How can I parse a specific cookie from this string in Java? - java

say I have the following string in a variable
cookie-one=someValue;HttpOnly;Secure;Path=/;SameSite=none, cookie-two=someOtherValue;Path=/;Secure;HttpOnly, cookie-three=oneMoreValue;Path=/;Secure
and I want a substring from the name of a cookie that I choose say cookie-two and store the string up to the contents of that cookie.
So basically I need
cookie-two=someOtherValue;Path=/;Secure;HttpOnly
How can I get this substring out?

You can just separate the String by commas first to separate the cookies. For example if you wanted just the cookie that has the name cookie-two:
String s = "cookie-one=someValue;HttpOnly;Secure;Path=/;SameSite=none, cookie-two=someOtherValue;Path=/;Secure;HttpOnly, cookie-three=oneMoreValue;Path=/;Secure";
String[] cookies = s.split(",");
for(String cookie : cookies){
if(cookie.trim().startsWith("cookie-two")){
System.out.println(cookie);
}
}

This is possible to achieve in several different ways depending on how the data might vary in the sting. For your specific example we could for instance do like this:
String cookieString = "cookie-one=someValue;HttpOnly;Secure;Path=/;SameSite=none, cookie-two=someOtherValue;Path=/;Secure;HttpOnly, cookie-three=oneMoreValue;Path=/;Secure";
String result = "";
for(String s: cookieString.split(", ")) {
if(s.startsWith("cookie-two")) {
result = s;
break;
}
}
We could also use regex and/or streams to make the code look nicer, but this is probably one of the most straight forward ways of achieving what you want.

Related

Unable to retrieve the value of a specific text in java

I have a long text like below:
name="sessionValidity" value="2018-09-13T16:28:28Z" type="hidden"
name="shipBeforeDate" value= "2018-09-17" name="merchantReturnData"
value= "",name="shopperLocale" value="en_GB" name="skinCode"
value="CeprdxkMuQ" name="merchantSig"
value="X70xAkOaaAeWGxNgWnTJolmy6/FFoFaBD47IzyBYWf4="
Now, I have to find all the data which are stored in the value string.
Please help.
Usually the worst thing you could do is parsing an HTML with regex. Detailed explonation here.
For the purpose of parsing the data and manipulate it the right way you should considering using an advanced markup parser like jaxb, jsoup, or any other.
Of course it is a case specific decision and in your case maybe this one could do the work...
private static List<String> extractValuesAsUselessList(String theString) {
List<String> attributes = new ArrayList<>();
if (theString != null && !theString.equals("")) {
Matcher matcher = Pattern.compile("\\s([\\w+|-|:]+)=\"(.*?)\"").matcher(theString);
while (matcher.find()) {
if ("value".equals(matcher.group(1))) {
attributes.add(matcher.group(2));
}
}
}
return attributes;
}

How to query contacts from exchange server using LIKE operator?

I want to query contacts from exchange server by using LIKE operator, i am using
SearchFilter.ContainsSubstring & passing text as LIKE Sa% but it's not returning any data. when i passing Sa% it's taking whole condition as a string.
if (comparisonOperation.equalsIgnoreCase("like")) {
SearchFilter filter = new SearchFilter.ContainsSubstring(filterData.getFieldType(), filterData.getFieldValue().toString(), ContainmentMode.Substring, ComparisonMode.IgnoreCase);
ilterCollection.add(filter);
}
There are nothing like LIKE Sa% in java, instead you can use Mactches with a regex for example you can replace Sa% with Sa(.*?) for example :
String str = "Samsung";
if(str.matches("Sa(.*?)")){
System.out.println("yes");
}

can jQuery serialize() use other separator than ampersand?

I am looking for some nice solution. I've got a couple of textfields on my page and I am sending these via Ajax using jQuery serialize method. This serialized string is parsed in my java method to hashmap with key = 'nameOfTextfield' nad value = 'valueInTextfield'
For example, I've got this String stdSel=value1&stdNamText=value2&stdRevText=value3 and everything works fine.
String[] sForm = serializedForm.split("&");
Map<String, String> fForm = new HashMap<String, String>();
for (String part : sForm) {
String key = null;
String value = null;
try {
key = part.split("=")[0];
value = part.split("=",2)[1];
fForm.put(key, value);
//if textfield is empty
} catch(IndexOutOfBoundsException e) {
fForm.put(key, "");
}
}
But this method will break down when ampersand in some textfield appears, for example this stdSel=value1&stdNamText=value2&stdRevText=val&&ue3. My thought was that I'll replace ampersand as separator in searialized string for some other character or maybe more characters. Is it possible and good idea or is there any better way?
Regards
Ondrej
Ampersands are escaped by the serialize function, so they don't break the URL.
What you need to unescape a field you got from an URL is
value = URLDecoder.decode(value,"UTF-8");
But, as was pointed by... Pointy, if you're using a web framework and not using only vanilla java.net java you probably don't have to do this.

How do I call this object to return all strings it finds?

I have the following code that defines a getParts method to find a given Part Name and Part Number in the system. Note that this code comes from our system's API, so if no one can help I'll just delete this question. I figured someone could potentially see a solution or help me along the way.
<%! private QueryResult getParts( String name, String number )
throws WTException, WTPropertyVetoException {
Class cname = wt.part.WTPart.class;
QuerySpec qs = new QuerySpec(cname);
QueryResult qr = null;
qs.appendWhere
(new SearchCondition(cname,
"master>name",
SearchCondition.EQUAL,
name,
false));
qs.appendAnd();
qs.appendWhere
(new SearchCondition(cname,
"master>number",
SearchCondition.EQUAL,
number,
false));
qr = PersistenceHelper.manager.find(qs);
System.out.println("...found: " + qr.size());
return qr;
}
%>
But I would like to allow the user more flexibility in finding these parts. So I set up conditional statements to check for a radio button. This allows them to search by part name and part number, find all, or search using a wildcard. However, I'm having trouble implementing the two latter options.
To attempt to accomplish the above, I have written the below code:
<%
String partName = request.getParameter("nameInput");
String partNumber = request.getParameter("numberInput");
String searchMethod = request.getParameter("selection");
//out.print(searchMethod);
QueryResult myResult = new QueryResult();
if(searchMethod.equals("search"))
myResult = getParts(partName, partNumber);
else if(searchMethod.equals("all"))
{
//Should I write a new function and do this?
//myResult = getAllParts();
//or is there a way I could use a for each loop to accomplish this?
}
//else if(searchMethod.equals("wildcard"))
//get parts matching %wildcard%
while(myResult.hasMoreElements())
{
out.print(myResult.nextElement().toString());
}
%>
Basically, it accepts user input and checks what type of search they would like to perform. Is there an easy way to pass all the values into the myResult object? And likewise for the wildcard search? Like I said before, it may be futile trying to help without access to the API, but hopefully it isn't.
Thanks!
You can (and should) reuse the function, but in order to do so, you will need a part name and number (as those are its input parameters). So for the multi-result options you will need to get a list/collection of part names+numbers and feed them individually to the function, then collect the result in the format that is most appropriate for your needs

How to replace tokens in a string without StringTokenizer

Given a string like so:
Hello {FIRST_NAME}, this is a personalized message for you.
Where FIRST_NAME is an arbitrary token (a key in a map passed to the method), to write a routine which would turn that string into:
Hello Jim, this is a personalized message for you.
given a map with an entry FIRST_NAME -> Jim.
It would seem that StringTokenizer is the most straight forward approach, but the Javadocs really say you should prefer to use the regex aproach. How would you do that in a regex based solution?
Thanks everyone for the answers!
Gizmo's answer was definitely out of the box, and a great solution, but unfortunately not appropriate as the format can't be limited to what the Formatter class does in this case.
Adam Paynter really got to the heart of the matter, with the right pattern.
Peter Nix and Sean Bright had a great workaround to avoid all of the complexities of the regex, but I needed to raise some errors if there were bad tokens, which that didn't do.
But in terms of both doing a regex and a reasonable replace loop, this is the answer I came up with (with a little help from Google and the existing answer, including Sean Bright's comment about how to use group(1) vs group()):
private static Pattern tokenPattern = Pattern.compile("\\{([^}]*)\\}");
public static String process(String template, Map<String, Object> params) {
StringBuffer sb = new StringBuffer();
Matcher myMatcher = tokenPattern.matcher(template);
while (myMatcher.find()) {
String field = myMatcher.group(1);
myMatcher.appendReplacement(sb, "");
sb.append(doParameter(field, params));
}
myMatcher.appendTail(sb);
return sb.toString();
}
Where doParameter gets the value out of the map and converts it to a string and throws an exception if it isn't there.
Note also I changed the pattern to find empty braces (i.e. {}), as that is an error condition explicitly checked for.
EDIT: Note that appendReplacement is not agnostic about the content of the string. Per the javadocs, it recognizes $ and backslash as a special character, so I added some escaping to handle that to the sample above. Not done in the most performance conscious way, but in my case it isn't a big enough deal to be worth attempting to micro-optimize the string creations.
Thanks to the comment from Alan M, this can be made even simpler to avoid the special character issues of appendReplacement.
Well, I would rather use String.format(), or better MessageFormat.
String.replaceAll("{FIRST_NAME}", actualName);
Check out the javadocs for it here.
Try this:
Note: The author's final solution builds upon this sample and is much more concise.
public class TokenReplacer {
private Pattern tokenPattern;
public TokenReplacer() {
tokenPattern = Pattern.compile("\\{([^}]+)\\}");
}
public String replaceTokens(String text, Map<String, String> valuesByKey) {
StringBuilder output = new StringBuilder();
Matcher tokenMatcher = tokenPattern.matcher(text);
int cursor = 0;
while (tokenMatcher.find()) {
// A token is defined as a sequence of the format "{...}".
// A key is defined as the content between the brackets.
int tokenStart = tokenMatcher.start();
int tokenEnd = tokenMatcher.end();
int keyStart = tokenMatcher.start(1);
int keyEnd = tokenMatcher.end(1);
output.append(text.substring(cursor, tokenStart));
String token = text.substring(tokenStart, tokenEnd);
String key = text.substring(keyStart, keyEnd);
if (valuesByKey.containsKey(key)) {
String value = valuesByKey.get(key);
output.append(value);
} else {
output.append(token);
}
cursor = tokenEnd;
}
output.append(text.substring(cursor));
return output.toString();
}
}
With import java.util.regex.*:
Pattern p = Pattern.compile("{([^{}]*)}");
Matcher m = p.matcher(line); // line being "Hello, {FIRST_NAME}..."
while (m.find) {
String key = m.group(1);
if (map.containsKey(key)) {
String value= map.get(key);
m.replaceFirst(value);
}
}
So, the regex is recommended because it can easily identify the places that require substitution in the string, as well as extracting the name of the key for substitution. It's much more efficient than breaking the whole string.
You'll probably want to loop with the Matcher line inside and the Pattern line outside, so you can replace all lines. The pattern never needs to be recompiled, and it's more efficient to avoid doing so unnecessarily.
The most straight forward would seem to be something along the lines of this:
public static void main(String[] args) {
String tokenString = "Hello {FIRST_NAME}, this is a personalized message for you.";
Map<String, String> tokenMap = new HashMap<String, String>();
tokenMap.put("{FIRST_NAME}", "Jim");
String transformedString = tokenString;
for (String token : tokenMap.keySet()) {
transformedString = transformedString.replace(token, tokenMap.get(token));
}
System.out.println("New String: " + transformedString);
}
It loops through all your tokens and replaces every token with what you need, and uses the standard String method for replacement, thus skipping the whole RegEx frustrations.
Depending on how ridiculously complex your string is, you could try using a more serious string templating language, like Velocity. In Velocity's case, you'd do something like this:
Velocity.init();
VelocityContext context = new VelocityContext();
context.put( "name", "Bob" );
StringWriter output = new StringWriter();
Velocity.evaluate( context, output, "",
"Hello, #name, this is a personalized message for you.");
System.out.println(output.toString());
But that is likely overkill if you only want to replace one or two values.
import java.util.HashMap;
public class ReplaceTest {
public static void main(String[] args) {
HashMap<String, String> map = new HashMap<String, String>();
map.put("FIRST_NAME", "Jim");
map.put("LAST_NAME", "Johnson");
map.put("PHONE", "410-555-1212");
String s = "Hello {FIRST_NAME} {LAST_NAME}, this is a personalized message for you.";
for (String key : map.keySet()) {
s = s.replaceAll("\\{" + key + "\\}", map.get(key));
}
System.out.println(s);
}
}
The docs mean that you should prefer writing a regex-based tokenizer, IIRC. What might work better for you is a standard regex search-replace.
Generally we'd use MessageFormat in a case like this, coupled with loading the actual message text from a ResourceBundle. This gives you the added benefit of being G10N friendly.

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