Develop Reference

Dependency injection with #Qualifier

Suppose the following code:
#Service
public class SearchService {
#Autowired
DependencyService dependencyService;
}
#Service
public class DependencyService {
private final Util util;
DependencyService(Util util){
this.util = util;
execute();
}
public void execute(){
util.execte();
}
}
#Component
public class ConcreteUtil implements Util{
#Override
public void execte() {
System.out.println("I'm the first concrete Util");
}
}
#Component
public class SecondConcreteUtil implements Util{
#Override
public void execte() {
System.out.println("I'm the second concrete Util");
}
}
In Plain Java I can do something like this:
public class SearchService {
DependencyService first = new DependencyService(new ConcreteUtil());
DependencyService second = new DependencyService(new SecondConcreteUtil());
}
But in Spring, it's not resolved by the client. We instruct Spring which bean to take from inside DependencyService:
DependencyService(#Qualifier("concreteUtil")Util util){
this.util = util;
execute();
}
And not like that:
#Autowired
#Qualifier("concreteUtil")
DependencyService dependencyService;
Why? To me this approach sounds like the opposite of decoupling. What do I miss? And how can Plain Java's result be achieved?
Edit:
I want this behaviour
public class SomeSerice {
DependencyService firstConcrete = new DependencyService(new ConcreteUtil());
}
public class OtherService {
DependencyService SecondConcrete = new DependencyService(new SecondConcreteUtil());
}
So I can reuse the code

You can declare multiple beans of type Dependency service inside some configuration class, like
#Qualifier("ConcreteUtilDepService")
#Bean
public DependencyService concreteUtilDS(#Qualifier("ConcreteUtil")Util util){
return new DependencyService (util);
}

How to call super constructor with params from abstract class if current class is spring bean?

I have two classes from custom library, that i can't change. Bass class have only constructor with custom param, that's not a bean. I want to pass param via child constructor, but i have no idea how to do that, so please help)
I tried this, but doesn't work. Idea underline param in Child constructor.
#Bean
public ChildClass childClass() {
return new ChildClass(new CustomParam(5));
}
Base class- can't use #Component, that class from library
public abstract class BaseClass {
private CustomParam customParam;
protected BaseClass(CustomParam customParam) {
this.customParam = customParam;
}
public Integer getCustomParam() {
return customParam.getParamValue();
}
}
Child class. My own extension
#Component
public class ChildClass extends BaseClass {
//idea underline customParam "could not autowire"
public ChildClass(CustomParam customParam) {
super(customParam);
}
}
Param class- can't use #Component, that class from library
public class CustomParam {
private Integer paramValue;
public CustomParam(Integer paramValue) {
this.paramValue = paramValue;
}
public Integer getParamValue() {
return paramValue;
}
public void setParamValue(Integer paramValue) {
this.paramValue = paramValue;
}
}

CustomParam need not to be annotated with #Component annotation, still you can declare it as bean using#Bean annotation
Config class
#Bean
public ChildClass childClass() {
return new ChildClass(customParam());
}
#Bean
public CustomParam customParam() {
return new CustomParam(5);
}

This should work. If you instantiate your bean like this you don't need the #Component annotation on your ChildClass. Make sure your bean definition is in a configurationclass (#Configuration) and your config is part of the component scan.
#Configuration
public class Config {
#Bean
public BaseClass childClass() {
return new ChildClass(new CustomParam(5));
}
}

Spring choose bean implementation at runtime

I'm using Spring Beans with annotations and I need to choose different implementation at runtime.
#Service
public class MyService {
public void test(){...}
}
For example for windows's platform I need MyServiceWin extending MyService, for linux platform I need MyServiceLnx extending MyService.
For now I know only one horrible solution:
#Service
public class MyService {
private MyService impl;
#PostInit
public void init(){
if(windows) impl=new MyServiceWin();
else impl=new MyServiceLnx();
}
public void test(){
impl.test();
}
}
Please consider that I'm using annotation only and not XML config.

1. Implement a custom Condition
public class LinuxCondition implements Condition {
#Override
public boolean matches(ConditionContext context, AnnotatedTypeMetadata metadata) {
return context.getEnvironment().getProperty("os.name").contains("Linux"); }
}
Same for Windows.
2. Use #Conditional in your Configuration class
#Configuration
public class MyConfiguration {
#Bean
#Conditional(LinuxCondition.class)
public MyService getMyLinuxService() {
return new LinuxService();
}
#Bean
#Conditional(WindowsCondition.class)
public MyService getMyWindowsService() {
return new WindowsService();
}
}
3. Use #Autowired as usual
#Service
public class SomeOtherServiceUsingMyService {
#Autowired
private MyService impl;
// ...
}

Let's create beautiful config.
Imagine that we have Animal interface and we have Dog and Cat implementation. We want to write write:
#Autowired
Animal animal;
but which implementation should we return?
So what is solution? There are many ways to solve problem. I will write how to use #Qualifier and Custom Conditions together.
So First off all let's create our custom annotation:
#Retention(RetentionPolicy.RUNTIME)
#Target({ElementType.METHOD, ElementType.FIELD, ElementType.TYPE})
public #interface AnimalType {
String value() default "";
}
and config:
#Configuration
#EnableAutoConfiguration
#ComponentScan
public class AnimalFactoryConfig {
#Bean(name = "AnimalBean")
#AnimalType("Dog")
#Conditional(AnimalCondition.class)
public Animal getDog() {
return new Dog();
}
#Bean(name = "AnimalBean")
#AnimalType("Cat")
#Conditional(AnimalCondition.class)
public Animal getCat() {
return new Cat();
}
}
Note our bean name is AnimalBean. why do we need this bean? because when we inject Animal interface we will write just #Qualifier("AnimalBean")
Also we crated custom annotation to pass the value to our custom Condition.
Now our conditions look like this (imagine that "Dog" name comes from config file or JVM parameter or...)
public class AnimalCondition implements Condition {
#Override
public boolean matches(ConditionContext conditionContext, AnnotatedTypeMetadata annotatedTypeMetadata) {
if (annotatedTypeMetadata.isAnnotated(AnimalType.class.getCanonicalName())){
return annotatedTypeMetadata.getAnnotationAttributes(AnimalType.class.getCanonicalName())
.entrySet().stream().anyMatch(f -> f.getValue().equals("Dog"));
}
return false;
}
}
and finally injection:
#Qualifier("AnimalBean")
#Autowired
Animal animal;

You can move the bean injection into the configuration, as:
#Configuration
public class AppConfig {
#Bean
public MyService getMyService() {
if(windows) return new MyServiceWin();
else return new MyServiceLnx();
}
}
Alternatively, you may use profiles windows and linux, then annotate your service implementations with the #Profile annotation, like #Profile("linux") or #Profile("windows"), and provide one of this profiles for your application.

Autowire all your implementations into a factory with #Qualifier annotations, then return the service class you need from the factory.
public class MyService {
private void doStuff();
}
My Windows Service:
#Service("myWindowsService")
public class MyWindowsService implements MyService {
#Override
private void doStuff() {
//Windows specific stuff happens here.
}
}
My Mac Service:
#Service("myMacService")
public class MyMacService implements MyService {
#Override
private void doStuff() {
//Mac specific stuff happens here
}
}
My factory:
#Component
public class MyFactory {
#Autowired
#Qualifier("myWindowsService")
private MyService windowsService;
#Autowired
#Qualifier("myMacService")
private MyService macService;
public MyService getService(String serviceNeeded){
//This logic is ugly
if(serviceNeeded == "Windows"){
return windowsService;
} else {
return macService;
}
}
}
If you want to get really tricky you can use an enum to store your implementation class types, and then use the enum value to choose which implementation you want to return.
public enum ServiceStore {
MAC("myMacService", MyMacService.class),
WINDOWS("myWindowsService", MyWindowsService.class);
private String serviceName;
private Class<?> clazz;
private static final Map<Class<?>, ServiceStore> mapOfClassTypes = new HashMap<Class<?>, ServiceStore>();
static {
//This little bit of black magic, basically sets up your
//static map and allows you to get an enum value based on a classtype
ServiceStore[] namesArray = ServiceStore.values();
for(ServiceStore name : namesArray){
mapOfClassTypes.put(name.getClassType, name);
}
}
private ServiceStore(String serviceName, Class<?> clazz){
this.serviceName = serviceName;
this.clazz = clazz;
}
public String getServiceBeanName() {
return serviceName;
}
public static <T> ServiceStore getOrdinalFromValue(Class<?> clazz) {
return mapOfClassTypes.get(clazz);
}
}
Then your factory can tap into the Application context and pull instances into it's own map. When you add a new service class, just add another entry to the enum, and that's all you have to do.
public class ServiceFactory implements ApplicationContextAware {
private final Map<String, MyService> myServices = new Hashmap<String, MyService>();
public MyService getInstance(Class<?> clazz) {
return myServices.get(ServiceStore.getOrdinalFromValue(clazz).getServiceName());
}
public void setApplicationContext(ApplicationContext applicationContext) throws BeansException {
myServices.putAll(applicationContext.getBeansofType(MyService.class));
}
}
Now you can just pass the class type you want into the factory, and it will provide you back the instance you need. Very helpful especially if you want to the make the services generic.

Simply make the #Service annotated classes conditional:
That's all. No need for other explicit #Bean methods.
public enum Implementation {
FOO, BAR
}
#Configuration
public class FooCondition implements Condition {
#Override
public boolean matches(ConditionContext context, AnnotatedTypeMetadata metadata) {
Implementation implementation = Implementation.valueOf(context.getEnvironment().getProperty("implementation"));
return Implementation.FOO == implementation;
}
}
#Configuration
public class BarCondition implements Condition {
#Override
public boolean matches(ConditionContext context, AnnotatedTypeMetadata metadata) {
Implementation implementation = Implementation.valueOf(context.getEnvironment().getProperty("implementation"));
return Implementation.BAR == implementation;
}
}
Here happens the magic.
The condition is right where it belongs: At the implementating classes.
#Conditional(FooCondition.class)
#Service
class MyServiceFooImpl implements MyService {
// ...
}
#Conditional(BarCondition.class)
#Service
class MyServiceBarImpl implements MyService {
// ...
}
You can then use Dependency Injection as usual, e.g. via Lombok's #RequiredArgsConstructor or #Autowired.
#Service
#RequiredArgsConstructor
public class MyApp {
private final MyService myService;
// ...
}
Put this in your application.yml:
implementation: FOO
👍 Only the implementations annotated with the FooCondition will be instantiated. No phantom instantiations. 👍

Just adding my 2 cents to this question. Note that one doesn't have to implement so many java classes as the other answers are showing. One can simply use the #ConditionalOnProperty. Example:
#Service
#ConditionalOnProperty(
value="property.my.service",
havingValue = "foo",
matchIfMissing = true)
class MyServiceFooImpl implements MyService {
// ...
}
#ConditionalOnProperty(
value="property.my.service",
havingValue = "bar")
class MyServiceBarImpl implements MyService {
// ...
}
Put this in your application.yml:
property.my.service: foo

MyService.java:
public interface MyService {
String message();
}
MyServiceConfig.java:
#Configuration
public class MyServiceConfig {
#Value("${service-type}")
MyServiceTypes myServiceType;
#Bean
public MyService getMyService() {
if (myServiceType == MyServiceTypes.One) {
return new MyServiceImp1();
} else {
return new MyServiceImp2();
}
}
}
application.properties:
service-type=one
MyServiceTypes.java
public enum MyServiceTypes {
One,
Two
}
Use in any Bean/Component/Service/etc. like:
#Autowired
MyService myService;
...
String message = myService.message()

FactoryBean doesn't use when bean instantiates

I am investigating how does FactoryBean works in spring framework.
As I understand it allow configure instantiation process.
I have the following beans:
#Component
public class MyInjectionClass {
String name;
Integer age;
//get and set methods
}
and
#Component
public class MyComponent {
#Autowired
MyInjectionClass myInjectionClass;
public MyInjectionClass getMyInjectionClass() {
return myInjectionClass;
}
}
and following cutom FactoryBean:
#Component
public class MyInjectionClassFactoryBean implements FactoryBean<MyInjectionClass> {
#Override
public MyInjectionClass getObject() throws Exception {
MyInjectionClass myInjectionClass = new MyInjectionClass();
myInjectionClass.setName("name");
myInjectionClass.setAge(12);
return myInjectionClass;
}
#Override
public Class<?> getObjectType() {
return MyInjectionClass.class;
}
#Override
public boolean isSingleton() {
return false;
}
}
Also I have wrote following code in my main method:
MyComponent bean = context.getBean(MyComponent.class);
System.out.println(bean.getMyInjectionClass().getAge());
It returns null.
What did I forget to do ?
P.S.
I use #ComponentScan("com.example.domain")
All beans and FactoryBean located there.
Solution
remove #Component above MyInjectionClass

How to inject ANY information about test in spring testing?

I would like some of my beans know something about test. SOMETHING. May be test class name or some of it's methods.
For example, suppose my test class has a method
public String getTestName() {
return getClass().getSimpleName();
}
This method returns test name and can be overridden.
Is it possible to inject this name into some beans of Spring context, to use during test?
For example, with autowire feature:
#Autowired
public String testName;
not only in test class, but in other beans too.
UPDATE
Below are two (failed) attempts to implement injecting testInstance. May be there are some convenient ways to do that?
#RunWith(SpringJUnit4ClassRunner.class)
#ContextConfiguration(classes = TestClassAwareTry._Config.class)
#TestExecutionListeners(value = { TestClassAwareTry._Listener.class },
mergeMode = TestExecutionListeners.MergeMode.MERGE_WITH_DEFAULTS)
public class TestClassAwareTry {
/**
* Interface to tag beans, who want to know if they are in test
*/
public interface TestInstanceAware {
void setTestInstance(Object value);
}
/**
* Sample bean, which would like to know if it is in test
*/
public static class MyBean implements TestInstanceAware {
private Object testInstance;
{
System.out.println("MyBean constructed");
}
public void setTestInstance(Object value) {
this.testInstance = value;
System.out.println("testInstance set");
}
public Object getTestInstance() {
return testInstance;
}
}
/**
* Attempt to inject testInstance with a bean, implementing {#link BeanPostProcessor}
*/
public static class TestInstanceInjector implements BeanPostProcessor {
public Object postProcessBeforeInitialization(Object bean, String beanName) throws BeansException {
if( bean instanceof TestInstanceAware ) {
TestInstanceAware aware = (TestInstanceAware) bean;
// we don't have access to test instance here
// otherwise I would write
//Object testInstance = getTestInstance();
//aware.setTestInstance(testInstance);
}
return bean;
}
public Object postProcessAfterInitialization(Object bean, String beanName) throws BeansException {
return bean;
}
}
/**
* Attempt to inject testInstance with test execution listener
*/
public static class _Listener extends AbstractTestExecutionListener {
#Override
public void prepareTestInstance(TestContext testContext) throws Exception {
Object testInstance = testContext.getTestInstance();
ApplicationContext context = testContext.getApplicationContext();
// we don't have setBean() method
// I would write if I have
// context.setBean("testInstance", context);
}
}
/**
* Java-based configuration
*/
#Configuration
public class _Config {
#Bean
public MyBean myBean() {
return new MyBean();
}
#Bean
public TestInstanceInjector testInstanceInjector() {
return new TestInstanceInjector();
// I would acquire test instance here and pass it to constructor, if I can
}
}
#Autowired
public MyBean myBean;
#Test
public void testInjected() {
assertSame( this, myBean.getTestInstance());
}
}

I've ended up creating ContextCustomizerFactory that registers BeanPostProcessor
package com.company.testing.base.spring;
import java.util.List;
import org.springframework.beans.factory.config.ConfigurableListableBeanFactory;
import org.springframework.test.context.ContextConfigurationAttributes;
import org.springframework.test.context.ContextCustomizer;
import org.springframework.test.context.ContextCustomizerFactory;
public class TestAwareContextCustomizerFactory implements ContextCustomizerFactory {
#Override
public ContextCustomizer createContextCustomizer(
Class<?> testClass, List<ContextConfigurationAttributes> configAttributes) {
return (context, mergedConfig) -> {
ConfigurableListableBeanFactory beanFactory = context.getBeanFactory();
beanFactory.addBeanPostProcessor(
new TestInstanceAwareBeanPostProcessor(mergedConfig.getTestClass()));
};
}
}
TestInstanceAwareBeanPostProcessor
public class TestInstanceAwareBeanPostProcessor implements BeanPostProcessor {
private final Class<?> testClass;
TestInstanceAwareBeanPostProcessor(Class<?> testClass) {
this.testClass = testClass;
}
#Override
public Object postProcessBeforeInitialization(Object bean, String beanName)
throws BeansException {
if (bean instanceof TestClassAware) {
((TestClassAware) bean).setTestClass(testClass);
}
return bean;
}
#Override
public Object postProcessAfterInitialization(Object bean, String beanName) throws BeansException {
return bean;
}
}
resources/META-INF/spring.factories
# ContextCustomizerFactories for the Spring TestContext Framework
org.springframework.test.context.ContextCustomizerFactory = \
com.company.testing.base.spring.TestAwareContextCustomizerFactory

The only way I've been able to do this is by delaying creation of the subject until you are in the test method and to have the bean in the prototype scope.
#RunWith(SpringJUnit4ClassRunner.class)
#ContextConfiguration(classes = { LiveConfig.class, DevConfig.class})
#ActiveProfiles("Dev")
public class MeTest {
#Autowired
public ApplicationContext context;
#Autowired
DevConfig devConfig;
#Rule
public TestName nameRule = new TestName();
#Before
public void setName() {
devConfig.setSettings(nameRule.getMethodName());
}
#Test
public void test() {
Bean subject = context.getBean(Bean.class);
System.out.println(subject.settings);
assertThat(subject.settings, is(nameRule.getMethodName()));
}
#Test
public void test2() {
Bean subject = context.getBean(Bean.class);
System.out.println(subject.settings);
assertThat(subject.settings, is(nameRule.getMethodName()));
}
}
#Configuration
class LiveConfig {
#org.springframework.context.annotation.Bean
public String getSettings() {
return "/some/real/file.txt";
}
#org.springframework.context.annotation.Bean
#Scope(value = ConfigurableBeanFactory.SCOPE_PROTOTYPE)
public Bean getBean() {
return new Bean();
}
}
#Configuration
class DevConfig {
private String settings;
#org.springframework.context.annotation.Bean
#Profile("Dev")
#Scope(value = ConfigurableBeanFactory.SCOPE_PROTOTYPE)
public String getSettings() {
return settings;
}
public void setSettings(String settings) {
this.settings = settings;
}
}
class Bean {
public Bean() {
System.out.println("Bean");
}
String settings;
#Autowired
void setSettings(String settings) {
System.out.println("Settings: " + settings);
this.settings = settings;
}
}
This uses Profiles to change what Live sees and what the tests see, and the a NameRule to get the name. It is clunky.
I would NOT use the TestName rule, but rather the TemporaryFolder rule and use that to set whatever setting your application uses for the output folder. I'd also only use DI in a test in very rare cases (i.e. full blown integration tests).

Do you mean like this?
public class MyTest {
#Test
public void testName() {
MyBean b = new MyBean(MyTest.class.getSimpleName());
b.doSomething();
}
}

You can achieve this in a more elegant way using Spring Boot Auto configuration feature by making yours, this way:
define a Configuration class that exposes or registers your bean this way:
#Configuration
public class MyBeanProviderConfiguration {
#ConditionalOnMissingBean
#Bean
public MyBean myBean() {
// return a fully initialised MyBean instance
}
}
Then define a custom annotation Spring Boot like, say #AutoConfigureMyBean this way:
#Retention(RetentionPolicy.RUNTIME)
#Target(ElementType.TYPE)
#ImportAutoConfiguration(MyBeanProviderConfiguration.class)
public #interface AutoConfigureMyBean {}
Then you can use this in your Spring test, here is an example:
#RunWith(SpringRunner.class)
#AutoConfigureMyBean
public class MyTest {
#Autowired
MyBean myBean;
}
Or also declare your MyBean #Autowired dependent bean in a regular Spring test (using a Config class), A MyBean instance will be automatically injected into it.