I have an InputStream containing a SOAP message, including the envelope. I don't know the contents of the body beforehand and therefore cannot create a Jaxb annotated class for it.
I've tried many ways, inlcuding a custom SOAPWrapper JaxB Class with XmlAnyElement and other ways. Currently I have this:
private InputStream removeSoapEnvelope(final InputStream inputStream) throws IOException, TransformerException
{
final SoapBody body = messageFactory.createWebServiceMessage(inputStream)
.getSoapBody();
final Transformer transformer = TransformerFactory.newInstance()
.newTransformer();
final DOMResult domResult = new DOMResult();
transformer.transform(body.getPayloadSource(), domResult);
final StringWriter writer = new StringWriter();
transformer.transform(new DOMSource(domResult.getNode()), new StreamResult(writer));
byte[] barray = writer.toString()
.getBytes(StandardCharsets.UTF_8);
return new ByteArrayInputStream(barray);
}
It seems to work but is horribly inefficient. Is there no short and concise way of achieving this with standard libraries and without regex?
Thanks
Here's a solution using XPath to get the element (pure JaxB? not sure). Takes the document as a regular XML document so it should work for any I guess
FileInputStream fileIS;
fileIS = new FileInputStream(System.getProperty("user.home") + "/tmp/soap.xml");
DocumentBuilderFactory builderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder builder = builderFactory.newDocumentBuilder();
Document xmlDocument;
xmlDocument = builder.parse(fileIS);
XPath xPath = XPathFactory.newInstance().newXPath();
String expression01 = "//*[local-name()='Body']";
Node currentNode = (Node) xPath.compile(expression01).evaluate(xmlDocument, XPathConstants.NODE);
StringWriter buf = new StringWriter();
Transformer xform = TransformerFactory.newInstance().newTransformer();
xform.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
xform.setOutputProperty(OutputKeys.INDENT, "yes");
xform.transform(new DOMSource(currentNode), new StreamResult(buf));
System.out.println(buf.toString());
Result:
<soap:Body>
<incident xmlns="http://example.com">
<Company type="String">Test</Company>
</incident>
</soap:Body>
I ended up doing it with regex. All other options are too slow:
private InputStream removeSoapEnvelope(final InputStream inputStream) throws IOException
{
final String text = new String(inputStream.readAllBytes(), UTF_8);
final String replace = text.replaceAll("\\s*<\\/?(?:SOAP-ENV|soap):(?:.|\\s)*?>", "");
File file = File.createTempFile("temp", XML_NS_PREFIX);
Files.writeString(file.toPath(), replace);
return new FileInputStream(file);
}
Related
I'm trying to sign xlm document using Certificate.
Code pretty much looks like this:
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
dbf.setNamespaceAware(true);
InputSource inputSource = new InputSource(new StringReader(xml));
inputSource.setEncoding("UTF-8");
Document document = dbf.newDocumentBuilder().parse(inputSource);
Element element = document.getDocumentElement();
DOMHelper.useIdAsXmlId(element);
FirstCertSelector firstCertSelector = new FirstCertSelector();
PassProvider passProvider = new PassProvider(cert.getCertPass());
KeyingDataProvider kdp = new FileSystemKeyStoreKeyingDataProvider("pkcs12", cert.getCertFilePath(), firstCertSelector, passProvider, passProvider, true);
DataObjectDesc dataObjectDesc = (new DataObjectReference("")).withTransform(new EnvelopedSignatureTransform());
SignedDataObjects signedDataObjects = (new SignedDataObjects()).withSignedDataObject(dataObjectDesc);
XadesSigner xadesSigner = (new XadesBesSigningProfile(kdp)).withAlgorithmsProviderEx(new SigningAlgorithm()).newSigner();
xadesSigner.sign(signedDataObjects, element);
TransformerFactory transformerFactory = TransformerFactory.newInstance();
Transformer transformer = transformerFactory.newTransformer();
transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
document.setXmlStandalone(true);
DOMSource source = new DOMSource(document);
StringWriter result = new StringWriter();
transformer.transform(source, new StreamResult(result));
String signedXML = result.toString();
Unfortunately signedXML in the signature and certificate part has some very strange characters at the end of line:
<ds:SignatureValue Id="xmldsig-some-id-bla-bla-sigvalue">
blablabla...
...
blablabla...
blabla==
</ds:SignatureValue>
<ds:KeyInfo>
<ds:X509Data>
<ds:X509Certificate>
blablabla...
...
blablabla...
blablabla...
blablabla...
blablabla...
blabla==
</ds:X509Certificate>
I've no idea where from comes this strange
ending.
I've tried may things (like -Dfile.encoding=UTF-8) to get read of this but without success.
I'm using
<dependency>
<groupId>com.googlecode.xades4j</groupId>
<artifactId>xades4j</artifactId>
<version>1.5.1</version>
</dependency>
Please help me.
My xml tag is :
<Description/>
I want with space :
<Description />
How can I do this in Java?
I am signing xml document , in original file space has been used but when I used following code and print it, it printing without space.
String thisLine = "";
String xmlString = "";
BufferedReader br = new BufferedReader(new FileReader(originalXmlFilePath));
while ((thisLine = br.readLine()) != null) {
xmlString = xmlString + thisLine.trim();
}
br.close();
ByteArrayInputStream xmlStream = new ByteArrayInputStream(xmlString.getBytes());
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
dbf.setNamespaceAware(true);
dbf.setIgnoringElementContentWhitespace(true);
dbf.setValidating(false);
Document doc = dbf.newDocumentBuilder().parse
(xmlStream );
doc.setXmlStandalone(true);
DOMSignContext dsc = new DOMSignContext
(keyEntry.getPrivateKey(), doc.getDocumentElement());
javax.xml.crypto.dsig.XMLSignature signature = fac.newXMLSignature(si, ki);
signature.sign(dsc);
// Output the resulting document.
// OutputStream os = new FileOutputStream(new File(destnSignedXmlFilePath));
TransformerFactory tf = TransformerFactory.newInstance();
Transformer trans = tf.newTransformer();
trans.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
trans.setOutputProperty(OutputKeys.INDENT, "yes");
StringWriter writer = new StringWriter();
trans.transform(new DOMSource(doc), new StreamResult(writer));
String output = writer.getBuffer().toString();//.replaceAll("\n|\r", "");
System.out.println("output== "+output);
What you are doing wrong is signing an arbitrary unprocessed text instead of submitting a canonical version of your document (without spaces in tags, but also with sorted attributes, with quotes of the same type, etc.) to the digital signature computation.
The Canonical XML and Exclusive Canonical XML W3C recommendations specify a standard and comprehensive way to eliminate arbitrary differences.
I am trying to read xml data from Document Object, and then using transformer to render the data inside the document object to pdf,using XSL,
My code is :
Document doc = toXML(arg1,arg2);
doc contains data like :
İlkyönetmeliği
with in tags
InputStream inputStream = new FileInputStream(xslFilePath);
transformer = factory.newTransformer(new StreamSource(inputStream));
transformer.setParameter("encoding", "UTF-8");
transformer.setOutputProperty(OutputKeys.ENCODING, "UTF-8");
transformer.transform(new DOMSource(doc.getDocumentElement()), res);
Special characters present in xml are not getting rendered accordingly and displaying like
#lk yard#m.
I have also set encoding to UTF-8 ,but still it is displaying like above.
It is not clear what causes your encoding problem because I cannot see how your document is read/constructed and how your transformation result res is set up. Try the following standalone example code which handles encoding with XSLT. Maybe you can even modify it gradually to use your actual data in order to see what goes wrong.
public static void main(String[] args) {
try {
String inputEncoding = "UTF-16";
String xsltEncoding = "ASCII";
String outputEncoding = "UTF-8";
ByteArrayOutputStream bos = new ByteArrayOutputStream();
OutputStreamWriter osw = new OutputStreamWriter(bos, inputEncoding);
osw.write("<?xml version='1.0' encoding='" + inputEncoding + "'?>");
osw.write("<root>İlkyönetmeliği</root>"); osw.close();
byte[] inputBytes = bos.toByteArray();
bos.reset();
osw = new OutputStreamWriter(bos, xsltEncoding);
osw.write("<?xml version='1.0' encoding='" + xsltEncoding + "'?>");
osw.write("<xsl:stylesheet xmlns:xsl='http://www.w3.org/1999/XSL/Transform' version='1.0'>");
osw.write("<xsl:template match='#*|node()'><xsl:copy><xsl:apply-templates select='#*|node()'/></xsl:copy></xsl:template>");
osw.write("</xsl:stylesheet>"); osw.close();
byte[] xsltBytes = bos.toByteArray();
bos.reset();
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
DocumentBuilder db = dbf.newDocumentBuilder();
Document d = db.parse(new InputSource(new InputStreamReader(new ByteArrayInputStream(inputBytes), inputEncoding)));
// if encoding declaration correct, use: Document d = db.parse(new InputSource(new ByteArrayInputStream(inputBytes)));
System.out.println(XPathFactory.newInstance().newXPath().evaluate("/root[1]", d));
TransformerFactory tf = TransformerFactory.newInstance();
Transformer t = tf.newTransformer(new StreamSource(new InputStreamReader(new ByteArrayInputStream(xsltBytes), xsltEncoding)));
// if encoding declaration correct, use: Transformer t = tf.newTransformer(new StreamSource(new ByteArrayInputStream(xsltBytes)));
StreamResult sr = new StreamResult(new OutputStreamWriter(bos, outputEncoding));
t.setOutputProperty(OutputKeys.ENCODING, outputEncoding);
t.transform(new DOMSource(d.getDocumentElement()), sr);
byte[] outputBytes = bos.toByteArray();
Scanner s = new Scanner(new InputStreamReader(new ByteArrayInputStream(outputBytes), outputEncoding));
String output = s.useDelimiter("</>").next(); // read all
s.close();
System.out.println(output);
} catch (Exception ex) {
ex.printStackTrace(System.err);
}
The example code applies the XSLT identity template to a minimal input containing the non-ASCII characters.
I output the string to check if it has been parsed correctly in the document using XPath. You may want to check your (intermediate) document if you know how to locate it with XPath.
Note that, if present, the parser tries to pick up the encoding declared in the XML processing instruction (PI) by default when reading an XML file. It assumes that actual and declared encoding are the same. If they differ or the PI is missing, then you can enforce the actual encoding e.g. by using an InputStreamReader as in the code above.
I have an XML that is UTF-8 and have some special characters in Chinese, I need to parse this xml.
DocumentBuilderFactory factory = DocumentBuilderFactory
.newInstance();
factory.setIgnoringElementContentWhitespace(true);
factory.setNamespaceAware(true);
factory.setValidating(true);
//byte[] buffer = xmlMsg.getBytes("UTF-16");
logger.info("transformToUTP " + xmlMsg);
//byte[] buffer = soapMessage.getBytes();
//ByteArrayInputStream stream = new ByteArrayInputStream(buffer);
InputSource is = new InputSource(new ByteArrayInputStream(
xmlMsg.getBytes("UTF-16")));
Document doc = factory.newDocumentBuilder().parse(is);
//Document doc = factory.newDocumentBuilder().parse(
new InputSource(new StringReader(xmlMsg)));
XPath xpath = XPathFactory.newInstance().newXPath();
xpath.setNamespaceContext(getNameSpace());
XPathExpression soapBodyExpr = xpath.compile(BODY_XPATH_EXP);
Node soapBody = (Node) soapBodyExpr.evaluate(doc,
XPathConstants.NODE);
Node reqMsgNode = soapBody.getFirstChild();
I am getting a null pointer exception on reqMsgNode.
Do not convert xml into a string, parse it as is, use
DocummentBuilder.parse(File) or DocumentBuilder.parse(InputStream)
the parser will take encoding from xml declaration e.g. <?xml version="1.0" encoding="UTF-8"?>, and if it is missing then it will use UTF-8 by default
How can I create an InputStream object from a XML Document or Node object to be used in xstream? I need to replace the ??? with some meaningful code. Thanks.
Document doc = getDocument();
InputStream is = ???;
MyObject obj = (MyObject) xstream.fromXML(is);
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
Source xmlSource = new DOMSource(doc);
Result outputTarget = new StreamResult(outputStream);
TransformerFactory.newInstance().newTransformer().transform(xmlSource, outputTarget);
InputStream is = new ByteArrayInputStream(outputStream.toByteArray());
If you are using Java without any Third Party Libraries, you can create InputStream using below code:
/*
* Convert a w3c dom node to a InputStream
*/
private InputStream nodeToInputStream(Node node) throws TransformerException {
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
Result outputTarget = new StreamResult(outputStream);
Transformer t = TransformerFactory.newInstance().newTransformer();
t.setOutputProperty(OutputKeys.OMIT_XML_DECLARATION, "yes");
t.transform(new DOMSource(node), outputTarget);
return new ByteArrayInputStream(outputStream.toByteArray());
}
One way to do it: Adapt the Document to a Source with DOMSource. Create a StreamResult to adapt a ByteArrayOutputStream. Use a Transformer from TransformerFactory.newTransformer to copy across the data. Retrieve your byte[] and stream with ByteArrayInputStream.
Putting the code together is left as an exercise.
public static InputStream document2InputStream(Document document) throws IOException {
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
OutputFormat outputFormat = new OutputFormat(document);
XMLSerializer serializer = new XMLSerializer(outputStream, outputFormat);
serializer.serialize(document);
return new ByteArrayInputStream(outputStream.toByteArray());
}
This works if you are using apache Xerces implementation, you can also set format parameter with the output format.
public static InputStream documentToPrettyInputStream(Document doc) throws IOException {
ByteArrayOutputStream outputStream = new ByteArrayOutputStream();
XMLWriter xmlWriter = new XMLWriter(outputStream, OutputFormat.createPrettyPrint());
xmlWriter.write(doc);
xmlWriter.close();
InputStream inputStream = new ByteArrayInputStream(outputStream.toByteArray());
return inputStream;
}
If you happen to use DOM4j and you need to print it pretty!