Develop Reference

Configure keybord layout before and after for testing with assertj-swing

I am using assertj-swing to test a simple GUI application. When I enter text in a JTextField, I am getting: IllegalArgumentException: Invalid key code '65406'
It seems it happens because I am using a german keyboard layout, so to solve this problem I added the code below into onSetUp method:
window.target().getInputContext().selectInputMethod(new Locale("en", "US"));
By changing the input method the test passed, but I could not restore the original keyboard layout after the test, thus after testing my layout is always en-US, instead of de-DE.
I tried to set direct to de-DE in the method onTearDown using the line above, or store the current layout onSetUp and restore onTearDown, but the value I am writing into selectInputMethod is always overwritten before I restore it or even after, so that sometimes I see it changes to de-DE and them back en-US.
Does someone had similar problems trying to configure the keyboard layout?
Below you can read an example of the tests I am having trouble with:
import static org.assertj.core.api.Assertions.assertThat;
import java.io.File;
import java.util.Locale;
import org.assertj.swing.edt.GuiActionRunner;
import org.assertj.swing.fixture.FrameFixture;
import org.assertj.swing.junit.testcase.AssertJSwingJUnitTestCase;
import org.junit.Rule;
import org.junit.Test;
import org.junit.rules.TemporaryFolder;
public class GuiExampleTest extends AssertJSwingJUnitTestCase {
private FrameFixture window;
private TransformationGui gui;
#Rule
public TemporaryFolder workingPath = new TemporaryFolder();
#Override
protected void onSetUp() {
gui = GuiActionRunner.execute(() -> new TransformationGui());
window = new FrameFixture(robot(), gui);
window.target().getInputContext().selectInputMethod(new Locale("en", "US"));
window.show();
}
#Override
protected void onTearDown() {
window.cleanUp();
}
#Test
public void acceptMyField() throws Exception {
window.textBox("myfield").enterText(givenSomeExcelFile().toString());
assertThat(window.textBox("myfield").text()).endsWith("SomeFile.xlsx");
}
private File givenSomeExcelFile() throws Exception {
return workingPath.newFile("SomeFile.xlsx");
}
}

When I run the Codename One HelloWorld Java Program from the Codename One HelloWorld Tutorial, I get an error

When I run the Codename One HelloWorld Java Program from the Codename One HelloWorld Tutorial video, I get this error:
java: cannot find symbol
symbol: class Button
location: class com.acmecorp.appname.AppName
I think I'm missing an import for class Button. How do I add the import statement for class Button so that the compilation won't have this error?
Here is my source code:
package com.acmecorp.appname;
import static com.codename1.ui.CN.*;
import com.codename1.ui.Display;
import com.codename1.ui.Form;
import com.codename1.ui.Dialog;
import com.codename1.ui.Label;
import com.codename1.ui.plaf.UIManager;
import com.codename1.ui.util.Resources;
import com.codename1.io.Log;
import com.codename1.ui.Toolbar;
import java.io.IOException;
import com.codename1.ui.layouts.BoxLayout;
import com.codename1.io.NetworkEvent;
/**
* This file was generated by Codename One for the purpose
* of building native mobile applications using Java.
*/
public class AppName {
private Form current;
private Resources theme;
public void init(Object context) {
// use two network threads instead of one
updateNetworkThreadCount(2);
theme = UIManager.initFirstTheme("/theme");
// Enable Toolbar on all Forms by default
Toolbar.setGlobalToolbar(true);
// Pro only feature
Log.bindCrashProtection(true);
addNetworkErrorListener(err -> {
// prevent the event from propagating
err.consume();
if(err.getError() != null) {
Log.e(err.getError());
}
Log.sendLogAsync();
Dialog.show("Connection Error", "There was a networking error in the connection to " + err.getConnectionRequest().getUrl(), "OK", null);
});
}
public void start() {
if(current != null){
current.show();
return;
}
Form hi = new Form("Hi World", BoxLayout.y());
hi.add(new Label("Hi World"));
Button b = new Button("Show Dialog");
hi.add(b);
b.addActionListener((e) -> Dialog.show("Dialog Title", "Hi", "OK", null));
hi.show();
}
public void stop() {
current = getCurrentForm();
if(current instanceof Dialog) {
((Dialog)current).dispose();
current = getCurrentForm();
}
}
public void destroy() {
}
}

I guess this com.codename1.ui.Button might works for u.

Run JavaFX app from the command line without GUI

I have a JavaFX in which the user can select files to be processed. Now I want to automate it so that you can run the application from the command line and pass those files as a parameter. I tried to do this:
java -jar CTester.jar -cl file.txt
public static void main(String[] args)
{
if (Arrays.asList(args).contains("-cl"))
{
foo();
}
else
{
launch(args);
}
}
The main is executed and the argument is correct, but this still creates the GUI.
From the docs:
The entry point for JavaFX applications is the Application class. The
JavaFX runtime does the following, in order, whenever an application
is launched:
Constructs an instance of the specified Application class
Calls the init() method
Calls the start(javafx.stage.Stage) method
Waits for the application to finish, which happens when either of the following
occur:
the application calls Platform.exit()
the last window has been closed and the implicitExit attribute on Platform is true
Calls the stop() method
So if I cannot use the main method, how can I create this "alterantive" flow? I thought about creating a normal java application as a wrapper but that seems a little bit overkill for such a simple task. Is there a more elegant way of doing this?

Simply exit the application after calling your foo() method:
Platform.exit();
Here is a quick sample application to demonstrate:
import javafx.application.Application;
import javafx.application.Platform;
import javafx.geometry.Insets;
import javafx.geometry.Pos;
import javafx.scene.Scene;
import javafx.scene.control.Label;
import javafx.scene.layout.VBox;
import javafx.stage.Stage;
public class CLSample extends Application {
public static void main(String[] args) {
if (Arrays.asList(args).contains("-cl")) {
commandLine();
Platform.exit();
} else {
launch(args);
}
}
public static void commandLine() {
System.out.println("Running only command line version...");
}
#Override
public void start(Stage primaryStage) {
// Simple Interface
VBox root = new VBox(10);
root.setAlignment(Pos.CENTER);
root.setPadding(new Insets(10));
root.getChildren().add(new Label("GUI Loaded!"));
// Show the stage
primaryStage.setScene(new Scene(root));
primaryStage.setTitle("CLSample Sample");
primaryStage.show();
}
}
If you pass -cl, then only the commandLine() method gets called.

Open External Application From JavaFX

I found a way to open a link on default browser using HostServices.
getHostServices().showDocument("http://www.google.com");
Is there any way to open a media in default media player?
Is there any way to launch a specific File or Application?

Generally speaking, you can use Desktop#open(file) to open a file natively as next:
final Desktop desktop = Desktop.isDesktopSupported() ? Desktop.getDesktop() : null;
if (desktop != null && desktop.isSupported(Desktop.Action.OPEN)) {
desktop.open(file);
} else {
throw new UnsupportedOperationException("Open action not supported");
}
Launches the associated application to open the file. If the specified
file is a directory, the file manager of the current platform is
launched to open it.
More specifically, in case of a browser you can use directly Desktop#browse(uri), as next:
final Desktop desktop = Desktop.isDesktopSupported() ? Desktop.getDesktop() : null;
if (desktop != null && desktop.isSupported(Desktop.Action.BROWSE)) {
desktop.browse(uri);
} else {
throw new UnsupportedOperationException("Browse action not supported");
}
Launches the default browser to display a URI. If the default browser
is not able to handle the specified URI, the application registered
for handling URIs of the specified type is invoked. The application is
determined from the protocol and path of the URI, as defined by the
URI class. If the calling thread does not have the necessary
permissions, and this is invoked from within an applet,
AppletContext.showDocument() is used. Similarly, if the calling does
not have the necessary permissions, and this is invoked from within a
Java Web Started application, BasicService.showDocument() is used.

If you want to either open a URL which has an http: scheme in the browser, or open a file using the default application for that file type, the HostServices.showDocument(...) method you referenced provides a "pure JavaFX" way to do this. Note that you can't use this (as far as I can tell) to download a file from a web server and open it with the default application.
To open a file with the default application, you must convert the file to the string representation of the file: URL. Here is a simple example:
import java.io.File;
import javafx.application.Application;
import javafx.event.ActionEvent;
import javafx.event.EventHandler;
import javafx.geometry.Insets;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.scene.control.Label;
import javafx.scene.control.TextField;
import javafx.scene.layout.HBox;
import javafx.scene.layout.VBox;
import javafx.stage.FileChooser;
import javafx.stage.Stage;
public class OpenResourceNatively extends Application {
#Override
public void start(Stage primaryStage) {
TextField textField = new TextField("http://stackoverflow.com/questions/39898704");
Button openURLButton = new Button("Open URL");
EventHandler<ActionEvent> handler = e -> open(textField.getText());
textField.setOnAction(handler);
openURLButton.setOnAction(handler);
FileChooser fileChooser = new FileChooser();
Button openFileButton = new Button("Open File...");
openFileButton.setOnAction(e -> {
File file = fileChooser.showOpenDialog(primaryStage);
if (file != null) {
open(file.toURI().toString());
}
});
VBox root = new VBox(5,
new HBox(new Label("URL:"), textField, openURLButton),
new HBox(openFileButton)
);
root.setPadding(new Insets(20));
primaryStage.setScene(new Scene(root));
primaryStage.show();
}
private void open(String resource) {
getHostServices().showDocument(resource);
}
public static void main(String[] args) {
launch(args);
}
}

Only the solution with java.awt.Desktop worked for me to open a file from JavaFX.
However, at first, my application got stuck and I had to figure out that it is necessary to call Desktop#open(File file) from a new thread. Calling the method from the current thread or the JavaFX application thread Platform#runLater(Runnable runnable) resulted in the application to hang indefinitely without an exception being thrown.
This is a small sample JavaFX application with the working file open solution:
import java.awt.Desktop;
import java.io.File;
import java.io.IOException;
import javafx.application.Application;
import javafx.concurrent.Task;
import javafx.scene.Scene;
import javafx.scene.control.Button;
import javafx.stage.FileChooser;
import javafx.stage.Stage;
public class FileOpenDemo extends Application {
#Override
public void start(Stage primaryStage) {
final Button button = new Button("Open file");
button.setOnAction(event -> {
final FileChooser fileChooser = new FileChooser();
final File file = fileChooser.showOpenDialog(primaryStage.getOwner());
if (file == null)
return;
System.out.println("File selected: " + file.getName());
if (!Desktop.isDesktopSupported()) {
System.out.println("Desktop not supported");
return;
}
if (!Desktop.getDesktop().isSupported(Desktop.Action.OPEN)) {
System.out.println("File opening not supported");
return;
}
final Task<Void> task = new Task<Void>() {
#Override
public Void call() throws Exception {
try {
Desktop.getDesktop().open(file);
} catch (IOException e) {
System.err.println(e.toString());
}
return null;
}
};
final Thread thread = new Thread(task);
thread.setDaemon(true);
thread.start();
});
primaryStage.setScene(new Scene(button));
primaryStage.show();
}
public static void main(String[] args) {
launch(args);
}
}
The other proposed solution with javafx.application.HostServices did not work at all. I am using OpenJFX 8u141 on Ubuntu 17.10 amd64 and I got the following exception when invoking HostServices#showDocument(String uri):
java.lang.ClassNotFoundException: com.sun.deploy.uitoolkit.impl.fx.HostServicesFactory
Obviously, JavaFX HostServices is not yet properly implemented on all platforms. On this topic see also: https://github.com/Qabel/qabel-desktop/issues/420

Boolean wont Update from Object.getBoolean();

Pretty much, I'm trying to write a simple program that lets the user choose a file. Unfortunately, JFileChooser through Swing is a little outdated, so I am trying to use JavaFX FileChooser for this. The goal is to run FileGetter as a thread, transfer the file data to the Main Class, and continue from there.
Main Class:
package application;
import java.io.File;
import javafx.application.Application;
import javafx.stage.Stage;
import javafx.scene.Scene;
import javafx.scene.layout.BorderPane;
public class Main {
public static void main(String[] args) {
Thread t1 = new Thread(new FileGetter());
FileGetter fg = new FileGetter();
t1.start();
boolean isReady = false;
while(isReady == false){
isReady = FileGetter.getIsReady();
}
File file = FileGetter.getFile();
System.out.println(file.getAbsolutePath());
...
}
}
FileGetter Class:
package application;
import java.io.File;
import javafx.application.Application;
import javafx.application.Platform;
import javafx.stage.FileChooser;
import javafx.stage.Stage;
import javafx.scene.Scene;
import javafx.scene.layout.BorderPane;
public class FileGetter extends Application implements Runnable {
static File file;
static boolean isReady = false;
#Override
public void start(Stage primaryStage) {
try {
FileChooser fc = new FileChooser();
while(file == null){
file = fc.showOpenDialog(primaryStage);
}
isReady = true;
Platform.exit();
} catch(Exception e) {
e.printStackTrace();
}
}
#Override
public void run() {
launch();
}
public static boolean getIsReady(){
return isReady;
}
public static File getFile(){
return file;
}
}
Problem is that the value of isReady in the while loop doesn't update to true when the user picked a file (the reason I have it is to prevent the code in Main from continuing with a File set to null).
Any help, alternative suggestions, or explanations as of why this happens is very much appreciated!

The java memory model does not require variable values to be the same in different threads except under specific conditions.
What is happening here is that the FileGetter thread is updating the value in the own memory that is only accessed from this thread, but your main thread doesn't see the updated value, since it only sees the version of the variable stored in it's own memory that is different from the one of the FileGetter thread. Each of the threads has it's own copy of the field in memory, which is perfectly fine according to the java specification.
To fix this, you can simply add the volatile modifier to isReady:
static volatile boolean isReady = false;
which makes sure the updated value will be visible from your main thread.
Furthermore I recommend reducing the number of FileGetter instances you create. In your code 3 instances are created, but only 1 is used.
Thread t1 = new Thread(() -> Application.launch(FileGetter.class));
t1.start();
...

The easiest way to implement this
Instead of trying to drive the horse with the cart, why not just follow the standard JavaFX lifecycle? In other words, make your Main class a subclass of Application, get the file in the start() method, and then proceed (in a background thread) with the rest of the application?
public class Main extends Application {
#Override
public void init() {
// make sure we don't exit when file chooser is closed...
Platform.setImplicitExit(false);
}
#Override
public void start(Stage primaryStage) {
File file = null ;
FileChooser fc = new FileChooser();
while(file == null){
file = fc.showOpenDialog(primaryStage);
}
final File theFile = file ;
new Thread(() -> runApplication(theFile)).start();
}
private void runApplication(File file) {
// run your application here...
}
}
What is wrong with your code
If you really want the Main class to be separate from the JavaFX Application class (which doesn't really make sense: once you have decided to use a JavaFX FileChooser, you have decided you are writing a JavaFX application, so the startup class should be a subclass of Application), then it gets a bit tricky. There are several issues with your code as it stands, some of which are addressed in other answers. The main issue, as shown in Fabian's answer, is that you are referencing FileGetter.isReady from multiple threads without ensuring liveness. This is exactly the issue addressed in Josh Bloch's Effective Java (Item 66 in the 2nd edition).
Another issue with your code is that you won't be able to use the FileGetter more than once (you can't call launch() more than once), which might not be an issue in your code now, but almost certainly will be at some point with this application as development progresses. The problem is that you have mixed two issues: starting the FX toolkit, and retrieving a File from a FileChooser. The first thing must only be done once; the second should be written to be reusable.
And finally your loop
while(isReady == false){
isReady = FileGetter.getIsReady();
}
is very bad practice: it checks the isReady flag as fast as it possibly can. Under some (fairly unusual) circumstances, it could even prevent the FX Application thread from having any resources to run. This should just block until the file is ready.
How to fix without making Main a JavaFX Application
So, again only if you have a really pressing need to do so, I would first create a class that just has the responsibility of starting the FX toolkit. Something like:
import java.util.concurrent.CountDownLatch;
import java.util.concurrent.atomic.AtomicBoolean;
import javafx.application.Application;
import javafx.application.Platform;
import javafx.stage.Stage;
public class FXStarter extends Application {
private static final AtomicBoolean startRequested = new AtomicBoolean(false);
private static final CountDownLatch latch = new CountDownLatch(1);
#Override
public void init() {
Platform.setImplicitExit(false);
}
#Override
public void start(Stage primaryStage) {
latch.countDown();
}
/** Starts the FX toolkit, if not already started via this method,
** and blocks execution until it is running.
**/
public static void startFXIfNeeded() throws InterruptedException {
if (! startRequested.getAndSet(true)) {
new Thread(Application::launch).start();
}
latch.await();
}
}
Now create a class that gets a file for you. This should ensure the FX toolkit is running, using the previous class. This implementation allows you to call getFile() from any thread:
import java.io.File;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.FutureTask;
import javafx.application.Platform;
import javafx.stage.FileChooser;
public class FileGetter {
/**
** Retrieves a file from a JavaFX File chooser. This method can
** be called from any thread, and will block until the user chooses
** a file.
**/
public File getFile() throws InterruptedException {
FXStarter.startFXIfNeeded() ;
if (Platform.isFxApplicationThread()) {
return doGetFile();
} else {
FutureTask<File> task = new FutureTask<File>(this::doGetFile);
Platform.runLater(task);
try {
return task.get();
} catch (ExecutionException exc) {
throw new RuntimeException(exc);
}
}
}
private File doGetFile() {
File file = null ;
FileChooser chooser = new FileChooser() ;
while (file == null) {
file = chooser.showOpenDialog(null) ;
}
return file ;
}
}
and finally your Main is just
import java.io.File;
public class Main {
public static void main(String[] args) throws InterruptedException {
File file = new FileGetter().getFile();
// proceed...
}
}
Again, this is pretty complex; I see no reason not to simply use the standard FX Application lifecycle for this, as in the very first code block in the answer.

In this code
while(isReady == false){
isReady = FileGetter.getIsReady();
}
there is nothing that is going to change the state of FileGetter's isReady to true