Need a variable to hold a value which will be assigned once and will be used by every method of a class
if I specify it as non static variable it is not holding the value
Class Test{
private String test;
public void method1(){
test = "String1";
}
public void method2(){
System.out.println(test.length());
}
}
Getting Null Pointer exception. the value of the test will be used in every method.
Could anyone help me, how to fix the issue.
The NullPointerException will be thrown whenever the test variable is null and you try to invoke methods on that variable. In your case, when you invoke method2() before method1(). That has nothing to do with global, local or whatever, as Long Vu already mentioned.
So first you should make sure, you don't access an uninitialized variable. Then, if you need a class with a single instance, which should be accessible application wide, you can implement this using the singleton pattern. For more about it, have a look at this Wikipedia page: https://en.wikipedia.org/wiki/Singleton_pattern
Maybe your problem is that you are creating multiple objects of class Test.
For example this should work:
Test test1=new Test();
test1.method1(); //call this first then other methods
test1.method2();
You should use this object "test1" as a parameter wherever you need it.
If you want to access the variable globally then create a Singletone class:
class Test{
private static Test single_instance = null;
private String test;
// private constructor restricted to this class itself
private Test(){
}
// static method to create instance of Singleton class
public static Test getInstance(){
if (single_instance == null)
single_instance = new Test();
return single_instance;
}
public void setTest(String value){
test = value;
}
public String getTest(){
return test;
}
public static void main(String args[]){
Test test = Test.getInstance();
test.setTest("String1");
test.getTest();
}
}
public class InstanceBuilder {
private static final InstanceBuilder INSTANCE = new InstanceBuilder();
private static String name = null;
private InstanceBuilder() {
System.out.println("Setting cons()");
name = "Testing";
}
public static String getName() {
return name;
}
}
public class Driver {
public static void main(String[] args) {
// TODO Auto-generated method stub
System.out.println("value is " + InstanceBuilder.getName());
}
}
Output:
Setting cons()
value is null
Why does it print value as null even though I have set the static variable in constructor and it is called as expected. If I try to print in constructor, it is printing Testing, but if I call from public static method, it is null. I know if I change it to INSTANCE.name, it works.
But I want to understand why it is not working if I directly access static variable since same copy should be shared.
What I am missing here?
Because the value of name is getting modified after the constructor invocation as per the declaration order.
Lets see what is happening:
1) When you call InstanceBuilder.getName(), InstanceBuilder class is getting loaded. As part of that process INSTANCE and name instance variables are getting initialized.
2) While initializing INSTANCE,
private static final InstanceBuilder INSTANCE = new InstanceBuilder();
constructor of InstanceBuilder class is getting invoked & Setting cons() statement is getting printed and name variable is initialized with Testing.
3) Next name is again getting re-initialized with null due to the below statement
private static String name = null;
so when the method call returns to Driver class, value of name is null and null is getting printed. So even though name is declared as static, static has no role in that context.
Note:
Check the below link on the order of which class members should be declared
http://www.oracle.com/technetwork/java/javase/documentation/codeconventions-141855.html#1852
Here value is null because static initialization occurs as its declare in order,
So First your
`private static final InstanceBuilder INSTANCE = new InstanceBuilder();`
code execute and assign value to "testing", then your
`private static String name = null;`
code exceute and override value to null(as static variable have coppy per class only), so final value will be null.
So here this behavior is just beacuse of order of execution of static variable
okay. I wrote the above code and I need to call it from another class. how can I do it?
plus it gives me this error with DefaultTableModel prodt = (DefaultTableModel) protable.getModel(); . the error is non-static variable protable cannot be referenced from a static context.
public static void refreshProtable() {
try {
Statement s1 = Db.connectDb().createStatement();
ResultSet rs1 = s1.executeQuery("SELECT * FROM product WHERE status='" + 0 + "'");
DefaultTableModel prodt = (DefaultTableModel) protable.getModel();
while (rs1.next()) {
Vector v1 = new Vector();
v1.add(rs1.getString("pid"));
v1.add(rs1.getString("pname"));
v1.add(rs1.getString("sp_rt"));
v1.add(rs1.getString("sp_wh"));
v1.add(rs1.getString("um"));
Statement s2 = Db.connectDb().createStatement();
ResultSet rs2 = s2.executeQuery("SELECT * FROM stock WHERE pid='" + rs1.getString("pid") + "'");
if (rs2.next()) {
v1.add(rs2.getString("qty"));
}
prodt.addRow(v1);
s2.close();
}
s1.close();
} catch (Exception e) {
e.printStackTrace();
}
}
Either mark your variable protable static or make the method non-static.
private static DefaultTableModel protable;
public static void refreshProtable() { ... }
Since the method is static, you call it using the class name that it is within.
E.g
class A {
public static void b() {
// do something
}
}
Would be called as follows:
A.b();
It might be handy to refresh yourself on how static variables work, here would be a starting point: http://docs.oracle.com/javase/tutorial/java/javaOO/classvars.html
You can make your function as non-static or make protable object static.
In a word, you can not reference non-static variable in static function.
but you can reference static variable in non-static function
you need to make protable as static as you can access only static variables from a static method.
private static DefaultTableModel protable;
public static void refreshProtable() { }
the variable you are trying to call is an instance-level variable;
static variable
It is a variable which belongs to the class and not to object(instance)
Static variables are initialized only once , at the start of the execution . These variables will be initialized first, before the initialization of any instance variables
A single copy to be shared by all instances of the class
A static variable can be accessed directly by the class name and doesn’t need any object
Syntax : .
static method
It is a method which belongs to the class and not to the object(instance)
A static method can access only static data. It can not access non-static data (instance variables)
static method can call only other static methods and can not call a non-static method from it.
A static method can be accessed directly by the class name and doesn’t need any object
Syntax : .
A static method cannot refer to “this” or “super” keywords in anyway
I'm trying to initialize a static class, with an argument, and then run some more static code in that class.
I'm aware of the static block, but it seems it can't take any arguments.
Is there a way to pass arguments to a static constructor?
If not, what is the recommended technique to initialize a Static class using an argument?
Edit:
A static class to my understanding is a class which cannot be instantiated (in c# they're called static classes, if Java has a different term for them, sorry for not being aware of it) - it's accessed through it's class name rather than an object name.
What I'm trying to achieve (very simplified) is a class which receives a dictionary as String, parses it, and has methods manipulate it like GetRandomEntry.
Here's an elaborated snippet of my code:
public class QuestionsRepository {
private static Map<String,String[]> easyDefinitions = new HashMap<String,String[]>();
//...
static
{
// need to receive and parse dictionary here
}
//...
Taking the relevant parts of a code snippet is never easy, hope i have chosen wisely (:
Another detail that may be relevant - I'm a c# programmer, usually. Just Started learning Java lately.
Thanks.
I think you would need to initialize the static fields of the class according to some input. You can do it in the following way by calling the static method of another class:
class ClassToInitialize {
static {
staticField = ParamPassClass.getParameter();
}
private static String staticField;
ClassToInitialize() {
System.out.println("This is the parameter: " + staticField);
}
}
class ParamPassClass {
private static String parameter;
static String getParameter() {
return parameter;
}
static void setParameter(String parameter) {
ParamPassClass.parameter = parameter;
}
}
class Main {
public static void main(String args[]) {
ParamPassClass.setParameter("Test param");
new ClassToInitialize();
}
}
Java doesn't have static constructors. It only has static initializers and static initializers do not take any arguments. It is executed when the class is first loaded, and there is no way to call it yourself.
You either need to use actual objects, or add some way of configuring the class (eg through a static method).
you should mention the member class with a static qualifier, otherwise there is no such a thing as a static class
Here you can find the explanation of using the word 'static' in this context.
Now you should just call its constructor and pass all the arguments you want,
the only restriction that you have on a static member class is that it can't refer the non-static fields of its outer class, it resembles a static methods on class that can't refer the non-static fields of class.
I didn't understand why do you mention a static initialization block here, could you please clarify a little?
Be aware also that in java there is no such a thing as static constructor....
Hope this helps
You can have a static method public static void setUp(Arg1 arg1, Arg2 arg2...) which sets up all your static fields and invoke it when your program starts.
You have to make sure this method will be called only once [or only when you want to reset these fields]
It is not possible to pass arguments directly to the static initializes (JLS:static initializers).
It would be nice if you could share more information about your goals.
You could use an enum to initialize a singleton with a string parameter like this
import java.util.*;
class Data {
static Map<String,String[]> easyDefinitions = new HashMap<String,String[]>();
}
public enum QuestionsRepository
{
repository("primary=red,green,blue;secondary=cyan,yellow,magenta");
QuestionsRepository(String dictionary) {
String[] rules = dictionary.split(";");
for (String rule:rules) {
String[] keyValuePair = rule.split("=",2);
Data.easyDefinitions.put(keyValuePair[0],keyValuePair[1].split(","));
}
}
}
As far as I understood the "static initialization block" is used to set values of static field if it cannot be done in one line.
But I do not understand why we need a special block for that. For example we declare a field as static (without a value assignment). And then write several lines of the code which generate and assign a value to the above declared static field.
Why do we need this lines in a special block like: static {...}?
The non-static block:
{
// Do Something...
}
Gets called every time an instance of the class is constructed. The static block only gets called once, when the class itself is initialized, no matter how many objects of that type you create.
Example:
public class Test {
static{
System.out.println("Static");
}
{
System.out.println("Non-static block");
}
public static void main(String[] args) {
Test t = new Test();
Test t2 = new Test();
}
}
This prints:
Static
Non-static block
Non-static block
If they weren't in a static initialization block, where would they be? How would you declare a variable which was only meant to be local for the purposes of initialization, and distinguish it from a field? For example, how would you want to write:
public class Foo {
private static final int widgets;
static {
int first = Widgets.getFirstCount();
int second = Widgets.getSecondCount();
// Imagine more complex logic here which really used first/second
widgets = first + second;
}
}
If first and second weren't in a block, they'd look like fields. If they were in a block without static in front of it, that would count as an instance initialization block instead of a static initialization block, so it would be executed once per constructed instance rather than once in total.
Now in this particular case, you could use a static method instead:
public class Foo {
private static final int widgets = getWidgets();
static int getWidgets() {
int first = Widgets.getFirstCount();
int second = Widgets.getSecondCount();
// Imagine more complex logic here which really used first/second
return first + second;
}
}
... but that doesn't work when there are multiple variables you wish to assign within the same block, or none (e.g. if you just want to log something - or maybe initialize a native library).
Here's an example:
private static final HashMap<String, String> MAP = new HashMap<String, String>();
static {
MAP.put("banana", "honey");
MAP.put("peanut butter", "jelly");
MAP.put("rice", "beans");
}
The code in the "static" section(s) will be executed at class load time, before any instances of the class are constructed (and before any static methods are called from elsewhere). That way you can make sure that the class resources are all ready to use.
It's also possible to have non-static initializer blocks. Those act like extensions to the set of constructor methods defined for the class. They look just like static initializer blocks, except the keyword "static" is left off.
It's also useful when you actually don't want to assign the value to anything, such as loading some class only once during runtime.
E.g.
static {
try {
Class.forName("com.example.jdbc.Driver");
} catch (ClassNotFoundException e) {
throw new ExceptionInInitializerError("Cannot load JDBC driver.", e);
}
}
Hey, there's another benefit, you can use it to handle exceptions. Imagine that getStuff() here throws an Exception which really belongs in a catch block:
private static Object stuff = getStuff(); // Won't compile: unhandled exception.
then a static initializer is useful here. You can handle the exception there.
Another example is to do stuff afterwards which can't be done during assigning:
private static Properties config = new Properties();
static {
try {
config.load(Thread.currentThread().getClassLoader().getResourceAsStream("config.properties");
} catch (IOException e) {
throw new ExceptionInInitializerError("Cannot load properties file.", e);
}
}
To come back to the JDBC driver example, any decent JDBC driver itself also makes use of the static initializer to register itself in the DriverManager. Also see this and this answer.
I would say static block is just syntactic sugar. There is nothing you could do with static block and not with anything else.
To re-use some examples posted here.
This piece of code could be re-written without using static initialiser.
Method #1: With static
private static final HashMap<String, String> MAP;
static {
MAP.put("banana", "honey");
MAP.put("peanut butter", "jelly");
MAP.put("rice", "beans");
}
Method #2: Without static
private static final HashMap<String, String> MAP = getMap();
private static HashMap<String, String> getMap()
{
HashMap<String, String> ret = new HashMap<>();
ret.put("banana", "honey");
ret.put("peanut butter", "jelly");
ret.put("rice", "beans");
return ret;
}
There are a few actual reasons that it is required to exist:
initializing static final members whose initialization might throw an exception
initializing static final members with calculated values
People tend to use static {} blocks as a convenient way to initialize things that the class depends on within the runtime as well - such as ensuring that particular class is loaded (e.g., JDBC drivers). That can be done in other ways; however, the two things that I mention above can only be done with a construct like the static {} block.
You can execute bits of code once for a class before an object is constructed in the static blocks.
E.g.
class A {
static int var1 = 6;
static int var2 = 9;
static int var3;
static long var4;
static Date date1;
static Date date2;
static {
date1 = new Date();
for(int cnt = 0; cnt < var2; cnt++){
var3 += var1;
}
System.out.println("End first static init: " + new Date());
}
}
It is a common misconception to think that a static block has only access to static fields. For this I would like to show below piece of code that I quite often use in real-life projects (copied partially from another answer in a slightly different context):
public enum Language {
ENGLISH("eng", "en", "en_GB", "en_US"),
GERMAN("de", "ge"),
CROATIAN("hr", "cro"),
RUSSIAN("ru"),
BELGIAN("be",";-)");
static final private Map<String,Language> ALIAS_MAP = new HashMap<String,Language>();
static {
for (Language l:Language.values()) {
// ignoring the case by normalizing to uppercase
ALIAS_MAP.put(l.name().toUpperCase(),l);
for (String alias:l.aliases) ALIAS_MAP.put(alias.toUpperCase(),l);
}
}
static public boolean has(String value) {
// ignoring the case by normalizing to uppercase
return ALIAS_MAP.containsKey(value.toUpper());
}
static public Language fromString(String value) {
if (value == null) throw new NullPointerException("alias null");
Language l = ALIAS_MAP.get(value);
if (l == null) throw new IllegalArgumentException("Not an alias: "+value);
return l;
}
private List<String> aliases;
private Language(String... aliases) {
this.aliases = Arrays.asList(aliases);
}
}
Here the initializer is used to maintain an index (ALIAS_MAP), to map a set of aliases back to the original enum type. It is intended as an extension to the built-in valueOf method provided by the Enum itself.
As you can see, the static initializer accesses even the private field aliases. It is important to understand that the static block already has access to the Enum value instances (e.g. ENGLISH). This is because the order of initialization and execution in the case of Enum types, just as if the static private fields have been initialized with instances before the static blocks have been called:
The Enum constants which are implicit static fields. This requires the Enum constructor and instance blocks, and instance initialization to occur first as well.
static block and initialization of static fields in the order of occurrence.
This out-of-order initialization (constructor before static block) is important to note. It also happens when we initialize static fields with the instances similarly to a Singleton (simplifications made):
public class Foo {
static { System.out.println("Static Block 1"); }
public static final Foo FOO = new Foo();
static { System.out.println("Static Block 2"); }
public Foo() { System.out.println("Constructor"); }
static public void main(String p[]) {
System.out.println("In Main");
new Foo();
}
}
What we see is the following output:
Static Block 1
Constructor
Static Block 2
In Main
Constructor
Clear is that the static initialization actually can happen before the constructor, and even after:
Simply accessing Foo in the main method, causes the class to be loaded and the static initialization to start. But as part of the Static initialization we again call the constructors for the static fields, after which it resumes static initialization, and completes the constructor called from within the main method. Rather complex situation for which I hope that in normal coding we would not have to deal with.
For more info on this see the book "Effective Java".
So you have a static field (it's also called "class variable" because it belongs to the class rather than to an instance of the class; in other words it's associated with the class rather than with any object) and you want to initialize it. So if you do NOT want to create an instance of this class and you want to manipulate this static field, you can do it in three ways:
1- Just initialize it when you declare the variable:
static int x = 3;
2- Have a static initializing block:
static int x;
static {
x=3;
}
3- Have a class method (static method) that accesses the class variable and initializes it:
this is the alternative to the above static block; you can write a private static method:
public static int x=initializeX();
private static int initializeX(){
return 3;
}
Now why would you use static initializing block instead of static methods?
It's really up to what you need in your program. But you have to know that static initializing block is called once and the only advantage of the class method is that they can be reused later if you need to reinitialize the class variable.
let's say you have a complex array in your program. You initialize it (using for loop for example) and then the values in this array will change throughout the program but then at some point you want to reinitialize it (go back to the initial value). In this case you can call the private static method. In case you do not need in your program to reinitialize the values, you can just use the static block and no need for a static method since you're not gonna use it later in the program.
Note: the static blocks are called in the order they appear in the code.
Example 1:
class A{
public static int a =f();
// this is a static method
private static int f(){
return 3;
}
// this is a static block
static {
a=5;
}
public static void main(String args[]) {
// As I mentioned, you do not need to create an instance of the class to use the class variable
System.out.print(A.a); // this will print 5
}
}
Example 2:
class A{
static {
a=5;
}
public static int a =f();
private static int f(){
return 3;
}
public static void main(String args[]) {
System.out.print(A.a); // this will print 3
}
}
If your static variables need to be set at runtime then a static {...} block is very helpful.
For example, if you need to set the static member to a value which is stored in a config file or database.
Also useful when you want to add values to a static Map member as you can't add these values in the initial member declaration.
It is important to understand that classes are instantiated from java.class.Class during runtime. That is when static blocks are executed, which allows you to execute code without instantiating a class:
public class Main {
private static int myInt;
static {
myInt = 1;
System.out.println("myInt is 1");
}
// needed only to run this class
public static void main(String[] args) {
}
}
The result is myInt is 1 printed to the console.
As supplementary, like #Pointy said
The code in the "static" section(s) will be executed at class load
time, before any instances of the class are constructed (and before
any static methods are called from elsewhere).
It's supposed to add System.loadLibrary("I_am_native_library") into static block.
static{
System.loadLibrary("I_am_a_library");
}
It will guarantee no native method be called before the related library is loaded into memory.
According to loadLibrary from oracle:
If this method is called more than once with the same library name,
the second and subsequent calls are ignored.
So quite unexpectedly, putting System.loadLibrary is not used to avoid library be loaded multi-times.
static block is used for any technology to initialize static data member in dynamic way,or we can say for the dynamic initialization of static data member static block is being used..Because for non static data member initialization we have constructor but we do not have any place where we can dynamically initialize static data member
Eg:-class Solution{
// static int x=10;
static int x;
static{
try{
x=System.out.println();
}
catch(Exception e){}
}
}
class Solution1{
public static void main(String a[]){
System.out.println(Solution.x);
}
}
Now my static int x will initialize dynamically ..Bcoz when compiler will go to Solution.x it will load Solution Class and static block load at class loading time..So we can able to dynamically initialize that static data member..
}
static int B,H;
static boolean flag = true;
static{
Scanner scan = new Scanner(System.in);
B = scan.nextInt();
scan.nextLine();
H = scan.nextInt();
if(B < 0 || H < 0){
flag = false;
System.out.println("java.lang.Exception: Breadth and height must be positive");
}
}