This question already has answers here:
How to Java String.format with a variable precision?
(4 answers)
Java printf using variable field size?
(4 answers)
Closed 2 years ago.
I'm a new programmer, and I'm coding a basic decimal calculator. (in Java)
If the user inputs how many decimals they want to round to, say 2, how would I incorporate that into the code, and have the answer round to 2 decimals?
Right now, I have something like this:
System.out.printf("%.3f %n", ans);
But that will always round to 3 decimals, no matter what the user input is.
Here's a link to the whole code, if necessary.
Is there a basic way to this?
Related
This question already has answers here:
Large Numbers in Java
(6 answers)
Closed 1 year ago.
I declared a long in Java code and it only take 19 decimal digits. I need a data type that takes over 300 decimal digits.
There is no primitive type that supports a number that long.
What you are searching for is most likely a BigInteger object. Calculations are done through the methods shown in the API.
As another user said, Javascript and Java are two different languages, please use the correct tag.
This question already has answers here:
How to round a number to n decimal places in Java
(39 answers)
Closed 3 years ago.
I want to take a float that can be entered by the user to any acceptable number of decimal places and format it so that it is only two decimal places. I am able to do this by converting it to a String but I want to keep it as a float and was wondering if there was an easier way to do this than changing from float to string and then back to a float?
Here's a way to do it:
https://stackoverflow.com/a/153785/4119650
It's a little more complicated than the String conversion method, but it gives you greater control over the truncation.
This question already has answers here:
Generate a random double in a range
(7 answers)
Using Math.round to round to one decimal place?
(9 answers)
Closed 4 years ago.
I am trying to round to the nearest decimal value, however, this line of code keeps returning a number between 0 and 1, I also want the output to be between 1 and 10. Where am I going wrong?
power[i] = rng.nextDouble();
Math.round(ThreadLocalRandom.nextDouble(1,10)*10)/10.0
You can use JDK's Math.round.
A detailed example can be found here.
This question already has answers here:
Best way to Format a Double value to 2 Decimal places [duplicate]
(2 answers)
Closed 7 years ago.
The title says it all. Right now if I input a number like 100.50, in my program it prints as 100.5. Is there an easy way to make the program recognize the zero?
You can do this trick.
String s = String.format("%.2f", 100.50);
This question already has answers here:
How to round a number to n decimal places in Java
(39 answers)
Closed 9 years ago.
I retrieve some data from a database but the number has a lot of digits and I want to round it. The thing is I do not want the whole number to be rounded.
Example :
I draw number 4.1010359882326385E10 which is of type long.
I want to round it to 4.10103598823264.
That is to round the number after the 15th digit.
Any way I can do this?
E10 in your number is a scientific notation, that says you number is actually 41010359882.326385. If you transform it to 4.10103598823264, you are not doing a rounding, you are doing something else.