How can I proper use flatMap in a hierarchical Map<String, MyData>? - java

I have a Map<String, MyData> and theMyDataobject contains a properties attribute that is also of Map<String, MyData> type.
I need to traverse this model, looking for a specific MyData object and return its key.
I've tried to construct a flatmap like the one below, but it is not working... somehow the result of the flatmap is a Stream<Object> instead of Stream<Entry<String, MyData>>
Could someone point me what I'm doing wrong, please?
public class MyData<S> {
private String name;
private Map<String, MyData> properties;
...
}
MyData target = ...;
String key = getAllData().entrySet().stream()
.flatMap(s -> s.getValue().getProperties().entrySet().stream())
.filter(e-> target == e.getValue())
.findFirst()
.map(o-> o.getKey())
.orElse("not found");

Related

How get a Map<String, List<Object>> from a Stream in Java 8

I have the next class:
public class ExampleClass {
private String title;
private String codeResponse;
private String fileName;
}
I need to generate a map in which the key is the filename, and the value is the list of objects that contain that filename. I did the following:
Map<String, List<ExampleClass>> mapValues = items
.stream()
.collect(Collectors.groupingBy(
item -> item.getFileName(),
Collectors.mapping(item -> item, Collectors.toList())
));
But in this case I am saving in each fileName the total list of objects, including those that do not apply.
All you need is Collectors.groupingBy. The instances will be placed in a list by default.
Map<String, List<ExampleClass>> mapValues = items.stream()
.collect(Collectors.groupingBy(item->item.getFileName()));
You could also use ExampleClass::getFileName in place of the lambda. But that is a matter of personal preference.

How do I convert List to Map where the key is one of the properties and value is the object using Collector [duplicate]

I want to translate a List of objects into a Map using Java 8's streams and lambdas.
This is how I would write it in Java 7 and below.
private Map<String, Choice> nameMap(List<Choice> choices) {
final Map<String, Choice> hashMap = new HashMap<>();
for (final Choice choice : choices) {
hashMap.put(choice.getName(), choice);
}
return hashMap;
}
I can accomplish this easily using Java 8 and Guava but I would like to know how to do this without Guava.
In Guava:
private Map<String, Choice> nameMap(List<Choice> choices) {
return Maps.uniqueIndex(choices, new Function<Choice, String>() {
#Override
public String apply(final Choice input) {
return input.getName();
}
});
}
And Guava with Java 8 lambdas.
private Map<String, Choice> nameMap(List<Choice> choices) {
return Maps.uniqueIndex(choices, Choice::getName);
}
Based on Collectors documentation it's as simple as:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(Choice::getName,
Function.identity()));
If your key is NOT guaranteed to be unique for all elements in the list, you should convert it to a Map<String, List<Choice>> instead of a Map<String, Choice>
Map<String, List<Choice>> result =
choices.stream().collect(Collectors.groupingBy(Choice::getName));
Use getName() as the key and Choice itself as the value of the map:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(Choice::getName, c -> c));
Most of the answers listed, miss a case when the list has duplicate items. In that case there answer will throw IllegalStateException. Refer the below code to handle list duplicates as well:
public Map<String, Choice> convertListToMap(List<Choice> choices) {
return choices.stream()
.collect(Collectors.toMap(Choice::getName, choice -> choice,
(oldValue, newValue) -> newValue));
}
Here's another one in case you don't want to use Collectors.toMap()
Map<String, Choice> result =
choices.stream().collect(HashMap<String, Choice>::new,
(m, c) -> m.put(c.getName(), c),
(m, u) -> {});
One more option in simple way
Map<String,Choice> map = new HashMap<>();
choices.forEach(e->map.put(e.getName(),e));
For example, if you want convert object fields to map:
Example object:
class Item{
private String code;
private String name;
public Item(String code, String name) {
this.code = code;
this.name = name;
}
//getters and setters
}
And operation convert List To Map:
List<Item> list = new ArrayList<>();
list.add(new Item("code1", "name1"));
list.add(new Item("code2", "name2"));
Map<String,String> map = list.stream()
.collect(Collectors.toMap(Item::getCode, Item::getName));
If you don't mind using 3rd party libraries, AOL's cyclops-react lib (disclosure I am a contributor) has extensions for all JDK Collection types, including List and Map.
ListX<Choices> choices;
Map<String, Choice> map = choices.toMap(c-> c.getName(),c->c);
You can create a Stream of the indices using an IntStream and then convert them to a Map :
Map<Integer,Item> map =
IntStream.range(0,items.size())
.boxed()
.collect(Collectors.toMap (i -> i, i -> items.get(i)));
I was trying to do this and found that, using the answers above, when using Functions.identity() for the key to the Map, then I had issues with using a local method like this::localMethodName to actually work because of typing issues.
Functions.identity() actually does something to the typing in this case so the method would only work by returning Object and accepting a param of Object
To solve this, I ended up ditching Functions.identity() and using s->s instead.
So my code, in my case to list all directories inside a directory, and for each one use the name of the directory as the key to the map and then call a method with the directory name and return a collection of items, looks like:
Map<String, Collection<ItemType>> items = Arrays.stream(itemFilesDir.listFiles(File::isDirectory))
.map(File::getName)
.collect(Collectors.toMap(s->s, this::retrieveBrandItems));
I will write how to convert list to map using generics and inversion of control. Just universal method!
Maybe we have list of Integers or list of objects. So the question is the following: what should be key of the map?
create interface
public interface KeyFinder<K, E> {
K getKey(E e);
}
now using inversion of control:
static <K, E> Map<K, E> listToMap(List<E> list, KeyFinder<K, E> finder) {
return list.stream().collect(Collectors.toMap(e -> finder.getKey(e) , e -> e));
}
For example, if we have objects of book , this class is to choose key for the map
public class BookKeyFinder implements KeyFinder<Long, Book> {
#Override
public Long getKey(Book e) {
return e.getPrice()
}
}
I use this syntax
Map<Integer, List<Choice>> choiceMap =
choices.stream().collect(Collectors.groupingBy(choice -> choice.getName()));
It's possible to use streams to do this. To remove the need to explicitly use Collectors, it's possible to import toMap statically (as recommended by Effective Java, third edition).
import static java.util.stream.Collectors.toMap;
private static Map<String, Choice> nameMap(List<Choice> choices) {
return choices.stream().collect(toMap(Choice::getName, it -> it));
}
Another possibility only present in comments yet:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(c -> c.getName(), c -> c)));
Useful if you want to use a parameter of a sub-object as Key:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(c -> c.getUser().getName(), c -> c)));
Map<String, Set<String>> collect = Arrays.asList(Locale.getAvailableLocales()).stream().collect(Collectors
.toMap(l -> l.getDisplayCountry(), l -> Collections.singleton(l.getDisplayLanguage())));
This can be done in 2 ways. Let person be the class we are going to use to demonstrate it.
public class Person {
private String name;
private int age;
public String getAge() {
return age;
}
}
Let persons be the list of Persons to be converted to the map
1.Using Simple foreach and a Lambda Expression on the List
Map<Integer,List<Person>> mapPersons = new HashMap<>();
persons.forEach(p->mapPersons.put(p.getAge(),p));
2.Using Collectors on Stream defined on the given List.
Map<Integer,List<Person>> mapPersons =
persons.stream().collect(Collectors.groupingBy(Person::getAge));
Here is solution by StreamEx
StreamEx.of(choices).toMap(Choice::getName, c -> c);
Map<String,Choice> map=list.stream().collect(Collectors.toMap(Choice::getName, s->s));
Even serves this purpose for me,
Map<String,Choice> map= list1.stream().collect(()-> new HashMap<String,Choice>(),
(r,s) -> r.put(s.getString(),s),(r,s) -> r.putAll(s));
If every new value for the same key name has to be overridden:
public Map < String, Choice > convertListToMap(List < Choice > choices) {
return choices.stream()
.collect(Collectors.toMap(Choice::getName,
Function.identity(),
(oldValue, newValue) - > newValue));
}
If all choices have to be grouped in a list for a name:
public Map < String, Choice > convertListToMap(List < Choice > choices) {
return choices.stream().collect(Collectors.groupingBy(Choice::getName));
}
List<V> choices; // your list
Map<K,V> result = choices.stream().collect(Collectors.toMap(choice::getKey(),choice));
//assuming class "V" has a method to get the key, this method must handle case of duplicates too and provide a unique key.
As an alternative to guava one can use kotlin-stdlib
private Map<String, Choice> nameMap(List<Choice> choices) {
return CollectionsKt.associateBy(choices, Choice::getName);
}
List<Integer> listA = new ArrayList<>();
listA.add(1);
listA.add(5);
listA.add(3);
listA.add(4);
System.out.println(listA.stream().collect(Collectors.toMap(x ->x, x->x)));
String array[] = {"ASDFASDFASDF","AA", "BBB", "CCCC", "DD", "EEDDDAD"};
List<String> list = Arrays.asList(array);
Map<Integer, String> map = list.stream()
.collect(Collectors.toMap(s -> s.length(), s -> s, (x, y) -> {
System.out.println("Dublicate key" + x);
return x;
},()-> new TreeMap<>((s1,s2)->s2.compareTo(s1))));
System.out.println(map);
Dublicate key AA
{12=ASDFASDFASDF, 7=EEDDDAD, 4=CCCC, 3=BBB, 2=AA}

How to convert set to map with a set as the value in java 8?

I have the following class:
class A {
private String id;
private String name;
private String systemid;
}
I'm getting a set of A and want to convert it to a map where the key is the system id, and the value is set of A. (Map<String, Set<A>)
There can be multiple A instances with the same systemid.
Can't seem to figure out how to do it..
got till here but the identity is clearly not right
Map<String, Set<A>> sysUidToAMap = mySet.stream().collect(Collectors.toMap(A::getSystemID, Function.identity()));
can you please assist?
You can use groupingBy instead of toMap:
Map<String, Set<A>> sysUidToAMap =
mySet.stream()
.collect(Collectors.groupingBy(A::getSystemID,
Collectors.toSet()));
my 2ยข: you can do it with Collectors.toMap but it's slightly more verbose:
yourSet
.stream()
.collect(Collectors.toMap(
A::getSystemId,
a -> {
Set<A> set = new HashSet<>();
set.add(a);
return set;
}, (left, right) -> {
left.addAll(right);
return left;
}));
As streams were not specifically requested, here's a way to do it only with the Map API:
Map<String, Set<A>> map = new HashMap<>();
mySet.forEach(a -> map.computeIfAbsent(a.getSystemId(), k -> new HashSet<>()).add(a));

Java 8: efficiently put values from List to the Map [duplicate]

I want to translate a List of objects into a Map using Java 8's streams and lambdas.
This is how I would write it in Java 7 and below.
private Map<String, Choice> nameMap(List<Choice> choices) {
final Map<String, Choice> hashMap = new HashMap<>();
for (final Choice choice : choices) {
hashMap.put(choice.getName(), choice);
}
return hashMap;
}
I can accomplish this easily using Java 8 and Guava but I would like to know how to do this without Guava.
In Guava:
private Map<String, Choice> nameMap(List<Choice> choices) {
return Maps.uniqueIndex(choices, new Function<Choice, String>() {
#Override
public String apply(final Choice input) {
return input.getName();
}
});
}
And Guava with Java 8 lambdas.
private Map<String, Choice> nameMap(List<Choice> choices) {
return Maps.uniqueIndex(choices, Choice::getName);
}
Based on Collectors documentation it's as simple as:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(Choice::getName,
Function.identity()));
If your key is NOT guaranteed to be unique for all elements in the list, you should convert it to a Map<String, List<Choice>> instead of a Map<String, Choice>
Map<String, List<Choice>> result =
choices.stream().collect(Collectors.groupingBy(Choice::getName));
Use getName() as the key and Choice itself as the value of the map:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(Choice::getName, c -> c));
Most of the answers listed, miss a case when the list has duplicate items. In that case there answer will throw IllegalStateException. Refer the below code to handle list duplicates as well:
public Map<String, Choice> convertListToMap(List<Choice> choices) {
return choices.stream()
.collect(Collectors.toMap(Choice::getName, choice -> choice,
(oldValue, newValue) -> newValue));
}
Here's another one in case you don't want to use Collectors.toMap()
Map<String, Choice> result =
choices.stream().collect(HashMap<String, Choice>::new,
(m, c) -> m.put(c.getName(), c),
(m, u) -> {});
One more option in simple way
Map<String,Choice> map = new HashMap<>();
choices.forEach(e->map.put(e.getName(),e));
For example, if you want convert object fields to map:
Example object:
class Item{
private String code;
private String name;
public Item(String code, String name) {
this.code = code;
this.name = name;
}
//getters and setters
}
And operation convert List To Map:
List<Item> list = new ArrayList<>();
list.add(new Item("code1", "name1"));
list.add(new Item("code2", "name2"));
Map<String,String> map = list.stream()
.collect(Collectors.toMap(Item::getCode, Item::getName));
If you don't mind using 3rd party libraries, AOL's cyclops-react lib (disclosure I am a contributor) has extensions for all JDK Collection types, including List and Map.
ListX<Choices> choices;
Map<String, Choice> map = choices.toMap(c-> c.getName(),c->c);
You can create a Stream of the indices using an IntStream and then convert them to a Map :
Map<Integer,Item> map =
IntStream.range(0,items.size())
.boxed()
.collect(Collectors.toMap (i -> i, i -> items.get(i)));
I was trying to do this and found that, using the answers above, when using Functions.identity() for the key to the Map, then I had issues with using a local method like this::localMethodName to actually work because of typing issues.
Functions.identity() actually does something to the typing in this case so the method would only work by returning Object and accepting a param of Object
To solve this, I ended up ditching Functions.identity() and using s->s instead.
So my code, in my case to list all directories inside a directory, and for each one use the name of the directory as the key to the map and then call a method with the directory name and return a collection of items, looks like:
Map<String, Collection<ItemType>> items = Arrays.stream(itemFilesDir.listFiles(File::isDirectory))
.map(File::getName)
.collect(Collectors.toMap(s->s, this::retrieveBrandItems));
I will write how to convert list to map using generics and inversion of control. Just universal method!
Maybe we have list of Integers or list of objects. So the question is the following: what should be key of the map?
create interface
public interface KeyFinder<K, E> {
K getKey(E e);
}
now using inversion of control:
static <K, E> Map<K, E> listToMap(List<E> list, KeyFinder<K, E> finder) {
return list.stream().collect(Collectors.toMap(e -> finder.getKey(e) , e -> e));
}
For example, if we have objects of book , this class is to choose key for the map
public class BookKeyFinder implements KeyFinder<Long, Book> {
#Override
public Long getKey(Book e) {
return e.getPrice()
}
}
I use this syntax
Map<Integer, List<Choice>> choiceMap =
choices.stream().collect(Collectors.groupingBy(choice -> choice.getName()));
It's possible to use streams to do this. To remove the need to explicitly use Collectors, it's possible to import toMap statically (as recommended by Effective Java, third edition).
import static java.util.stream.Collectors.toMap;
private static Map<String, Choice> nameMap(List<Choice> choices) {
return choices.stream().collect(toMap(Choice::getName, it -> it));
}
Another possibility only present in comments yet:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(c -> c.getName(), c -> c)));
Useful if you want to use a parameter of a sub-object as Key:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(c -> c.getUser().getName(), c -> c)));
Map<String, Set<String>> collect = Arrays.asList(Locale.getAvailableLocales()).stream().collect(Collectors
.toMap(l -> l.getDisplayCountry(), l -> Collections.singleton(l.getDisplayLanguage())));
This can be done in 2 ways. Let person be the class we are going to use to demonstrate it.
public class Person {
private String name;
private int age;
public String getAge() {
return age;
}
}
Let persons be the list of Persons to be converted to the map
1.Using Simple foreach and a Lambda Expression on the List
Map<Integer,List<Person>> mapPersons = new HashMap<>();
persons.forEach(p->mapPersons.put(p.getAge(),p));
2.Using Collectors on Stream defined on the given List.
Map<Integer,List<Person>> mapPersons =
persons.stream().collect(Collectors.groupingBy(Person::getAge));
Here is solution by StreamEx
StreamEx.of(choices).toMap(Choice::getName, c -> c);
Map<String,Choice> map=list.stream().collect(Collectors.toMap(Choice::getName, s->s));
Even serves this purpose for me,
Map<String,Choice> map= list1.stream().collect(()-> new HashMap<String,Choice>(),
(r,s) -> r.put(s.getString(),s),(r,s) -> r.putAll(s));
If every new value for the same key name has to be overridden:
public Map < String, Choice > convertListToMap(List < Choice > choices) {
return choices.stream()
.collect(Collectors.toMap(Choice::getName,
Function.identity(),
(oldValue, newValue) - > newValue));
}
If all choices have to be grouped in a list for a name:
public Map < String, Choice > convertListToMap(List < Choice > choices) {
return choices.stream().collect(Collectors.groupingBy(Choice::getName));
}
List<V> choices; // your list
Map<K,V> result = choices.stream().collect(Collectors.toMap(choice::getKey(),choice));
//assuming class "V" has a method to get the key, this method must handle case of duplicates too and provide a unique key.
As an alternative to guava one can use kotlin-stdlib
private Map<String, Choice> nameMap(List<Choice> choices) {
return CollectionsKt.associateBy(choices, Choice::getName);
}
List<Integer> listA = new ArrayList<>();
listA.add(1);
listA.add(5);
listA.add(3);
listA.add(4);
System.out.println(listA.stream().collect(Collectors.toMap(x ->x, x->x)));
String array[] = {"ASDFASDFASDF","AA", "BBB", "CCCC", "DD", "EEDDDAD"};
List<String> list = Arrays.asList(array);
Map<Integer, String> map = list.stream()
.collect(Collectors.toMap(s -> s.length(), s -> s, (x, y) -> {
System.out.println("Dublicate key" + x);
return x;
},()-> new TreeMap<>((s1,s2)->s2.compareTo(s1))));
System.out.println(map);
Dublicate key AA
{12=ASDFASDFASDF, 7=EEDDDAD, 4=CCCC, 3=BBB, 2=AA}

Java 8 List<V> into Map<K, V>

I want to translate a List of objects into a Map using Java 8's streams and lambdas.
This is how I would write it in Java 7 and below.
private Map<String, Choice> nameMap(List<Choice> choices) {
final Map<String, Choice> hashMap = new HashMap<>();
for (final Choice choice : choices) {
hashMap.put(choice.getName(), choice);
}
return hashMap;
}
I can accomplish this easily using Java 8 and Guava but I would like to know how to do this without Guava.
In Guava:
private Map<String, Choice> nameMap(List<Choice> choices) {
return Maps.uniqueIndex(choices, new Function<Choice, String>() {
#Override
public String apply(final Choice input) {
return input.getName();
}
});
}
And Guava with Java 8 lambdas.
private Map<String, Choice> nameMap(List<Choice> choices) {
return Maps.uniqueIndex(choices, Choice::getName);
}
Based on Collectors documentation it's as simple as:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(Choice::getName,
Function.identity()));
If your key is NOT guaranteed to be unique for all elements in the list, you should convert it to a Map<String, List<Choice>> instead of a Map<String, Choice>
Map<String, List<Choice>> result =
choices.stream().collect(Collectors.groupingBy(Choice::getName));
Use getName() as the key and Choice itself as the value of the map:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(Choice::getName, c -> c));
Most of the answers listed, miss a case when the list has duplicate items. In that case there answer will throw IllegalStateException. Refer the below code to handle list duplicates as well:
public Map<String, Choice> convertListToMap(List<Choice> choices) {
return choices.stream()
.collect(Collectors.toMap(Choice::getName, choice -> choice,
(oldValue, newValue) -> newValue));
}
Here's another one in case you don't want to use Collectors.toMap()
Map<String, Choice> result =
choices.stream().collect(HashMap<String, Choice>::new,
(m, c) -> m.put(c.getName(), c),
(m, u) -> {});
One more option in simple way
Map<String,Choice> map = new HashMap<>();
choices.forEach(e->map.put(e.getName(),e));
For example, if you want convert object fields to map:
Example object:
class Item{
private String code;
private String name;
public Item(String code, String name) {
this.code = code;
this.name = name;
}
//getters and setters
}
And operation convert List To Map:
List<Item> list = new ArrayList<>();
list.add(new Item("code1", "name1"));
list.add(new Item("code2", "name2"));
Map<String,String> map = list.stream()
.collect(Collectors.toMap(Item::getCode, Item::getName));
If you don't mind using 3rd party libraries, AOL's cyclops-react lib (disclosure I am a contributor) has extensions for all JDK Collection types, including List and Map.
ListX<Choices> choices;
Map<String, Choice> map = choices.toMap(c-> c.getName(),c->c);
You can create a Stream of the indices using an IntStream and then convert them to a Map :
Map<Integer,Item> map =
IntStream.range(0,items.size())
.boxed()
.collect(Collectors.toMap (i -> i, i -> items.get(i)));
I was trying to do this and found that, using the answers above, when using Functions.identity() for the key to the Map, then I had issues with using a local method like this::localMethodName to actually work because of typing issues.
Functions.identity() actually does something to the typing in this case so the method would only work by returning Object and accepting a param of Object
To solve this, I ended up ditching Functions.identity() and using s->s instead.
So my code, in my case to list all directories inside a directory, and for each one use the name of the directory as the key to the map and then call a method with the directory name and return a collection of items, looks like:
Map<String, Collection<ItemType>> items = Arrays.stream(itemFilesDir.listFiles(File::isDirectory))
.map(File::getName)
.collect(Collectors.toMap(s->s, this::retrieveBrandItems));
I will write how to convert list to map using generics and inversion of control. Just universal method!
Maybe we have list of Integers or list of objects. So the question is the following: what should be key of the map?
create interface
public interface KeyFinder<K, E> {
K getKey(E e);
}
now using inversion of control:
static <K, E> Map<K, E> listToMap(List<E> list, KeyFinder<K, E> finder) {
return list.stream().collect(Collectors.toMap(e -> finder.getKey(e) , e -> e));
}
For example, if we have objects of book , this class is to choose key for the map
public class BookKeyFinder implements KeyFinder<Long, Book> {
#Override
public Long getKey(Book e) {
return e.getPrice()
}
}
I use this syntax
Map<Integer, List<Choice>> choiceMap =
choices.stream().collect(Collectors.groupingBy(choice -> choice.getName()));
It's possible to use streams to do this. To remove the need to explicitly use Collectors, it's possible to import toMap statically (as recommended by Effective Java, third edition).
import static java.util.stream.Collectors.toMap;
private static Map<String, Choice> nameMap(List<Choice> choices) {
return choices.stream().collect(toMap(Choice::getName, it -> it));
}
Another possibility only present in comments yet:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(c -> c.getName(), c -> c)));
Useful if you want to use a parameter of a sub-object as Key:
Map<String, Choice> result =
choices.stream().collect(Collectors.toMap(c -> c.getUser().getName(), c -> c)));
Map<String, Set<String>> collect = Arrays.asList(Locale.getAvailableLocales()).stream().collect(Collectors
.toMap(l -> l.getDisplayCountry(), l -> Collections.singleton(l.getDisplayLanguage())));
This can be done in 2 ways. Let person be the class we are going to use to demonstrate it.
public class Person {
private String name;
private int age;
public String getAge() {
return age;
}
}
Let persons be the list of Persons to be converted to the map
1.Using Simple foreach and a Lambda Expression on the List
Map<Integer,List<Person>> mapPersons = new HashMap<>();
persons.forEach(p->mapPersons.put(p.getAge(),p));
2.Using Collectors on Stream defined on the given List.
Map<Integer,List<Person>> mapPersons =
persons.stream().collect(Collectors.groupingBy(Person::getAge));
Here is solution by StreamEx
StreamEx.of(choices).toMap(Choice::getName, c -> c);
Map<String,Choice> map=list.stream().collect(Collectors.toMap(Choice::getName, s->s));
Even serves this purpose for me,
Map<String,Choice> map= list1.stream().collect(()-> new HashMap<String,Choice>(),
(r,s) -> r.put(s.getString(),s),(r,s) -> r.putAll(s));
If every new value for the same key name has to be overridden:
public Map < String, Choice > convertListToMap(List < Choice > choices) {
return choices.stream()
.collect(Collectors.toMap(Choice::getName,
Function.identity(),
(oldValue, newValue) - > newValue));
}
If all choices have to be grouped in a list for a name:
public Map < String, Choice > convertListToMap(List < Choice > choices) {
return choices.stream().collect(Collectors.groupingBy(Choice::getName));
}
List<V> choices; // your list
Map<K,V> result = choices.stream().collect(Collectors.toMap(choice::getKey(),choice));
//assuming class "V" has a method to get the key, this method must handle case of duplicates too and provide a unique key.
As an alternative to guava one can use kotlin-stdlib
private Map<String, Choice> nameMap(List<Choice> choices) {
return CollectionsKt.associateBy(choices, Choice::getName);
}
List<Integer> listA = new ArrayList<>();
listA.add(1);
listA.add(5);
listA.add(3);
listA.add(4);
System.out.println(listA.stream().collect(Collectors.toMap(x ->x, x->x)));
String array[] = {"ASDFASDFASDF","AA", "BBB", "CCCC", "DD", "EEDDDAD"};
List<String> list = Arrays.asList(array);
Map<Integer, String> map = list.stream()
.collect(Collectors.toMap(s -> s.length(), s -> s, (x, y) -> {
System.out.println("Dublicate key" + x);
return x;
},()-> new TreeMap<>((s1,s2)->s2.compareTo(s1))));
System.out.println(map);
Dublicate key AA
{12=ASDFASDFASDF, 7=EEDDDAD, 4=CCCC, 3=BBB, 2=AA}

Categories

Resources