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Beginners Java Question (int, float)
(4 answers)
Division of integers in Java [duplicate]
(7 answers)
Closed 2 years ago.
If I divide a double type variable, the Decimal part becomes zero.
a=13122/10;
System.out.println (a);
Prints
1312.0
As you can see, the Decimal part became zero when I divided it.
But I need the value
1312.2
Your problem is that while you may have stored "a" as a double, you are really dividing two "ints" and saving that. When you divide 2 ints, the number automatically gets rounded down. So, it's rounded down to 1312.0.
What you need is this,
a = (double)13122/10;
or this:
a = 13122.0/10;
You are dividing integers. You can cast the division and then you are ok
double a = (double) 13122/10;
System.out.println (a);
Related
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How to round a number to n decimal places in Java
(39 answers)
Closed 3 years ago.
I want to take a float that can be entered by the user to any acceptable number of decimal places and format it so that it is only two decimal places. I am able to do this by converting it to a String but I want to keep it as a float and was wondering if there was an easier way to do this than changing from float to string and then back to a float?
Here's a way to do it:
https://stackoverflow.com/a/153785/4119650
It's a little more complicated than the String conversion method, but it gives you greater control over the truncation.
This question already has answers here:
Integer division: How do you produce a double?
(11 answers)
Java integer-double division confusion [duplicate]
(5 answers)
Closed 4 years ago.
I think 5 is an int. But there are no variables. I don't know why the output is a double. I tried in Netbeans already.
Multiplication and division are done left to right (and regardless, you put parentheses around the first operation), and if you divide any primitive umber by a double, you will get a double out of it.
5/2.0 will clearly be evaluated first.
So, even though ‘5’ is an int, if you do 5/2.0, you’ll get a double (namely, 2.5). Now, at this point, your code is already working with a double.
When you multiply 2.5 by 2, you then output 5.0, since 2.5 is a double.
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is there anyway to convert from Double to BigInteger?
(3 answers)
Closed 5 years ago.
How do you convert a double to a BigInteger, as accurately as possible? BigInteger doesn't have a valueOf(double) method. It does have a valueOf(long) method, but converting via long, would destroy any value outside the 2^64 range, and in particular I'm trying to get large numbers like 1e100 to convert to their corresponding integer values to the sixteen or so significant figures allowed by floating point precision.
You can convert the double into a BigDecimal and then into a BigInteger:
BigInteger k = BigDecimal.valueOf(doublevalue).toBigInteger();
You could use BigDecimal.valueOf(double) and then call toBigIntegerExact() on that. Like,
BigInteger bi = BigDecimal.valueOf(Math.PI).toBigIntegerExact();
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How many significant digits do floats and doubles have in java?
(6 answers)
Closed 7 years ago.
I have a problem when it comes to calculating pi with more than 15 decimal places(i used double).
My result looks quite good except my variable is limited to 15 decimal places:
3.140592653839794
Anybody could tell me what i have to do if i want more decimal places?
Thanks and Greeting!
Use java.math.BigDecimal instead of double for arbitrary (finite) precision.
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Simple division in Java - is this a bug or a feature?
(5 answers)
Closed 7 years ago.
Found below output strange. Is it really?
double rate = 11/12; // outputs 0.0
double rate = 11.00/12; // outputs 0.916666667;
Why so much difference?
In the 1st case first division is done so an int divided by an int gives a integer i.e, 11/12=0 Then this integer is converted to double .ie, 0.0. In the 2nd case a double(11.00) is divided by a integer(12).The integer 12 is then automatically type casted to double as division should occur with similar types. This division gives a double value which is exact in reality(0.916666667)
See this link https://docs.oracle.com/javase/specs/jls/se7/html/jls-5.html