Column(name = "home_directory")
private String home_directory;
#Column(name = "login_shell")
private String login_shell;
#Column(name = "group_id")
private String group_id;
//getters,setters....
#Entity
#Table(name = "postgre_user")
#SQLDelete(sql = "update postgre_user set status = 'removed' where id = ?")
public class UserEntity implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(name = "name", unique = true, nullable = false)
private String name;
#Column(name = "password")
private String password;
#Enumerated(EnumType.STRING)
#Column(name = "status")
private UserStatus status;
#Column(name = "firstname")
private String firstName;
#Column(name = "lastname")
private String lastName;
#Column(name = "email")
private String email;
#Column(name = "usertype")
private String userType;
#OneToMany(cascade = CascadeType.ALL, mappedBy = "user")
private List<UserRoleTargetGroupEntity> userRoleTargetGroupEntity;
#Column(name = "last_login")
private String lastLogin;
#Column(name = "previous_login")
private String previousLogin;
#JsonIgnore
#Column(name = "change_password_flag")
private Boolean userPasswordResetFlag;
#OneToOne(cascade=CascadeType.ALL)
#PrimaryKeyJoinColumn
private PosixUserEntity posixUserEntity;
You may also need to know that FOREIGN KEY (user_id) REFERENCES postgre_user (id) - it should look like that
Can you know how can I modify my SELECT?
I've tested a simplified version of your classes
#Entity
#Table(name = "posix_user")
public class PosixUserEntity {
#Id
#Column(name = "user_id")
private Long user_id;
// getter + setter
}
#Entity
#Table(name = "postgre_user")
public class UserEntity {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
private String name;
#OneToOne(cascade=CascadeType.ALL)
#PrimaryKeyJoinColumn
private PosixUser posixUserEntity;
// getter + setter
}
And this JPQL query works as expected
String jpql = "SELECT p "
+ "FROM UserEntity n JOIN n.posixUserEntity p "
+ "WHERE n.name LIKE :uid_number)";
JOIN is allowed because you have mapped the relationship in UserEntity.
and you don't need to specify the complete name of your entity class.
Check if it has been included when you define your persistence unit.
Hope this helps.