How can I get actual query from MongoCollection? - java

I using a MongoCollection as following code :
MongoDatabase conn = getMongoConnection(DbName);
MongoCollection collection = conn.getConnection(CollectionName);
List<BasicDBObject> query = new ArrayList();
if (searchKey.containsKey("filter1")) {
String filter1= (String) searchKey.get("filter1");
query.add(new BasicDBObject("filter1", filter1));
}
if (searchKey.containsKey("filter2")) {
String filter2= (String) searchKey.get("filter2");
query.add(new BasicDBObject("filter2", filter2));
}
int rowAmount = (int) collection.count(new BasicDBObject("$and", query));
rowAmount gets the correct amount of data, but I want to know an actual query when it got the result. Any ideas how?

You can see actual queries sent to the server via command monitoring.

Related

How to distinct query in MongoDB with projection and filters?

I have list of attributes in mongo and I am querying some nested field. Here is my code,
public List<Brand> searchBrands(Request request) {
final MongoCollection<Document> collection = mongoDatabase.getCollection("shop");
final Document query = new Document();
final Document projection = new Document();
final List<Brand> brandList = new ArrayList<>();
query.append("_id", request.getId());
query.append("isActive", true);
if (request.Year() != null) {
query.append("attributes.name", "myYear");
query.append("attributes.value", request.getYear());
}
projection.append("brand.code", 1.0);
projection.append("brand.description", 1.0);
projection.append("_id", 0.0);
Block<Document> processBlock = document -> brandList.
add(Brand.builder().code(document.get("brand",Document.class).getString("code"))
.description(document.get("brand",Document.class).getString("description"))
.build());
collection.find(query).projection(projection).forEach(processBlock);
return brandList;}
Above code return results correctly, 72 item with same brand.code. But I want to fetch distinct according to brand.code How can I do that?
I'm not sure which mongodb client library you're using to create queries for mongodb;
I'm sharing the query that you can run in mongodb console to get the results you want. I hope you know how to create this query using your mongodb client library
db.shop.distinct('brand.code', myQuery)
//Replace myQuery with your query e.g. {isActive: true}

Convert data strings into Date format using ISODate function during the insertion mongo query to java code

db.collection.find().forEach(function(element){
element.BOOKING_CREATED_DATE = ISODate(element.BOOKING_CREATED_DATE);
db.collection.save(element);
})
Please help to convert this query to DBobject type to run in spring boot
Finally found the answer
MongoClient mongo = new MongoClient();
DB db = mongo.getDB("datarepo");
DBCollection collection = db.getCollection("rawdata");
db.eval("db.rawdata.find( { BOOKING_CREATED_DATE : { $type : 2 } } ).forEach(function(element){" +
"element.BOOKING_CREATED_DATE = ISODate(element.BOOKING_CREATED_DATE);" +
"db.rawdata.save(element);})")

Get field of json from array of jsons

I have the following json document. I want to retrieve only all the names. Given a movie name I need to return all the user names.
I am using Java, if you can also assist me in Java it will be awesome. How can I do this?
You can use something like if you're using Mongo 3.x driver.
MongoClient mongoClient = new MongoClient();
MongoDatabase db = mongoClient.getDatabase("test");
MongoCollection<Document> movieToUsers = db.getCollection("movieToUsers");
Bson filter = Filters.eq("movieName", "Green Mile");
List<String> names = movieToUsers.distinct("user.name", filter, String.class).into(new ArrayList<>());
You org.json library
sample
//Json object
JSONObject obj = new JSONObject(" .... ");
String id = obj.getString("_id");
String movieName = obj.getString("movieName");
//Json array
JSONArray users = obj.getJSONArray("user");
for (int i = 0; i < arr.length(); i++)
{
String name = user.getJSONObject(i).getString("name");
String name = user.getJSONObject(i).getString("date");
}
You can use distinct() function with a query as follows:
mongo shell:
var results = db.movieToUsers.distinct("user.name", { "movieName": "Green Mile" });
printjson(results);
In Java, this is implemented by the distinct() method, for example
// Get a new connection to the db assuming that it is running
MongoClient m1 = new MongoClient();
// use test as a database or use your own database
DB db = m1.getDB("test");
// fetch the collection object
DBCollection coll = db.getCollection("movieToUsers");
// call distinct method with the query and store results in variable results
List results = coll.distinct("speed", new BasicDBObject("movieName", "Green Mile"));
// iterate through the results list and print the names
for(int i=0;i<results.size();i++){
System.out.println(results.get(i));
}

Hibernate : ScrollableResults to list

I am trying to do fetch the data from database using ScrollableResults. Part of my code is below :
List list = null;
ScrollableResults items = null;
String sql = " from " + topBO.getClass().getName(); // topBO is my parent class so i pass the any of my child class name .
StringBuffer sqlQuery = new StringBuffer(sql);
Query query = sessionFactory.getCurrentSession().createQuery(sqlQuery.toString());
items = query.scroll();
int i = 0;
TopBO topBO;
while(items.next())
{
topBO= (TopBO) items.get()[i];
list.add(TopBO2); // got the exception at this line.
i++;
topBO= null;
}
items.close();
If i run the above code i am getting runtime error like java.lang.NullPointerException
You are trying to add the value in list which is not initialize.
It may helps you :
List list = new ArrayList();
replace with
List list = null;
I think topBO= (TopBO) items.get()[i]; is causing the problem.
I would suggest that you use result set transformer of query something like this
Query query = sessionFactory.getCurrentSession().createQuery(sqlQuery.toString());
list=query.setResultTransformer(Transformers.aliasToBean(YourClassName.class)).list();

Upgrading mongo search from runCommand to find using Java driver

I am using a Java driver to run some mongo text searches.
An example of my previous code is (where values is a String passed in):
DBCollection coll = db.getCollection("testCollection");
//create the basic object
DBObject searchCmd = new BasicDBObject();
//create the search cmd
searchCmd.put("text", "testCollection"); // the name of the collection (string)
// define the search word
searchCmd.put("search", value); // the term to search for (string)
// define the return values
searchCmd.put("project", new BasicDBObject("score", 1).append("name", 1).append("path", 0).append("_id", 0));
// get the results
BasicDBObject commandResult = db.command(searchCmd);
// Just out the results key
BasicDBList results = (BasicDBList) commandResult.get("results");
then I loop over the "results" and I get for each it score by
// Get the number ii
BasicDBObject element = (BasicDBObject) results.get(ii);
// Now get the score
double score = (double) element.get("score");
I want to upgrade to use find since that seems the way 2.6 and later prefers it. So far I have:
DBCollection coll = db.getCollection("testCollection");
BasicDBObject query = new BasicDBObject();
query.append("$text", new BasicDBObject("$search", value));
DBCursor cursor = coll.find(query);
However, I am not sure how to get the score.
I tried doing something like:
query.append("score", new BasicDBObject("$meta", "textScore"));
But this does not work. I would like to be able to get the name and the score so that I can then insert them into a new collection that will also hold the score.
I can get the name easily by:
while (cursor.hasNext())
{
DBObject next = cursor.next();
String name = next.get("name").toString();
}
But how do I get the score?
I found this interesting page: http://api.mongodb.org/java/current/
it appears that find can take a second DBObject which has the fields.
I created a new object:
BasicDBObject fields = new BasicDBObject();
fields.append("score", new BasicDBObject("$meta", "textScore"));
and I am calling find using:
DBCursor cursor = coll.find(query, fields);
and now I can get the score the same way I can get the name.

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