How to deserialize json object into flatten format direct field? - java

I have the following structure:
public class User {
private Account account;
//constuctors, getters and setters
}
public class Account {
private String id;
private String description;
//constructor, getters and setters
}
When I performing the request I need to create the following JSON structure:
{
"account":
{
"id": "1",
"description": "Some description"
}
}
But I want to specify this information in a short way and ignore(left 'null') the 'description' field in the following way:
{
"account": "1" // I want to set directly the id field in the account object.
}
How may I do it? I tried #JsonCreator annotation and #JsonUnwrapped but without result.

You can use a custom deserializer
public class AccountFromIdDeserializer extends StdDeserializer<Account> {
public AccountFromIdDeserializer() { this(null);}
protected AccountFromIdDeserializer(Class<Account> type) { super(type);}
#Override
public Account deserialize(JsonParser parser, DeserializationContext context)
throws IOException, JsonProcessingException {
Account account = new Account();
account.setId(parser.getValueAsString());
return account;
}
}
And use on account node of User using #JsonDeserialize
public class User {
#JsonDeserialize(using = AccountFromIdDeserializer.class)
private Account account;
//constuctors, getters and setters
}

Finally I used #JsonCreator annotation and created two constructors:
#JsonCreator
public Account(#JsonProperty("id") String id, #JsonProperty("description") String description) {
this.id = id;
this.description = description;
}
#JsonCreator
public Account(String id) {
this.id = id;
}

Related

How can I prevent an empty JSON object from being deserialized to a Java bean? [duplicate]

At the deserialization process (which as I understand is the process of converting JSON data into a Java Object), how can I tell Jackson that when it reads a object that contains no data, it should be ignored?
I'm using Jackson 2.6.6 and Spring 4.2.6
The JSON data received by my controller is as follows:
{
"id": 2,
"description": "A description",
"containedObject": {}
}
The problem is that the object "containedObject" is interpreted as is and it's being instantiated. Therefore, as soon as my controller reads this JSON data, it produces an instance of the ContainedObject object type but I need this to be null instead.
The easiest and fastest solution would be that in the JSON data received, this value be null like this:
{
"id": 2,
"description": "A description",
"containedObject": null
}
But this isn't possible since I'm not in control of the JSON data that is sent to me.
Is there an annotation (like this explained here) that works for the deserialization process and could be helpfull in my situation?
I leave a representation of my classes for more information:
My entity class is as follows:
public class Entity {
private long id;
private String description;
private ContainedObject containedObject;
//Contructor, getters and setters omitted
}
And my contained object class as follows:
public class ContainedObject {
private long contObjId;
private String aString;
//Contructor, getters and setters omitted
}
I would use a JsonDeserializer. Inspect the field in question, determine, if it is emtpy and return null, so your ContainedObject would be null.
Something like this (semi-pseudo):
public class MyDes extends JsonDeserializer<ContainedObject> {
#Override
public String deserialize(JsonParser jsonParser, DeserializationContext context) throws IOException, JsonProcessingException {
//read the JsonNode and determine if it is empty JSON object
//and if so return null
if (node is empty....) {
return null;
}
return node;
}
}
then in your model:
public class Entity {
private long id;
private String description;
#JsonDeserialize(using = MyDes.class)
private ContainedObject containedObject;
//Contructor, getters and setters omitted
}
Hope this helps!
You can implement a custom deserializer as follows:
public class Entity {
private long id;
private String description;
#JsonDeserialize(using = EmptyToNullObject.class)
private ContainedObject containedObject;
//Contructor, getters and setters omitted
}
public class EmptyToNullObject extends JsonDeserializer<ContainedObject> {
public ContainedObject deserialize(JsonParser jp, DeserializationContext ctxt) throws IOException, JsonProcessingException {
JsonNode node = jp.getCodec().readTree(jp);
long contObjId = (Long) ((LongNode) node.get("contObjId")).numberValue();
String aString = node.get("aString").asText();
if(aString.equals("") && contObjId == 0L) {
return null;
} else {
return new ContainedObject(contObjId, aString);
}
}
}
Approach 1 : This is mostly used. #JsonInclude is used to exclude properties with empty/null/default values.Use #JsonInclude(JsonInclude.Include.NON_NULL) or #JsonInclude(JsonInclude.Include.NON_EMPTY) as per your requirement.
#JsonInclude(JsonInclude.Include.NON_NULL)
public class Employee {
private String empId;
private String firstName;
#JsonInclude(JsonInclude.Include.NON_NULL)
private String lastName;
private String address;
private String emailId;
}
More info about the jackson annotations : https://github.com/FasterXML/jackson-annotations/wiki/Jackson-Annotations
Approach 2 : GSON
use GSON (https://code.google.com/p/google-gson/)

What's the best way to add a new Object using the HTTP POST call through Spring?

I'm learning the Spring Framework and I'm struggling with the Rest services with spring, in particular for the POST call that it's supposed to add a new object to the database.
I've seen a lot of different implementations through the web, but I don't know how to pick the best.
Let's take for example a film class:
#Entity
public class Film {
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
private long id;
private String title;
private String description;
//Constructor, Getter and Setter Omitted.
}
Assuming the repository extends the JpaRepository<Film,Long>, this would be the Controller class:
#RestController
public class FilmController {
#Autowired
FilmRepository filmRepository;
//Implementation #1
#PostMapping("/film")
public Film addNew(#RequestBody Map<String,String> body){
String title = body.get("title");
String description = body.get("description");
return filmRepository.save(new Film(title,description));
}
//Implementation #2
#PostMapping("/film")
public Film addNew(String title, String description){
Film film = new Film(title,description);
System.out.println(film.getTitle() + " " + film.getDescription());
return filmRepository.save(film);
}
//Implementation #3
#PostMapping("/film")
public Film addNew(#RequestBody Film newFilm){
return filmRepository.save(newFilm);
}
}
Why some implementations have as parameter a Map<String, String> ? Is that a body mapped to a key/value pair ?
Also bear in mind that I managed to implement correctly just the implementation #2, the first and the third gave me a
415 error:"Unsupported Media Type" org.springframework.web.HttpMediaTypeNotSupportedException: Content type 'multipart/form-data;boundary=--------------------------901298977805450214809889;charset=UTF-8' not supported]
(Despite I followed the official Spring tutorial) on REST services.
I also read something about the creation of DTO classes where I can define attributes without exposing the object to the controller, how can be implemented such solution?
Implementation 3 is the best practice, but you should create a lightweight DTO class (maybe FilmDto) to avoid exposing the internal structure of your entity, please see LocalDTO, Martin Fowler.
You may use ModelMapper to map FilmDto to Film, and make sure there are proper getters and setters in both classes, if the getters and setters have the same names in both classes, then ModelMapper will do the conversion smoothly:
public class FilmDto {
private long id;
private String title;
private String description;
public long getId() {
return id;
}
public void setId(long id) {
this.id = id;
}
public String getTitle() {
return title;
}
public void setTitle(String title) {
this.title = title;
}
public String getDescription() {
return description;
}
public void setDescription(String description) {
this.description = description;
}
}
and you controller:
#RestController
#RequestMapping("/api")
public class FilmController {
private final FilmRepository filmRepository;
private ModelMapper modelMapper = new ModelMapper();
#Autowired
public FilmController(FilmRepository filmRepository) {
this.filmRepository = filmRepository;
}
//Implementation #3
#PostMapping("/film")
public ResponseEntity<FilmDto> addNew(#RequestBody FilmDto filmDto){
Film newFilm = modelMapper.map(filmDto, Film.class);
newFilm = filmRepository.save(newFilm);
filmDto.setId(newFilm.getId());//you may use modelMapper here
return ResponseEntity.ok(filmDto);
}
}
you can test using postman by passing the film as below:
{
"title": "some title",
"description": "some description"
}
and the body should be of type "raw", "JSON".
Why some implementations have as parameter a Map<String, String> ?
some implementations use map<key,value> because they need the properties that map interface provide such as non-duplicate key value or the classes that implement map interface such as TreeMap and LinkedHashMap.
about your implementation of the class FilmController i think its not necessary to use map<String,String> for posting your domain in the data base simply you can have this implementation
#RestController
public class FilmController {
#Autowired
FilmRepository filmRepository;
#PostMapping("/film")
public ResponseEntity addNew(#RequestBody Film film){
return ResponseEntity.ok(filmRepository.save(film));

How can I create a custom setter for setting objects in Jersey/Jackson?

I have an entity called Checkout which has a user and an item. So when a user wants to create a new checkout object, they POST to "/checkout". Now, I was thinking to set the user and item, the user would instead include a username and a serial number, like this for example:
{
"id": "1",
"user": "hassan",
"item": "sdf2ljt234jt09jsd"
}
Then I would just write custom setters in my Checkout class that take Strings rather than Users and Items:
public void setUser(String username) {
this.user = ...
}
But Jersey is never calling my setter. Both the user and the item properties remain null, and I'm not sure why. If this isn't the proper way to set objects with Jersey/Jackson, is there something else I should be trying?
You can use #JsonDeserialize to specify a builder class that can hold the custom logic for going from a String to a User or Item:
#JsonDeserialize(builder = Checkout.Builder.class)
public class Checkout {
private Long id;
private User user;
private Item item;
// getters and setters
public static class Builder {
private Long id;
private String username;
private String serialNumber;
#JsonProperty("id")
public Builder setId(Long id) {
this.id = id;
return this;
}
#JsonProperty("user")
public Builder setUsername(String username) {
this.username = username;
return this;
}
#JsonProperty("item")
public Builder setSerialNumber(String serialNumber) {
this.serialNumber = serialNumber;
return this;
}
public Checkout build() {
Checkout checkout = new Checkout();
checkout.setId(id);
checkout.setUser(/* lookup user by username */);
checkout.setItem(/* lookup item by serialNumber */);
return checkout;
}
}
}
Notice the use of #JsonProperty on each of the setters of the Builder class and how they use the names of the properties in your JSON. That's important to make sure your JSON structure maps properly into the builder fields.

Custom Jackson Deserializer to handle a property of any bean

I have a class called Channel which will have roles property as follows
public class Channel{
private int id;
private String roles;
}
And my JSON from client would be
{
"id":"12345787654323468",
"roles":[
{"name":"admin","permissions":["can publish","can reject"]},
{"name":"moderator","permissions":["can publish","can reject"]}
]
}
But when I convert this JSON to Channel object I am getting following exception
com.google.appengine.repackaged.org.codehaus.jackson.map.JsonMappingException: Can not deserialize instance of java.lang.String out of START_ARRAY token
at [Source: java.io.StringReader#6d25f91; line: 1, column: 253] (through reference chain: com.pokuri.entity.Channel["roles"])
Now I want to deserialize this as a string into property roles of Channel class. Also can I write single custom deserializer to handle property of JSON array in any bean.
A custom Deserializer can do the trick here. :
class CustomDeserializer extends JsonDeserializer<String> {
#Override
public String deserialize(JsonParser jsonParser, DeserializationContext context) throws IOException, JsonProcessingException {
JsonNode node = jsonParser.readValueAsTree();
return node.toString();
}
}
now to use this in your bean, you have to include it on roles field :
class Channel {
private long id;
#JsonDeserialize(using = CustomDeserializer.class)
private String roles;
public long getId() {
return id;
}
public void setId(long id) {
this.id = id;
}
public String getRoles() {
return roles;
}
public void setRoles(String roles) {
this.roles = roles;
}
}
Note : I have taken value of id as long as it was showing error for int, as value is too large in id attribute.
Now ObjectMapper can easily deserialize your JSON to Channel class :
String json = "{\"id\":\"12345787654323468\",\"roles\":[{\"name\":\"admin\",\"permissions\":[\"can publish\",\"can reject\"]},{\"name\":\"moderator\",\"permissions\":[\"can publish\",\"can reject\"]}]}";
ObjectMapper mapper = new ObjectMapper();
Channel channel = mapper.readValue(json, Channel.class);
System.out.println("Roles :"+channel.getRoles());

Jackson library: custom mapping of a Java object in a JSON element

I have two class
public class Person {
private long id;
private String name;
private Gender gender;
// getter and setter omitted
}
and
public class Gender {
private long id;
private String value;
// getter and setter omitted
}
By default the JSON mapping with Jackson library of a Person object is:
{
id: 11,
name: "myname",
gender: {
id: 2,
value: "F"
}
}
I'd like to known how to configure Jackson to obtain:
{
id: 11,
name: "myname",
gender: "F"
}
I don't want mapping all the Gender object but only its value property.
You can use a custom serializer:
public class GenderSerializer extends JsonSerializer<Gender> {
public GenderSerializer() {
}
#Override
public void serialize(Gender gender, JsonGenerator jgen, SerializerProvider provider) throws IOException, JsonProcessingException {
jgen.writeString(gender.getValue());
}
}
And in your Person class:
public class Person {
private long id;
private String name;
#JsonSerialize(using = GenderSerializer.class)
private Gender gender;
}
you might wanna see this for custom mapping OR if you need a short cut then you can change getter/setter of gender like this
public String getGender(String type){
this.getGender().getValue();
}
public void setGender(String value){
Gender gender = new Gender();
gender.setId(2);
gender.setValue(value);
this.gender = gender;
}
further you can also put condition for setting male/female on value= M/F
No need for custom serializer/deserializer if you can modify Gender class. For serialization you can use #JsonValue, for deserialization simple constructor (optionally annotated with #JsonCreator):
public class Gender {
#JsonCreator // optional
public Gender(String desc) {
// handle detection of "M" or "F"
}
#JsonValue
public String asString() { // name doesn't matter
if (...) return "M";
return "F";
}
}
Alternatively you could use a static factory method instead of constructor; if so, it must be annotated with #JsonCreator.
And return type of method annotated with #JsonValue can be anything that Jackson knows how to serialize; here we use String, but Enum, POJO and such are fine as well.

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