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Replacing multiple substrings from a string in Java/Android [duplicate]

This question already has answers here:
Java Replacing multiple different substring in a string at once (or in the most efficient way)
(11 answers)
Closed 6 years ago.
Example:
String originalString = "This is just a string folks";
I want to remove(or replace them with "") : 1. "This is" , 2. "folks"
Desired output :
finalString = "just a string";
For a sole substring it's easy, we can just use replace/replaceAll.
I also know it works for various numeric values replace("[0-9]","")
But can that be done for characters?

You can create a function like below:
String replaceMultiple (String baseString, String ... replaceParts) {
for (String s : replaceParts) {
baseString = baseString.replaceAll(s, "");
}
return baseString;
}
And call it like:
String finalString = replaceMultiple("This is just a string folks", "This is", "folks");
You can pass multiple strings that are to be replaced after the first parameter.

It works like this:
String originalString = "This is just a string folks";
originalString = originalString.replace("This is", "");
originalString = originalString.replace("folks", "");
//originalString is now finalString

How to escape backslash in Java [duplicate]

This question already has an answer here:
regex: How to escape backslashes and special characters?
(1 answer)
Closed 8 years ago.
I was trying to escape a Json string as an input via Scanner and print to console,
i was not able to escape " \ " by replacing it with " \\ ",
I'm getting PatternSyntaxException
Here is my code
Scanner s = new Scanner(System.in);
String str = s.next();
String s3 = "";
if (str.contains("\\")) {
s3 = str.replaceAll("\\", "\\\\");
System.out.println(s3);
}
Here is my input to scanner
{"name":"nokia"}\
Help me please !

If you are using regex you have to use 4 backslashes \\\\ to parse the backslash as a literal.
So use s3 = str.replaceAll("\\\\", someOtherString);

Splitting of String delimited by '[' and ']' [duplicate]

This question already has answers here:
java regular expression to extract content within square brackets
(3 answers)
How do I split a string in Java?
(39 answers)
Closed 8 years ago.
I have some sampel data written on a file. The data are in the following format -
[Peter Jackson] [UK] [United Kingdom] [London]....
I have to extract the information delimited by '[' and ']'. So that I found -
Peter Jackson
UK
United Kingdom
London
...
...
I am not so well known with string splitting. I only know how to split string when they are only separated by a single character (eg - string1-string2-string3-....).

You should use regex for this.
Pattern p = Pattern.compile("\\[(.*?)\\]");
Matcher results = p.matcher("[Peter Jackson] [UK] [United Kingdom] [London]....");
while (results.find()) {
System.out.println(results.group(1));
}

You can use this regex:
\\[(.+?)\\]
And the captured group will have your content.
Sorry for not adding the code. I don't know java

Is each item separated by spaces? if so, you could split by "\] \[" then replace all the left over brackets:
String vals = "[Peter Jackson] [UK] [United Kingdom] [London]";
String[] list = vals.split("\\] \\[");
for(String str : list){
str = str.replaceAll("\\[", "").replaceAll("\\]", "");
System.out.println(str);
}
Or if you want to avoid a loop you could use a substring to remove the beginning and ending brackets then just separate by "\\] \\[" :
String vals = " [Peter Jackson] [UK] [United Kingdom] [London] ";
vals = vals.trim(); //removes beginning whitspace
vals = vals.substring(1,vals.length()-1); // removes beginning and ending bracket
String[] list = vals.split("\\] \\[");

Try to replace
String str = "[Peter Jackson] [UK] [United Kingdom] [London]";
str = str.replace("[", "");
str = str.replace("]", "");
And then you can try to split it.

Splitting on "] [" should sort you, as in:
\] \[
Debuggex Demo
After this, just replace the '[' and the ']' and join using newline.

Storing in String [duplicate]

This question already has answers here:
Closed 11 years ago.
Possible Duplicate:
What's the most elegant way to concatenate a list of values with delimiter in Java?
I have 3 different words listed in property file in 3 different lines.
QWERT
POLICE
MATTER
I want to read that property file and store those 3 words in String, not in aarylist separated by whitespace. The output should look like this
String str = { QWERT POLICE MATTER}
Now I used the follwoing code and getting the output without white space in between the words:
String str = {QWERTPOLICEMATTER}. What should I do to the code to get the string result with words separated by whitespace.
FileInputStream in = new FileInputStream("abc.properties");
pro.load(in);
Enumeration em = pro.keys();
StringBuffer stringBuffer = new StringBuffer();
while (em.hasMoreElements()){
String str = (String)em.nextElement();
search = (stringBuffer.append(pro.get(str)).toString());

Try:
search = (stringBuffer.append(" ").append(pro.get(str)).toString());

Just append a blank space in your loop. See the extra append below:
while (em.hasMoreElements()){
String str = (String)em.nextElement();
search = (stringBuffer.append(pro.get(str)).toString());
if(em.hasNext()){
stringBuffer.append(" ")
}
}

Java how to replace backslash? [duplicate]

This question already has answers here:
String replace a Backslash
(8 answers)
Closed 6 years ago.
In java, I have a file path, like 'C:\A\B\C', I want it changed to ''C:/A/B/C'. how to replace the backslashes?

String text = "C:\\A\\B\\C";
String newString = text.replace("\\", "/");
System.out.println(newString);

Since you asked for a regular expression, you'll have to escape the '\' character several times:
String path = "c:\\A\\B\\C";
System.out.println(path.replaceAll("\\\\", "/"));

You can do this using the String.replace method:
public static void main(String[] args) {
String foo = "C:\\foo\\bar";
String newfoo = foo.replace("\\", "/");
System.out.println(newfoo);
}

String oldPath = "C:\\A\\B\\C";
String newPath = oldPath.replace('\\', '/');

To replace all occurrences of a given character :
String result = candidate.replace( '\\', '/' );
Regards,
Cyril