JDBI3 Returning a Parameterized Class - java

I have an abstract EntryPoint class that looks like this:
public abstract class EntryPoint<T extends Tag> implements Serializable {
public EntryPoint(){}
protected ArrayList<T> tiedTags;
public abstract ArrayList<T> getTiedTags();
public abstract void setTiedTags(List<T> tiedTags);
}
I then have subclasses of this EntryPoint class that each accept only one kind of Tag. For instance an SNMPEntryPoint only stores SNMPTags. The subclasses provide implementations of the abstract methods:
public class SNMPEntryPoint extends EntryPoint<SNMPTag> implements Serializable {
//Default Constructor for Serialization
public SNMPEntryPoint(){}
#Override
public ArrayList<SNMPTag> getTiedTags(){ return tiedTags; }
//etc
}
Is there a means to create a JDBI query that returns a List of parameterized classes? At the moment, this is what I'm doing:
public List<SNMPEntryPoint> getSNMPEntryPoints(){
try(Handle handle = daoFactory.getDataSourceController().open()) {
return handle.createQuery("SELECT * FROM dbo.EntryPoints WHERE Active = 1 AND SiteID = :sID AND Protocol = 'SNMP'")
.mapToBean(SNMPEntryPoint.class)
.list();
}
catch(Exception e){
if(sysconfig.getVerbose()){ e.printStackTrace(); }
}
return null;
}
But this feels like a raw use of the class. So I guess my question is, if I use this code to generate SNMPEntryPoints and then call getTiedTags or setTiedTags on those EntryPoints, will that work? Am I breaking any coding conventions by creating my SNMPEntryPoint objects in this way?

Just wanted to close this out. My classes weren't actually parameterized. As you can see above they extend the parameterized abstract class however SNMPEntryPoint doesn't actually take any parameters, so there's no need to do anything differently from what I'm doing above.
HOWEVER, if you do need to return a parameterized generic from JDBI you can do so using the details found here.

Related

Java generic : Restricting a class to specific implementations.

I have the following class hierarchy:
public abstract class Config<T> implements Proxy<T> {
public abstract T parse();
public T get() {....}
}
public class IntegerConfig<Integer> extends Config<Integer> {
public Integer parse() {...}
}
public class LongConfig<Long> extends Config<Long> {
public Long parse() {...}
}
public class IntegerListConfig<List<Integer>> extends Config<List<Integer>> {
public List<Integer> parse() {....}
}
And so on...
I'd like to introduce a new class:
public class ConfigMutation<T> implements Proxy<T> {
public ConfigMutation(....) {
//// create a concrete implementation of Config<T> according to actual parameterized type
}
}
Essentially, I'd like to avoid repeating the entire class hierarchy of Config, and support in ConfigMutation all types that have parameterized implementations in Config class hierarchy.
Couldn't find a way to do it. (Class<T>)((ParameterizedType)getClass().getGenericInterfaces()[0]).getActualTypeArguments()[0] obviously returns T, and not the actual type.
Also, once this problem is solved, I'd be happy if someone could suggest some factory pattern with generic types, so when I'm instantiating a Config derived class inside ConfigMutation, I wouldn't have to do it with a huge if...else block on actual type.
Thanks,
Lior
Change your ConfigMutation class to :
public class ConfigMutation<U,T extends Config<U>> implements Proxy<U> {
public ConfigMutation() {
}
}
You can then use ConfigMutation as :
ConfigMutation<Integer,IntegerConfig> mutation;
You won't be able to do something as follows which is what you want :
ConfigMutation<String,IntegerConfig> mutation;
That said, there is a change you need to make to your concrete Config implementers as well. For example, change IntegerConfig to :
public class IntegerConfig extends Config<Integer> {
public Integer parse() {...}
}
The Integer in IntegerConfig<Integer> will be considered as a type parameter and not the Integer class which is not what you want. (An IDE should give you a warning for this; The type parameter Integer is hiding the type Integer)

Generics, Interface puzzle, what is the advantage of declaring interface like this?

In my project I see the interface like this. All the model extend the interface. I am wondering what is the use ?
public interface IModel {
<T> T modelTo(Class<T> clazz);
}
public interface IPerson extends IModel {
public String getFirstName();
public void setFirstName(String firstName);
public String getMiddleName();
public void setMiddleName(String middleName);
}
Then in some places in the code I see like
#Override
public void modelJoin(IModel parent, IModel sample) {
//Some code
IPerson sample= sample.modelTo(IPerson.class);
IPerson person = parent.modelTo(IPerson.class);
//Some code
}
Can you explain me the insight of it ?
It looks like the use of the Adapter pattern. The idea is to create a "view" of a class given another class, or adapt one type of class to act as another.
A simple real world example can be that of electrical sockets. In different countries different types of sockets are used. So you use adapters to plug in your phone into an electrical socket it normally doesn't "recognize".
This can of course be modelled using object oriented programming and the adapter pattern as well. Using your IModel interface but naming it IAdaptable it could be used like this.
public interface IAdaptable {
<T> T adaptAs(Class<T> clazz);
}
public interface IChargeAmerican { void chargePhoneInAmerica(); }
public interface IChargeEurope { void chargePhoneInEurope(); }
public class EuropeanSocket implements IAdaptable, IChargeEurope {
public <T> T adaptAs(Class<T> clazz) {
if (clazz.equals(IChargeAmerican.class)) {
return new EuropeanSocketToAmericanSocketAdapter(this);
}
throw new RuntimeException("unknown");
}
public void chargePhoneInEurope() {
;
}
}
public class AmericanSocket implements IChargeAmerican {
public void chargePhoneInAmerica() {
;
}
}
public class EuropeanSocketToAmericanSocketAdapter implements IChargeAmerican {
private EuropeanSocket socket;
public EuropeanSocketToAmericanSocketAdapter(EuropeanSocket socket) {
this.socket = socket;
}
public void chargePhoneInAmerica() {
socket.chargePhoneInEurope();
}
}
And to use it one would simply adapt the european socket to an american one, sort of like plugging in an adapter in between the two.
public void foo() {
EuropeanSocket europe = new EuropeanSocket();
IChargeAmerican murica = europe.adaptAs(IChargeAmerican.class);
murica.chargePhoneInAmerica();
}
This example shows how the adaptAs method creates a link between the two interfaces IChargeAmerican and IChargeEurope. Even though they don't have anything in common the adapter can act as they do.
Now, the EuropeanSocket implements the IAdaptable interface in order to "convert" itself to another known socket. Usually though the class should not be responsible for this. As the example at wikipedia shows, a factory or provider is better suited for this.
I think that you ask why the method signature
<T> T modelTo(Class<T> clazz);
is used.
The parameter clazz is used to have the type information inside the method implemented. You can then access the type information very easy.
You can then create an object and return it from the implemented method that has the given class.
The method signature looks a bit clumsy but is helpful as the generic information is missing after compilation (type erasure) and the parameters give you the possibility to access the type information (and thereforethe expected return type).
I can imagine it may have been made that way to allow type casting by passing a Class object as a parameter of other methods calling the modelTo(Class clazz) method, or in other words : having other methods casting IModel objects to any class without even knowing which class they will cast it into (nothing even prevents from passing a Class instance to this method which isn't even a subtype of IModel...)
It would be interesting to know how this modelTo method is implemented. Is there a single, final implementation in an abstract skeleton class ? How does it respond to errors (like passing null as the clazz parameter, or triggering a ClassCastException) ? In other words : could this be an attempt to encapsulate all class casts into a single method, to replace ClassCastExceptions with a custom Exception or something like that ? (ClassCastException being a RuntimeException, it could have been a way to make sure a checked exception is thrown instead to enforce explicit exception handling everywhere in the code, I've already seen projects using such an approach...)

Bound mismatch with Java Generics "nesting"

I'm having difficulty using generics for a redesign/refactoring I'm doing on an existing design.
public interface DataDto {
// some data here
}
public interface SetDto<MyDataDto extends DataDto> {
List<MyDataDto> getData();
}
public interface Results<MySetDto extends SetDto<DataDto>> {
MySetDto getResults();
}
public interface MyProblemInterface<MyDataDto extends DataDto,
MySetDto extends SetDto<MyDataDto>,
MyResults extends Results<MySetDto>> {
// some stuff here
}
My problem is that I get the following error for MyProblemInterface:
Bound mismatch: The type MySetDto is not a valid substitute for the
bounded parameter <MySetDto extends SetDto<DataDto>> of the type
Results<MySetDto>
I admit my experience with generics is somewhat limited, but basically I'm trying to enforce that all three of the types in MyProblemInterface are the same "type". For example, if I have ADataDto, BDataDto, ASetDto<ADataDto>, BSetDto<BDataDto>, AResults<ASetDto>, BResults<BSetDto>, I want to ensure a class can't implement MyProblemInterface in a manner like AMyProblemInterface<ADataDto, ASetDto, BResults>. I would think that since MySetDto extends SetDto<MyDataDto> just fine, I could continue to take that further, but I'm apparently wrong.
Thank you for any help.
You want too much from Java generics.
It would be simpler to declare your interface as following:
public interface MyProblemInterface<MyDataDto extends DataDto>
And then force method to use SetDto<MyDataDto> and Results<MySetDto>.
By using generics in class/interface declaration you specify some kind of variety which is determined later in definition. But in your case you said that SetDto and Results will always have MyDataDto as parameter, so there is no variety.
Shouldn't it be something like this instead, and you add the actual classes only when implementing the interfaces.
Updated the code, because I forgot to add the right Results definition. This should work.
public interface DataDto {
// some data here
}
public interface SetDto<T extends DataDto> {
List<T> getData();
}
public interface Results<T extends SetDto<? extends DataDto>> {
T getResults();
}
public interface MyProblemInterface<T extends DataDto, E extends SetDto<T>, K extends Results<E>> {
// some stuff here
}

Using 2 levels of generics in an Abstract Class definition

I have this generic interface:
public interface TjbListener<T> {
public void hearChange(T t);
}
Which I use like this:
public interface ObjectOneListener extends TjbListener<ClassOne> {
}
I would like to write an abstract generic class A which takes a generic type U as a parameter and has a method (1) which itself calls a method (2) on U. Below is my attempt U should extend (or implement maybe?) the generic TjbListener interface.
public abstract class ListenerInformer<U extends TjbListener<"what should I write here">> {
List<U> mListeners = new ArrayList<U>();
public void addListener(U u){
mListeners.add(u);
}
public void informAll("what should I write here"){
for(U u:mListeners){
u.hearChange("what should I write here");
}
}
}
One solution I thought of as I was writing this question is below, but I don't know if it's really a solution, or if it has subtle problems I don't understand:
public abstract class ListenerInformer<U extends TjbListener<T>,T> {
List<U> mListeners = new ArrayList<U>();
public void addListener(U u){
mListeners.add(u);
}
public void informAll(T t){
for(U u:mListeners){
u.hearChange(t);
}
}
}
UPDATE: BEWARE
I have just discovered that this approach is almost useless for my particular case because the same class cannot implement the same interface with different parameters. See the question linked below. This means that I cannot have one class be a listener of two different types with my (or Johanna's) solution, without using a different strategy like composition.
How to make a Java class that implements one interface with two generic types?
Your second example should work. But if it is as simple as that, then there is no need for the Generic U, because every instance of a subclass of TjbListener also is an instance of TjbListener.
You can do more simple:
public abstract class ListenerInformer<T> {
List<TjbListener<T>> mListeners = new ArrayList<TjbListener<T>>();
public void addListener(TjbListener<T> u){
mListeners.add(u);
}
public void informAll(T t){
for(TjbListener<T> u:mListeners){
u.hearChange(t);
}
}
}
That works as your code does and is easier to handle.
Two generic types is necessary if you need the final implementation type of the subclass of TjbListener as return value of parameter, for example if you have
public U informAll2(T t){
for(U u:mListeners){
u.hearChange(t);
if (...)
return u;
}
}
In this case your declaration with two generic types is correct (just I'm not sure if it is possible to declare the generic U, which depends of T, before you declare T, of if you have to declare T first, like public abstract class ListenerInformer<T, U extends TjbListener<T>> )

Extending Generic Abstract Class & Correct Use of Super

public abstract class AbstractTool<AT extends AbstractThing> {
protected ArrayList<AT> ledger;
public AbstractTool() {
ledger = new ArrayList<AT>();
}
public AT getToolAt(int i) {
return ledger.get(i);
}
// More code Which operates on Ledger ...
}
public class Tool<AT extends AbstractThing> extends AbstractTool {
public Tool() {
super();
}
}
How do I correctly call super to pass the AT generic of Tool to the AbstractTool constructor?
It seems no matter what I pick AT to be when I declare Tool (Say, Tool<Thing>), that I always get back an AbstractThing instead of Thing. This seems to defeat the purpose of generics...
Help?
public class Tool<AT extends AbstractThing> extends AbstractTool<AT> {
In other words, if you extend or implement something with generics, remember to define the generics arguments for them.
Shouldn't it rather be
Tool<AT extends...> extends AbstractTool<AT>?
I think what you probably want is:
public abstract class AbstractTool<AT extends AbstractThing> {
protected List<AT> ledger = new ArrayList<AT>();
public AT getToolAt(int i) {
return ledger.get(i);
}
// More code Which operates on Ledger ...
}
public class Tool extends AbstractTool<Thing> {
// Tool stuff ...
}
Since Tool is a concrete class, it doesn't need to be parametrized itself. There is no need for the constructors if you initialize the List (oh and remember to program to the interface) at declaration, and because it is protected the subclasses can access it directly.

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