Jackson: Serializing Map<Object, BigDecimal> yields undesired object reference - java

Suppose I am trying to serialize the following with Jackson:
public class Investment implements Serializable{
private String shortName;
private MutualFund mutualFund;
public String getShortName() {
return shortName;
}
public void setShortName(String shortName) {
this.shortName = shortName;
}
public MutualFund getMutualFund() {
return mutualFund;
}
public void setMutualFund(MutualFund mutualFund) {
this.mutualFund = mutualFund;
}
}
That in turn refers to:
public class MutualFund implements Serializable{
private BigDecimal expenseRatio;
private Map<Investment, BigDecimal> underlyingInvestments;
public BigDecimal getExpenseRatio() {
return BigDecimalHelper.guard(expenseRatio);
}
public void setExpenseRatio(BigDecimal expenseRatio) {
this.expenseRatio = expenseRatio;
}
public Map<Investment, BigDecimal> getUnderlyingInvestments() {
return underlyingInvestments;
}
public void setUnderlyingInvestments(Map<Investment, BigDecimal>
underlyingFunds) {
this.underlyingInvestments = underlyingFunds;
}
}
When I try to serialize this with Jackson, everything else is fine except that I end up with an Investment object reference instead of the string with attributes like I was expecting:
"underlyingInvestments":{"com.financial.detail.Investment#5d465e4b":1}}
I've tried to fashion some custom serializers, but without success as I always get an object reference for the nested Investment(s). So, I have a two part question:
Can this problem be addressed simply with Jackson annotations?
If I have to build a custom serializer, could someone kindly point me in the right direction on how to best
approach this issue given the nested nature of this (e.g. an Investment could contain a Mutual Fund, which in turn has an Investment with a Mutual Fund...)

The problem is that you are using the object Investment as keys of a Map, so the question here is, what keys do you expect the json to have? Json keys cand only be strings so the mapper is executing the toString() method of the Investment class. If you know what that key should be, then you can implement the method, like this:
public class Investment implements Serializable {
private String shortName;
private MutualFund mutualFund;
// ...
#Override
public String toString() {
return shortName;
}
}
This will create a json object like this:
{
"expenseRatio": 1,
"underlyingInvestments": {
"shortName": 10
}
}
Also, as #chrylis-cautiouslyoptimistic suggested, another option is to use #JsonValue to indicate which method to use when serializing, like this:
public class Investment implements Serializable{
private String shortName;
private MutualFund mutualFund;
#JsonValue
public String getShortName() {
return shortName;
}
// ...
}

Related

Jakson polymorphic Enum case

I am glued with some Jackson polymorphic problem.
I work on a web JDR Character Editor personnal project. I use Springboot and try to stuck with the phylosophy. Moreover, I try to make some independent packages, because of study-case for my real work (another springboot project).
With no Jackson configuration, I have no problem for serialization of a Competence. But when I try to get back any modification on the web editor, so when Jackson make a deserialization of a Competence, problems occur with "dependance" property.
Here are my classes:
The one I try to serialize/deserialize:
public class Competence implements Composante, ComposanteTemplate {
public enum Categorie {
APPRENTI,
COMPAGNON
}
private String nom;
private String description;
private Categorie categorie;
private Chapitre chapitre;
private AttributTemplate dependance;
private List sousCompetences = new ArrayList();
public String getNom() {
return nom;
}
public void setNom(String nom) {
this.nom = nom;
}
public String getDescription() {
return description;
}
public void setDescription(String description) {
this.description = description;
}
public Competence getTemplate() {
return this;
}
public Categorie getCategorie() {
return categorie;
}
public void setCategorie(Categorie categorie) {
this.categorie = categorie;
}
public Chapitre getChapitre() {
return chapitre;
}
public void setChapitre(Chapitre chapitre) {
this.chapitre = chapitre;
}
public AttributTemplate getDependance() {
return dependance;
}
public void setDependance(AttributTemplate dependance) {
this.dependance = dependance;
}
public List getSousCompetences() {
return sousCompetences;
}
public void setSousCompetences(List sousCompetences) {
this.sousCompetences = sousCompetences;
}
public boolean isOuverte() {
return !sousCompetences.isEmpty();
}
}
The superclass of the property I have a problem with:
public interface AttributTemplate extends ComposanteTemplate {}
The two subclasses which could be use for Competence#dependance property:
public enum Carac implements AttributTemplate, Attribut {
FORT(Type.PHYSIQUE),
AGILE(Type.PHYSIQUE),
RESISTANT(Type.PHYSIQUE),
OBSERVATEUR(Type.PHYSIQUE),
SAVANT(Type.MENTALE),
RUSE(Type.MENTALE),
TALENTUEUX(Type.MENTALE),
CHARMEUR(Type.MENTALE);
public enum Type {
PHYSIQUE,
MENTALE
}
public final Type type;
public final String nom = name().toLowerCase();
private String description;
Carac(Type type) {
this.type = type;
}
#Override
public String getNom() { return nom; }
#Override
public String getDescription() { return description; }
#Override
public Carac getTemplate() { return this; }
public void setDescription(String description) { this.description = description; }
}
public enum ArtTemplate implements AttributTemplate {
ART_GUERRIER(2, 1),
ART_ETRANGE(1, 2),
ART_GUILDIEN(1, 1);
public static final String ART_PREFIX = "ART";
public final String nom = name().toLowerCase().replace("_", " ");
public final int nbCaracsPhysiques;
public final int nbCaracsMentales;
private String description;
ArtTemplate(int nbCaracsPhysiques, int nbCaracsMentales) {
this.nbCaracsMentales = nbCaracsMentales;
this.nbCaracsPhysiques = nbCaracsPhysiques;
}
#Override
public String getNom() {
return nom;
}
#Override
public String getDescription() {
return description;
}
public void setDescription(String description) {
this.description = description;
}
public int getNbCaracs() {
return nbCaracsPhysiques + nbCaracsMentales;
}
}
The result json (and then the json I send) is:
{"nom":"Comp_1489746646510","description":"ezbuixnwrclfvmgwdviubcauenzytpzzvumnohwyhpuynxaqhkjdbqygtrmbtlschthovuyoiolkauucwokkfjnaujnufshrjboykuqce","categorie":"APPRENTI","chapitre":"GUERRE","dependance":"ART_ETRANGE","ouverte":false,"sousCompetences":[]}
QUESTION:
I understand that my problem is caused by the abstract relation AttributTemplate, and then when Jackson try to deserialize, he does not know which of Carac or ArtTemplate class to use.
I try to keep unchanged Competence (Competence come from an external jar), so no annotation on this class is possible.
I've tried many of the solutions I found (Jackson 1.5: Polymorphic Type Handling, first steps ) and the only one which has worked was to define a DeserializationProblemHandler
mapper.addHandler(new DeserializationProblemHandler() {
#Override
public Object handleMissingInstantiator(DeserializationContext ctxt, Class<?> instClass, JsonParser p, String msg) throws IOException {
if (instClass == AttributTemplate.class) {
String name = p.getText();
return !name.startsWith(ArtTemplate.ART_PREFIX) ? Carac.valueOf(name) : ArtTemplate.valueOf(name);
}
return super.handleMissingInstantiator(ctxt, instClass, p, msg);
}
});
But I feel bad with this solution, because I am sure there is an other beautiful one.
So is it possible to configure the mapper in order that he is able to determine which of Carac or ArtTemplate he must use to get AttributTemplate?
EDIT:
I managed to have this:
{"nom":"Comp_1489756873433","description":"kruzueemlwisibshlkotasayfkhdqkqolvhlqgsnntndkpvbmmgklqysabiakaolempmupeyiqaztdcrhwimdksgzybbdzttwnwqjxhfo","categorie":"COMPAGNON","chapitre":"GUERRE","dependance":["mova.ged.perso.inne.Carac","AGILE"],"ouverte":true,"sousCompetences":[...]}
by configuring like this the mapper
abstract class CompetenceMixIn {
private AttributTemplate dependance;
#JsonTypeInfo(use=JsonTypeInfo.Id.CLASS, include=JsonTypeInfo.As.EXISTING_PROPERTY, property="dependance")
#JsonSubTypes({ #JsonSubTypes.Type(value = Carac.class, name = "carac"), #JsonSubTypes.Type(value = ArtTemplate.class, name = "artTemplate") })
public void setDependance(AttributTemplate dependance) {
this.dependance = dependance;
}
}
ObjectMapper mapper = jsonConverter.getObjectMapper();
mapper.addMixIn(Competence.class, CompetenceMixIn.class);
As you could see, I'm still parasited with the array that wrapped dependance value. I would (...)"dependance": "AGILE", (...) not (...)"dependance":["mova.ged.perso.inne.Carac", "AGILE"], (...)
And I don't know what to change in order to have this.
i have been looking into what you are trying to do. Unfortunatelly, I believe there are issues with Enums + inheritance.
I have an alternative solution that you could be using which is to use a custom creator and ignore unknown properties. See the following example:
public class JacksonInheritance {
public static void main(String[] args) throws IOException {
ObjectMapper mapper = new ObjectMapper();
Competence c = new Competence();
c.desc = "desc";
c.nome = "nome";
c.template = Att1.TEST_Att1;
String test = mapper.writeValueAsString(c);
System.out.println(test);
Competence readValue = mapper.readValue(test, Competence.class);
System.out.println(readValue.template);
}
#JsonIgnoreProperties(ignoreUnknown = true)
public static class Competence {
private static final Map<String, AttributeTemplate> templates;
static {
templates = new HashMap<>();
Stream.of(Att1.values()).forEach( a -> templates.put(a.name(), a));
Stream.of(Att2.values()).forEach( a -> templates.put(a.name(), a));
}
#JsonProperty
String nome;
#JsonProperty
String desc;
#JsonIgnore
AttributeTemplate template;
#JsonProperty("template_type")
public String getTempl() {
// Here you can do whichever way uou would like to serialise your template. This will be the key
return template.toString();
}
#JsonCreator
public static Competence create(#JsonProperty("template_type") String templateType) {
Competence c = new Competence();
c.template = templates.get(templateType);
return c;
}
}
public static interface AttributeTemplate {
}
public static enum Att1 implements AttributeTemplate {
TEST_Att1;
}
public static enum Att2 implements AttributeTemplate {
TEST2_Att2;
}
}
Here I am detaching the enum logic from the jackson logic and implement my own. This does not require a custom serialisation.
I basically say that I serialise my enum as its value (you can obviously choose which ever properties you would like for this).
My output json then looks as:
{"template_type":"TEST_Att1","nome":"nome","desc":"desc"}
At the return step I now know that the information I need to construct the correct enum template type from the template_type attribute. This is what I can inject into my factory method create.
In the create I can use my statically created map to populate the correct enum into my object. We can just create this map statically since our enums are finite and static.
The beauty of this is also that the generator is only used for creation. Using #JsonIgnoreProperties(ignoreUnknown = true), we can tell jackson to not freak out by all our custom elements in the json. It will simply deserialise any fields it can detect and leave the other ones (since we are using a custom template_type for our enum resolution).
Finally, I am ignoring the actual template in my bean because jackson won't be able to construct that.
I hope that this works for you/helps you. Sorry about the delay.
Reason for not using inheritance:
There seem to be issues with enum + inheritance in jackson. Particularly jackson by default uses reflection and calls the private constructor of the enum for generation. You may be able to get creators to work in a similar way as above though.
The deserialisation expects the template. I am going of the assumption that you do NOT necessarily want to serialise all elements of the enum. This is because the enum name, in my case TEST_Att1 makes the enum unique. There is no need to serialise and send all the different attributes these enums have around. However, Deserialization with #JsonSubTypes for no value - missing property error shows that jackson requires your template field to be at least present. This is a a slight issue, because you want to use an external property for this instead (so why include a null-field as suggested in your json just to make jackson happy)
This may not be the best solution, but I think it is relatively elegant given the restrictions. I hope that helps you,
Artur

Gson.fromJson() always returns null

I'm trying to deserialize some JSON to a generic class. The structure is roughly as follows:
public abstract class AbstractRequest implements Constants
{
public abstract Class<?> getClazz();
}
public class GetTransaction extends AbstractTransactionRequest
{
#Override
public Class<Transaction> getClazz()
{
return Transaction.class;
}
}
And the Transaction class is as follows:
public class Transaction implements Serializable
{
#SerializedName("_id")
private String id;
private int amount;
#SerializedName("details")
private Map<String, String> transactionDetails;
private class Details {
private String issuer;
#SerializedName("redirect_url")
private String redirectUrl;
#SerializedName("approval_url")
private String approvalUrl;
}
}
All classes are slightly more complicated but I removed irrelevant variables.
Here's a JSON sample:
{
"_id": "2740096e-58a0-4677-8947-84fcc54cfaad",
"amount": 456,
"details": {
"issuer": "MYBANK",
"redirect_url": "https://example.com/redirect/MYBANK",
"approval_url": "https://example.com/v1/transaction/2740096e-58a0-4677-8947-84fcc54cfaad/MYBANK/authorize"
}
}
Now, I deserialize this code by doing
response.setData(Gson.fromJson(this.getResponse(), this.request.getClazz()));
Where setData accepts a Object, and getResponse returns the JSON as a String. I then do (Transaction) response.getData() which casts data to a Transaction. However, this is always null. Can anyone tell my why?
Sorry for the potentially confusing code!

Converting LinkedHashMap<String,MyClass> to Java Object

How can I convert the JSON string like this:
{ "summary": {
"totalMR":4.599000000000903E12,
"totalMA":1.9174920000386694E11,
"totalQA":5.1111111181E9,
"totalQR":1.000020666115264E11
},
"result": [{},{}],
"success":"true",
"total":49
}
to a Java object. I went through many similar posts and implemented constructors but couldn't find the proper explanation of why I'm unable to De-serialize the JSON.
Am I doing anything wrong?
My Class:
public class expResponse {
private String success;
private String total;
private ArrayList<LinkedHashMap<String,Object>> result;
private LinkedHashMap<String,SummaryResponse> summary;
// Constructor: public expResponse(){}
// Getter and Setter
}
public class SummaryResponse {
private Float totalQR;
private Float totalQA;
private Float totalMR;
private Float totalMA;
public SummaryResponse(){}
// Setter and Getter
}
My Code:
private expResponse processResult(String result) throws IOException{
ObjectMapper objectMapper = new ObjectMapper();
expResponse expResponseObj =
objectMapper.readValue(result, expResponse.class);
return expResponseObj;
The json you posted would not deserialize into a map of SummaryResponse objects, but rather an individual SummaryResponse object. To make your binding work, you would have to have json that looked something like this:
{
...
'summary': {
'summary1': {"totalMR":4.599000000000903E12,"totalMA":1.9174920000386694E11,"totalQA":5.1111111181E9,"totalQR":1.000020666115264E11}
'summary2': {"totalMR":4.599000000000903E12,"totalMA":1.9174920000386694E11,"totalQA":5.1111111181E9,"totalQR":1.000020666115264E11}
}
...
}
Alternatively, if you need to make your Java class conform to the json you provided, you simply need to change the declaration of summary:
private SummaryResponse summary;
Field summary in your json is an object of type SummaryResponse and not a LinkedHashMap.
public class ExpResponse {
private String success;
private String total;
private ArrayList<LinkedHashMap<String,Object>> result;
private Summary summary;
}
I don't think you have a problem in the code. Your input fails because it is not in the correct format. If you try to write the same values from an object with the same values to string you get something like:
{
"success":"true",
"total":"49",
"result":null,
"summary":{
"one_summary":{
"totalQR":2000.0,
"totalQA":1500.0,
"totalMR":1000.0,
"totalMA":500.0
}
}
}
And the major difference is the one summary. This is because summary is a map and maps need a key for each entryset. That means that summary is your map which has a one_summary key.
Is it the SummaryResponse that can't be deserialised?
I guess your attributes should have the same name "totalMR", "totalMA"....
or you should use an annotation JsonProperty(value="totalMR") and so on.

Convert JSON many objects to single JSON using Jackson

I have JSON, with differents levels field, so I want to convert to a single JSON with fields with one level for example:
{
"prop1":"value1",
"prob2":"value2",
"prop3": {
"prop4":"value4",
"prop5":"value5"
}
... many level fields
}
result
{
"prop1":"value1",
"prop2":"value2",
"prop4":"value4",
"prop5":"value5"
.......
}
I'm using Jackson with annotation #JsonProperty("field"), I haven't problem wih fields of first level , but I donĀ“t know how to access field where to into more inside JSON , for this example are prop4 and prop5.
JsonUnwrapped is the annotation to use, it even works for multi-level nesting. For example:
#RunWith(JUnit4.class)
public class Sample {
#Test
public void testName() throws Exception {
SampleClass sample = new SampleClass("value1", "value2", new SubClass("value4", "value5", new SubSubClass("value7")));
new ObjectMapper().writeValue(System.out, sample);
}
#JsonAutoDetect(fieldVisibility=Visibility.ANY)
public static class SampleClass {
private String prop1;
private String prop2;
#JsonUnwrapped
private SubClass prop3;
public SampleClass(String prop1, String prop2, SubClass prop3) {
this.prop1 = prop1;
this.prop2 = prop2;
this.prop3 = prop3;
}
}
#JsonAutoDetect(fieldVisibility=Visibility.ANY)
public static class SubClass {
private String prop4;
private String prop5;
#JsonUnwrapped
private SubSubClass prop6;
public SubClass(String prop4, String prop5, SubSubClass prop6) {
this.prop4 = prop4;
this.prop5 = prop5;
this.prop6 = prop6;
}
}
#JsonAutoDetect(fieldVisibility=Visibility.ANY)
public static class SubSubClass{
private String prop7;
public SubSubClass(String prop7) {
this.prop7 = prop7;
}
}
}
will generate
{"prop1":"value1","prop2":"value2","prop4":"value4","prop5":"value5","prop7":"value7"}
Try implementing the #JsonUnwrapped annotation. More information at http://jackson.codehaus.org/1.9.9/javadoc/org/codehaus/jackson/annotate/JsonUnwrapped.html

Jackson enum Serializing and DeSerializer

I'm using JAVA 1.6 and Jackson 1.9.9 I've got an enum
public enum Event {
FORGOT_PASSWORD("forgot password");
private final String value;
private Event(final String description) {
this.value = description;
}
#JsonValue
final String value() {
return this.value;
}
}
I've added a #JsonValue, this seems to do the job it serializes the object into:
{"event":"forgot password"}
but when I try to deserialize I get a
Caused by: org.codehaus.jackson.map.JsonMappingException: Can not construct instance of com.globalrelay.gas.appsjson.authportal.Event from String value 'forgot password': value not one of declared Enum instance names
What am I missing here?
The serializer / deserializer solution pointed out by #xbakesx is an excellent one if you wish to completely decouple your enum class from its JSON representation.
Alternatively, if you prefer a self-contained solution, an implementation based on #JsonCreator and #JsonValue annotations would be more convenient.
So leveraging on the example by #Stanley the following is a complete self-contained solution (Java 6, Jackson 1.9):
public enum DeviceScheduleFormat {
Weekday,
EvenOdd,
Interval;
private static Map<String, DeviceScheduleFormat> namesMap = new HashMap<String, DeviceScheduleFormat>(3);
static {
namesMap.put("weekday", Weekday);
namesMap.put("even-odd", EvenOdd);
namesMap.put("interval", Interval);
}
#JsonCreator
public static DeviceScheduleFormat forValue(String value) {
return namesMap.get(StringUtils.lowerCase(value));
}
#JsonValue
public String toValue() {
for (Entry<String, DeviceScheduleFormat> entry : namesMap.entrySet()) {
if (entry.getValue() == this)
return entry.getKey();
}
return null; // or fail
}
}
Note that as of this commit in June 2015 (Jackson 2.6.2 and above) you can now simply write:
public enum Event {
#JsonProperty("forgot password")
FORGOT_PASSWORD;
}
The behavior is documented here: https://fasterxml.github.io/jackson-annotations/javadoc/2.11/com/fasterxml/jackson/annotation/JsonProperty.html
Starting with Jackson 2.6 this annotation may also be used to change serialization of Enum like so:
public enum MyEnum {
#JsonProperty("theFirstValue") THE_FIRST_VALUE,
#JsonProperty("another_value") ANOTHER_VALUE;
}
as an alternative to using JsonValue annotation.
You should create a static factory method which takes single argument and annotate it with #JsonCreator (available since Jackson 1.2)
#JsonCreator
public static Event forValue(String value) { ... }
Read more about JsonCreator annotation here.
Actual Answer:
The default deserializer for enums uses .name() to deserialize, so it's not using the #JsonValue. So as #OldCurmudgeon pointed out, you'd need to pass in {"event": "FORGOT_PASSWORD"} to match the .name() value.
An other option (assuming you want the write and read json values to be the same)...
More Info:
There is (yet) another way to manage the serialization and deserialization process with Jackson. You can specify these annotations to use your own custom serializer and deserializer:
#JsonSerialize(using = MySerializer.class)
#JsonDeserialize(using = MyDeserializer.class)
public final class MyClass {
...
}
Then you have to write MySerializer and MyDeserializer which look like this:
MySerializer
public final class MySerializer extends JsonSerializer<MyClass>
{
#Override
public void serialize(final MyClass yourClassHere, final JsonGenerator gen, final SerializerProvider serializer) throws IOException, JsonProcessingException
{
// here you'd write data to the stream with gen.write...() methods
}
}
MyDeserializer
public final class MyDeserializer extends org.codehaus.jackson.map.JsonDeserializer<MyClass>
{
#Override
public MyClass deserialize(final JsonParser parser, final DeserializationContext context) throws IOException, JsonProcessingException
{
// then you'd do something like parser.getInt() or whatever to pull data off the parser
return null;
}
}
Last little bit, particularly for doing this to an enum JsonEnum that serializes with the method getYourValue(), your serializer and deserializer might look like this:
public void serialize(final JsonEnum enumValue, final JsonGenerator gen, final SerializerProvider serializer) throws IOException, JsonProcessingException
{
gen.writeString(enumValue.getYourValue());
}
public JsonEnum deserialize(final JsonParser parser, final DeserializationContext context) throws IOException, JsonProcessingException
{
final String jsonValue = parser.getText();
for (final JsonEnum enumValue : JsonEnum.values())
{
if (enumValue.getYourValue().equals(jsonValue))
{
return enumValue;
}
}
return null;
}
I've found a very nice and concise solution, especially useful when you cannot modify enum classes as it was in my case. Then you should provide a custom ObjectMapper with a certain feature enabled. Those features are available since Jackson 1.6. So you only need to write toString() method in your enum.
public class CustomObjectMapper extends ObjectMapper {
#PostConstruct
public void customConfiguration() {
// Uses Enum.toString() for serialization of an Enum
this.enable(WRITE_ENUMS_USING_TO_STRING);
// Uses Enum.toString() for deserialization of an Enum
this.enable(READ_ENUMS_USING_TO_STRING);
}
}
There are more enum-related features available, see here:
https://github.com/FasterXML/jackson-databind/wiki/Serialization-Features
https://github.com/FasterXML/jackson-databind/wiki/Deserialization-Features
Try this.
public enum Event {
FORGOT_PASSWORD("forgot password");
private final String value;
private Event(final String description) {
this.value = description;
}
private Event() {
this.value = this.name();
}
#JsonValue
final String value() {
return this.value;
}
}
I like the accepted answer. However, I would improve it a little (considering that there is now Java higher than version 6 available).
Example:
public enum Operation {
EQUAL("eq"),
NOT_EQUAL("ne"),
LESS_THAN("lt"),
GREATER_THAN("gt");
private final String value;
Operation(String value) {
this.value = value;
}
#JsonValue
public String getValue() {
return value;
}
#JsonCreator
public static Operation forValue(String value) {
return Arrays.stream(Operation.values())
.filter(op -> op.getValue().equals(value))
.findFirst()
.orElseThrow(); // depending on requirements: can be .orElse(null);
}
}
You can customize the deserialization for any attribute.
Declare your deserialize class using the annotationJsonDeserialize (import com.fasterxml.jackson.databind.annotation.JsonDeserialize) for the attribute that will be processed. If this is an Enum:
#JsonDeserialize(using = MyEnumDeserialize.class)
private MyEnum myEnum;
This way your class will be used to deserialize the attribute. This is a full example:
public class MyEnumDeserialize extends JsonDeserializer<MyEnum> {
#Override
public MyEnum deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException {
JsonNode node = jsonParser.getCodec().readTree(jsonParser);
MyEnum type = null;
try{
if(node.get("attr") != null){
type = MyEnum.get(Long.parseLong(node.get("attr").asText()));
if (type != null) {
return type;
}
}
}catch(Exception e){
type = null;
}
return type;
}
}
Here is another example that uses string values instead of a map.
public enum Operator {
EQUAL(new String[]{"=","==","==="}),
NOT_EQUAL(new String[]{"!=","<>"}),
LESS_THAN(new String[]{"<"}),
LESS_THAN_EQUAL(new String[]{"<="}),
GREATER_THAN(new String[]{">"}),
GREATER_THAN_EQUAL(new String[]{">="}),
EXISTS(new String[]{"not null", "exists"}),
NOT_EXISTS(new String[]{"is null", "not exists"}),
MATCH(new String[]{"match"});
private String[] value;
Operator(String[] value) {
this.value = value;
}
#JsonValue
public String toStringOperator(){
return value[0];
}
#JsonCreator
public static Operator fromStringOperator(String stringOperator) {
if(stringOperator != null) {
for(Operator operator : Operator.values()) {
for(String operatorString : operator.value) {
if (stringOperator.equalsIgnoreCase(operatorString)) {
return operator;
}
}
}
}
return null;
}
}
There are various approaches that you can take to accomplish deserialization of a JSON object to an enum. My favorite style is to make an inner class:
import com.fasterxml.jackson.annotation.JsonCreator;
import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.annotation.JsonProperty;
import org.hibernate.validator.constraints.NotEmpty;
import java.util.Arrays;
import java.util.Map;
import java.util.function.Function;
import java.util.stream.Collectors;
import static com.fasterxml.jackson.annotation.JsonFormat.Shape.OBJECT;
#JsonFormat(shape = OBJECT)
public enum FinancialAccountSubAccountType {
MAIN("Main"),
MAIN_DISCOUNT("Main Discount");
private final static Map<String, FinancialAccountSubAccountType> ENUM_NAME_MAP;
static {
ENUM_NAME_MAP = Arrays.stream(FinancialAccountSubAccountType.values())
.collect(Collectors.toMap(
Enum::name,
Function.identity()));
}
private final String displayName;
FinancialAccountSubAccountType(String displayName) {
this.displayName = displayName;
}
#JsonCreator
public static FinancialAccountSubAccountType fromJson(Request request) {
return ENUM_NAME_MAP.get(request.getCode());
}
#JsonProperty("name")
public String getDisplayName() {
return displayName;
}
private static class Request {
#NotEmpty(message = "Financial account sub-account type code is required")
private final String code;
private final String displayName;
#JsonCreator
private Request(#JsonProperty("code") String code,
#JsonProperty("name") String displayName) {
this.code = code;
this.displayName = displayName;
}
public String getCode() {
return code;
}
#JsonProperty("name")
public String getDisplayName() {
return displayName;
}
}
}
In the context of an enum, using #JsonValue now (since 2.0) works for serialization and deserialization.
According to the jackson-annotations javadoc for #JsonValue:
NOTE: when use for Java enums, one additional feature is that value returned by annotated method is also considered to be the value to deserialize from, not just JSON String to serialize as. This is possible since set of Enum values is constant and it is possible to define mapping, but can not be done in general for POJO types; as such, this is not used for POJO deserialization.
So having the Event enum annotated just as above works (for both serialization and deserialization) with jackson 2.0+.
Besides using #JsonSerialize #JsonDeserialize, you can also use SerializationFeature and DeserializationFeature (jackson binding) in the object mapper.
Such as DeserializationFeature.READ_UNKNOWN_ENUM_VALUES_USING_DEFAULT_VALUE, which give default enum type if the one provided is not defined in the enum class.
In my case, this is what resolved:
import com.fasterxml.jackson.annotation.JsonCreator;
import com.fasterxml.jackson.annotation.JsonFormat;
import com.fasterxml.jackson.annotation.JsonProperty;
#JsonFormat(shape = JsonFormat.Shape.OBJECT)
public enum PeriodEnum {
DAILY(1),
WEEKLY(2),
;
private final int id;
PeriodEnum(int id) {
this.id = id;
}
public int getId() {
return id;
}
public String getName() {
return this.name();
}
#JsonCreator
public static PeriodEnum fromJson(#JsonProperty("name") String name) {
return valueOf(name);
}
}
Serializes and deserializes the following json:
{
"id": 2,
"name": "WEEKLY"
}
I hope it helps!
#JsonFormat(shape = JsonFormat.Shape.OBJECT)
public enum LoginOptionType {
PHONE(1, "Phone"), MAIL(2, "mail"), PERSONAL_EMAIL(3, "Personal email");
private static List<LoginOptionType> all;
static {
all = new ArrayList<LoginOptionType>() {
{
add(LoginOptionType.PHONE);
add(LoginOptionType.MAIL);
add(LoginOptionType.PERSONAL_EMAIL);
}
};
}
private final Integer viewValue;
private final String name;
LoginOptionType(Integer viewValue, String name) {
this.viewValue = viewValue;
this.name = name;
}
public Integer getViewValue() {
return viewValue;
}
public String getName() {
return name;
}
public static List<LoginOptionType> getAll() {
return all;
}
}
Response
[
{
"viewValue": 1,
"name": "Phone"
},
{
"viewValue": 2,
"name": "mail"
},
{
"viewValue": 3,
"name": "Personal email"
}
]
Here, 'value' acts as a deserialiser and 'namespace' acts as a serialiser. Hence, you can pass in value "Student Absent" to API while saving, and in DB it will be saved as "STUDENT_ABSENT". On the other hand, while retrieving data in your class, your API will return "Student Absent"
import com.fasterxml.jackson.annotation.JsonProperty;
public enum AttendanceEnums {
STUDENT_PRESENT,
#JsonProperty(value = "Student Absent", namespace = "Student Absent")
STUDENT_ABSENT;
}
I had been looking for a solution to enum serialization and I finally made a solution.
https://github.com/sirgilligan/EnumerationSerialization
https://digerati-illuminatus.blogspot.com/2022/10/java-enum-generic-serializer-and.html
It uses a new annotation and two new classes, EnumerationSerializer and EnumerationDeserializer. You can subclass the EnumerationDeserializer and make a class that sets the enum Class (typical approach) or you can annotate the enum and you don't have to have a subclass of EnumerationDeserializer.
#JsonSerialize(using = EnumerationSerializer.class)
#JsonDeserialize(using = EnumerationDeserializer.class)
#EnumJson(serializeProjection = Projection.NAME, deserializationClass = RGB.class)
enum RGB {
RED,
GREEN,
BLUE
}
Notice how the implementation of ContextualDeserializer pulls the class from the annotation.
https://github.com/sirgilligan/EnumerationSerialization/blob/main/src/main/java/org/example/EnumerationDeserializer.java
There is a lot of good code in this that might give insights.
For your specific question you could do this:
#JsonSerialize(using = EnumerationSerializer.class)
#JsonDeserialize(using = EnumerationDeserializer.class)
#EnumJson(serializeProjection = Projection.NAME, deserializationClass = Event.class)
public enum Event {
FORGOT_PASSWORD("forgot password");
//This annotation is optional because the code looks for value or alias.
#EnumJson(serializeProjection = Projection.VALUE)
private final String value;
private Event(final String description) {
this.value = description;
}
}
Or you could do this:
#JsonSerialize(using = EnumerationSerializer.class)
#JsonDeserialize(using = EnumerationDeserializer.class)
#EnumJson(serializeProjection = Projection.NAME, deserializationClass = Event.class)
public enum Event {
FORGOT_PASSWORD("forgot password");
private final String value;
private Event(final String description) {
this.value = description;
}
}
That's all you have to do.
Then if you have a class that "has a" event you can annotate each occurance to serialize the way you want.
class EventHolder {
#EnumJson(serializeProjection = Projection.NAME)
Event someEvent;
#EnumJson(serializeProjection = Projection.ORDINAL)
Event someOtherEvent;
#EnumJson(serializeProjection = Projection.VALUE)
Event yetAnotherEvent;
}
The simplest way I found is using #JsonFormat.Shape.OBJECT annotation for the enum.
#JsonFormat(shape = JsonFormat.Shape.OBJECT)
public enum MyEnum{
....
}
I did it like this :
// Your JSON
{"event":"forgot password"}
// Your class to map
public class LoggingDto {
#JsonProperty(value = "event")
private FooEnum logType;
}
//Your enum
public enum FooEnum {
DATA_LOG ("Dummy 1"),
DATA2_LOG ("Dummy 2"),
DATA3_LOG ("forgot password"),
DATA4_LOG ("Dummy 4"),
DATA5_LOG ("Dummy 5"),
UNKNOWN ("");
private String fullName;
FooEnum(String fullName) {
this.fullName = fullName;
}
public String getFullName() {
return fullName;
}
#JsonCreator
public static FooEnum getLogTypeFromFullName(String fullName) {
for (FooEnum logType : FooEnum.values()) {
if (logType.fullName.equals(fullName)) {
return logType;
}
}
return UNKNOWN;
}
}
So the value of the property "logType" for class LoggingDto will be DATA3_LOG
This post is old, but if it can help someone, use JsonFormat.Shape.STRING
#JsonFormat(shape = JsonFormat.Shape.STRING)
public enum SomeEnum{
#JsonProperty("SOME_PROPERTY")
someProperty,
...
}
Code results is like this
{"someenum":"SOME_PROPERTY"}

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