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Spring Boot #GetMapping rule for multiple mapping

I have 3 different method in controller for get requests.
-the 1st one to get a user by id with a path variable:
#GetMapping(path="/{id}")
public ResponseEntity<UserInfoDTO> getUserById(#PathVariable Long id)
The 2nd gets a user based on the username parameter:
public ResponseEntity<UserInfoDTO> getUserByUsername(#RequestParam String username)
And finally another one to get all users
public ResponseEntity<List<UserInfoDTO>> getAllUsers()
What should be the #GetMapping for the 2nd and 3rd method?
For exemple #GetMapping for all users and #GetMapping(path="/") for a user by username?
Or whatever...
Thanks.

Defining the Mappings purely depends on the context of your application and its usecases.
We can define a context prefixed by users and modified mappings are show in the snippet below and at the time of invocation it can be called like mentioned in the comments,
#GetMapping(path="/users/")
public ResponseEntity<UserInfoDTO> getUserByUsername(#RequestParam String username) {
}
// GET: <protocol>://<hostUrl>/users?username=<username>
#GetMapping(path="/users")
public ResponseEntity<List<UserInfoDTO>> getAllUsers() {
}
// GET: <protocol>://<hostUrl>/users
#GetMapping(path="/users/{id}")
public ResponseEntity<UserInfoDTO> getUserById(#PathVariable Long id)
// GET: <protocol>://<hostUrl>/users/<userid>

For example, optional username param:
#GetMapping(path = "/")
public ResponseEntity<?> getUserByUsername(#RequestParam(required = false) final String username) {
if (username != null) {
// http://localhost:8080/?username=myname
return new ResponseEntity<>(new UserInfoDTO("by username: " + username), HttpStatus.OK);
} else {
// http://localhost:8080/
return getAllUsers();
}
}
private ResponseEntity<List<UserInfoDTO>> getAllUsers() {
return new ResponseEntity<>(List.of(new UserInfoDTO("user1-of-all"), new UserInfoDTO("user2-of-all")),
HttpStatus.OK);
}
public static class UserInfoDTO {
public UserInfoDTO(final String name) {
this.name = name;
}
private final String name;
public String getName() {
return name;
}
}

Java Spring hash AND validate passwords

I'm pulling my hair out over this. I have a simple User entity like this
#Entity
public class User {
private static final PasswordEncoder pwEncoder = new BCryptPasswordEncoder();
#Id
#GeneratedValue
private long id;
#NotNull(message = "FIELD_IS_NULL")
#NotEmpty(message = "FIELD_IS_REQUIRED")
#Length(min = 3, message = "FIELD_MUST_HAVE_AT_LEAST_3_CHARACTERS")
private String username;
#NotNull(message = "FIELD_IS_NULL")
#NotEmpty(message = "FIELD_IS_REQUIRED")
#Length(min = 6, message = "FIELD_MUST_HAVE_AT_LEAST_6_CHARACTERS")
#Pattern(regexp = "^(?=.*\\d)(?=.*[a-z])(?=.*[A-Z]).{6,128}$", message="PW_MIN_6_MAX_128_1_UPPER_1_LOWER_1_NUMERIC")
private String password;
public User(String username, String password){
this.username = username;
this.password = pwEncoder.encode(password);
}
/* getters and setters */
}
This works fine except that the password hashing happens before any validation, which means that the hashed password is validated instead of the unhashed.
I'm using a PagingAndSortingRepository for all my repository needs and I'd really like to avoid implementing a controller just for this case.
I'm feeling like I'm missing something really big there...

If you using this constructor
public User(String username, String password){
this.username = username;
this.password = pwEncoder.encode(password);
}
you'll have encoded password instead of original value
you can make #PrePersist method like this:
#PrePersist
public void prePersist(){
password = pwEncoder.encode(password);
}

javax validation for login(email or phone)

class SingIn {
private String login;
private String password;
public SingIn(String login, String password) {
this.login = login;
this.password = password;
}
public String getLogin() {
return login;
}
public String getPassword() {
return password;
}
}
Login property could be an email(pattern ".+#.+") or a phone number(pattern "\+\d+").
Is it possible somehow with javax annotation to validate the login property?

Yes, it's possible by composing 2 #Pattern annotations with logical OR:
#ConstraintComposition(OR)
#Pattern(regexp = ".+#.+")
#Pattern(regexp = "\+\d+")
#ReportAsSingleViolation
#Target({ METHOD, FIELD })
#Retention(RUNTIME)
#Constraint(validatedBy = { })
public #interface EmailOrPhone {
See also the topic Boolean composition of constraints in the Hibernate Validator documentation.

Read & extract objects out of properties file with the following format in java/spring

My entity class
public class User {
String name;
String userName;
String password;
String[] roles;
static class ROLES {
static String ADMIN="ADMINISTRATOR";
static String USER="USER";
}
public User(){
}
public User(String name, String userName, String password, String... roles) {
this.name = name;
this.userName = userName;
this.password = password;
this.roles = roles;
}
}
Format of the properties file
user[0].name=Sujal Mandal
user[0].userName=sujal12
user[0].password=sujal123
user[0].roles=ADMIN,USER,SUPER_USER
user[1].name=Busra Ercelik
user[1].userName=busra12
user[1].password=busra123
user[1].roles=USER
I would like to write an util class which will read the properties file & return me the objects of Users
What would be the best way of doing this in Java/Spring boot enviornment?

The simplest solution is shown below where in you need to use #ConfigurationProperties:
#Component
#ConfigurationProperties("myproject")
public class UsersPopulator {
private List<User> users;//all users will be populated from application.properties
//add getter method
}
Your application.properties file looks like the below:
myproject.users[0].name=Sujal Mandal
myproject.users[0].userName=sujal12
myproject.users[0].password=sujal123
myproject.users[0].roles=ADMIN,USER,SUPER USER
myproject.users[1].name=Busra Ercelik
myproject.users[1].userName=busra12
myproject.users[1].password=busra123
myproject.users[1].roles=USER
You need to ensure that #EnableConfigurationProperties is added to the launcher class file.

Content type not support java Spring

I have created a route
#RequestMapping( value = "login" , method = RequestMethod.POST , consumes = MediaType.APPLICATION_FORM_URLENCODED_VALUE )
public void greet( #RequestBody Login l){
System.out.println(l.getName());
}
class Login{
public void setName(String name) {
this.name = name;
}
public void setPassword(String password) {
this.password = password;
}
private String name;
private String password;
public String getName() {
return name;
}
public String getPassword() {
return password;
}
public Login(){};
}
And i am using postman to send data to it:
headers:
'Accept':application/x-www-form-urlencoded
Content-Type:application/x-www-form-urlencoded
data:
name:Greet
password:Me
Yet i keep getting erorr:
"message": "Content type 'application/x-www-form-urlencoded;charset=UTF-8' not supported",
I have read various questions and post about this but i fail to find solution to fix this.
All help is appreciated, thanks.

Whenever we use MediaType.APPLICATION_FORM_URLENCODED_VALUE Spring does not understand it as a RequestBody. So remove RequestBody and do like this
#RequestMapping( value = "login" , method = RequestMethod.POST , consumes = MediaType.APPLICATION_FORM_URLENCODED_VALUE )
public void greet(Login l ){
if(l != null /*or whatever you want to do*/)
System.out.println(l.getName());
}

In Spring don't use #RequestBody annotation when consuming API with Content-type: 'application/x-www-form-urlencoded'.
You have to use MultiValueMap in case of application/x-www-form-urlencoded.